Create a function mean comp that compares the mean value of the odd n.pdf
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Consider the titration of50.0 mL of 0.217 M hydrazoic acid (HN3, Ka=2.6 x 10^-5) with 0.183M NaOH. The pH of the soluion before any NaOH is added is____ The answer is 2.62 I cant figure out what to do after you get the moles Solution Concentration of acid = 0.217M [H+] = sqrt (Ka* C) [H+] = 2.37 * 10 ^ -3 so pH = -log([H+]) = 2.624.
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![Create a function mean comp that compares the mean value of the odd numbered elements with
the mean value of the even numbered elements and returns: if they are equal, if the mean of the
odd numbered elements is greater, if the mean of the even numbered elements is greater.
Solution
A sample Java Program methods
public static void main(String []args){
float[] list = {1.0f, 7.0f, 8.0f, 1.0f};
System.out.println(meancomp(list));
}
static int meancomp(float[] list) {
float evenSum = 0.0f;
float oddSum = 0.0f;
for (int i = 0; i < list.length; i++) {
if (i % 2 == 1)
evenSum = evenSum + list[i];
else
oddSum = oddSum + list[i];
}
int noOfEvenElements = list.length / 2;
int noOfOddElements = list.length / 2 + list.length % 2;
float evenMean = evenSum / (float) noOfEvenElements;
float oddMean = oddSum / (float) noOfOddElements;
int result = Float.compare(evenMean, oddMean);
if (result == 0)
return 0;
else if (result < 0)
return 1;
else
return 2;
}](https://image.slidesharecdn.com/createafunctionmeancompthatcomparesthemeanvalueoftheoddn-230708042932-931e20e5/85/Create-a-function-mean-comp-that-compares-the-mean-value-of-the-odd-n-pdf-1-320.jpg)
Recommended
Create a menu-driven program that will accept a collection of non-ne.pdf
Create a menu-driven program that will accept a collection of non-negative integers from the
keyboard, calculate the mean and median values and display those values on the screen. Your
menu should have 6 options: 1. Add a number to the array 2. Display the mean 3. Display the
median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit
Program particulars: Use an array of type int to store the integers entered by the user. There
must be error checking on the input integer. If it is negative, the program will print an error
message and re-prompt. This process will continue until a non-negative integer is entered. You
must use a try-catch structure to trap both types of input errors (like letters where numbers
should go) and range errors (like -1). You must write your own selectionSort utility method to
sort your array. Place the method in an external file named SortSearchUtil.java. There must be
error checking on the menu choice entered. If the user enters a choice not on the menu, the
program will print an error message, re-display the menu and re-prompt. This process will
continue until a valid option value is entered. Your solution must be modular. The design of your
methods is up to you, but the rules of “highly cohesive” and “loosely coupled” must be followed.
Your program should be well-documented. Explain what you’re doing in your code. Be sure to
include the usual name and assignment notes. Note your program will have to sort your array
before you can find the median. Include your SortSearchUtil.java file which will contain your
sort method.
This is what my project looks like already: Please fix it thanks. The SortSearchUtil will also be
included.
import java.util.Scanner;
public class ArraySorting
{
public static void main(String[] args)
{
int option;
int integer = 0;
int optionOne;
int optionTwo;
int optionThree;
int optionFour;
int optionFive;
int[] numbers = new int[5];
Scanner kb = new Scanner(System.in);
System.out.println(\"Please enter a non-negative integer: \");
integer = kb.nextInt();
while((integer < 0))
{
System.out.println(\"I am sorry that is not a non-negative integer.\");
System.out.println(\"\");
System.out.println(\"Please enter a non-negative integer: \");
integer = kb.nextInt();
}
option = displayMenu(kb);
while (option != 6)
{
switch (option)
{
case 1:
optionOne(numbers);
System.out.println(\"\");
break;
case 2:
optionTwo(numbers);
System.out.println(\"\");
case 3:
//optionThree();
System.out.println(\"\");
break;
case 4:
//optionFour();
System.out.println(\"\");
break;
case 5:
//optionFive();
System.out.println(\"\");
break;
}
option = displayMenu(kb);
}
if (option == 6)
{
System.out.println();
System.out.println(\"Thank you. Have a nice day.\");
}
}
private static int displayMenu(Scanner kb)
{
int option = 0;
while (option != 1 && option != 2 && option != 3 && option != 4 && option !=5 && option
!=6)
{
System.out.println(\"\\t\\t1. Add a number to the array\ \\t\\t2. Display the mean\ \\t\.
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Step 1You need to run the JAVA programs in sections 3.3 and 3.5 for.pdf
Step 1:You need to run the JAVA programs in sections 3.3 and 3.5 for selection sort and
insertion sort. You need to attach the output results.
Step 2: You need to modify these two programs, save them, submit them, and add some
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should be IndexHighest instead IndexSmallest.
Step3: Run the modified programs and print out the results and submit them.
In the end, you need the running results for original JAVA programs (selection and insertion sort
JAVA programs), the two modified programs to sort the values from high to low value for
selection and insertion sorts, and the results for the modified programs.
This program uses the selection sort algorithm to sort an array. The code has been modified to
also calculate how many item comparisons are done. You can try running the program with
different arrays to see how the total number of comparisons changes (or doesn't change).
CODE 3.3 ---
import java.util.Arrays;
public class SelectionSortDemo {
private static int selectionSort(int[] numbers) {
// A variable to hold the number of item comparisons
int comparisons = 0;
for (int i = 0; i < numbers.length - 1; i++) {
// Find index of smallest remaining element
int indexSmallest = i;
for (int j = i + 1; j < numbers.length; j++) {
comparisons++;
if (numbers[j] < numbers[indexSmallest]) {
indexSmallest = j;
}
}
// Swap numbers[i] and numbers[indexSmallest]
int temp = numbers[i];
numbers[i] = numbers[indexSmallest];
numbers[indexSmallest] = temp;
}
return comparisons;
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the selectionSort method
int comparisons = selectionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
System.out.println("Total comparisons: " + comparisons);
}
}
CODE 3.5 ---
import java.util.Arrays;
public class InsertionSortDemo {
private static void insertionSort(int[] numbers) {
for (int i = 1; i < numbers.length; i++) {
int j = i;
while (j > 0 && numbers[j] < numbers[j - 1]) {
// Swap numbers[j] and numbers [j - 1]
int temp = numbers[j];
numbers[j] = numbers[j - 1];
numbers[j - 1] = temp;
j--;
}
}
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the insertionSort method
insertionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
}
}.
