Create a menu-driven program that will accept a collection of non-ne.pdf
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Create a menu-driven program that will accept a collection of non-negative integers from the keyboard, calculate the mean and median values and display those values on the screen. Your menu should have 6 options: 1. Add a number to the array 2. Display the mean 3. Display the median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit Program particulars: Use an array of type int to store the integers entered by the user. There must be error checking on the input integer. If it is negative, the program will print an error message and re-prompt. This process will continue until a non-negative integer is entered. You must use a try-catch structure to trap both types of input errors (like letters where numbers should go) and range errors (like -1). You must write your own selectionSort utility method to sort your array. Place the method in an external file named SortSearchUtil.java. There must be error checking on the menu choice entered. If the user enters a choice not on the menu, the program will print an error message, re-display the menu and re-prompt. This process will continue until a valid option value is entered. Your solution must be modular. The design of your methods is up to you, but the rules of “highly cohesive” and “loosely coupled” must be followed. Your program should be well-documented. Explain what you’re doing in your code. Be sure to include the usual name and assignment notes. Note your program will have to sort your array before you can find the median. Include your SortSearchUtil.java file which will contain your sort method. This is what my project looks like already: Please fix it thanks. The SortSearchUtil will also be included. import java.util.Scanner; public class ArraySorting { public static void main(String[] args) { int option; int integer = 0; int optionOne; int optionTwo; int optionThree; int optionFour; int optionFive; int[] numbers = new int[5]; Scanner kb = new Scanner(System.in); System.out.println(\"Please enter a non-negative integer: \"); integer = kb.nextInt(); while((integer < 0)) { System.out.println(\"I am sorry that is not a non-negative integer.\"); System.out.println(\"\"); System.out.println(\"Please enter a non-negative integer: \"); integer = kb.nextInt(); } option = displayMenu(kb); while (option != 6) { switch (option) { case 1: optionOne(numbers); System.out.println(\"\"); break; case 2: optionTwo(numbers); System.out.println(\"\"); case 3: //optionThree(); System.out.println(\"\"); break; case 4: //optionFour(); System.out.println(\"\"); break; case 5: //optionFive(); System.out.println(\"\"); break; } option = displayMenu(kb); } if (option == 6) { System.out.println(); System.out.println(\"Thank you. Have a nice day.\"); } } private static int displayMenu(Scanner kb) { int option = 0; while (option != 1 && option != 2 && option != 3 && option != 4 && option !=5 && option !=6) { System.out.println(\"\\t\\t1. Add a number to the array\ \\t\\t2. Display the mean\ \\t\.
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![Create a menu-driven program that will accept a collection of non-negative integers from the
keyboard, calculate the mean and median values and display those values on the screen. Your
menu should have 6 options: 1. Add a number to the array 2. Display the mean 3. Display the
median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit
Program particulars: Use an array of type int to store the integers entered by the user. There
must be error checking on the input integer. If it is negative, the program will print an error
message and re-prompt. This process will continue until a non-negative integer is entered. You
must use a try-catch structure to trap both types of input errors (like letters where numbers
should go) and range errors (like -1). You must write your own selectionSort utility method to
sort your array. Place the method in an external file named SortSearchUtil.java. There must be
error checking on the menu choice entered. If the user enters a choice not on the menu, the
program will print an error message, re-display the menu and re-prompt. This process will
continue until a valid option value is entered. Your solution must be modular. The design of your
methods is up to you, but the rules of “highly cohesive” and “loosely coupled” must be followed.
Your program should be well-documented. Explain what you’re doing in your code. Be sure to
include the usual name and assignment notes. Note your program will have to sort your array
before you can find the median. Include your SortSearchUtil.java file which will contain your
sort method.
This is what my project looks like already: Please fix it thanks. The SortSearchUtil will also be
included.
import java.util.Scanner;
public class ArraySorting
{
public static void main(String[] args)
{
int option;
int integer = 0;
int optionOne;
int optionTwo;
int optionThree;
int optionFour;
int optionFive;
int[] numbers = new int[5];](https://image.slidesharecdn.com/createamenu-drivenprogramthatwillacceptacollectionofnon-ne-230708191014-00a760b9/85/Create-a-menu-driven-program-that-will-accept-a-collection-of-non-ne-pdf-1-320.jpg)
Recommended
An Introduction to Programming in Java: Arrays
An Introduction to Programming in Java: Arrays. Last delivered in 2012. All educational material listed or linked to on these pages in relation to King's College London may be provided for reference only, and therefore does not necessarily reflect the current course content.
Step 1You need to run the JAVA programs in sections 3.3 and 3.5 for.pdf
Step 1:You need to run the JAVA programs in sections 3.3 and 3.5 for selection sort and
insertion sort. You need to attach the output results.
Step 2: You need to modify these two programs, save them, submit them, and add some
comments and explanations to them to sort the list elements from high to low value. The index
should be IndexHighest instead IndexSmallest.
Step3: Run the modified programs and print out the results and submit them.
In the end, you need the running results for original JAVA programs (selection and insertion sort
JAVA programs), the two modified programs to sort the values from high to low value for
selection and insertion sorts, and the results for the modified programs.
This program uses the selection sort algorithm to sort an array. The code has been modified to
also calculate how many item comparisons are done. You can try running the program with
different arrays to see how the total number of comparisons changes (or doesn't change).
CODE 3.3 ---
import java.util.Arrays;
public class SelectionSortDemo {
private static int selectionSort(int[] numbers) {
// A variable to hold the number of item comparisons
int comparisons = 0;
for (int i = 0; i < numbers.length - 1; i++) {
// Find index of smallest remaining element
int indexSmallest = i;
for (int j = i + 1; j < numbers.length; j++) {
comparisons++;
if (numbers[j] < numbers[indexSmallest]) {
indexSmallest = j;
}
}
// Swap numbers[i] and numbers[indexSmallest]
int temp = numbers[i];
numbers[i] = numbers[indexSmallest];
numbers[indexSmallest] = temp;
}
return comparisons;
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the selectionSort method
int comparisons = selectionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
System.out.println("Total comparisons: " + comparisons);
}
}
CODE 3.5 ---
import java.util.Arrays;
public class InsertionSortDemo {
private static void insertionSort(int[] numbers) {
for (int i = 1; i < numbers.length; i++) {
int j = i;
while (j > 0 && numbers[j] < numbers[j - 1]) {
// Swap numbers[j] and numbers [j - 1]
int temp = numbers[j];
numbers[j] = numbers[j - 1];
numbers[j - 1] = temp;
j--;
}
}
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the insertionSort method
insertionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
}
}.
Im having an issue with the simulateOPT() methodthis is the p.pdf
I'm having an issue with the simulateOPT() method
this is the purpose:
this is my code:
import java.util.Scanner;
public class Main {
private static int n;
private static int[] referenceString;
private static int[] physicalFrames;
private static int[] victimPages;
private static int pageFaults;
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int choice;
do {
System.out.println("0 - Exit");
System.out.println("1 - Input N");
System.out.println("2 - Input the reference string");
System.out.println("3 - Simulate the OPT algorithm");
System.out.println("4 - Simulate the NEW algorithm");
System.out.print("Select option: ");
choice = input.nextInt();
switch (choice) {
case 0:
System.out.println("Exiting the program...");
break;
case 1:
System.out.print("Enter the value of N (2-8): ");
n = input.nextInt();
if (n < 2 || n > 8) {
System.out.println("Invalid value of N!");
n = 0;
} else {
physicalFrames = new int[n];
victimPages = new int[n];
System.out.println("N set to " + n + ".");
}
break;
case 2:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else {
System.out.print("Enter the reference string (length at least " + n + ", max length 20): ");
String[] strArr = input.next().split("");
int len = strArr.length;
if (len < n || len > 20) {
System.out.println("Invalid length of reference string!");
} else {
referenceString = new int[len];
for (int i = 0; i < len; i++) {
int page = Integer.parseInt(strArr[i]);
if (page < 0 || page > 9) {
System.out.println("Invalid page number!");
referenceString = null;
break;
}
referenceString[i] = page;
}
if (referenceString != null) {
System.out.println("Reference string set to " + String.join("", strArr) + ".");
}
}
}
break;
case 3:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else if (referenceString == null) {
System.out.println("Please enter the reference string first!");
} else {
System.out.println("Simulating the OPT algorithm...");
simulateOPT();
}
break;
case 4:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else if (referenceString == null) {
System.out.println("Please enter the reference string first!");
} else {
System.out.println("Simulating the NEW algorithm...");
simulateNEW();
}
break;
default:
System.out.println("Invalid choice!");
break;
}
System.out.println();
} while (choice != 0);
}
private static void simulateOPT() {
pageFaults = 0;
int len = referenceString.length;
System.out.println("Reference String\tPhysical Frames\tPage Faults\tVictim Pages");
for (int i = 0; i < len; i++) {
int page = referenceString[i];
boolean found = false;
for (int j = 0; j < n; j++) {
if (physicalFrames[j] == page) {
found = true;
break;
}
}
if (!found) {
pageFaults++;
int maxDist = 0;
int victimPage = -1;
for (int j = 0; j < n; j++) {
int dist = 0;
for (int k = i + 1; k < len; k++) {
dist++;
if (physicalFrames[j] == referenceString[k]) {
break;
}
}
if (dist > maxDist) {
maxDist = dist;
victimPage = j;
}
}
.
Write a method called uniqueNumbers that takes an int array as param.pdf
Write a method called uniqueNumbers that takes an int array as parameter, and returns a
different int array, which only contains the list of unique numbers in the original array. Hint: Use
the isPresent method defined below to accomplish your
here is the code we need to add too
Solution
solution
package com.mt.classes;
import java.util.ArrayList;
import java.util.List;
public class Lab8e {
public static void main(String[] args) {
int[] numbers = new int[20];
// Generate random numbers between 0 and 99 and fill up the array
for (int i = 0; i < numbers.length; i++) {
numbers[i] = (int) (Math.random() * 50);
}
System.out.println(\"The list is:\");
printNumbers(numbers);
// Task 1
System.out.println(\"The smallest number in the list is \"
+ smallestNumber(numbers));
// Task 2
System.out.println(\"The largest number in the list is \"
+ largestNumber(numbers));
// Task 3
System.out.println(\"The average of numbers in the list is \"
+ averageOfNumbers(numbers));
// Task 4: Extra Credit. Uncomment the following
// two lines if you complete this task.
System.out.println(\"The list of unique numbers is:\");
uniqueNumbers(numbers);
}
private static void uniqueNumbers(int[] numbers) {
for (int i = 0; i < numbers.length; i++) {
boolean isDuplicate = false;
for (int j = 0; j < i; j++) {
if (numbers[i] == numbers[j]) {
isDuplicate = true;
break;
}
}
if (!isDuplicate) {
System.out.print(numbers[i] + \" \");
}
}
}
public static void printNumbers(int[] list) {
for (int i = 0; i < list.length; i++) {
System.out.print(list[i] + \" \");
}
System.out.println();
}
// 1. Write a method called smallestNumber that
// takes an int array as parameter, and returns the
// smallest number
public static int smallestNumber(int[] list) {
int small = 100;
for (int i = 0; i < list.length; i++) {
if (list[i] < small) {
small = list[i];
}
}
return small;
}
// 2. Write a method called largestNumber that
// takes an int array as parameter, and returns the
// largest number
public static int largestNumber(int[] list) {
int large = 0;
for (int i = 0; i < list.length; i++) {
if (list[i] > large) {
large = list[i];
}
}
return large;
}
// 3. Write a method called averageOfNumbers that
// takes an int array as parameter, and returns the
// average of the numbers
public static double averageOfNumbers(int[] list) {
double average = 0.0;
for (int i = 0; i < list.length; i++) {
average = average + list[i];
}
average = average / list.length;
return average;
}
public static boolean isPresent(int[] list, int target) {
boolean found = false;
for (int i = 0; i < list.length && !found && list[i] != 0; i++) {
if (list[i] == target) {
found = true;
}
}
return found;
}
}
output
The list is:
16 14 11 31 7 8 18 49 27 43 9 39 38 18 6 16 8 30 32 15
The smallest number in the list is 6
The largest number in the list is 49
The average of numbers in the list is 21.75
The list of unique numbers is:
16 14 11 31 7 8 18 49 27 43 9 39 38 6 30 32 15.
