The document contains the certification for a student named UTTAMGUPTA who completed a research project under the guidance of their teacher Mr. Amit Dutta. It also includes thanks from the student to their teacher and family for their support and assistance. The remainder of the document lists 20 questions related to programming concepts and tasks for the student to complete as part of their project.

1. 0
Gandhinagar
Ranchi

2. 1
This is to certify that UTTAMGUPTA , a
student of class XII-S1 has successfully
completed the research on the below
mentioned project under the guidance of
Mr.Amit Dutta ( Subject Teacher ) during
the year 2017-2018 in Computer Practical
Examination conducted by CBSE, New
Delhi.

3. 2
………………………………….
Signatureof ExternalExaminer
…………………………………..
Signatureof ComputerTeacher
UTTAM KUMAR GUPTA of Std. XII would
like to express my sincere thanks to my
computer teacher “Amit Sir” for assigning
me this project. I feel extremely lucky to
have been given a golden chance or
opportunity to work under such a highly
experienced teacher.

4. 3
Secondly I would also like to thank all my
family members without whose support it
was impossible for me to complete this
project.
Last but not least I would also like to thank
all my friends provided me some suggestion
in completing this project.
Thank You!
Q1.Enter name, age and salary and display it by using
outside the class member.
Q2. Program which gives the squares of all the odd
numbers stored in an array .
Q3.Program to store numbers in an array and allow user to
enter any number which he/she wants to find in array
.(Binary Search)
Q4.Program for copy constructor .
Q5.Enter numbers in an array in any order and it will give
the output of numbers in ascending order .

5. 4
Q6.Enter any numberfrom2 digit to 5 digitand the output
will be the sum ofall the distinguish digitsofthe numbers.
Q7.Enter rows and columns and the output will be the sum
of the diagonals .
Q8. Enter item no. , price and quantity in a class .
Q9.Enter any line or character in a file and press * to exit
the program .
Q10. Program will read the words which starts from
vowels stored in a file .
Q11. Enter employee no , name , age , salary and store it in
a file.

6. 5
Q12. Deleting the information of employee by entering the
employee number .
Q13. Enter any number and its power and the output will the
power of the number .
Q14. Enter 3 strings and the output will show the
longest string and the shortest string .
Q.15 Enter any number and the output will be all the
prime numbers up to that number .
Q16. Selection sort
Q17. Using loop concept the program will give the output
of numbers making a right triangle .
Q18. Program for Stacks and Queue .
Q.19Enter two arrays and the output will be the merge of
two arrays .
Q20. Sequence sort .
……………………………………………………………………

7. 6
Q1.Enter name , age and salary and display it by using
outside the class member .
#include<iostream.h>
#include<conio.h>
class abc
{
//private:
char n[20];
int a;
float sal;
public:
void getdata(void)
{
cout<<"nEnter name ";
cin>>n;
cout<<"nEnter age ";
cin>>a;
cout<<"nEnter salary ";
cin>>sal;
}
void putdata(void)
{
cout<<"nnNAME IS "<<n;
cout<<"nAGE IS "<<a;
cout<<"nSALARY IS "<<sal;
}
};
main()
{
abc p;
clrscr();
p.getdata();
p.putdata();
getch();
}

8. 7
Q2. Program which gives the squares of all the odd
numbers stored in an array .
#include<iostream.h>
#include<conio.h>
main()
{
int a[20],i,x;
clrscr();
cout<<"nEnter no of elements ";
cin>>x;
for(i=0;i<x;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nnArr1: ";
for(i=0;i<x;i++)
cout<<" "<<a[i];
cout<<"nnArr1: ";
for(i=0;i<x;i++)
{
if(a[i]%2==1)
a[i]=a[i]*a[i];
cout<<" "<<a[i];
}
getch();
}

9. 8
Q3.Program to store numbers in an array and allow user to
enter any number which he/she wants to find in array
.(Binary Search)
#include<iostream.h>
#include<conio.h>
main()
{
int a[20],n,i,no,low=0,high,mid,f=0;
clrscr();
cout<<"nEnter no of elements ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
cout<<"nEnter no to be search ";
cin>>no;
high=n-1;
while(low<=high && f==0)
{
mid=(low+high)/2;
if(a[mid]==no)
{
cout<<"nn"<<no<<" store at "<<mid+1;
f=1;
break;
}
else if(no>a[mid])
low=mid+1;
else
high=mid-1;
}
if(f==0)
cout<<"nn"<<no<<" does not exist";
getch();
}