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Step 1: Implement the getSortedRunLength() method
Implement the getSortedRunLength() method in NaturalMergeSorter.java. Access
NaturalMergeSorter.java by clicking on the orange arrow next to NaturalMerge.java at the top of
the coding window.
getSortedRunLength() has three parameters:
array: a reference to an array of integers,
arrayLength: an integer for the array's length, and
startIndex: an integer for the run's starting index.
The method returns the number of array elements sorted in ascending order, starting at startIndex
and ending either at the end of the sorted run, or the end of the array, whichever comes first. The
method returns 0 if startIndex is out of bounds.
File NaturalMerge.java has several test cases for getSortedRunLength() that can be run by
clicking the "Run program" button. One test case also exists for naturalMergeSort(), but that can
be ignored until step two is completed.
The program's output does not affect grading.
Submit for grading to ensure that the getSortedRunLength() unit tests pass before proceeding.
Step 2: Implement the naturalMergeSort() method
Implement the naturalMergeSort() method in NaturalMergeSorter.java. naturalMergeSort() must:
Start at index i=0
Get the length of the first sorted run, starting at i
Return if the first run's length equals the array length
If the first run ends at the array's end, reassign i=0 and repeat step 2
Get the length of the second sorted run, starting immediately after the first
Merge the two runs with the provided merge() method
Reassign i with the first index after the second run, or 0 if the second run ends at the array's end
Go to step 2
NaturalMergeSorter.java
public class NaturalMergeSorter {
public static int getSortedRunLength(int[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static int getSortedRunLength(double[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static void naturalMergeSort(int[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLength) {
return;
}
int secondRunLength = getSortedRunLength(array, arrayLength, i + firstRunLength);
merge(array, i, i + firstRunLength - 1, i + firstRunLength + secondRunLength - 1);
if (i + firstRunLength + secondRunLength == arrayLength) {
i = 0;
} else {
i = i + firstRunLength + secondRunLength;
}
}
}
public static void naturalMergeSort(double[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
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Create a menu-driven program that will accept a collection of non-ne.pdf
Create a menu-driven program that will accept a collection of non-negative integers from the
keyboard, calculate the mean and median values and display those values on the screen. Your
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median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit
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This is what my project looks like already: Please fix it thanks. The SortSearchUtil will also be
included.
import java.util.Scanner;
public class ArraySorting
{
public static void main(String[] args)
{
int option;
int integer = 0;
int optionOne;
int optionTwo;
int optionThree;
int optionFour;
int optionFive;
int[] numbers = new int[5];
Scanner kb = new Scanner(System.in);
System.out.println(\"Please enter a non-negative integer: \");
integer = kb.nextInt();
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}
option = displayMenu(kb);
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{
case 1:
optionOne(numbers);
System.out.println(\"\");
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case 2:
optionTwo(numbers);
System.out.println(\"\");
case 3:
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break;
case 4:
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System.out.println(\"\");
break;
case 5:
//optionFive();
System.out.println(\"\");
break;
}
option = displayMenu(kb);
}
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System.out.println();
System.out.println(\"Thank you. Have a nice day.\");
}
}
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while (option != 1 && option != 2 && option != 3 && option != 4 && option !=5 && option
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By Gohar
references:
Automate the stuff boring with Python( 2nd edition), Al Sweigart
Learn web development with Python, Fabrizio Romano, Gaston C. Hillar and Arun Ravindran
Step 1You need to run the JAVA programs in sections 3.3 and 3.5 for.pdf
Step 1:You need to run the JAVA programs in sections 3.3 and 3.5 for selection sort and
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Step 2: You need to modify these two programs, save them, submit them, and add some
comments and explanations to them to sort the list elements from high to low value. The index
should be IndexHighest instead IndexSmallest.
Step3: Run the modified programs and print out the results and submit them.
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JAVA programs), the two modified programs to sort the values from high to low value for
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This program uses the selection sort algorithm to sort an array. The code has been modified to
also calculate how many item comparisons are done. You can try running the program with
different arrays to see how the total number of comparisons changes (or doesn't change).
CODE 3.3 ---
import java.util.Arrays;
public class SelectionSortDemo {
private static int selectionSort(int[] numbers) {
// A variable to hold the number of item comparisons
int comparisons = 0;
for (int i = 0; i < numbers.length - 1; i++) {
// Find index of smallest remaining element
int indexSmallest = i;
for (int j = i + 1; j < numbers.length; j++) {
comparisons++;
if (numbers[j] < numbers[indexSmallest]) {
indexSmallest = j;
}
}
// Swap numbers[i] and numbers[indexSmallest]
int temp = numbers[i];
numbers[i] = numbers[indexSmallest];
numbers[indexSmallest] = temp;
}
return comparisons;
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the selectionSort method
int comparisons = selectionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
System.out.println("Total comparisons: " + comparisons);
}
}
CODE 3.5 ---
import java.util.Arrays;
public class InsertionSortDemo {
private static void insertionSort(int[] numbers) {
for (int i = 1; i < numbers.length; i++) {
int j = i;
while (j > 0 && numbers[j] < numbers[j - 1]) {
// Swap numbers[j] and numbers [j - 1]
int temp = numbers[j];
numbers[j] = numbers[j - 1];
numbers[j - 1] = temp;
j--;
}
}
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the insertionSort method
insertionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
}
}.
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Step 1: Implement the getSortedRunLength() method
Implement the getSortedRunLength() method in NaturalMergeSorter.java. Access
NaturalMergeSorter.java by clicking on the orange arrow next to NaturalMerge.java at the top of
the coding window.
getSortedRunLength() has three parameters:
array: a reference to an array of integers,
arrayLength: an integer for the array's length, and
startIndex: an integer for the run's starting index.
The method returns the number of array elements sorted in ascending order, starting at startIndex
and ending either at the end of the sorted run, or the end of the array, whichever comes first. The
method returns 0 if startIndex is out of bounds.
File NaturalMerge.java has several test cases for getSortedRunLength() that can be run by
clicking the "Run program" button. One test case also exists for naturalMergeSort(), but that can
be ignored until step two is completed.
The program's output does not affect grading.
Submit for grading to ensure that the getSortedRunLength() unit tests pass before proceeding.