Recommended
An Introduction to Programming in Java: Arrays
An Introduction to Programming in Java: Arrays. Last delivered in 2012. All educational material listed or linked to on these pages in relation to King's College London may be provided for reference only, and therefore does not necessarily reflect the current course content.
Step 1You need to run the JAVA programs in sections 3.3 and 3.5 for.pdf
Step 1:You need to run the JAVA programs in sections 3.3 and 3.5 for selection sort and
insertion sort. You need to attach the output results.
Step 2: You need to modify these two programs, save them, submit them, and add some
comments and explanations to them to sort the list elements from high to low value. The index
should be IndexHighest instead IndexSmallest.
Step3: Run the modified programs and print out the results and submit them.
In the end, you need the running results for original JAVA programs (selection and insertion sort
JAVA programs), the two modified programs to sort the values from high to low value for
selection and insertion sorts, and the results for the modified programs.
This program uses the selection sort algorithm to sort an array. The code has been modified to
also calculate how many item comparisons are done. You can try running the program with
different arrays to see how the total number of comparisons changes (or doesn't change).
CODE 3.3 ---
import java.util.Arrays;
public class SelectionSortDemo {
private static int selectionSort(int[] numbers) {
// A variable to hold the number of item comparisons
int comparisons = 0;
for (int i = 0; i < numbers.length - 1; i++) {
// Find index of smallest remaining element
int indexSmallest = i;
for (int j = i + 1; j < numbers.length; j++) {
comparisons++;
if (numbers[j] < numbers[indexSmallest]) {
indexSmallest = j;
}
}
// Swap numbers[i] and numbers[indexSmallest]
int temp = numbers[i];
numbers[i] = numbers[indexSmallest];
numbers[indexSmallest] = temp;
}
return comparisons;
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the selectionSort method
int comparisons = selectionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
System.out.println("Total comparisons: " + comparisons);
}
}
CODE 3.5 ---
import java.util.Arrays;
public class InsertionSortDemo {
private static void insertionSort(int[] numbers) {
for (int i = 1; i < numbers.length; i++) {
int j = i;
while (j > 0 && numbers[j] < numbers[j - 1]) {
// Swap numbers[j] and numbers [j - 1]
int temp = numbers[j];
numbers[j] = numbers[j - 1];
numbers[j - 1] = temp;
j--;
}
}
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the insertionSort method
insertionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
}
}.
Im having an issue with the simulateOPT() methodthis is the p.pdf
I'm having an issue with the simulateOPT() method
this is the purpose:
this is my code:
import java.util.Scanner;
public class Main {
private static int n;
private static int[] referenceString;
private static int[] physicalFrames;
private static int[] victimPages;
private static int pageFaults;
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int choice;
do {
System.out.println("0 - Exit");
System.out.println("1 - Input N");
System.out.println("2 - Input the reference string");
System.out.println("3 - Simulate the OPT algorithm");
System.out.println("4 - Simulate the NEW algorithm");
System.out.print("Select option: ");
choice = input.nextInt();
switch (choice) {
case 0:
System.out.println("Exiting the program...");
break;
case 1:
System.out.print("Enter the value of N (2-8): ");
n = input.nextInt();
if (n < 2 || n > 8) {
System.out.println("Invalid value of N!");
n = 0;
} else {
physicalFrames = new int[n];
victimPages = new int[n];
System.out.println("N set to " + n + ".");
}
break;
case 2:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else {
System.out.print("Enter the reference string (length at least " + n + ", max length 20): ");
String[] strArr = input.next().split("");
int len = strArr.length;
if (len < n || len > 20) {
System.out.println("Invalid length of reference string!");
} else {
referenceString = new int[len];
for (int i = 0; i < len; i++) {
int page = Integer.parseInt(strArr[i]);
if (page < 0 || page > 9) {
System.out.println("Invalid page number!");
referenceString = null;
break;
}
referenceString[i] = page;
}
if (referenceString != null) {
System.out.println("Reference string set to " + String.join("", strArr) + ".");
}
}
}
break;
case 3:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else if (referenceString == null) {
System.out.println("Please enter the reference string first!");
} else {
System.out.println("Simulating the OPT algorithm...");
simulateOPT();
}
break;
case 4:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else if (referenceString == null) {
System.out.println("Please enter the reference string first!");
} else {
System.out.println("Simulating the NEW algorithm...");
simulateNEW();
}
break;
default:
System.out.println("Invalid choice!");
break;
}
System.out.println();
} while (choice != 0);
}
private static void simulateOPT() {
pageFaults = 0;
int len = referenceString.length;
System.out.println("Reference String\tPhysical Frames\tPage Faults\tVictim Pages");
for (int i = 0; i < len; i++) {
int page = referenceString[i];
boolean found = false;
for (int j = 0; j < n; j++) {
if (physicalFrames[j] == page) {
found = true;
break;
}
}
if (!found) {
pageFaults++;
int maxDist = 0;
int victimPage = -1;
for (int j = 0; j < n; j++) {
int dist = 0;
for (int k = i + 1; k < len; k++) {
dist++;
if (physicalFrames[j] == referenceString[k]) {
break;
}
}
if (dist > maxDist) {
maxDist = dist;
victimPage = j;
}
}
.
Write a method called uniqueNumbers that takes an int array as param.pdf
Write a method called uniqueNumbers that takes an int array as parameter, and returns a
different int array, which only contains the list of unique numbers in the original array. Hint: Use
the isPresent method defined below to accomplish your
here is the code we need to add too
Solution
solution
package com.mt.classes;
import java.util.ArrayList;
import java.util.List;
public class Lab8e {
public static void main(String[] args) {
int[] numbers = new int[20];
// Generate random numbers between 0 and 99 and fill up the array
for (int i = 0; i < numbers.length; i++) {
numbers[i] = (int) (Math.random() * 50);
}
System.out.println(\"The list is:\");
printNumbers(numbers);
// Task 1
System.out.println(\"The smallest number in the list is \"
+ smallestNumber(numbers));
// Task 2
System.out.println(\"The largest number in the list is \"
+ largestNumber(numbers));
// Task 3
System.out.println(\"The average of numbers in the list is \"
+ averageOfNumbers(numbers));
// Task 4: Extra Credit. Uncomment the following
// two lines if you complete this task.
System.out.println(\"The list of unique numbers is:\");
uniqueNumbers(numbers);
}
private static void uniqueNumbers(int[] numbers) {
for (int i = 0; i < numbers.length; i++) {
boolean isDuplicate = false;
for (int j = 0; j < i; j++) {
if (numbers[i] == numbers[j]) {
isDuplicate = true;
break;
}
}
if (!isDuplicate) {
System.out.print(numbers[i] + \" \");
}
}
}
public static void printNumbers(int[] list) {
for (int i = 0; i < list.length; i++) {
System.out.print(list[i] + \" \");
}
System.out.println();
}
// 1. Write a method called smallestNumber that
// takes an int array as parameter, and returns the
// smallest number
public static int smallestNumber(int[] list) {
int small = 100;
for (int i = 0; i < list.length; i++) {
if (list[i] < small) {
small = list[i];
}
}
return small;
}
// 2. Write a method called largestNumber that
// takes an int array as parameter, and returns the
// largest number
public static int largestNumber(int[] list) {
int large = 0;
for (int i = 0; i < list.length; i++) {
if (list[i] > large) {
large = list[i];
}
}
return large;
}
// 3. Write a method called averageOfNumbers that
// takes an int array as parameter, and returns the
// average of the numbers
public static double averageOfNumbers(int[] list) {
double average = 0.0;
for (int i = 0; i < list.length; i++) {
average = average + list[i];
}
average = average / list.length;
return average;
}
public static boolean isPresent(int[] list, int target) {
boolean found = false;
for (int i = 0; i < list.length && !found && list[i] != 0; i++) {
if (list[i] == target) {
found = true;
}
}
return found;
}
}
output
The list is:
16 14 11 31 7 8 18 49 27 43 9 39 38 18 6 16 8 30 32 15
The smallest number in the list is 6
The largest number in the list is 49
The average of numbers in the list is 21.75
The list of unique numbers is:
16 14 11 31 7 8 18 49 27 43 9 39 38 6 30 32 15.
The java code works, I just need it to display the results as in t.pdf
The internal rate of return (IRR) refers to the compound annual rate of return that a project
generates based on its up-front cost and subsequent cash flows. Consider the case of Blue Llama
Mining Company:
Blue Llama Mining Company is evaluating a proposed capital budgeting project (project Sigma)
that will require an initial investment of $850,000.
Blue Llama Mining Company has been basing capital budgeting decisions on a projects NPV;
however, its new CFO wants to start using the IRR method for capital budgeting decisions. The
CFO says that the IRR is a better method because returns in percentage form are easier to
understand and compare to required returns. Blue Llama Mining Companys WACC is 8%, and
project Sigma has the same risk as the firms average project.
The project is expected to generate the following net cash flows:
Which of the following is the correct calculation of project Sigmas IRR?
24.78%
33.04%
27.53%
31.66%
If this is an independent project, the IRR method states that the firm should .
If the projects cost of capital were to increase, how would that affect the IRR?
The IRR would increase.
The IRR would decrease.
The IRR would not change.YearCash FlowYear 1$300,000Year 2$425,000Year 3$400,000Year
4$425,000.
This is a lab for a java program that I am very unsure of, it has to.pdf
This is a lab for a java program that I am very unsure of, it has to do with Binary trees, and I am
very confused on how to work with them, if anyone can help I will be very grateful, thank you!!
You are to create a balanced binary tree which means that at each node n, the size of the left
subtree of n is within one of the size of the right subtree of n
Your program shall read in from user input a list of positive integers into an array (at most 100
elements). Your input stops when it reads a 0 (sentinel ).
Your program will then sort the elements in the array. You MUST write your own sort routine
You are then to create a balanced binary tree from this data.
You are then to print out your balanced tree using pre-order, in-order, and post-order routines
Requirements
1) Program must read integers from user input into an array
2) Program must sort integers with sort routine written by user
3) Program must implement a binary tree object using links (not arrays)
4) Program must implement at least methods PREORDER, INORDER, POSTORDER, ADD
(create a balanced binary search tree from the given array).