10. 9
Q4.Program for copy constructor.
#include<iostream.h>
#include<conio.h>
#include<string.h>
class data
{
char n[20];
int age;
float sal;
public:
data(){}
data(char x[],int a,float k)
{
strcpy(n,x);
age=a;
sal=k;
}
data(data &p)
{
strcpy(n,p.n);
age=p.age;//+20;
sal=p.sal;//+1000;
}
display()
{
cout<<"nnNAME : "<<n;
cout<<"nnAGE : "<<age;
cout<<"nnSalary: "<<sal;
}
};
main()
{
clrscr();
data d("ajay",44,5000); //implicit caling
data d2=d;
data d3;
d3=d2;
d1.display();
d2.display();d3.display();
getch();
}

11. 10
Q5.Enter numbers in an array in any order and it will give the
output of numbers in ascending order .(Bubble Sort)
#include<iostream.h>
#include<conio.h>
void main()
{
int a[20],n,i,j,t;
clrscr();
cout<<"nEnter no of elements in A ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
for(i=0;i<n;i++)
for(j=0;j<n-i-1;j++)
if(a[j]>a[j+1])
{
t=a[j];
a[j]=a[j+1];
a[j+1]=t;
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
getch();
}

12. 11
Q6.Enter any numberfrom2 digit to 5 digitand the output
will be the sum ofall the distinguish digitsofthe numbers.
#include<iostream.h>
#include<conio.h>
void main()
{
int a=0,b=0,c;
clrscr();
cout<<"nEnter value for A ";
cin>>a;
while(a>0) // for(;a>0;) or for(i=a;i>0;i=i/10)
{
c=a%10;
b=b+c;
a=a/10;
}
cout<<"nSum of digits "<<b;
getch();
}

13. 12
Q7.Enter rows and columns and the output will be the sum
of the diagonals .
int a[10][10],i,j,r,c;
clrscr();
cout<<"nEnter no of rows ";
cin>>r;
cout<<"nEnter no of Col ";
cin>>c;
for(i=0;i<r;i++)
for(j=0;j<c;j++)
{
cout<<"nEnter no ";
cin>>a[i][j];
}
int sum=0,sum1=0;
for(i=0;i<r;i++)
{
cout<<"n";
for(j=0;j<c;j++)
{
cout<<" "<<a[i][j];
/// if(i==j) //&& a[i][j]>0)
// cout<<a[i][j];
// else
// cout<<" ";
//sum=sum+a[i][j];
/* if(i+j==r-1)// && a[i][j]>0)
cout<<a[i][j];
else
cout<<" "; */
if(i==j)
sum1=sum1+a[i][j];
}
}
for(i=0;i<r;i++)
{
cout<<"n";
for(j=0;j<c;j++)
{
// cout<<" "<<a[i][j];
/* if(i==j) //&& a[i][j]>0)
cout<<a[i][j];
else
cout<<" ";*/
//sum=sum+a[i][j];

14. 13
// if(i+j==r-1)// && a[i][j]>0)
// cout<<a[i][j];
// else
// cout<<" ";
sum=sum+a[i][j];
}
}
cout<<"nnFirst diagonal sum "<<sum1;
cout<<"nnSecond diagonal sum "<<sum;
getch();
}

15. 14
Q8. Enteritemno., price and quantity in a class .
#include<iostream.h>
#include<conio.h>
class dd
{
char item[20];
int pr,qty;
public:
void getdata();
void putdata();
};
void dd::getdata()
{
cout<<"nEnter item name ";
cin>>item;
cout<<"nEnter price ";
cin>>pr;
cout<<"nEnter quantity ";
cin>>qty;
}
void dd::putdata()
{
cout<<"nnItem name:"<<item;
cout<<"nnPrice: "<<pr;
cout<<"nnQty:"<<qty;
}
main()
{
dd a1,o1,k1;
clrscr();
a1.getdata();
o1.getdata();
k1.getdata();
a1.putdata();
o1.putdata();
k1.putdata();
getch();
}

16. 15
Q9.Enter any line or character in a file and press * to exit
the program .
#include<iostream.h>
#include<fstream.h>
#include<conio.h>
main()
{
char ch;
clrscr();
ofstream f1("emp"); //implicit
//ofstream f1;
//f1.open("emp",ios::out); //explicit
cout<<"nEnter char ";
while(1) //infinity
{
ch=getche(); // to input a single
charactor by keybord.
if(ch=='*')
break;
if(ch==13)
{
cout<<"n";
f1<<'n';
}
f1<<ch;
}
f1.close();
//getch();
}

17. 16
Q10. Program will read the words which starts from vowels
stored in a file .
#include<iostream.h>
#include<fstream.h>
#include<conio.h>
main()
{
char ch[80];
int cnt=0;
clrscr();
ifstream f1("emp");
ofstream f2("temp");
while(!f1.eof())
{
f1>>ch;
cout<<ch<<"n";
if(ch[0]=='a' || ch[0]=='e' || ch[0]=='o' || ch[0]=='i' || ch[0]=='u')
f2<<"n"<<ch;
}
f1.close();
f2.close();
cout<<"nnName start with vowels nn";
f1.open("temp",ios::in);
while(f1) //while(!f1.eof())
{
f1>>ch;
cout<<"n"<<ch;
if(f1.eof())
break;
}
f1.close();
getch();
}