Step 2: Implement the naturalMergeSort() method
Implement the naturalMergeSort() method in NaturalMergeSorter.java. naturalMergeSort() must:
Start at index i=0
Get the length of the first sorted run, starting at i
Return if the first run's length equals the array length
If the first run ends at the array's end, reassign i=0 and repeat step 2
Get the length of the second sorted run, starting immediately after the first
Merge the two runs with the provided merge() method
Reassign i with the first index after the second run, or 0 if the second run ends at the array's end
Go to step 2
NaturalMergeSorter.java
public class NaturalMergeSorter {
public static int getSortedRunLength(int[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
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break;
}
}
return length;
}
public static int getSortedRunLength(double[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static void naturalMergeSort(int[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLength) {
return;
}
int secondRunLength = getSortedRunLength(array, arrayLength, i + firstRunLength);
merge(array, i, i + firstRunLength - 1, i + firstRunLength + secondRunLength - 1);
if (i + firstRunLength + secondRunLength == arrayLength) {
i = 0;
} else {
i = i + firstRunLength + secondRunLength;
}
}
}
public static void naturalMergeSort(double[] array, int arrayLength) {
int i = 0;
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Javaa. The mean of a list of numbers is its arithmetic average. T.pdf
Java:
a. The mean of a list of numbers is its arithmetic average. The median of a list is its middle value
when the values are placed in order. For example, if a list contains 1, 4, 7, 8, and 10, then the
mean is 6 and the median is 7. Write an application that allows you to enter five integers and
displays the values, their mean, and their median.
Save the file as MeanMedian.java.
b. Revise the MeanMedian class so that the user can enter any number of values up to 20. If the
list has an even number of values, the median is the numeric average of the values in the two
middle positions. Save the file as
MeanMedian2.java
Solution
Ans a):
import java.util.*;
import java.lang.*;
import java.io.*;
class MeanMedian
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner scan=new Scanner(System.in);
int arr[]=new int[5];
System.out.println(\"Enter the integers :\"); //asking the user to enter 5 integers
for(int i=0;i<5;i++)
arr[i]=scan.nextInt();
int sum=0;
for(int i=0;i<5;i++)
sum=sum+arr[i];
int mean=sum/5; //calculating mean
int median=arr[2]; //calculating median
System.out.println(\"Integers entered by the user \");
for(int i=0;i<5;i++)
System.out.print(arr[i]+\" \"); //printing values entered by user
System.out.println();
System.out.println(\"Mean = \"+mean); //printing mean
System.out.println(\"Median = \"+median); //printing median
}
}
******OUTPUT******
Enter the integers :
1 4 7 8 10
Integers entered by the user
1 4 7 8 10
Mean = 6
Median = 7
******OUTPUT******
Ansb):
import java.util.*;
import java.lang.*;
import java.io.*;
class MeanMedian //class MeanMedian
{
public static void main (String[] args) throws java.lang.Exception
{
int sum=0; //variable to store the sum of values
int mean=0; //variable to store the mean of values
int median=0; //variable to store the median of values
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter the number of values upto you want to enter,it must not be greater
than 20 :\"); //asking the user for no.of values
int n=scan.nextInt(); //store size in n
int arr[]=new int[n]; //array to store integers
System.out.println(\"Enter the integers\"); //asking the user to enter the integers
for(int i=0;i.
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iii) Logical operators
iv)Ternary operator
v) Bitwise operators
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vii) Unary operators
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Java Code The traditional way to deal with these in Parsers is the .pdf
Java Code: The traditional way to deal with these in Parsers is the Expression-Term-Factor
pattern:
Expression: TERM {+|- TERM}
Term: FACTOR {*|/ FACTOR}
Factor: number | ( EXPRESSION )
A couple of notation comments:
| means "or" - either + or -, either * or /
{} means an optional repeat. That's what allows this to parse 1+2+3+4
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It turns out that it is. Let's substitute that in:
TERM: FACTOR(6) / FACTOR(2)
But remember that our pattern is a REPEATING pattern (hint: loop):
TERM: FACTOR(6) / FACTOR(2) {*|/ FACTOR}
We see the * and call factor. But this time, the factor is not a number but a parenthetical
expression.
Factor: number | ( EXPRESSION )
Factor calls expression.
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it passes the 1 up. Expression sees the + and calls term. Term calls factor which returns the 2.
Expression doesn't see a +|- value so ends the loop and returns 1+2.
So, remember that we were here:
TERM: FACTOR(6) / FACTOR(2) * FACTOR
Our factor is (1+2). That can't be broken down. That math HAS to be done before can multiply
or divide. That's what enforces order of operations.
In code, this looks like something like this (pseudo-code):
Node Factor()
num = matchAndRemove(NUMBER)
if (num.isPresent) return num
if (matchAndRemove(LPAREN).isPresent)
exp = Expression()
if (exp == null) throw new Exception()
if (matchAndRemove(RPAREN).isEmpty)
throw new Exception()
Node Term()
left = Factor()
do
op = MatchAndRemove(TIMES)
if (op.isEmpty) op=MatchAndRemove(DIVIDE)
if (op.isEmpty) return left
right = Factor()
left = MathOpNode(left, op, right)
while (true)
Node Expression()
left = Term()
do
op = MatchAndRemove(PLUS)
if (op.isEmpty) op=MatchAndRemove(MINUS)
if (op.isEmpty) return left
right = Term()
left = MathOpNode(left, op, right)
while (true)
What is this "MathOpNode"? It's "just" a new node type that holds two other nodes (left and
right) and an operation type: *, /, +, -. Notice that the loops use the result of one operation as the
left side of the next operation. This is called left associative - the left most part is done first.
Right associativity is the opposite - the rightmost part is done first, then we work our way left.
Generally, notice the pattern here - we call a function that is the lo.
Define a knowledge-based agent, and describe its major components. W.pdf
Create a function mean comp that compares the mean value of the odd numbered elements with
the mean value of the even numbered elements and returns: if they are equal, if the mean of the
odd numbered elements is greater, if the mean of the even numbered elements is greater.
Solution
A sample Java Program methods
public static void main(String []args){
float[] list = {1.0f, 7.0f, 8.0f, 1.0f};
System.out.println(meancomp(list));
}
static int meancomp(float[] list) {
float evenSum = 0.0f;
float oddSum = 0.0f;
for (int i = 0; i < list.length; i++) {
if (i % 2 == 1)
evenSum = evenSum + list[i];
else
oddSum = oddSum + list[i];
}
int noOfEvenElements = list.length / 2;
int noOfOddElements = list.length / 2 + list.length % 2;
float evenMean = evenSum / (float) noOfEvenElements;
float oddMean = oddSum / (float) noOfOddElements;
int result = Float.compare(evenMean, oddMean);
if (result == 0)
return 0;
else if (result < 0)
return 1;
else
return 2;
}.