5) Output demonstrating input and output
Solution
import java.io.*;
import java.util.*;
class Nodetype
{
int info;
int ht;
Nodetype left;
Nodetype right;
Nodetype(int i)
{
info=i;
ht=0;
left=null;
right=null;
}
}
class Functions
{
Nodetype AVLroot;
void create()
{
int x,n,i;
AVLroot=null;
int[] a=new int[100];
String str;
int counter=0;
System.out.println(\"\ Enter numbers:\");
do
{
x=getNumber();
a[counter]=x;
counter++;
}while(x!=0);
int[] finalarr=new int[100];
finalarr=sort(a);
int tcntr=0;
while(finalarr[tcntr]!=0)
{
AVLroot=insert(AVLroot,finalarr[tcntr]);
tcntr++;
}
System.out.println(\"\ Preorder sequene:\");
preorder(AVLroot);
System.out.println(\"\ Inorder sequence:\");
inorder(AVLroot);
System.out.println(\"\ Postorder sequence:\");
postorder(AVLroot);
}
int[] sort(int[] arr)
{
int n = arr.length;
int temp = 0;
for(int i=0; i < n; i++){
for(int j=1; j < (n-i); j++){
if(arr[j-1] > arr[j]&&arr[j]!=0){
//swap elements
temp = arr[j-1];
arr[j-1] = arr[j];
arr[j] = temp;
}
}
}
return (arr);
}
int getNumber()
{
String str;
int ne=0;
InputStreamReader input=new InputStreamReader(System.in);
BufferedReader in=new BufferedReader(input);
try
{
str=in.readLine();
ne=Integer.parseInt(str);
}
catch(Exception e)
{
System.out.println(\"\ I/O error.\");
}
return ne;
}
Nodetype insert(Nodetype T,int x)
{
if(T==null)
{
Nodetype node=new Nodetype(x);
T=node;
}
else
if(x>T.info)
{
T.right=insert(T.right,x);
if(BF(T)==-2)
if(x>T.right.info)
T=RR(T);
else
T=RL(T);
}
else
if(xrh)
return(lh);
return(rh);
}
Nodetype rotateright(Nodetype x)
{
Nodetype y;
y=x.left;
x.left=y.right;
y.right=x;
x.ht=height(x);
y.ht=height(y);
return(y);
}
Nodetype rotateleft(Nodetype x)
{
Nodetype y;
y=x.right;
x.right=y.left;
y.left=x;
x.ht=height(x);
y.ht=height(y);
return(y);
}
Nodetype RR(Nodetype T)
{
T=rotateleft(T);
return(T);
}
Nodetype LL(Nodetype T)
{
T=rotateright(T);
return(T);
.
import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
Write a program that will test a name) method no sorting routine from.docx
Write a program that will test a name) method no sorting routine from
Program 1 (Practicing an example of function using call by referenc.pdf
Program 1: (Practicing an example of function using call by reference)
Write a program that reads a set of information related to students in C++ class and prints them
in a table format. The information is stored in a file called data.txt. Each row of the file contains
student number, grade for assignment 1, grade for assignment 2, grade for assignment 3, and
grade for assignment 4. Your main program should read each row, pass the grades for the three
assignments to a function called ProcessRow to calculate the average of the grades, minimum of
the four assignments, and the maximum of the four assignments. The results (average,
maximum, and minimum) should be returned to the main program and the main program prints
them on the screen in a table format. For example, if the file includes
126534 7 8 10 7
321345 5 6 4 9
324341 8 3 8 5
your program should print
Std-Id A1 A2 A3 A4 Min Max Average
----------------------------------------------------------------------------------
126534 7 8 10 7 7 10 8
321345 5 6 4 9 4 9 6
324341 8 3 8 5 3 8 6
You must use call by reference to do the above question.
_________________________________________________________________
Program 2: (Practicing an example of function using call by value)
Repeat the above question using call by value. This means you need to have three different
functions: one to calculate the average, another to calculate the minimum, and the third one to
calculate the maximum. This is how to call these functions:
Max = CalculateMax(A1,A2,A3, A4);
Min = CalculateMin(A1,A2,A3, A4);
Average = CalculateAvg(A1,A2,A3, A4);
_________________________________________________________________
Program 3:
Write a program with several functions that performs the following tasks. :
Create a function that reads the following 5 float numbers from the file data.txt into array Called
Arr1.
12.0 15.0 29.3 25.0 93.2
Copy array Arr1 into array Arr2 in reverse order
Print array Arr1.
Print array Arr2.
Find the number of elements in array Arr1 that are >= 80 and <=100.
Find the number of the elements in array Arr1 in which their contents are divisible by 5
Find the index of the elements in array Arr1 in which their contents are divisible by 3.
Find mean (average) in array Arr1.
Find the maximum number in array Arr1.
Ask the user to input a key. Then search for the key in array Arr1 and inform the user about the
existence (true / false) of the key in array
Your program should include several functions.
A function for filling up the information from file into an array (part a should call this function)
A function that does the copying of one array into another in reverse order. Arrays must have the
same size (part b should call this function)
Printing any array with any size (part c and d should call this function)
finding and returning the number of elements between 80 and 100 in any array with any size
(part e calls this function)
finding and returning the number of elements in an array that are divisible by 5 (par.
ArrayTest.java import java.util.Arrays; import java.util.Scann.pdf
ArrayTest.java
import java.util.Arrays;
import java.util.Scanner;
public class ArrayTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int table[] = new int[10];
int count = 0;
Scanner scan = new Scanner(System.in);
for(int i=0; i<10; i++){
System.out.println(\"Enter Array Element:\");
int n = scan.nextInt();
if(n < 0){
System.out.println(\"Invalid Number.\");
i--;
if(count >= 5)
break;
}else{
table[i] = n;
count++;
}
}
int sum = 0;
System.out.println(\"Array Elements are: \"+Arrays.toString(table));
for(int i=0; i avg){
high++;
}
else{
equal++;
}
}
System.out.println(\"Number of elements less than average \"+less);
System.out.println(\"Number of elements greater than average \"+high);
System.out.println(\"Number of elements equal to average \"+equal);
for(;;){
System.out.println(\"Enter Search Element (-1 to quit): \");
int searchNum = scan.nextInt();
if(searchNum == -1){
break;
}
int index = find(searchNum, table, count);
if(index == -1){
System.out.println(\"Element not found\");
}
else{
System.out.println(\"Element found at \"+index);
}
}
smallest(table, count);
}
public static int find (int valueToSearchFor, int intArray[ ], int numberOfValidEnties){
for(int i=0; i a[i]){
min = a[i];
index = i;
}
}
System.out.println(\"The smallest element is \"+min+\" index is \"+index);
int temp = a[0];
a[0] = a[index];
a[index] = temp;
System.out.println(\"After swap array elements are :\"+Arrays.toString(a));
}
}
Output:
Enter Array Element:
3
Enter Array Element:
4
Enter Array Element:
5
Enter Array Element:
2
Enter Array Element:
1
Enter Array Element:
6
Enter Array Element:
7
Enter Array Element:
8
Enter Array Element:
-1
Invalid Number.
Array Elements are: [3, 4, 5, 2, 1, 6, 7, 8, 0, 0]
The Sum is 36
The Average is : 4.5
Number of elements less than average 4
Number of elements greater than average 4
Number of elements equal to average 0
Enter Search Element (-1 to quit):
2
Element found at 3
Enter Search Element (-1 to quit):
3
Element found at 0
Enter Search Element (-1 to quit):
1
Element found at 4
Enter Search Element (-1 to quit):
6
Element found at 5
Enter Search Element (-1 to quit):
-1
The smallest element is 1 index is 4
After swap array elements are :[1, 4, 5, 2, 3, 6, 7, 8, 0, 0]
Solution
ArrayTest.java
import java.util.Arrays;
import java.util.Scanner;
public class ArrayTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int table[] = new int[10];
int count = 0;
Scanner scan = new Scanner(System.in);
for(int i=0; i<10; i++){
System.out.println(\"Enter Array Element:\");
int n = scan.nextInt();
if(n < 0){
System.out.println(\"Invalid Number.\");
i--;
if(count >= 5)
break;
}else{
table[i] = n;
count++;
}
}
int sum = 0;
System.out.println(\"Array Elements are: \"+Arrays.toString(table));
for(int i=0; i avg){
high++;
}
else{
equal++;
}
}
System.out.println(\"Number of elements less than average \"+less);
System.out.println(\"Number of.
Getting StartedCreate a class called Lab8. Use the same setup for .pdf
Getting Started
Create a class called Lab8. Use the same setup for setting up your class and main method as you
did for the previous assignments. Be sure to name your file Lab8.java. Additionally, make
another file called Arrays.java. This file will be an object, so simply start it off by declaring an
Arrays class. You can copy the following skeleton and fill in the appropriate code below each of
the comments:
public class Arrays {
/ Instance Variables
// Constructors
// findMin 1
// findMax
// calcSum
// calcAverage
// toString
}
Task Overview
Your task for this lab is to create a class called Arrays with some array processing methods. This
class will maintain an array and the number of elements present in it. Additionally, methods will
be available to display the current min and max elements along with the average of all of them.
Finally, a toString() method will be available to cleanly display all the array elements. Finally,
you will write a simple driver class to test out the above Arrays class.
Part 1: Instance Variables for Arrays
The first thing to do for the Arrays class is to set up its instance variables. Declare the following
(private) instance variables:
• An int array called array ? this will be the array we will be writing methods for.
• An int called count - this represents the number of valid elements in the array.
Part 2:
Constructors for Arrays The Arrays class will have two constructors. The first constructor takes
the maximum size of the array as input as a parameter and initializes the array instance variable
appropriately. It also sets count to size. Finally, it will initialize all of the array elements to some
values between 0 and 10, inclusive. To create this constructor, follow these steps:
• Import java.util.Random to make use of the random number generator.
• Create a constructor with the following header: public Arrays(int size)
• Initialize your array variable and set its size to size (see the chart on page 252 for reference on
initializing arrays). Be very careful that you are setting the value of your array instance variable,
as opposed to creating a new variable called array.
• Set the value of the count variable to size because we will be populating the entire array.
• Copy the following code to the constructor in order to generate random values between 0 and
10, inclusive:
Random rand = new Random();
for (int i = 0; i < count; i++)
{
array[i] = (rand.nextInt(10));
}
Next, create another constructor with the following header: public Arrays(int[] arr). This
constructor will initialize the class by using the passed arr argument in order to fill its instance
variables. The following things need to be done inside of this constructor:
• Set the array variable equal to arr.
• Set the count variable equal to the length of the array.
Part 3: Displaying the Output findMin()
The first method of this class will search the array for the minimum element. Copy the following
code for the findMin method. Note how the count i.
write Ocaml programe to add all numbers in a list the solution .pdf
write Ocaml programe to add all numbers in a list ?
the solution :
let rec sum list =
match list with
[ ] -> 0
| x:: tail -> x + (sum tail);;
let a = [2;4;5;6;1;9;10 ];;
sum a;;
question is :-Write a Ocaml Program to multiply each element in a list by 2. a= [2;4;5;6;1;9;10 ]
Solution
let rec intmult : int list * int -> int list =
function ([],_) -> [0]
| ([x] ,al) -> [x * al]
| (x::xs,al) -> x * al :: intmult (xs, al);;
Also, you can use the map function as I mentioned below,
let intmult (l,m)= List.map (fun x -> x * m) l.
why is lifelong learning important for Engineers Give an example to.pdf
why is lifelong learning important for Engineers? Give an example to support your argument.
please help me with this ..
Solution
A decade ago, a group of experts estimated the half-life of an engineer\'s technical skills--how
long it would take for half of everything an engineer knew about his or her field to become
obsolete. For mechanical engineers it was 7.5 years. For electrical engineers it was 5. And for
software engineers, it was a mere 2.5 years, less time than it takes to get an undergraduate
degree. Today, those numbers are surely even smaller.