18. 17
Q11. Enter employee no , name , age , salary and store it in
a file.
#include<iostream.h>
#include<conio.h>
#include<fstream.h>
int row=5,col=2;
class abc
{
private:
int empno;
char n[20];
int age;
float sal;
public:
void getdata()
{
char ch;
cin.get(ch); // To empty buffer
cout<<"nEnter employee no ";
cin>>empno;
cout<<"nEnter name ";
cin>>n;
cout<<"nEnter age ";
cin>>age;
cout<<"nEnter salary ";
cin>>sal;
}
void putdata()
{
// gotoxy(col,row);
cout<<"n"<<empno;
// gotoxy(col+10,row);
cout<<"t"<<n;
// gotoxy(col+25,row);
cout<<"t"<<age;
// gotoxy(col+35,row);
cout<<"t"<<sal;
// row++;
}
};
main()
{
clrscr();

19. 18
abc p,p1;
fstream f1("emp5.txt",ios::in|ios::out|ios::binary);
int i;
for(i=0;i<3;i++)
{
p.getdata();
f1.write((char *)&p,sizeof(p));
}
cout<<"nnEMPNOtNAMEtAGEtSALARYn";
f1.seekg(0);
//f1.clear();
//clrscr();
for(i=0;i<3;i++)
{
f1.read((char*)&p1,sizeof(p1));
p1.putdata();
}
f1.close();
getch();
}

20. 19
Q12. Deleting the information of employee by entering the
employee number .
#include<iostream.h>
#include<conio.h>
#include<fstream.h>
#include<stdio.h>
class abc
{
private:
int empno;
char n[20];
int age;
float sal;
public:
void getdata()
{
cout<<"nEnter employee no ";
cin>>empno;
cout<<"nEnter name ";
cin>>n;
cout<<"nEnter age ";
cin>>age;
cout<<"nEnter salary ";
cin>>sal;
}
void putdata()
{
cout<<"nn"<<empno<<"t"<<n<<"t"<<age<<"t"<<sal;
}
int get_empno()
{
return empno;
}
};
main()
{
abc p,p1;
clrscr();
ifstream f1("emp5.txt",ios::in|ios::binary);
ofstream f2("temp",ios::out|ios::binary);
int i,emp;
cout<<"nnNAMEtAGEtSALARY";

21. 20
f1.clear();
f1.seekg(0);
//for(i=0;i<4;i++)
while(!f1.eof())
{
f1.read((char*)&p1,sizeof(p1));
if(f1.eof())
break;
p1.putdata();
}
cout<<"nEnter employee no ";
cin>>emp;
f1.clear();
f1.seekg(0);
//while(f1)
while(!f1.eof())
{
f1.read((char*)&p1,sizeof(p1));
if(f1.eof())
break;
if(emp!=p1.get_empno())
f2.write((char*)&p1,sizeof(p1));
}
f1.close();
f2.close();
remove("emp5.txt");
rename("temp","emp5.txt");
f1.open("emp5.txt",ios::in|ios::binary);
cout<<"nnNAMEtAGEtSALARY";
f1.seekg(0);
//for(i=0;i<3;i++)
while(!f1.eof())
{
f1.read((char*)&p1,sizeof(p1));
if(f1.eof())
break;
p1.putdata();
}
f1.close();
getch();
}

22. 21
Q13. Enter any number and its power and the output will the
power of the number .
#include<iostream.h>
#include<conio.h>
#include<math.h>
#define CUBE(a,b) pow(a,b)
//a>b?a:b
main()
{
int x,y,z;
clrscr();
cout<<"nEnter base value ";
cin>>x;
cout<<"nEnter power ";
cin>>y;
z=CUBE(x,y);
cout<<"n"<<z;
getch();
}

23. 22
Q14. Enter 3 strings and the output will show the
longest string and the shortest string .
#include<iostream.h>
#include<conio.h>
#include<string.h>
main()
{
char n[20],n1[20],n2[20];
int l1,l2,l3;
clrscr();
cout<<"nEnter String1 ";
cin>>n;
cout<<"nEnter String2 ";
cin>>n1;
cout<<"nEnter String3 ";
cin>>n2;
l1=strlen(n);
l2=strlen(n1);
l3=strlen(n2);
(l1>l2 && l1>l3) ?cout<<"nLong: "<<n:(l2>l1 && l2>l3) ? cout<<"nLong: "<<n1
:cout<<"nLong: "<<n2;
(l1<l2 && l1<l3)?cout<<"nshort:"<<n:(l2<l1 && l2<l3)?
cout<<"nshort:"<<n1:cout<<"nshort:"<<n2;
getch();
}