Compare naive, effector, and memory T & B cells (survival time, Ig &.pdf
Choose one of the evolutions of CIT and discuss how it may have made the application of CIT to
specific leadership consultations more useful.
Solution
Ans:- In late 2004, Georgia began implementation of a statewide Crisis Intervention Team (CIT)
program to train a portion of its law enforcement officers to respond safely and effectively to
individuals with mental illnesses who are in crisis. This overview provides a description of the
evolution of the Georgia CIT, including discussions of the historical context in which the
program developed; the program\'s vision, mission, and objectives; the importance of the
multidisciplinary Georgia CIT Advisory Board; the training curriculum; the role played by state
and local coordinators; the value of stakeholders\' meetings; practical operations of the program;
the importance of considering the adequacy of community-based and hospital-based psychiatric
services; costs and funding; the program\'s expansion plan; and evaluation, research, and
academic collaborations. These detailed descriptions of the Georgia CIT program may be useful
for professionals involved in local, regional, or state CIT program planning and may provide a
practical synopsis of one example of this collaborative model that is being rapidly disseminated
across the U.S.
: When meeting with the Athens County Planning Committee, the reviewers thought it important
to set the tone of the onsite review process by discussing the purpose and role of the Core
Elements. While there is a lot of variability across CIT development (which is good for
innovation), the Core elements can provide direction for communities to positively assess their
CIT program. Most developing CIT programs go through common growth stages. From its
inception to a committed group of people that bring an initial training to their community, to a
policy driven, data rich CIT program, the core elements provide a way to guide the growth of
programs. Such elements also create consensus on what CIT is NOT: A twelve hour training that
does not include role play is not CIT training.
It is when the Core elements are used to define “fidelity” concerning CIT programs, that natural
tensions arise. Rural vs. urban, large vs. small departments, disparities in resources, and how
well developed other Criminal Justice initiates are within a county, like specialized courts and/or
jail diversion programs, all impact the specific elements. Three common areas of tension are the
length of trainings, who gets trained (voluntary or mandatory), and how the deescalation/role
play blocks of the training are taught. The reviewers noted that their goal is not to assign where
Athens county is in their program fidelity, but rather use the Core elements to focus discussions
on program development. To illustrate this, the reviewers provide a handout (The CIT Pyramid)
depicting the typical path that CIT program development can take (see Attachment #1). As CIT
develops beyond training and into a full fle.
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Lambda Functions in Java 8
Do you want to learn functional programming in Java using lambda expressions introduced in Java 8? Do you want to explore the foundational concepts to explore powerful stream API? This presentation provides an overview of lambda functions introduced in Java 8 through examples. Topics covered: What is functional programming, creating lambda expressions, functional interfaces, built-in functional interfaces, and method references.
Make sure you have JDK 8 installed for trying out the programs as you go through the self-contained programming examples.
Javaa. The mean of a list of numbers is its arithmetic average. T.pdf
Java:
a. The mean of a list of numbers is its arithmetic average. The median of a list is its middle value
when the values are placed in order. For example, if a list contains 1, 4, 7, 8, and 10, then the
mean is 6 and the median is 7. Write an application that allows you to enter five integers and
displays the values, their mean, and their median.
Save the file as MeanMedian.java.
b. Revise the MeanMedian class so that the user can enter any number of values up to 20. If the
list has an even number of values, the median is the numeric average of the values in the two
middle positions. Save the file as
MeanMedian2.java
Solution
Ans a):
import java.util.*;
import java.lang.*;
import java.io.*;
class MeanMedian
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner scan=new Scanner(System.in);
int arr[]=new int[5];
System.out.println(\"Enter the integers :\"); //asking the user to enter 5 integers
for(int i=0;i<5;i++)
arr[i]=scan.nextInt();
int sum=0;
for(int i=0;i<5;i++)
sum=sum+arr[i];
int mean=sum/5; //calculating mean
int median=arr[2]; //calculating median
System.out.println(\"Integers entered by the user \");
for(int i=0;i<5;i++)
System.out.print(arr[i]+\" \"); //printing values entered by user
System.out.println();
System.out.println(\"Mean = \"+mean); //printing mean
System.out.println(\"Median = \"+median); //printing median
}
}
******OUTPUT******
Enter the integers :
1 4 7 8 10
Integers entered by the user
1 4 7 8 10
Mean = 6
Median = 7
******OUTPUT******
Ansb):
import java.util.*;
import java.lang.*;
import java.io.*;
class MeanMedian //class MeanMedian
{
public static void main (String[] args) throws java.lang.Exception
{
int sum=0; //variable to store the sum of values
int mean=0; //variable to store the mean of values
int median=0; //variable to store the median of values
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter the number of values upto you want to enter,it must not be greater
than 20 :\"); //asking the user for no.of values
int n=scan.nextInt(); //store size in n
int arr[]=new int[n]; //array to store integers
System.out.println(\"Enter the integers\"); //asking the user to enter the integers
for(int i=0;i.
Operators in java
In this session you learn about
1. How to download and install java in your PC
2, How to write simple Java Program
3. Operators in Java
4. Types of operators
i) Arithmetic operators
ii) Relational operators
iii) Logical operators
iv)Ternary operator
v) Bitwise operators
vi) Assignment operators
vii) Unary operators
viii) Special operators
5. Operators precedence
Java Code The traditional way to deal with these in Parsers is the .pdf
Java Code: The traditional way to deal with these in Parsers is the Expression-Term-Factor
pattern:
Expression: TERM {+|- TERM}
Term: FACTOR {*|/ FACTOR}
Factor: number | ( EXPRESSION )
A couple of notation comments:
| means "or" - either + or -, either * or /
{} means an optional repeat. That's what allows this to parse 1+2+3+4
Think of these as functions. Every CAPTIALIZED word is a function call.
Consider our meme expression above: 6/2*(1+2)
We will start by looking at expression. Expression starts with a TERM. We can't do anything
until we resolve TERM, so let's go there.
A term starts with FACTOR. Again, we can't do anything until we deal with that.
A factor is a number or a (EXPRESSION). Now we can look at our token (hint:
MatchAndRemove). We see a number. OK - our factor is a number. We "return" that.
Remember that we got to factor from term. Let's substitute our number in:
TERM: FACTOR(6) {*|/ FACTOR}
Now we deal with our optional pattern. Is the next character * or /? Yes! Now is the next thing a
factor?