Technology is rushing headlong into the future at a pace that takes one\'s breath away. Personal
computers, the Internet, genetic engineering, advanced materials, new forms of chemical
synthesis--all these things and more are changing our world swiftly, profoundly, and, in most
cases, for the better. But the excitement and the progress come at a cost. Rapid change is not
always comfortable, and no one knows this better than the people whose job it is to stoke the
technological juggernaut.
Think about it. In some specialties, engineers must update half of everything they know every
couple of years, all the while working full-time to design products according to the best
standards of the moment--which might change next month. In even the slower-paced fields,
engineers must reinvent themselves at least once a decade.
There\'s more. A generation ago, an engineer could expect to carve out a niche in one well-
defined area-- automotive steering systems, say, or chemical plant instrumentation--and remain
there for a lifetime. No longer. As technological change accelerates and product lines rise and
fall in ever-diminishing life cycles, engineers find themselves switching jobs more often, to the
point that those starting out today may hold half a dozen jobs over their careers, even if they
manage to remain with the same company throughout. So besides staying abreast of
developments in their own specialties, engineers must be prepared to switch nimbly to a new
field when the old one peters out.
And, to complicate things further, these professional demands come at a time of upheaval in the
employment landscape. Global competition has sparked a wave of downsizings in technology
firms, destroying much of the job security that engineers used to take for granted and pushing
companies to contract out more and more of their design work. Today, service firms such as
Andersen Consulting are the largest recruiters of engineering graduates on some college
campuses, eclipsing the big manufacturing companies in the number of hires.
The bottom line: A large and growing percentage of engineers now work as contract technical
experts, hiring out for a particular job at a particular company, then moving on when it is
finished. They may be independent consultants or they may work for consulting firms, but either
way they don\'t have the long-term stability that joining a traditional manufacturing firm used to
provide.
I.
Which of the following is true of aldol reactions1.The thermodyna.pdf
Which of the following is true of aldol reactions?
1.The thermodynamics and kinetics of aldol reactions can be controlled by base selection.
2.Aldol reactions can be completed by reacting an aldehyde and a ketone in the presence of a
base.
3.The yields of aldol reactions involving only one type of a hydrogen are generally higher than
the yields of those involving multiple types of a hydrogens.
4.Aldol reactions are used to create carbon–carbon bonds.
5.All of the above are true of aldol reactions.
Solution
Answer:
5.All of the above are true of aldol reactions.
Explanation:
Aldol reaction is the reaction between two cabonyl compounds with one carbonyl compound
contains one alpha -hydrogen in the presence of base to give beta hydroxy carbonyl compound.
So option 1 is correct.
The kinetic prodduct is the formation of C-C bond on the less substituted alpha carbon atom, can
be acheived by the bulky base LDA and thermodynamic product is the formation of C-C bond on
the more substituted alpha carbon to the carbonyl carbon can be achieved by the less bulky base
like NaOC2H5. so option 2 is correct.
If there are more kinds of active hydrogens gives mixed aldol product that gives less yield and
the compound with one kind of active hydrogen gives only one product with more yield. So
option 4 is correct.
In aldol reaction there is a formation of c-c bond. so option 4 is also correct..
Using at least two examples (whenever applicable), concisely discuss .pdf
Using at least two examples (whenever applicable), concisely discuss the following terms. You
are strongly recommended to at least visit and study the posted article on websites listed in the
reference section. Programming paradigm Procedural programming OOP or Object-Oriented
Programming Abstract Data Type or ADT Four basic principles of object orientation
Abstraction Encapsulation/Information hiding Inheritance Polymorphism Benefits of OOP
Object-Oriented Design & Analysis or OODA or OODA UML for OOD Attributes and
behaviors of an object C++ classes and objects Instance and instantiation of an object State of
an object
Solution
1) Programming paradigm is a way or style of writing programming languages.
For example in python, blocks are represented using blocks. In python intendation is important.
IN java, flower/open braces are used.
2)
Procedural programming
This is style of routines and subroutines.
Declaring the subroutine, top of program declaring prototype declaring and bottom of program
writing the implementation of methods.
Also subroutine is accssible is depends on public accessifiers.
3)
OOPS programming language where all variables and methods are accessed via object.
Object is real entity which stores the data.
Java, python,c++ are examples of OOPS programming languages.
4)
Abstract data type is representing the hidden object. It hides the implementation.
Example: We can see the car physically but cannot see the internal strucure.
Seeing the machine physically but doesn\'t bother about internal strucure..
Transforming Cultures from Consumerism to Sustainability - Essay.pdf
Transforming Cultures from Consumerism to Sustainability - Essay
Solution
Some 60 percent of ecosystem services are being despoiled or used unsustainably. The damage is
the consequence of cultural systems which give confidence to people to describe their happiness
in addition to success in terms of how much they consume. This propensity, together with
unsustainable population growth rates, is overpowering our finite planet, intimidating to cause
noteworthy disruptions to Earth\'s climate and ecosystems, and consequently to human
civilization. Consumerism has engulfed human cultures and Earth’s ecosystems and if left
unaddressed, we threat global disaster. However if we direct this wave, deliberately changing our
cultures to center on sustainability, we will not only put off disaster, however may steer in an era
of sustainability—one which allows all people to prosper whilst protecting, even restoring, Earth.
World watch Institute\'s Transforming Cultures plan turns a critical eye to how we can transfer
today\'s consumer cultures in the direction of cultures of sustainability. The solution to this
revolution will lie in harnessing institutions which play a vital role in shaping society— like
media, educational services, business, governments, traditions, as well as social movements—to
inspire this new cultural course.
The plan also seeks to bring women into educational, economic, political as well as health parity
with men. This will necessitate the wearing away of cultural norms which endorse early and
frequent childbearing while intensifying women\'s capability to decide when to bear children.
Studies explain that such advances slow and ultimately end population growth, allowing for
more sustainable growth all-inclusive..
Trane has 145 marbles. He gives 20 to Katie, 52 to Gwen, and 31 to Yu.pdf
Trane has 145 marbles. He gives 20 to Katie, 52 to Gwen, and 31 to Yusef. He keeps the rest.
Who has the most marbles? Trane Katie Gwen Yusef
Solution
Trane has 145 marbles , he gave 20 to Katie and 52 to Gwen , and 31 to Yusef.
It means now
Katie has = 20 ,
Gwen has = 52
Yusef has = 31
and Trane has =145 -20 -52 -31 = 42
It means Gwen has the most marbles , that is 52.
This project should be done in C# using Visual Studio - Windows Form.pdf
This project should be done in C# using Visual Studio - Windows Forms.
This is a puzzle game of Wheel of Fortune. I need the puzzle to be \"Back to the Future\", and it
should not matter if the player guesses a upper or lowercase letter. If possible I could use step by
step instructions for creating the windows form and then entering the code to make the program
run. All the requirements for the game will be in pictures below.
The example uses the puzzle \"pulp fiction\", but again I need my puzzle to be \"Back to the
Future\". Thanks! You are to create the classic game of Wheel of Fortune. Your application
should consist of 3 players, underlines to represent letters in the puzzle, and the available letters.
The initial screen should look something like:
Solution
form1 designer:
namespace Wheel_Of_Fortune
{
partial class Form1
{
///
/// Required designer variable.
///
private System.ComponentModel.IContainer components = null;
///
/// Clean up any resources being used.
///
/// true if managed resources should be disposed; otherwise, false.
protected override void Dispose(bool disposing)
{
if (disposing && (components != null))
{
components.Dispose();
}
base.Dispose(disposing);
}
#region Windows Form Designer generated code
///
/// Required method for Designer support - do not modify
/// the contents of this method with the code editor.
///
private void InitializeComponent()
{
this.label1 = new System.Windows.Forms.Label();
this.labelLetters = new System.Windows.Forms.Label();
this.panel1 = new System.Windows.Forms.Panel();
this.label2 = new System.Windows.Forms.Label();
this.textBox1 = new System.Windows.Forms.TextBox();
this.textBox2 = new System.Windows.Forms.TextBox();
this.textBox3 = new System.Windows.Forms.TextBox();
this.textBox4 = new System.Windows.Forms.TextBox();
this.textBox5 = new System.Windows.Forms.TextBox();
this.textBox6 = new System.Windows.Forms.TextBox();
this.textBox7 = new System.Windows.Forms.TextBox();
this.textBox8 = new System.Windows.Forms.TextBox();
this.textBox9 = new System.Windows.Forms.TextBox();
this.textBox10 = new System.Windows.Forms.TextBox();
this.textBox11 = new System.Windows.Forms.TextBox();
this.textBox12 = new System.Windows.Forms.TextBox();
this.textBox13 = new System.Windows.Forms.TextBox();
this.textBox14 = new System.Windows.Forms.TextBox();
this.textBox15 = new System.Windows.Forms.TextBox();
this.buttonSpin = new System.Windows.Forms.Button();
this.buttonSolve = new System.Windows.Forms.Button();
this.label3 = new System.Windows.Forms.Label();
this.label4 = new System.Windows.Forms.Label();
this.label5 = new System.Windows.Forms.Label();
this.textBoxP1 = new System.Windows.Forms.TextBox();
this.textBoxP2 = new System.Windows.Forms.TextBox();
this.textBoxP3 = new System.Windows.Forms.TextBox();
this.labelPrompt = new System.Windows.Forms.Label();
this.panel1.SuspendLayout();
this.SuspendLayout();
//
// label1
//
this.label1.AutoSize = true;
this.label1.Location = new System.Drawing.Point(68, 13.
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The java code works, I just need it to display the results as in t.pdf
The internal rate of return (IRR) refers to the compound annual rate of return that a project
generates based on its up-front cost and subsequent cash flows. Consider the case of Blue Llama
Mining Company:
Blue Llama Mining Company is evaluating a proposed capital budgeting project (project Sigma)
that will require an initial investment of $850,000.
Blue Llama Mining Company has been basing capital budgeting decisions on a projects NPV;
however, its new CFO wants to start using the IRR method for capital budgeting decisions. The
CFO says that the IRR is a better method because returns in percentage form are easier to
understand and compare to required returns. Blue Llama Mining Companys WACC is 8%, and
project Sigma has the same risk as the firms average project.
The project is expected to generate the following net cash flows:
Which of the following is the correct calculation of project Sigmas IRR?
24.78%
33.04%
27.53%
31.66%
If this is an independent project, the IRR method states that the firm should .
If the projects cost of capital were to increase, how would that affect the IRR?
The IRR would increase.
The IRR would decrease.
The IRR would not change.YearCash FlowYear 1$300,000Year 2$425,000Year 3$400,000Year
4$425,000.
This is a lab for a java program that I am very unsure of, it has to.pdf
This is a lab for a java program that I am very unsure of, it has to do with Binary trees, and I am
very confused on how to work with them, if anyone can help I will be very grateful, thank you!!
You are to create a balanced binary tree which means that at each node n, the size of the left
subtree of n is within one of the size of the right subtree of n
Your program shall read in from user input a list of positive integers into an array (at most 100
elements). Your input stops when it reads a 0 (sentinel ).
Your program will then sort the elements in the array. You MUST write your own sort routine
You are then to create a balanced binary tree from this data.
You are then to print out your balanced tree using pre-order, in-order, and post-order routines
Requirements
1) Program must read integers from user input into an array
2) Program must sort integers with sort routine written by user
3) Program must implement a binary tree object using links (not arrays)
4) Program must implement at least methods PREORDER, INORDER, POSTORDER, ADD
(create a balanced binary search tree from the given array).
