Answer Key
Testname: CH099A EX FINAL WINTER 2013 REVIEW
         -tffffii,                                ffi tbxfflbt *,}{$
  1                                  uzlnr{                                                        = s,+3 KsoJ {anf
  2. a) dinitrogen        tetroxide   v
    b) silver sulfate
    c) hydrogen iodide
    d) calcium bromide
    e) sulfurous          acid                                                                                                         fJr,r-t b"r r + gC r r{"f " * j _
                              b)   HsPog c)HBr
  i llfi^[?                                          ,';,3t1    g   o?,Vl7ty,'           s+, tsA
                                                                                     --4,'v;:
                                                                                                         u!. +1&t        .,n 3.[3ii,i*iy'*r, is* *"

    l*:;"toztz                                   /L*i,qtc - #j,;1,:                                          i,,, ,, **xft;fi;-'.=*'f,*'"'
                                                  4'L 3 H ' +i '''                 **    u':iq';:,
                                                                                                                                                   i
    3fi?:,
     H2Se(g)
    f)
                                                              ,            , '' 'T,t                                                                        'lus^ 4=1r

                                                            #'1,,* z !.1tw,ra }
  5F                 -l                            su'{srua                                                                                           ^6-.g
  u-ur-it.,,lffi]=5.55molesC(carcandcorr)                       I                             ?-   4    vl           I
                                                                                                             =
                                                                                                                                 Y7.'.,,':';'r"'i&'F'pu
                                                                                                                             ,6::'cl,l; %
    1.1.2   sH.l#H] = 11.08e10e mores H (carc) =                 11.1 mores   H   (corr)                                     b;;";,"i';,T' '*for
                                                                                                                 'k          /   ntt r{'r
         22.2   so.                 =L3srsmoles o (carc) = l   3e moles   o   (corr)                                     '                            ,iL -':;-"
                      lffi]
                                                                                                                 *f L*, t,rr.r..luop
                                                                                                                                                       /i



    .,#=3.9928058(calc)=3.99(corr)                                                                                    orrr;,:;;
                                                                                                                         * iee $"i.r t-s) ..{.s I.} gl*
                  =7'98c611'5(calc) = 7'e9 (corr)
    "' +#
                                                                       .el
    ot
          ffi=        1   (calc)= 1'oo (corr)                         t)                                                                cq) tR
                                                                              'Lr* fuuor,^o'o ''u'+ai)
    :ffi[:lilX;;ftlt?'.r+8(1.0)                       +1,(15.a)=72.0      ') Nt*+'ottnL), ur'ohr-
                                                                          t2"" - (uia                                            ^u?or,*r{ftr7,
     Molecular        mass '44                                                a1   'J                       - ']ri { 7,a *-"
                                                                                                             r   :

       F"r*"I""r"* =m=z]lu                                                                                                   - '*
                                                                                                                                                            .-rF."
                                                                          i... 7!.t r(_oi_   r e.$,g,ar,.r, ,1,                r,
                                                                                                                 , ,.._ ,
     Molecular forrnula =      Lm.frCgH16O?                                         .t t.<* t r',in      .7 1 ", a# L,
                                                                                                3 .- t16'+1 ;"
                                                                                                                  ""      !;
                                                                                                                          r, ,t    '
                                                                                                                                                       ,.     ,. ,_,. i",
  T. rt,40Kt9- t-lo^ -tV QCISX 7.                ' ';;'i?*''"urryffitu            t4s]:-&7                           "{
  t
  g.     t'iL * lnt +ir,in.
                  'L                   '''",          7rAr, * g t,C ":./                      tLrt""ii..
                                                                                                        :.1{'
                                                                                    ,
 if;n*pu?if_lrig#v
                                                                                   {')   ,    ?,, .
                                                                                                        ,        --s,..._..:, --,y ,,-".
                                                                                                                                             ,,..3,,-',."''
 12.4179                                                                                                                                  l* --* 7 ''
 13. "C = K     - 273= 198 -       nn. o.o-
                                   273 = -75"C
                                                                                                   -l                                         I   ?
  r4.9L
                                                                    13 oI12
                                                                                                                                              lu
wr^tt?OnP
                             Y-liunbt'V) ?t'E
                                         $n'of
                                Yt1a@
r*ffW'                          r'l-r.sQQ'Q   r o-' o'b
         u=   o),X, "tU;+
                   hwnno/b'''1
          y*nv*A                   ,=   Q: LQ'L)1':o
                                              9x3rq1 '{
                                   n,ot Q'?'- ttrh V
                           41Yw'}             ol)
                                     o'L Lr ^d1't'{
                {rr-rY*A
                                         (n
                                                      (t,0b
     ft,q,rLr--*ru-;Y,w               16 tW
                 YVW   1
                 W
                                                              o1+
Answer Key
Testname: CH099A EX FINAL WINTER 2013 REVIEW


                                         6oog
 15.    Volume: -Iutt -                             -     =74.7 cm3
               densrtv              8.03 g/cm3
 16. Theoretical yield:



                    .                    .                           .                   = Bs sz86zz4 (ca,c)
                        f#ffi] [T*#]
        40 0 g N2
                                                                         [fr#f#+".'u]
                            =140 gNaCN (corr)

        Percent yield:


                             x 100 = 17.8571428o/o(calc): 17.9"11(con)
        tr##
 17.    Determination of limiting reactant:


        1o.o g H2s      -
                            I I mole HrS     I     [2 moles HrOl
                                                            Hrs j
                            fAre;f{ mole H2O(calc)
                                      Lz*"r",
                                                 ^
                            = C.58685446                             = 6.597 mole H2O (corr)

              l1 r,rcie Or I [2                   moles    HrOl
        aoogo2.l3a00g6tj"l3*"l.'aj
                            = 0.83333333 mole H2O (calc) = 0.833 mole H2O (corr)

        H2S is the lirniting reactant.