It turns out that it is. Let's substitute that in:
TERM: FACTOR(6) / FACTOR(2)
But remember that our pattern is a REPEATING pattern (hint: loop):
TERM: FACTOR(6) / FACTOR(2) {*|/ FACTOR}
We see the * and call factor. But this time, the factor is not a number but a parenthetical
expression.
Factor: number | ( EXPRESSION )
Factor calls expression.
Expression calls term, term calls factor, factor returns the number 1. Term doesn't see a * or / so
it passes the 1 up. Expression sees the + and calls term. Term calls factor which returns the 2.
Expression doesn't see a +|- value so ends the loop and returns 1+2.
So, remember that we were here:
TERM: FACTOR(6) / FACTOR(2) * FACTOR
Our factor is (1+2). That can't be broken down. That math HAS to be done before can multiply
or divide. That's what enforces order of operations.
In code, this looks like something like this (pseudo-code):
Node Factor()
num = matchAndRemove(NUMBER)
if (num.isPresent) return num
if (matchAndRemove(LPAREN).isPresent)
exp = Expression()
if (exp == null) throw new Exception()
if (matchAndRemove(RPAREN).isEmpty)
throw new Exception()
Node Term()
left = Factor()
do
op = MatchAndRemove(TIMES)
if (op.isEmpty) op=MatchAndRemove(DIVIDE)
if (op.isEmpty) return left
right = Factor()
left = MathOpNode(left, op, right)
while (true)
Node Expression()
left = Term()
do
op = MatchAndRemove(PLUS)
if (op.isEmpty) op=MatchAndRemove(MINUS)
if (op.isEmpty) return left
right = Term()
left = MathOpNode(left, op, right)
while (true)
What is this "MathOpNode"? It's "just" a new node type that holds two other nodes (left and
right) and an operation type: *, /, +, -. Notice that the loops use the result of one operation as the
left side of the next operation. This is called left associative - the left most part is done first.
Right associativity is the opposite - the rightmost part is done first, then we work our way left.
Generally, notice the pattern here - we call a function that is the lo.
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Javaa. The mean of a list of numbers is its arithmetic average. T.pdf
Javaa. The mean of a list of numbers is its arithmetic average. T.pdf
How to start functional programming (in Scala): Day1
How to start functional programming (in Scala): Day1
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More from fathimaoptical
Define a knowledge-based agent, and describe its major components. W.pdf
Create a function mean comp that compares the mean value of the odd numbered elements with
the mean value of the even numbered elements and returns: if they are equal, if the mean of the
odd numbered elements is greater, if the mean of the even numbered elements is greater.
Solution
A sample Java Program methods
public static void main(String []args){
float[] list = {1.0f, 7.0f, 8.0f, 1.0f};
System.out.println(meancomp(list));
}
static int meancomp(float[] list) {
float evenSum = 0.0f;
float oddSum = 0.0f;
for (int i = 0; i < list.length; i++) {
if (i % 2 == 1)
evenSum = evenSum + list[i];
else
oddSum = oddSum + list[i];
}
int noOfEvenElements = list.length / 2;
int noOfOddElements = list.length / 2 + list.length % 2;
float evenMean = evenSum / (float) noOfEvenElements;
float oddMean = oddSum / (float) noOfOddElements;
int result = Float.compare(evenMean, oddMean);
if (result == 0)
return 0;
else if (result < 0)
return 1;
else
return 2;
}.
Compare naive, effector, and memory T & B cells (survival time, Ig &.pdf
Choose one of the evolutions of CIT and discuss how it may have made the application of CIT to
specific leadership consultations more useful.
Solution
Ans:- In late 2004, Georgia began implementation of a statewide Crisis Intervention Team (CIT)
program to train a portion of its law enforcement officers to respond safely and effectively to
individuals with mental illnesses who are in crisis. This overview provides a description of the
evolution of the Georgia CIT, including discussions of the historical context in which the
program developed; the program\'s vision, mission, and objectives; the importance of the
multidisciplinary Georgia CIT Advisory Board; the training curriculum; the role played by state
and local coordinators; the value of stakeholders\' meetings; practical operations of the program;
the importance of considering the adequacy of community-based and hospital-based psychiatric
services; costs and funding; the program\'s expansion plan; and evaluation, research, and
academic collaborations. These detailed descriptions of the Georgia CIT program may be useful
for professionals involved in local, regional, or state CIT program planning and may provide a
practical synopsis of one example of this collaborative model that is being rapidly disseminated
across the U.S.
: When meeting with the Athens County Planning Committee, the reviewers thought it important
to set the tone of the onsite review process by discussing the purpose and role of the Core
Elements. While there is a lot of variability across CIT development (which is good for
innovation), the Core elements can provide direction for communities to positively assess their
CIT program. Most developing CIT programs go through common growth stages. From its
inception to a committed group of people that bring an initial training to their community, to a
policy driven, data rich CIT program, the core elements provide a way to guide the growth of
programs. Such elements also create consensus on what CIT is NOT: A twelve hour training that
does not include role play is not CIT training.
It is when the Core elements are used to define “fidelity” concerning CIT programs, that natural
tensions arise. Rural vs. urban, large vs. small departments, disparities in resources, and how
well developed other Criminal Justice initiates are within a county, like specialized courts and/or
jail diversion programs, all impact the specific elements. Three common areas of tension are the
length of trainings, who gets trained (voluntary or mandatory), and how the deescalation/role
play blocks of the training are taught. The reviewers noted that their goal is not to assign where
Athens county is in their program fidelity, but rather use the Core elements to focus discussions
on program development. To illustrate this, the reviewers provide a handout (The CIT Pyramid)
depicting the typical path that CIT program development can take (see Attachment #1). As CIT
develops beyond training and into a full fle.
Consider the titration of50.0 mL of 0.217 M hydrazoic acid (HN3, Ka=.pdf
Consider blending polypropylene (80%) and EDPM (20%) in the melting zone of the screw
channel of a single screw extruder with a speed of 120 rpm and a flow rate Q of 3 times 10^-6
m^3/s at 190 degree C. Calculate the viscosity ratio needed for the breakup of the droplets under
the following conditions: Screw speed = 120 rpm L/D s 5 Flight clearance = 0.2 mm Right width
= 4 mm Screw diameter = 25 mm Initial radius of EPDM particles = 1 mu m PP/EDPM
interfacial tension @ 190 degree C = 3 times 10^-3 N/m PP viscosity = 400 Pa-s
Solution
The answer of following question is as follows..