5) Output demonstrating input and output
Solution
import java.io.*;
import java.util.*;
class Nodetype
{
int info;
int ht;
Nodetype left;
Nodetype right;
Nodetype(int i)
{
info=i;
ht=0;
left=null;
right=null;
}
}
class Functions
{
Nodetype AVLroot;
void create()
{
int x,n,i;
AVLroot=null;
int[] a=new int[100];
String str;
int counter=0;
System.out.println(\"\ Enter numbers:\");
do
{
x=getNumber();
a[counter]=x;
counter++;
}while(x!=0);
int[] finalarr=new int[100];
finalarr=sort(a);
int tcntr=0;
while(finalarr[tcntr]!=0)
{
AVLroot=insert(AVLroot,finalarr[tcntr]);
tcntr++;
}
System.out.println(\"\ Preorder sequene:\");
preorder(AVLroot);
System.out.println(\"\ Inorder sequence:\");
inorder(AVLroot);
System.out.println(\"\ Postorder sequence:\");
postorder(AVLroot);
}
int[] sort(int[] arr)
{
int n = arr.length;
int temp = 0;
for(int i=0; i < n; i++){
for(int j=1; j < (n-i); j++){
if(arr[j-1] > arr[j]&&arr[j]!=0){
//swap elements
temp = arr[j-1];
arr[j-1] = arr[j];
arr[j] = temp;
}
}
}
return (arr);
}
int getNumber()
{
String str;
int ne=0;
InputStreamReader input=new InputStreamReader(System.in);
BufferedReader in=new BufferedReader(input);
try
{
str=in.readLine();
ne=Integer.parseInt(str);
}
catch(Exception e)
{
System.out.println(\"\ I/O error.\");
}
return ne;
}
Nodetype insert(Nodetype T,int x)
{
if(T==null)
{
Nodetype node=new Nodetype(x);
T=node;
}
else
if(x>T.info)
{
T.right=insert(T.right,x);
if(BF(T)==-2)
if(x>T.right.info)
T=RR(T);
else
T=RL(T);
}
else
if(xrh)
return(lh);
return(rh);
}
Nodetype rotateright(Nodetype x)
{
Nodetype y;
y=x.left;
x.left=y.right;
y.right=x;
x.ht=height(x);
y.ht=height(y);
return(y);
}
Nodetype rotateleft(Nodetype x)
{
Nodetype y;
y=x.right;
x.right=y.left;
y.left=x;
x.ht=height(x);
y.ht=height(y);
return(y);
}
Nodetype RR(Nodetype T)
{
T=rotateleft(T);
return(T);
}
Nodetype LL(Nodetype T)
{
T=rotateright(T);
return(T);
.
import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
Write a program that will test a name) method no sorting routine from.docx
Write a program that will test a name) method no sorting routine from
Program 1 (Practicing an example of function using call by referenc.pdf
Program 1: (Practicing an example of function using call by reference)
Write a program that reads a set of information related to students in C++ class and prints them
in a table format. The information is stored in a file called data.txt. Each row of the file contains
student number, grade for assignment 1, grade for assignment 2, grade for assignment 3, and
grade for assignment 4. Your main program should read each row, pass the grades for the three
assignments to a function called ProcessRow to calculate the average of the grades, minimum of
the four assignments, and the maximum of the four assignments. The results (average,
maximum, and minimum) should be returned to the main program and the main program prints
them on the screen in a table format. For example, if the file includes
126534 7 8 10 7
321345 5 6 4 9
324341 8 3 8 5
your program should print
Std-Id A1 A2 A3 A4 Min Max Average
----------------------------------------------------------------------------------
126534 7 8 10 7 7 10 8
321345 5 6 4 9 4 9 6
324341 8 3 8 5 3 8 6
You must use call by reference to do the above question.
_________________________________________________________________
Program 2: (Practicing an example of function using call by value)
Repeat the above question using call by value. This means you need to have three different
functions: one to calculate the average, another to calculate the minimum, and the third one to
calculate the maximum. This is how to call these functions:
Max = CalculateMax(A1,A2,A3, A4);
Min = CalculateMin(A1,A2,A3, A4);
Average = CalculateAvg(A1,A2,A3, A4);
_________________________________________________________________
Program 3:
Write a program with several functions that performs the following tasks. :
Create a function that reads the following 5 float numbers from the file data.txt into array Called
Arr1.
12.0 15.0 29.3 25.0 93.2
Copy array Arr1 into array Arr2 in reverse order
Print array Arr1.
Print array Arr2.
Find the number of elements in array Arr1 that are >= 80 and <=100.
Find the number of the elements in array Arr1 in which their contents are divisible by 5
Find the index of the elements in array Arr1 in which their contents are divisible by 3.
Find mean (average) in array Arr1.
Find the maximum number in array Arr1.
Ask the user to input a key. Then search for the key in array Arr1 and inform the user about the
existence (true / false) of the key in array
Your program should include several functions.
A function for filling up the information from file into an array (part a should call this function)
A function that does the copying of one array into another in reverse order. Arrays must have the
same size (part b should call this function)
Printing any array with any size (part c and d should call this function)
finding and returning the number of elements between 80 and 100 in any array with any size
(part e calls this function)
finding and returning the number of elements in an array that are divisible by 5 (par.
ArrayTest.java import java.util.Arrays; import java.util.Scann.pdf
ArrayTest.java
import java.util.Arrays;
import java.util.Scanner;
public class ArrayTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int table[] = new int[10];
int count = 0;
Scanner scan = new Scanner(System.in);
for(int i=0; i<10; i++){
System.out.println(\"Enter Array Element:\");
int n = scan.nextInt();
if(n < 0){
System.out.println(\"Invalid Number.\");
i--;
if(count >= 5)
break;
}else{
table[i] = n;
count++;
}
}
int sum = 0;
System.out.println(\"Array Elements are: \"+Arrays.toString(table));
for(int i=0; i avg){
high++;
}
else{
equal++;
}
}
System.out.println(\"Number of elements less than average \"+less);
System.out.println(\"Number of elements greater than average \"+high);
System.out.println(\"Number of elements equal to average \"+equal);
for(;;){
System.out.println(\"Enter Search Element (-1 to quit): \");
int searchNum = scan.nextInt();
if(searchNum == -1){
break;
}
int index = find(searchNum, table, count);
if(index == -1){
System.out.println(\"Element not found\");
}
else{
System.out.println(\"Element found at \"+index);
}
}
smallest(table, count);
}
public static int find (int valueToSearchFor, int intArray[ ], int numberOfValidEnties){
for(int i=0; i a[i]){
min = a[i];
index = i;
}
}
System.out.println(\"The smallest element is \"+min+\" index is \"+index);
int temp = a[0];
a[0] = a[index];
a[index] = temp;
System.out.println(\"After swap array elements are :\"+Arrays.toString(a));
}
}
Output:
Enter Array Element:
3
Enter Array Element:
4
Enter Array Element:
5
Enter Array Element:
2
Enter Array Element:
1
Enter Array Element:
6
Enter Array Element:
7
Enter Array Element:
8
Enter Array Element:
-1
Invalid Number.
Array Elements are: [3, 4, 5, 2, 1, 6, 7, 8, 0, 0]
The Sum is 36
The Average is : 4.5
Number of elements less than average 4
Number of elements greater than average 4
Number of elements equal to average 0
Enter Search Element (-1 to quit):
2
Element found at 3
Enter Search Element (-1 to quit):
3
Element found at 0
Enter Search Element (-1 to quit):
1
Element found at 4
Enter Search Element (-1 to quit):
6
Element found at 5
Enter Search Element (-1 to quit):
-1
The smallest element is 1 index is 4
After swap array elements are :[1, 4, 5, 2, 3, 6, 7, 8, 0, 0]
Solution
ArrayTest.java
import java.util.Arrays;
import java.util.Scanner;
public class ArrayTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int table[] = new int[10];
int count = 0;
Scanner scan = new Scanner(System.in);
for(int i=0; i<10; i++){
System.out.println(\"Enter Array Element:\");
int n = scan.nextInt();
if(n < 0){
System.out.println(\"Invalid Number.\");
i--;
if(count >= 5)
break;
}else{
table[i] = n;
count++;
}
}
int sum = 0;
System.out.println(\"Array Elements are: \"+Arrays.toString(table));
for(int i=0; i avg){
high++;
}
else{
equal++;
}
}
System.out.println(\"Number of elements less than average \"+less);
System.out.println(\"Number of.
Getting StartedCreate a class called Lab8. Use the same setup for .pdf
Getting Started
Create a class called Lab8. Use the same setup for setting up your class and main method as you
did for the previous assignments. Be sure to name your file Lab8.java. Additionally, make
another file called Arrays.java. This file will be an object, so simply start it off by declaring an
Arrays class. You can copy the following skeleton and fill in the appropriate code below each of
the comments:
public class Arrays {
/ Instance Variables
// Constructors
// findMin 1
// findMax
// calcSum
// calcAverage
// toString
}
Task Overview
Your task for this lab is to create a class called Arrays with some array processing methods. This
class will maintain an array and the number of elements present in it. Additionally, methods will
be available to display the current min and max elements along with the average of all of them.
Finally, a toString() method will be available to cleanly display all the array elements. Finally,
you will write a simple driver class to test out the above Arrays class.
Part 1: Instance Variables for Arrays
The first thing to do for the Arrays class is to set up its instance variables. Declare the following
(private) instance variables:
• An int array called array ? this will be the array we will be writing methods for.
• An int called count - this represents the number of valid elements in the array.
Part 2:
Constructors for Arrays The Arrays class will have two constructors. The first constructor takes
the maximum size of the array as input as a parameter and initializes the array instance variable
appropriately. It also sets count to size. Finally, it will initialize all of the array elements to some
values between 0 and 10, inclusive. To create this constructor, follow these steps:
• Import java.util.Random to make use of the random number generator.
• Create a constructor with the following header: public Arrays(int size)
• Initialize your array variable and set its size to size (see the chart on page 252 for reference on
initializing arrays). Be very careful that you are setting the value of your array instance variable,
as opposed to creating a new variable called array.
• Set the value of the count variable to size because we will be populating the entire array.
• Copy the following code to the constructor in order to generate random values between 0 and
10, inclusive:
Random rand = new Random();
for (int i = 0; i < count; i++)
{
array[i] = (rand.nextInt(10));
}
Next, create another constructor with the following header: public Arrays(int[] arr). This
constructor will initialize the class by using the passed arr argument in order to fill its instance
variables. The following things need to be done inside of this constructor:
• Set the array variable equal to arr.
• Set the count variable equal to the length of the array.
Part 3: Displaying the Output findMin()
The first method of this class will search the array for the minimum element. Copy the following
code for the findMin method. Note how the count i.