24. 23
Q.15 Enter any number and the output will be all the
prime numbers up to that number .
#include<iostream.h>
#include<conio.h>
main()
{
int n,i,j,p;
clrscr();
cout<<"nEnter no of N ";
cin>>n;
for(i=1;i<=n;i++)
{
p=0;
for(j=2;j<=i/2;j++)
if(i%j==0)
p=1;
if(p==0)
cout<<" "<<i;
}
getch();
}

25. 24
Q16. Selection sort
#include<iostream.h>
#include<conio.h>
void main()
{
int a[20],n,i,j,t,min,p;
clrscr();
cout<<"nEnter no of elements in A ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
for(i=0;i<n;i++)
{
min=a[i];
p=i;
for(j=i;j<n;j++)
{
if(a[j]<min)
{
min=a[j];
p=j;
}
}
t=a[i];
a[i]=a[p];
a[p]=t;
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
getch();
}

26. 25
Q17. Using loop concept the program will give the output
of numbers making a right triangle .
#include<iostream.h>
#include<conio.h>
main()
{
int i,j;
clrscr();
for(i=1;i<=4;i++)
{
cout<<"nn";
for(j=1;j<=i;j++)
cout<<" "<<i;
}
getch();
}

27. 26
Q18. Program for Stacks and Queue .
#include<iostream.h>
#include<conio.h>
#include<stdlib.h>
struct queue
{
int x;
queue *next;
}*front=NULL,*rear;
void insert(int);
void delnode();
void display();
void main()
{
int a,ch;
clrscr();
do
{
cout<<"nEnter 1 for Insert";
cout<<"nEnter 2 for Delete";
cout<<"nEnter 3 for display";
cout<<"nEnter 4 for exit";
cout<<"nnEnter your choice ";
cin>>ch;
switch(ch)
{
case 1: cout<<"nEnter no for insert ";
cin>>a;
insert(a);
break;
case 2: delnode();
break;
case 3: display();
break;
case 4: exit(0);
}
}
while(1);
getch();
}
void insert(int no) // char str[]
{
queue *ptr;
ptr=new queue; // strcpy(ptr->n,str)

28. 27
// ptr=(struct queue*)malloc(sizeof(struct
queue)); ptr->x=no;
ptr->next=NULL;
if(front==NULL)
{
front=ptr;
rear=ptr;
}
else
{
rear->next=ptr;
rear=ptr;
}
}
void delnode()
{
int p;
queue *ptr;
if(front==NULL)
{
cout<<"nnQueue is Empty";
return;
}
p=front->x; //strcpy(p,front->n)
ptr=front;
front=front->next;
delete ptr;
cout<<"nndeleted element "<<p<<"n";
}
void display()
{
queue *ptr;
cout<<"nQueue now:- n";
for(ptr=front;ptr!=NULL;ptr=ptr->next)
cout<<" "<<ptr->x;
}

29. 28
Q.19Enter two arrays and the output will be the merge of
two arrays .
# include <iostream.h>
# include <conio.h>
main()
{
int arr1[100],arr2[100],arr3[100],c,i=0,j=0,k=0,size1,size2;
clrscr();
cout<<"n enter no of element of arr1 ";
cin>>size1;
for (i=0;i<size1;i++)
{
cout<<"n enter no. ";
cin>>arr1[i];
}
cout<<"n enter no of element of arr2 ";
cin>>size2;
for (i=0;i<size2;i++)
{
cout<<"n enter no. ";
cin>>arr2[i];
}
cout<<"n arr1 "; for
(i=0;i<size1;i++)
cout<<" "<<arr1[i];
cout<<"n arr2 ";
for (i=0;i<size2;i++)
cout<<" "<<arr2[i];
i=0;j=0;k=0;
while (i<size1 && j<size2)
{
if (arr1[i]<arr2[j])
arr3[k++]=arr1[i++];
else if (arr2[j]<arr1[i])
arr3[k++]=arr2[j++];
else
i++;
}
while (i<size1)
arr3[k++]=arr1[i++];
while (j<size2)

30. 29
arr3[k++]=arr2[j++];
cout<<"n arr3 ";
for (i=0;i<k;i++)
cout<<" "<<arr3[i];
getch();
}

31. 30
Q20.Sequence Sort(Insertion Sort)
#include<iostream.h>
#include<conio.h>
{
int a[20],n,i,j,t;
clrscr();
cout<<"nEnter no of elements in A ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
for(i=0;i<n;i++)
for(j=i+1;j<n;j++)
if(a[i]>a[j])
{
t=a[i];
a[i]=a[j];
a[j]=t;
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
getch();
}
……………………………………………………

32. 31
Books
1.Sumita Arora
2.Arihant Solved Q/A
3.Togetherwith learning with C++

33. 32