The maximum viscosity ratio for the given problem is 8:5.
Choose one of the evolutions of CIT and discuss how it may have made.pdf
canvas.northseattle.edu Microeconomics Midterm Chapter 2 Flashcards | Qui.. economics
assignment canvas exam - Google Sea. O Increasing the amount of resources devoted to the
production of military goods Increasing the human capital of its labor force Question 16 0.1 pts
Productive efficiency O is represented by the points outside and to the right of the Production
Possibilities Frontier. O means that all the economy\'s resources are fully employed using the
current technology O requires developing new technology and better human capital in the
Production Possibilities Frontier model. O applies to points inside the Production Possibilities
Frontier as well as points along the frontier O means there is no opportunity cost to increasing
production. 0.1 pts D Question 17 The concave shape of the Production Possibilities Frontier
indicates
Solution
Answer 16 : Production efficiency means that all the economic resources are fully employed
using the current technology. It is used to show that various possible combination of goods and
services produced within a particular period of time within a given technology and resources.
Answer 17 : The concave shape of the production possibility frontier indicated the law of
increasing oppournity cost. As the production possibility curve is downward sloping it means
that one more unit of production increases the sacrificing of more another units.
Answer 18 : The statement is True that when the firm has an absolute advantage when it can
produced a product it is not necessary to have comparative advantages also. A nation might have
an absolute advantage but not a comparative advantage in the production of a given product.A
country enjoyed an absolute advantage over another country when they used fewer resources to
produce that product from another country..
Write a GUI application to simulate writing out a check. The value o.pdf
Use a power series to approximate the definite integral,I, to six decimal places.
Solution
(x^3)/(1 + x^4) = (x^3)*(1 + x^4)^-1 = (x^3)*(1 - x^4 + x^8 + . . . using the
binomial formula. (I doubt whether any more is necessary.) INT [0, 0.2] (x^3)/(1 + x^4) dx =
INT [0, 0.2] x^3 - x^7 + x^11 - . . . = (1/4)x^4 - (1/8)x^8 + (1/12)x^12 - . . . = (1/4)*0.2^4 -
(1/8)*0.2^8 + (1/12)*0.2^12 - . . . = 0.000399680 =0.000400 (6 dec. pl.).
Without the effects of cyanobacteria or algae on lichen metabolism, .pdf
two more pages of elaboration to how Trumpcare and Obamacare relates to health care finance.
30 resources
Obamacare, also known as the Affordable Care Act (ACA), was passed in 2010 as a health care
insurance plan for all Americans. The law made many changes to the existing minimum
coverage in insurance, and increase the federal subsidies for the middle-income households of
the country. Trumpcare, also known as the American Health Care Act (AHCA), is a replacement
health insurance plan designed to partly repeal the existing ACA. The new healthcare bill, is one
step closer to repealing . The nonpartisan Congressional Budget Office (CBO) has an estimate
with ACA as the law of the land, the uninsured Americans would be 28 million will remain
stable for the next decade. The analysis of an earlier version of the bill, there is an estimate of 54
million could be uninsured by 2026 in case of implementation of the AHCA. The ACA have
provision to impose penalty on consumers who can afford to buy health insurance but do not do
so, known as the individual mandate payment. it’s paid when you file your federal tax return.
This penalty can be either 2.5% of income up to the total yearly premium or $695 per person up
to $2,085, whichever is higher. AHCA eliminates the individual mandate and offers an incentive
to consumers who maintain insurance coverage: insurance companies can charge a 30% penalty
who buy health insurance after had a gap in required coverage exceeding 63 days. The 30%
penalty would apply for 12 months. The ACA requires that all major health policies sold to
consumers offer coverage for 10 categories of essential health benefits: Outpatient services,
Emergency services , Maternity and newborn care, Hospitalization. Prescription medication ,
Mental health and substance abuse services, Laboratory services. Pediatric services,
Rehabilitation services, including vision and oral. Preventative, wellness, and chronic disease
management services. The AHCA eliminates these protections by giving a waiver to define what
they consider essential health benefits. States could allow insurance companies to sell plans that
do not cover prescription drugs or maternity care. The ACA and AHCA have the same rules for
newborns. A baby can be added to family existing health insurance plan or can buy a new plan to
give cover the baby. AHCA is making major changes in the health insurance by reducing the
requirements and making change in the structure of total offered government subsidies. On the
analysis, the CBO has reported the current changes would make health insurance more
affordable for few customers. Obamacare: The ACA increased Medicare taxes for the
households having incomes above $250,000. The legislation gave some tax credits to middle-
income earners to help them pay out-of-pocket health expenses. The AHCA repeals taxes of
previous insurance plan. It was mandatory for the companies employing more than 50 employees
to offer health insurance or pay a pena.
What is this image trying to tell you about the American West.pdf
The probability that a man will be alive in 10 year is 0.8 and the probability that his wife will be
alive in 10 years is 0.9 Find the probability that in 10 years Both will be alive; Only the man will
be alive; Only the wife will be alive; At least one will be alive.
Solution
(a)
P = 0.8*0.9 = 0.72
(b)
P = 0.8*(1-0.9) = 0.08
(c)
P = (1-0.8)*(0.9) = 0.18
(d)
P =1- (1-0.8)(1-0.9) = 1-0.02 = 0.98.
What is the difference between a defined-benefit and a defined-contr.pdf
The lateral surface area of a cone of radius r and height h (the surface area excluding the base) is
A=pir . Find dr/dh for a cone with lateral surface area of A = 4500picm2. Evaluate this
derivative when r = 60 cm and h = 45 cm. dr/dh= cm3
Solution
4500=rsqrt(r2+h2) 2025*10^4=r^4+r^2 h^2 0= 4r^3 dr/dh +2rh^2dr/dh+2r^2h
dr/dh=-rh/2r^2+h^2 =-45*60/2*3600+2025 =-0.292.
This is question about excel cuers.How would you use Financial Fun.pdf
The average temperatures for Annapolis, MD are: 44, 48, 57, 68, 77, 86, 90, 88, 81, 69, 59, and
48
A. create a box-and-whisper plot for the data.
B. What is the median temperature?
C. 75% of the temperatures are below what value? How do you know?
D. 75% of the temperatures are above what value? How do you know?
E. What conclusions can you draw about the temperature in Maryland?
Solution
Ascending order for given data is,
44
48
48
57
59
68
69
77
81
86
88
90
hence median is 68.5
75 percent temperatures are below 81
75 percent temperatures are above 57
In maryland
temperature sustains either at highest or lowest range of temperature not around median range.