Similar to Create a menu-driven program that will accept a collection of non-ne.pdf (15)
The java code works, I just need it to display the results as in t.pdf
The java code works, I just need it to display the results as in t.pdf
This is a lab for a java program that I am very unsure of, it has to.pdf
This is a lab for a java program that I am very unsure of, it has to.pdf
import java.util.;public class Program{public static void.pdf
import java.util.;public class Program{public static void.pdf
Write a program that will test a name) method no sorting routine from.docx
Write a program that will test a name) method no sorting routine from.docx
Program 1 (Practicing an example of function using call by referenc.pdf
Program 1 (Practicing an example of function using call by referenc.pdf
ArrayTest.java import java.util.Arrays; import java.util.Scann.pdf
ArrayTest.java import java.util.Arrays; import java.util.Scann.pdf
Getting StartedCreate a class called Lab8. Use the same setup for .pdf
Getting StartedCreate a class called Lab8. Use the same setup for .pdf
More from rajeshjangid1865
write Ocaml programe to add all numbers in a list the solution .pdf
write Ocaml programe to add all numbers in a list ?
the solution :
let rec sum list =
match list with
[ ] -> 0
| x:: tail -> x + (sum tail);;
let a = [2;4;5;6;1;9;10 ];;
sum a;;
question is :-Write a Ocaml Program to multiply each element in a list by 2. a= [2;4;5;6;1;9;10 ]
Solution
let rec intmult : int list * int -> int list =
function ([],_) -> [0]
| ([x] ,al) -> [x * al]
| (x::xs,al) -> x * al :: intmult (xs, al);;
Also, you can use the map function as I mentioned below,
let intmult (l,m)= List.map (fun x -> x * m) l.
why is lifelong learning important for Engineers Give an example to.pdf
why is lifelong learning important for Engineers? Give an example to support your argument.
please help me with this ..
Solution
A decade ago, a group of experts estimated the half-life of an engineer\'s technical skills--how
long it would take for half of everything an engineer knew about his or her field to become
obsolete. For mechanical engineers it was 7.5 years. For electrical engineers it was 5. And for
software engineers, it was a mere 2.5 years, less time than it takes to get an undergraduate
degree. Today, those numbers are surely even smaller.
Technology is rushing headlong into the future at a pace that takes one\'s breath away. Personal
computers, the Internet, genetic engineering, advanced materials, new forms of chemical
synthesis--all these things and more are changing our world swiftly, profoundly, and, in most
cases, for the better. But the excitement and the progress come at a cost. Rapid change is not
always comfortable, and no one knows this better than the people whose job it is to stoke the
technological juggernaut.
Think about it. In some specialties, engineers must update half of everything they know every
couple of years, all the while working full-time to design products according to the best
standards of the moment--which might change next month. In even the slower-paced fields,
engineers must reinvent themselves at least once a decade.
There\'s more. A generation ago, an engineer could expect to carve out a niche in one well-
defined area-- automotive steering systems, say, or chemical plant instrumentation--and remain
there for a lifetime. No longer. As technological change accelerates and product lines rise and
fall in ever-diminishing life cycles, engineers find themselves switching jobs more often, to the
point that those starting out today may hold half a dozen jobs over their careers, even if they
manage to remain with the same company throughout. So besides staying abreast of
developments in their own specialties, engineers must be prepared to switch nimbly to a new
field when the old one peters out.
And, to complicate things further, these professional demands come at a time of upheaval in the
employment landscape. Global competition has sparked a wave of downsizings in technology
firms, destroying much of the job security that engineers used to take for granted and pushing
companies to contract out more and more of their design work. Today, service firms such as
Andersen Consulting are the largest recruiters of engineering graduates on some college
campuses, eclipsing the big manufacturing companies in the number of hires.
The bottom line: A large and growing percentage of engineers now work as contract technical
experts, hiring out for a particular job at a particular company, then moving on when it is
finished. They may be independent consultants or they may work for consulting firms, but either
way they don\'t have the long-term stability that joining a traditional manufacturing firm used to
provide.
I.
Which of the following is true of aldol reactions1.The thermodyna.pdf
Which of the following is true of aldol reactions?
1.The thermodynamics and kinetics of aldol reactions can be controlled by base selection.
2.Aldol reactions can be completed by reacting an aldehyde and a ketone in the presence of a
base.
3.The yields of aldol reactions involving only one type of a hydrogen are generally higher than
the yields of those involving multiple types of a hydrogens.
4.Aldol reactions are used to create carbon–carbon bonds.
5.All of the above are true of aldol reactions.
Solution
Answer:
5.All of the above are true of aldol reactions.
Explanation:
Aldol reaction is the reaction between two cabonyl compounds with one carbonyl compound
contains one alpha -hydrogen in the presence of base to give beta hydroxy carbonyl compound.
So option 1 is correct.
The kinetic prodduct is the formation of C-C bond on the less substituted alpha carbon atom, can
be acheived by the bulky base LDA and thermodynamic product is the formation of C-C bond on
the more substituted alpha carbon to the carbonyl carbon can be achieved by the less bulky base
like NaOC2H5. so option 2 is correct.
If there are more kinds of active hydrogens gives mixed aldol product that gives less yield and
the compound with one kind of active hydrogen gives only one product with more yield. So
option 4 is correct.
In aldol reaction there is a formation of c-c bond. so option 4 is also correct..
Using at least two examples (whenever applicable), concisely discuss .pdf
Using at least two examples (whenever applicable), concisely discuss the following terms. You
are strongly recommended to at least visit and study the posted article on websites listed in the
reference section. Programming paradigm Procedural programming OOP or Object-Oriented
Programming Abstract Data Type or ADT Four basic principles of object orientation
Abstraction Encapsulation/Information hiding Inheritance Polymorphism Benefits of OOP
Object-Oriented Design & Analysis or OODA or OODA UML for OOD Attributes and
behaviors of an object C++ classes and objects Instance and instantiation of an object State of
an object
Solution
1) Programming paradigm is a way or style of writing programming languages.
For example in python, blocks are represented using blocks. In python intendation is important.
IN java, flower/open braces are used.
2)
Procedural programming
This is style of routines and subroutines.
Declaring the subroutine, top of program declaring prototype declaring and bottom of program
writing the implementation of methods.
Also subroutine is accssible is depends on public accessifiers.
3)
OOPS programming language where all variables and methods are accessed via object.
Object is real entity which stores the data.
Java, python,c++ are examples of OOPS programming languages.
4)
Abstract data type is representing the hidden object. It hides the implementation.
Example: We can see the car physically but cannot see the internal strucure.
Seeing the machine physically but doesn\'t bother about internal strucure..
Transforming Cultures from Consumerism to Sustainability - Essay.pdf
Transforming Cultures from Consumerism to Sustainability - Essay
Solution
Some 60 percent of ecosystem services are being despoiled or used unsustainably. The damage is
the consequence of cultural systems which give confidence to people to describe their happiness
in addition to success in terms of how much they consume. This propensity, together with
unsustainable population growth rates, is overpowering our finite planet, intimidating to cause
noteworthy disruptions to Earth\'s climate and ecosystems, and consequently to human
civilization. Consumerism has engulfed human cultures and Earth’s ecosystems and if left
unaddressed, we threat global disaster. However if we direct this wave, deliberately changing our
cultures to center on sustainability, we will not only put off disaster, however may steer in an era
of sustainability—one which allows all people to prosper whilst protecting, even restoring, Earth.
World watch Institute\'s Transforming Cultures plan turns a critical eye to how we can transfer
today\'s consumer cultures in the direction of cultures of sustainability. The solution to this
revolution will lie in harnessing institutions which play a vital role in shaping society— like
media, educational services, business, governments, traditions, as well as social movements—to
inspire this new cultural course.
The plan also seeks to bring women into educational, economic, political as well as health parity
with men. This will necessitate the wearing away of cultural norms which endorse early and
frequent childbearing while intensifying women\'s capability to decide when to bear children.
Studies explain that such advances slow and ultimately end population growth, allowing for
more sustainable growth all-inclusive..
Trane has 145 marbles. He gives 20 to Katie, 52 to Gwen, and 31 to Yu.pdf
Trane has 145 marbles. He gives 20 to Katie, 52 to Gwen, and 31 to Yusef. He keeps the rest.
Who has the most marbles? Trane Katie Gwen Yusef
Solution
Trane has 145 marbles , he gave 20 to Katie and 52 to Gwen , and 31 to Yusef.
It means now
Katie has = 20 ,
Gwen has = 52
Yusef has = 31
and Trane has =145 -20 -52 -31 = 42
It means Gwen has the most marbles , that is 52.
This project should be done in C# using Visual Studio - Windows Form.pdf
This project should be done in C# using Visual Studio - Windows Forms.
This is a puzzle game of Wheel of Fortune. I need the puzzle to be \"Back to the Future\", and it
should not matter if the player guesses a upper or lowercase letter. If possible I could use step by
step instructions for creating the windows form and then entering the code to make the program
run. All the requirements for the game will be in pictures below.
The example uses the puzzle \"pulp fiction\", but again I need my puzzle to be \"Back to the
Future\". Thanks! You are to create the classic game of Wheel of Fortune. Your application
should consist of 3 players, underlines to represent letters in the puzzle, and the available letters.
The initial screen should look something like:
Solution
form1 designer:
namespace Wheel_Of_Fortune
{
partial class Form1
{
///
/// Required designer variable.
///
private System.ComponentModel.IContainer components = null;
///
/// Clean up any resources being used.
///
/// true if managed resources should be disposed; otherwise, false.
protected override void Dispose(bool disposing)
{
if (disposing && (components != null))
{
components.Dispose();
}
base.Dispose(disposing);
}
#region Windows Form Designer generated code
///
/// Required method for Designer support - do not modify
/// the contents of this method with the code editor.
///
private void InitializeComponent()
{
this.label1 = new System.Windows.Forms.Label();
this.labelLetters = new System.Windows.Forms.Label();
this.panel1 = new System.Windows.Forms.Panel();
this.label2 = new System.Windows.Forms.Label();
this.textBox1 = new System.Windows.Forms.TextBox();
this.textBox2 = new System.Windows.Forms.TextBox();
this.textBox3 = new System.Windows.Forms.TextBox();
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this.textBox15 = new System.Windows.Forms.TextBox();
this.buttonSpin = new System.Windows.Forms.Button();
this.buttonSolve = new System.Windows.Forms.Button();
this.label3 = new System.Windows.Forms.Label();
this.label4 = new System.Windows.Forms.Label();
this.label5 = new System.Windows.Forms.Label();
this.textBoxP1 = new System.Windows.Forms.TextBox();
this.textBoxP2 = new System.Windows.Forms.TextBox();
this.textBoxP3 = new System.Windows.Forms.TextBox();
this.labelPrompt = new System.Windows.Forms.Label();
this.panel1.SuspendLayout();
this.SuspendLayout();
//
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this.label1.AutoSize = true;
this.label1.Location = new System.Drawing.Point(68, 13.
The table below gives the probabilities of combinations of religion a.pdf
The table below gives the probabilities of combinations of religion and political parties in a
major U.S. city. Reli Political parties Protestant (A) Catholic (B) Democrat (3 Republican (
Independent- 0.35 0.27 0.05 0.10 0.09 0.03 What is the probability that a randomly selected
person would be a Democrat who was not Jewish? 0 a. 0.07 O b.0.47 O c. 0.93 O d. 0.50 O e.
None of these Check My Work 0- Icon Key xit Submit Assignment for Grading Question 47 o
Solution
Probability that the person is democrat but not jewish. It also means that the person is democrat
and he can be Protestant, Catholic or other.
Therefore probability of a democrat not being jewish= 0.10+0.35+0.02= 0.47
b. 0.47 is correct.