The surface area to volume ration is least improtant in thea. sink.pdf
Temperature is an example of a variable that uses
a.the ratio scale
b.the interval scale
c.the ordinal scale
d.either the ratio or the ordinal scale
Temperature is an example of a variable that uses
a.the ratio scale
b.the interval scale
c.the ordinal scale
d.either the ratio or the ordinal scale
Temperature is an example of a variable that uses
a.the ratio scale
b.the interval scale
c.the ordinal scale
d.either the ratio or the ordinal scale
Solution
Temperature is an example of a variable that uses the interval scale.
Beacuse, interval scales are numerical scales in which intervals have the same interpretation
throughout. As an example, we can take the Fahrenheit scale of temperature..
The Martian calendar has sixteen months instead of twelve. What is t.pdf
Suppose that lines l1, l2, l3 are lines in an affine plane. Suppose that lines l1, l2 are parallel.
Prove that if l1, l3 intersect then l2, l3 intersect.
Solution
Here we have the rule that when two parallel lines are intersected by a transversal, then the
exteriior corresponding angles, thus formed are equal to each other. Now it is given that l1 and l2
are parallel lines and l3 intersects l1, that means l3 is transversal here, so that the exterior angles
thus forming on line l1 and l3 will be equal to each other.
Now as both exterior angles are forming at two different intersecting points of parallel lines l1
and l2, when intersected by line l3, that proved that being parallel lines, line l3 intersects both
lines l1 and l2.
Proved.
Baby names and birth weights”IntroductionBabies are weighed soon.pdf
At a glass manufacturing facility, crystal stemware is carefully inspected for correct dimensions,
quality, and production trends. After lengthy studies, the factory is known to produce 15%
defectives. Most of these pieces are discovered through inspection and are reworked or
discarded. Suppose two pieces are randomly selected for inspection. Fill in the blank. (Give your
answer to four decimal places.) Suppose at least one of the pieces has a flaw. The probability that
both are defective is...
Solution
PROBABILITY OF DEFECTIVE = 0.15
PROBABILITY NON DEFECTIVE =1-0.15 = 0.85
PROBABILITY BOTH DEFECTIVE = 2C2*(0.15)^2*(0.85)^0 = 0.0225.
Question How can I called this method in the main, and how can I .pdf
Question 1. List and describe three rules of natural justice, provide an example of a situation
where each of the three selected rules may be breached or contravened ( you may make up
examples, draw from your own experience, or use examples from the textbook.)
Solution
The principles of natural justice is fairness and guarantee a fair decision is reached by an
objective decision maker.
Maintaining fairness protects the rights of individuals and increase public confidence in the
process.
The principles of natural justice were evolve from the Romans who admit that few legal
principles were \"natural\" or self-evident and did not need a statutory basis.
These two primary legal safeguards carrry out all decisions by judges or government officials
when they take quasi-judicial or judicial decisions.
The 3 common law rules are referred to in alliance to natural justice or procedural fairness.
The Hearing Rule
A person must be allowed an adequate opportunity to present their case where certain interests
and rights may be adversely altered by a decision-maker.
To ensure that these rights are valued, the authority which is assigned for deciding give both the
opportunity to prepare and present evidence and to chase to arguments presenting by the opposite
side.
When oversee an investigation in relation to a complaint it is important that the person being
accuse against is advised of the affirmations in as much detail as possible and given the
opportunity to reply to the affirmations.
The Bias Rule
This rule states that no one concern to be judge in his or her case. This is the requirement that the
deciding authority must be unbiased when according the hearing or making the judgment.
Additionally, investigators and decision-makers must act without bias in all channels connected
with the making of a decision.
A decision-maker must be impartial and must make a decision based on a balanced and
considered assessment of the information and evidence before him or her without fondness over
another party.
Investigators should ensure that there is no battle of interest which would make it inappropriate
for them to conduct the investigation .
The Evidence Rule
This rule is that an administrative decision must be based upon analytical proof or evidence
material.
Investigators and decision makers should not base their decisions on mere belief or gut feelings .
Rather, an investigator or decision maker should be able to clearly point to the evidence on
which the inference or decision is based.
Evidence (arguments, allegations, documents, photos, etc..) conferred by one party must be
expose to the other party, who may then subject it to analysis.
For example - the idea of fair hearing particularly varies significantly in different contexts such
as whether it is a sophisticated full fledged hearing or a blunt and minimal one ; hearing prior to
the decision or post decisional hearing.
Case : Tanjong jaga vs minister of labour (1987)
- Tanjong jaga contend that it was a .
Question 1. List and describe three rules of natural justice, provid.pdf
PROBLEM I. A nightclub manager realizes that demand for drinks is more elastic among
students and tries to determine the optimal pricing schedule. Specifically, he estimates that the
demand functions are given by g.-30-6P1 for students and = 24-4p for non-students. Assume that
drinks cost the nightclub S2 each. Q1. If the market cannot be segmented, what is the uniform
monopoly price? (a) $3.10 (b) $3.30 (c) S3.50 (d) S3.70 (e) S4.20 Q2. If the nightclub can
charge according to whether or not the customer is a student but is limited to linear pricing, what
price (per drink) should be set for students? (a) $3.10 (b) S3.25 (c) $3.40 (d) S3.50 (e) $3.80 Q3.
Under the same conditions of Q2, what price (per drink) should be set for non-students? (a) s3.80
(b) $4.00 (c) S4.30 (d) $4.60 (e) $5.20
Solution
(Q1) (d)
Without segmentation, p1 = p2 = p
q1 = 30 - 6p
q2 = 24 - 4p
Market demand: q = q1 + q2 = 30 - 6p + 24 - 4p
q = 54 - 10p
10p = 54 - q
p = 5.4 - 0.1q
Profit is maximized when Marginal revenue (MR) equals Marginal cost (MC).