The effects Poverty in SocietySolution Poor children are at gre.pdf
The effects Poverty in Society
Solution
Poor children are at greater risk and Anti social behavior. Poverty result in un hygienic
practices such as poor sanitation,improper dumping of waste etc. Which results in growth and
spread of diseases. Poverty greatly influences Unemployment and criminal behavior. Poverty
affects Economic prosperity of a community which causes decrease Economic out put. Issues
like hunger,thirst etc.are major affects of poverty. Poverty greatly impacts on the development of
child due to malnutrition features of poverty such as poor health,lack of water ,or housing,child
abuse greatly influences the life of people. Poverty encourages child trafficking. Due to poverty,
children, elderly Individual, pregnant women face the problem of malnutrition which indirectly
increases the death rate and decreases birth rates. Improper disposal of waste, improper sewage
system,a an over crowding in the slum regions causes.Environmental pollution which adversely
affect the healthy life of Individuals..
Suppose 1.01g of FeCl3 is placed in a 10.0ml volumetric glass, water.pdf
Suppose 1.01g of FeCl3 is placed in a 10.0ml volumetric glass, water is added, the mixture is
shaken to disolve the solid and then water is added to the calibration mark of the flask. Calculate
the molarity of of each ion present in the solution.
Please walk me through the steps I\'m trying to help my daughter with her chem. homework and
I don\'t know any chem.
Solution
molarity = mass of the compound FeCl3/ molar mass of FeCl3 *volume of the solution (L)
here mass of the compound = 1.01 gms
molar mass of FeCl3 = 162.2 gms/mol
volume of the solution = 10ml = 0.01L
molar mass of FECl3 Â Â = 162.2 gm/mol
molarity = 1.01/162.2*0.01 =0.622M.
Specialized regions on the cell surface through which cells are joine.pdf
Specialized regions on the cell surface through which cells are joined to each other or to the
extracellular matrix. (two words)
Solution
Answer is cell junction.
Cell junctions are especially important in enabling communication between neighbouring cells
via specialised proteins called communicating protein..
Section 404 of the Sarbanes Oxley Act requires auditors of a public .pdf
Section 404 of the Sarbanes Oxley Act requires auditors of a public company to analyze and
report on the effectiveness of the client\'s internal controls over financial reporting. Describe the
responsibilities that auditors of public companies have to discover and report (a) significant
deficiencies in internal controls and (b) material weaknesses in internal controls. Include a
definition of each item in your answer. Under what condition or conditions can auditors issue an
unqualified or clean opinion on the effectiveness of a client\'s internal controls over financial
reporting?
Solution
Note: Please note, that there is no specific definition of \"Internal Control Deficiency\" and
\"Significant Control deficiency\" in the audit subject. Definition of Material Weakness has been
added. In case of any further clarification please let me know.
Definiton of Internal Control: \"Internal Control\" means the planning of an organisation and all
the policies and procedures adopted by an organisation\'s management to ensure orderly and
efficient conduct of business.
Defintion of Material Weakness: \"Material Weakness\" is a weakness or deficiency in internal
control due to which there is a possibility that the material misstatement in financial statement
will not be prevented or detected on a timely basis.
It is not the responsibility of the auditorto identify each and every deficieny in Internal Control
and express an opinion on it. His responsibility is \"To communicate any significant deficiency
in internal control identified during audit to management/Those Charged With
Governance(TCWG)/Audit Committee.
Auditor can issue an unqualified or clean opinion on the effectiveness of a client\'s internal
controls if their internal controls are seems effective to the auditor, if significant related party
transactions are scrutinized by the management/TCWG, if Management fraud prevented by
Internal Control, if non compliance of Laws & Regulations are prevented and properly followed
by management, if Internal Control designed and implemented in a way so that it can prevent or
detect and correct misstatements in Financial Statement on timely basis..
Reiji and Tuneko Okazaki conducted a now classic experiment in 1968 .pdf
Reiji and Tuneko Okazaki conducted a now classic experiment in 1968 in which they discovered
a population of short fragments synthesized during DNA replication. They introduced a short
pulse of 3H -thymidine into a culture of E. coli and extracted DNA from the cells at various
intervals. In analyzing the DNA after centrifugation in denaturing gradients, they noticed that as
the interval between the time of 3H -thymidine introduction and the time of centrifugation
increased, the proportion of short strands decreased and more labeled DNA was found in larger
strands. What would account for this observation?
a. the ligation of Okazaki fragments by DNA ligase
b. the degradation of Okazaki fragments by DNA polymerase I
c. the accumulation of Okazaki fragments produced on the lagging strand
d. the mutation affecting the activity of DNA ligase
Solution
Answer C: The accumulation of Okazaki fragments produced on the lagging strand
Replication of DNA on lagging strand is discontinuous and replications occur in small sections.
These new stretches of DNA are called Okazaki fragments and each one requires its own RNA
primer. During DNA replication, each Okazaki fragment is separated by their own RNA primers
and are unligated until RNA primers are removed, followed by enzyme ligase connecting
(ligating) an Okazaki fragment onto the (now continuous) newly synthesized complementary
strand. After the introduction of 3H -thymidine (radioactive thymidine) into a culture of E. coli,
3H –thymidine gradually incorporated into both complimentary strands of leading and lagging
strands of DNA during replication. With time, each Okazaki fragment ligated with adjacent
fragment with the help of DNA ligase result in the increase of the length of the complementary
strand. Due to accumulation and ligation of Okazaki fragments produced on the lagging strand,
the proportion of short strands decreased and more labeled DNA was found in larger strands..
Problem 2-1A Suppose the following items are taken from the 2017 bala.pdf
Problem 2-1A Suppose the following items are taken from the 2017 balance sheet of Windsor,
Inc. (All dollars are in millions.) Goodwill Common stock Equipment Accounts payable Patents
Stock investments (long-term) Accounts receivable Prepaid rent Debt investments (short-term)
Retained earnings Cash Notes payable (long-term) Unearned sales revenue Accumulated
depreciation-equipment $4,060 6,060 1,560 150 210 3,230 1,200 230 1,300 6,580 2,330 720 410
200 Prepare a classified balance sheet for Windsor, Inc. as of December 31, 2017. (List current
assets in order of liquidity.)
Solution
Balance sheet :AssetsCurrent assetsCash2330Account receivable1200Prepaid rent230Debt
investment (short term)1300Total current assets5060Long term investmentStock investment
(long term)3230Property,plant and equipmentEquipment1560Less: Accumlated depreciation-
2001360Other assetsGoodwill4060Patents2104270Total Assets13920Liabilities &
Stockholder\'s equityCurrent liabilitiesAccount payable150Unearned sales revenue410Total
current liabilities560Long term liabilitiesNotes payable720Total liabilities1280Stockholder\'s
equityCommon Stock6060Retained earnings6580Total Stockholder\'s equity12640Total
liabilities & Stockholder\'s equity13920.
Prepare a 2017 income statement for Shanta Corporation based on the f.pdf
Prepare a 2017 income statement for Shanta Corporation based on the following information:
Cost of goods sold Operating expenses Other expenses and losses $490,000 100,000 30,000
700,000 30% Sales revenue Tax rate SHANTA CORPORATION Income Statement For the
Year Ended December 31, 2017
Solution
Sales revenue 700000 Cost of goods sold 490000 Gorss profit 210000 Operating
expenses 100000 Operating income 110000 Other expenses and losses 30000 Income
before income taxes 80000 Income taxes 24000 Net income 56000.
Organizations need to have a pool of managerial talent to take on jo.pdf
Organizations need to have a pool of managerial talent to take on jobs from senior managers and
new management jobs that may be created. One way is to hire from outside, another way is to
\"grow your own manager talent pool\" from within.
Create a 700 to 1050 word recommendation that describes how you will grow the manager talent
pool at your organization.
How will you select candidates for your manager development program? For example: select
from existing staff or hire them in? How would you assess their potential so you know who to
pick? For example: interviews, tests. What might you need to do so that you consider all
potential candidates and do not unfairly discrimminate?
How would you develop these candidates and over what time period? What different
jobs/experiences should they have so that at the end of say 2-3 years they are ready for a
management slot? What formal training might they need?
So after all the training and job experience, how will you assess who is ready to move up to the
position of manager? Again, consider how you would make sure you individuals are chosen
fairly and objectively.
What support should be provided to new managers to ensure their success?
Solution
It is clear that there is need for consideration of the managerial talent which is an entire role and
responsibility of the HR management in the context of ensuring an organization retains its
employees and ensuring effectiveness through competition which is an organization strategy to
effectively compete in the market.
.
Selecting candidates for a managerial development program
The main consideration that in selecting various candidates existing in the organization for the
managerial development programs includes;
The process will involve internal selection in the context that the process is less costly as
compared with external hiring where the process is costly due to lack of experience based on our
organizational operations which will require more resources to integrate employees with our
organizational operations. In this regards, to this angle the main assessment considerations will
be based on;
Past performance of potential candidate for the managerial development program in the context
that the candidate should be among the top performers in the organization operations. This is in
regards that if the current performance of an employee is poor this has great prediction for the
future managerial position.
The potential of the candidate which will be based on considerations such as current performance
by the employee, lateral potential in that an employee is able to move into other positions at the
same level, potential of an employee to supervise and relate with other employees and high
potential based on that the employee can be promoted to the managerial position within 1 year or
making multiple move upwards in the next couple of years.
There will also be consideration of the requisite knowledge and ability through clearly outlining
the knowledge and ski.
Objective Manipulate the Linked List Pointer.Make acopy of LList..pdf
Objective: Manipulate the Linked List Pointer.
Make acopy of LList.java and rename it to LListr.java. Add a reverse function in LListr.java to
reverse the order of the linked list.
You can either use the gamescore.txt to test the reverse function.
Llist.Java File:
/** Source code example for \"A Practical Introduction to Data
Structures and Algorithm Analysis, 3rd Edition (Java)\"
by Clifford A. Shaffer
Copyright 2008-2011 by Clifford A. Shaffer
*/
// Doubly linked list implementation
class LList implements List {
private DLink head; // Pointer to list header
private DLink tail; // Pointer to last element in list
protected DLink curr; // Pointer ahead of current element
int cnt; // Size of list
//Constructors
LList(int size) { this(); } // Ignore size
LList() {
curr = head = new DLink(null, null); // Create header node
tail = new DLink(head, null);
head.setNext(tail);
cnt = 0;
}
public void clear() { // Remove all elements from list
head.setNext(null); // Drop access to rest of links
curr = head = new DLink(null, null); // Create header node
tail = new DLink(head, null);
head.setNext(tail);
cnt = 0;
}
public void moveToStart() // Set curr at list start
{ curr = head; }
public void moveToEnd() // Set curr at list end
{ curr = tail.prev(); }
/** Insert \"it\" at current position */
public void insert(E it) {
curr.setNext(new DLink(it, curr, curr.next()));
curr.next().next().setPrev(curr.next());
cnt++;
}
/** Append \"it\" to list */
public void append(E it) {
tail.setPrev(new DLink(it, tail.prev(), tail));
tail.prev().prev().setNext(tail.prev());
cnt++;
}
/** Remove and return current element */
public E remove() {
if (curr.next() == tail) return null; // Nothing to remove
E it = curr.next().element(); // Remember value
curr.next().next().setPrev(curr);
curr.setNext(curr.next().next()); // Remove from list
cnt--; // Decrement the count
return it; // Return value removed
}
/** Move curr one step left; no change if at front */
public void prev() {
if (curr != head) // Can\'t back up from list head
curr = curr.prev();
}
// Move curr one step right; no change if at end
public void next()
{ if (curr != tail.prev()) curr = curr.next(); }
public int length() { return cnt; }
// Return the position of the current element
public int currPos() {
DLink temp = head;
int i;
for (i=0; curr != temp; i++)
temp = temp.next();
return i;
}
// Move down list to \"pos\" position
public void moveToPos(int pos) {
assert (pos>=0) && (pos<=cnt) : \"Position out of range\";
curr = head;
for(int i=0; i. The vertical
* bar represents the current location of the fence. This method
* uses toString() on the individual elements.
* @return The string representation of this list
*/
public String toString()
{
// Save the current position of the list
int oldPos = currPos();
int length = length();
StringBuffer out = new StringBuffer((length() + 1) * 4);
moveToStart();
out.append(\"< \");
for (int i = 0; i < oldPos; i++) {
if (getValue()!=null)
{
out.append(getValue());
out.append(\.
Militarism Alliances Imperialism Nationalism Class, the powder keg.pdf
Militarism Alliances Imperialism Nationalism
Class, the powder keg that ignited Europe was the assassination of the Archduke Franz
Ferdinand. Nationalist Serbs- the Black Hand assassinated him. They believed in Pan Slavism.
What is Pan Slavism? Why did Russia enter WWI? Who fought on which sides during WWI?
Solution
Pan-Slavism, a development which solidified in the mid-nineteenth century, is the political
philosophy worried about the headway of respectability and solidarity for the Slavic-talking
people groups. Its fundamental effect happened in the Balkans, where non-Slavic domains had
ruled the South Slavs for a considerable length of time. These were chiefly the Byzantine
Empire, Austria-Hungary (both as discrete entities for the vast majority of the period), the
Ottoman Empire, and Venice.
The Pan-Slavism development soon went up against political hints, and in June 1848, while the
Austrian Empire was debilitated by transformation, the Czech history specialist František
Palacký assembled a Slav congress in Prague. Comprising of agents of every Slav nationality
controlled by the Austrians, the congress was proposed to compose agreeable endeavors among
them to compel the Emperor to change his government into an alliance of equivalent people
groups under a vote based Habsburg run the show.
In spite of the fact that the congress had minimal commonsense impact, the development stayed
dynamic, and by the 1860s it turned out to be especially mainstream in Russia, to which
numerous Pan-Slavs searched for authority and also for insurance from Austro-Hungarian and
Turkish run the show. Russian Pan-Slavists, be that as it may, changed the hypothetical bases of
the development. Embracing the Slavophile thought that western Europe was profoundly and
socially bankrupt and that it was Russia\'s noteworthy mission to revive Europe by increasing
political strength over it, the Pan-Slavists included the idea that Russia\'s central goal couldn\'t be
satisfied without the help of other Slav people groups, who must be freed from their Austrian and
Turkish experts and joined into a Russian-ruled Slav confederation.In spite of the fact that the
Russian government did not authoritatively bolster this view, some essential individuals from its
remote division, including its agents at Constantinople and Belgrade, were fervent Pan-Slavists
and prevailing with regards to drawing both Serbia and Russia into wars against the Ottoman
Empire in 1876– 77. At the point when endeavors were made in the mid twentieth century to call
new Pan-Slav congresses and resuscitate the development, the nationalistic contentions among
the different Slav people groups kept their successful cooperation.
Russia entered WW1 due to following reasons:
Russia was drawn into WW1 by similar stumbles and habits that tormented her neighboring
European nations, radical rivalry, harmful patriotism, military haughtiness, and insufficient trust
in tact and dependence on collusions. While Russia enter.
In the subject of cryptography, what policy or organizational challe.pdf
In the subject of cryptography, what policy or organizational challenges might impede or prevent
the deployment of a worldwide universal Public-Key Infrastructure?
Solution
Below challenges may present the deployment of Universal PKI :
1. Token Logistics:
There are many advantages of implementing PKI on a hardware token, such as a
smart card. These include security, portability and ease of use to add
other user specific applications and visual information.
However, the logistics of managing security tokens requires a considerable effort and cost
to a Public-Key Infrastructure implementation.
2. Network Issues:
The implementation of PKI will surely add to the network load. The potential additional traffic
that should be
considered are:
i. Certificate issuance
ii. Email Usage
iii. Directory Replication.
3. Network Issues - Encryption:
Usually the organisations implement anti-virus software and on regular basis perform inspection
on servers at
the perimeter of their networks. Some organizations has security policies that rejects or
quarantines
encrypted traffic.
To provide user-to-user confidentiality, the messages will traverse networks with their payload
hidden from inspection by virus and content checking.
Possible solutions include:
· Performing virus & content checking at the client machine.
· Storing user confidentiality private keys on a secure key server.
· Co-encrypting messages to a Gateway which then decrypts and checks the message before it is
delivered.
4. Email Address in Certificate:
Usually employees change their email addresses more frequently than the certificate. Until
unless a solution is built which allows the employees to keep the same email
address for a long period, certificates would have to be re-issued every time an employee
changes their email address.
5. Availability and storage of reliable user information
6. Certificate Validity Checking
7. PIN management:
smart Card PIN management may cause some problem to the employees..
is Google making us stupid Nicholas Carr Summarize Article. https.pdf
is Google making us stupid Nicholas Carr Summarize Article.
https://www.theatlantic.com/magazine/archive/2008/07/is-google-making-us-stupid/306868/
Solution
The articles talks about the modernisation of the technology and internet , putting traditional
methods of reading and interpretation in contrast. It refers to loosing out essence of
understanding and using the knowledge , using online and convinient form. The type of lifestyle
ie the the type of ease we have now baecause of google and its tool is seperating our roots from
orginality and real wisdom. The simplicity we seek in internet now a days , curbs our way of
going deeper into text and interpretation..
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Create a menu-driven program that will accept a collection of non-ne.pdf
- 1. Create a menu-driven program that will accept a collection of non-negative integers from the keyboard, calculate the mean and median values and display those values on the screen. Your menu should have 6 options: 1. Add a number to the array 2. Display the mean 3. Display the median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit Program particulars: Use an array of type int to store the integers entered by the user. There must be error checking on the input integer. If it is negative, the program will print an error message and re-prompt. This process will continue until a non-negative integer is entered. You must use a try-catch structure to trap both types of input errors (like letters where numbers should go) and range errors (like -1). You must write your own selectionSort utility method to sort your array. Place the method in an external file named SortSearchUtil.java. There must be error checking on the menu choice entered. If the user enters a choice not on the menu, the program will print an error message, re-display the menu and re-prompt. This process will continue until a valid option value is entered. Your solution must be modular. The design of your methods is up to you, but the rules of “highly cohesive” and “loosely coupled” must be followed. Your program should be well-documented. Explain what you’re doing in your code. Be sure to include the usual name and assignment notes. Note your program will have to sort your array before you can find the median. Include your SortSearchUtil.java file which will contain your sort method. This is what my project looks like already: Please fix it thanks. The SortSearchUtil will also be included. import java.util.Scanner; public class ArraySorting { public static void main(String[] args) { int option; int integer = 0; int optionOne; int optionTwo; int optionThree; int optionFour; int optionFive; int[] numbers = new int[5];
- 2. Scanner kb = new Scanner(System.in); System.out.println("Please enter a non-negative integer: "); integer = kb.nextInt(); while((integer < 0)) { System.out.println("I am sorry that is not a non-negative integer."); System.out.println(""); System.out.println("Please enter a non-negative integer: "); integer = kb.nextInt(); } option = displayMenu(kb); while (option != 6) { switch (option) { case 1: optionOne(numbers); System.out.println(""); break; case 2: optionTwo(numbers); System.out.println(""); case 3: //optionThree(); System.out.println(""); break; case 4: //optionFour(); System.out.println(""); break; case 5: //optionFive(); System.out.println("");
- 3. break; } option = displayMenu(kb); } if (option == 6) { System.out.println(); System.out.println("Thank you. Have a nice day."); } } private static int displayMenu(Scanner kb) { int option = 0; while (option != 1 && option != 2 && option != 3 && option != 4 && option !=5 && option !=6) { System.out.println("tt1. Add a number to the array tt2. Display the mean tt3. Display the median tt4. Print the array to the screen tt5. Print the array in reverse order tt6. Quit"); option = kb.nextInt(); if (!(option == 1 || option == 2 || option == 3 || option == 4 || option == 5 || option == 6)) System.out.println("I am sorry that is an invalid choice. Please try again."); } return option; } private static int[] optionOne() { Scanner input = new Scanner(System.in); int[] numbers = new int[1]; for (int i = 0; i < numbers.length; i++) { System.out.println("Please enter number"); numbers[i] = input.nextInt(); } return numbers;
- 4. } private static void optionTwo(int[] numbers) { int sum = 0; for(int i=0; i < numbers.length; i++) sum = sum + numbers[i]; double average = sum / numbers.length; System.out.println("Average value of array element is: " + average); } public class SortSearchUtil { public static void selectionSort(int[] array) { int current, indexSmallest, posToFill; int temp; for(posToFill = 0; posToFill < array.length - 1; posToFill++) { indexSmallest = posToFill; for(current = posToFill + 1; current < array.length; current++) { if(array[current] < array[indexSmallest]) { indexSmallest = current; } } temp = array[posToFill]; array[posToFill] = array[indexSmallest]; array[indexSmallest] = temp; } } public static void selectionSort(String[] array) { int current, indexSmallest, posToFill;
- 5. String temp; for (posToFill = 0; posToFill < array.length - 1; posToFill++) { indexSmallest = posToFill; for (current = posToFill + 1; current < array.length; current++) { if (array[current].compareTo(array[indexSmallest]) <0) { indexSmallest = current; } } temp = array[posToFill]; array[posToFill] = array[indexSmallest]; array[indexSmallest] = temp; } } } Solution import java.util.Arrays; import java.util.Scanner; public class ArraySorting { public static void main(String[] args) { int option; int integer = 0; int optionOne; int optionTwo; int optionThree; int optionFour; int optionFive;
- 6. Scanner kb = new Scanner(System.in); System.out.println("Enter size of array "); int n=kb.nextInt(); int[] numbers = new int[n]; System.out.println("Enter elements of array "); for(int i=0;i=0 ; i--) System.out.println(" array element in reverse are: " + numbers[i]); } public class SortSearchUtil { public void selectionSort(int[] array) { int current, indexSmallest, posToFill; int temp; for(posToFill = 0; posToFill < array.length - 1; posToFill++) { indexSmallest = posToFill; for(current = posToFill + 1; current < array.length; current++) { if(array[current] < array[indexSmallest]) { indexSmallest = current; } } temp = array[posToFill]; array[posToFill] = array[indexSmallest]; array[indexSmallest] = temp; } } public void selectionSort(String[] array) { int current, indexSmallest, posToFill;
- 7. String temp; for (posToFill = 0; posToFill < array.length - 1; posToFill++) { indexSmallest = posToFill; for (current = posToFill + 1; current < array.length; current++) { if (array[current].compareTo(array[indexSmallest]) <0) { indexSmallest = current; } } temp = array[posToFill]; array[posToFill] = array[indexSmallest]; array[indexSmallest] = temp; } } } } ========================================================== Enter size of array 3 Enter elements of array 1 2 3 1. Add a number to the array 2. Display the mean 3. Display the median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit 1 enter number 4
- 8. 1. Add a number to the array 2. Display the mean 3. Display the median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit 5 array element in reverse are: 4 array element in reverse are: 3 array element in reverse are: 2 array element in reverse are: 1 1. Add a number to the array 2. Display the mean 3. Display the median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit 4 array element are: 1 array element are: 2 array element are: 3 array element are: 4 1. Add a number to the array 2. Display the mean 3. Display the median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit 6 Thank you. Have a nice day.