Total revenue (TR) = p x q = 5.4q - 0.1q2
MR = dTR/dq = 5.4 - 0.2q
Equating with MC,
5.4 - 0.2q = 2
0.2q = 3.4
q = 17
p = 5. - (0.1 x 17) = 5.4 - 1.7 = $3.7
(Q2) (d)
With segmentation, profit is maximized when MR1 = MC and MR2 = MC
For students,
q1 = 30 - 6p1
6p1 = 30 - q1
p1 = (30 - q1) / 6
TR1 = p1 x q1 = (30q1 - q12) / 6
MR1 = dTR1/dq1 = (30 - 2q1) / 6
Equating with MC,
(30 - 2q1) / 6 = 2
30 - 2q1 = 12
2q1 = 18
q1 = 9
p1 = (30 - 9) / 6 = 21 / 6 = $3.5
(Q3) (b)
For non-students, q2 = 24 - 4p2
4p2 = 24 - q2
p2 = 6 - 0.25q2
TR2 = p2 x q2 = 6q2 - 0.25q22
MR2 = dTR2/dq2 = 6 - 0.5q2
Equating with MC,
6 - 0.5q2 = 2
0.5q2 = 4
q2 = 8
p2 = 6 - (0.25 x 8) = 6 - 2 = $4.
Postal ClerkAssistant. Why do the five steps of the recruitment pro.pdf
Please help with this question related to Assembly Language! As discussed in class, the
instruction li $s0, 0x123489ab will be translated into two instructions lui $at, 0x1234 ori $s0,
$at, 0x89ab Instead of using the Instruction ori, can the second Instruction be addi $s0, $at,
0x89ab and why? a. Yes, but we need to change the instruction addi to addi $at, $30, 0x89ab.
b. No, There is no instruction addi in MIPS. c. Yes, we can use the instruction addi instead of
ori. d. No, The instruction addi will consider 0x89ab as a negative number. If the instruction
addi is used as shown in the question, the actual value stored in the register $sO will be 0x1234
0000 + 0xffff88ab.
Solution
ADDI:
ORI:
so the ans is d.
OverviewWe will be adding some validation to our Contact classes t.pdf
On March 4 of the current year, Barefoot Bay, Inc. reacquired 5,000 shares of its common stock
at $89 per share. On August 7, Barefoot Bay sold 3,500 of the reacquired shares at $100 per
share. The remaining 1,500 shares were sold at $88 per share on November 29.
1. Journalize the transactions of March 4, August 7, and November 29. If an amount box does
not require an entry, leave it blank or enter \"0\".
2. What is the balance in Paid-in Capital from Sale of Treasury Stock on December 31 of the
current year?
$Mar. 4Aug. 7Nov. 29
Solution
4-Mar Treasury stock 445000 =5000*89 Cash 445000 7-Aug Cash 350000
=3500*100 Treasury stock 311500 =3500*89 Paid in capital-Treasury stock
38500 29-Nov Cash 132000 =1500*88 Paid in capital-Treasury stock 1500
Treasury stock 133500 =1500*89 2 Balance in Paid-in Capital from Sale of Treasury
Stock = 38500-1500 = $37000.
Negotiation - Porto (Porto case).note this is a case study so the.pdf
MULTIPLE CHOICE:
On January 1, a customer paid X Company $21,600 in advance for cleaning services. The
cleaning was going to be done once in January, once in February, and once in March, so the
payment was recorded as Deferred Revenue. What will be the result of the adjusting entry on
January 31?
A: a balance of $7,200 in the Deferred Revenue account on the Balance Sheet
B: a $7,200 increase in the Cash account on the Balance Sheet
C: revenue of $7,200 reported on the Income Statement
D: a $7,200 increase in the Deferred Revenue account on the Balance Sheet
Solution
Income to be recorded for the month of January = $21,600 / 3 months = $7,200
Hence, $7,200 shall be recognised as income for the month of January by transferring from
deferred revenue
The adjusting entry shall be
C: revenue of $7,200 reported on the Income Statement.
need help with my computer science lab assignemnt. this assignment i.pdf
mosome segregation n somatic cells reproduction or (c) A gynandromorph Sex comb XX XO
Solution
Determination of sex in human is different than flys.human having xxy ,xxxy are phenotypocally
male while in flys x chromosome matterial to autosomes determines the sex.in flys y
chromosome encodes only genes for sperms.So it depends on x:A ratio (x chromosome and
autosome ratio).If the ratio is 1 or more than 1 ,then it is a female while less than 1 I:e; 0.5 is
male.
XY-AA- 0.5 - normal male, XO-AA -0.5- sterile male.Therefore Turner syndrome of human xo
is female while a fruit fly with Turner syndrome xo is male..
Name a protein that contacts the insulin receptor inside the cell.pdf
mer EcoRO three-legged stool for retirement savi What sources of income make up the three-
legg ings?
Solution
Sources of income that make up the three legged stool for retirement savings: Social security,
Retirement plans and Personal savings.
Stool leg 1 : SOCIAL SECURITY:
Social security was designed to provide a minimum level of support . That is why it is also
known as social insurance. For every dollar a person earn , the government takes a percentage to
support social security . Your employer is also required to pay the same amount. When a person
retire , having a history of higher esrnings means social security will replace less of pre-
retirement income.
Stool leg 2 : RETIREMENT PLANS:
Retirement plans come in two forms: defined benefit and defined contribution. Defined benefit
pays you a retirement income and is usually paid in full by your employer. Defined contribution
plan provides an annual contribution to an account in your name, based on your annual salary.
Stool leg 3: PERSONAL SAVINGS:
Retirement income will depend on person\'s savings..
Modify this code to do an Insert function for an AVL tree, instead o.pdf
Match the cost behavior that is described with the proper cost type. The unit cost of an item is
$30 per unit when activity is 10,000 units and $15 per unit when activity is 20,000 units. The
total cost of an item is $30,000 when activity is 10,000 units and $30,000 when activity is 20,000
units. The total cost of an item is $30,000 when activity is 10,000 units and $50,000 when
activity is 20,000 units. 1. Variable cost 2. Fixed Cost The unit cost of an item is $30 per unit
when activity is 10,000 units and $20 per unit when activity is 20,000 units 3. Mixed Cost The
total cost of an item is $30,000 when activity is 10,000 units and $60,000 when activity is 20,000
units. The unit cost of an item is $30 per unit when activity is 10,000 units and $30 per unit when
activity is 20,000 units.
Solution
Variable cost is constant or same in per unit but varies in total with change in output
Fixed cost is constant in total but varies in per unit [ that is doesnot change with change in
output]
Mixed cost is neither constant in total nor in per unit
A)Fixed cost ,since same in total [10000*30 = 300000 or 15*20000 = 300000]
B)Fixed cost ,since same in total
C)Mixed cost,neither constant in per unit nor in total
D)Mixed cost ,neither constant in per unit nor in total
E)Variable cost ,constant in per unit [30000/10000 or 60000/20000 = $ 3 per unit]
F)Variable cost .
c).
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