                                 18.02 e     HrO
        0.587 mole HZO x
                                 1;ffi                  - 10.57774   g SH2O (catc) = 10.6 g H2O (corr)

   1.C
  2,D
  3.C
  4.8
  5.D
  5.8
  7.D
  8.A
  9.8
 10. B
 11. C
 12. A
 13.    A
 14. B
 15. D
 16. A
  17.   A
 18. E
 19. C
 20. A
 21,.8
                                                                              74 of 72
Answer Key
Testname: CH099A EX FINAL WINTER 201: REVIEW


 22. B
 23. A
 24. C
 25. C
 26. B
 27. C
 28. A
 29.   A
 30.   c
 31.   B
 32.   C
 33.   D
 34.   D
 35.   B
  1. A scientific lar,^,'is different from a theory in that ihe law onlv describes a natural phenomenon; it does not attempt to
     explain the phenornenon. A theory is an attempt at explanation.
  2. The examples snould follow this rule: Matter has rrass and volume; nonmatter has no mass or volume. Examples of
     matter are: air, 'water, metal, rock, solutions. Exa:nples of nonmatter are: energy, vacuum, force, magnetic or electric or
       gravitational fields.
  3. A substance is a particular kind of matter that has a tmiform and definite composition. A diamond is a substance.
  4. No. Changes ir, tire physical properties of a substance do not affect the chemical properties of the substance.
  5. A solution is a type of mixture, namely a mixture ihat has a uniform composition. A mixture can have a nonuniform
     composition, brit .r solution cannot. AII solutions are mixtures, but not all mixtures are solutions. Salt water (brine) is a
     solution; sand in lvater is a mixture.
  6. The examples sl'rould follow this rule: A homogeneous mixture is uniform in compositiory whereas a heterogeneous
     mixture is not. An example of a homogeneous rr,irture is air; an example of a heterogeneous mixture is soup.
  7. An element cannot be broken dolr.'n into simpler .omponents in chemical reactions. Compounds are substances that
     can be broken dcrrrn into simpler substances in chemical reactions.
  8. Physical changes Co not aiter the composition of ; substance, but chemical changes do. A/hen water is boiled the
     resulting gas is still made up of water molecules;ust like those in the liquid. However, when water molecules are
     broken down intc elemental hydrogen and oxygt.n in a chemical reaction, the water rnolecules no longer exist. The
     latter is a chemical change; the former a physical :hange.
  9. The law of conservation of mass states that in anr ;ohysical or chemical reaction" mass is neither created nor destroyed.
     According to this iar'r., the total mass the product- in the reaction referred to here rvould be 10 grams, namely the same
     mass as that of the reactants.
 10. The answer of an addition or subtraction can have no more digits to the right of the decimal point than are contained in
     tire measurement with the least number of digits to the right of the decimal point. The answer of a multiplication or
     division can have no more significant figures thai-r the measurement having the least number of significant figures. For
     these two opera.tions, the position of the decimal ncint has nothing to do with the number of significant figures.




                                                            15 of 12

Ch099 a ex final winter 2013 review key

  • 1.
    Answer Key Testname: CH099AEX FINAL WINTER 2013 REVIEW -tffffii, ffi tbxfflbt *,}{$ 1 uzlnr{ = s,+3 KsoJ {anf 2. a) dinitrogen tetroxide v b) silver sulfate c) hydrogen iodide d) calcium bromide e) sulfurous acid fJr,r-t b"r r + gC r r{"f " * j _ b) HsPog c)HBr i llfi^[? ,';,3t1 g o?,Vl7ty,' s+, tsA --4,'v;: u!. +1&t .,n 3.[3ii,i*iy'*r, is* *" l*:;"toztz /L*i,qtc - #j,;1,: i,,, ,, **xft;fi;-'.=*'f,*'"' 4'L 3 H ' +i ''' ** u':iq';:, i 3fi?:, H2Se(g) f) , , '' 'T,t 'lus^ 4=1r #'1,,* z !.1tw,ra } 5F -l su'{srua ^6-.g u-ur-it.,,lffi]=5.55molesC(carcandcorr) I ?- 4 vl I = Y7.'.,,':';'r"'i&'F'pu ,6::'cl,l; % 1.1.2 sH.l#H] = 11.08e10e mores H (carc) = 11.1 mores H (corr) b;;";,"i';,T' '*for 'k / ntt r{'r 22.2 so. =L3srsmoles o (carc) = l 3e moles o (corr) ' ,iL -':;-" lffi] *f L*, t,rr.r..luop /i .,#=3.9928058(calc)=3.99(corr) orrr;,:;; * iee $"i.r t-s) ..{.s I.} gl* =7'98c611'5(calc) = 7'e9 (corr) "' +# .el ot ffi= 1 (calc)= 1'oo (corr) t) cq) tR 'Lr* fuuor,^o'o ''u'+ai) :ffi[:lilX;;ftlt?'.r+8(1.0) +1,(15.a)=72.0 ') Nt*+'ottnL), ur'ohr- t2"" - (uia ^u?or,*r{ftr7, Molecular mass '44 a1 'J - ']ri { 7,a *-" r : F"r*"I""r"* =m=z]lu - '* .-rF." i... 7!.t r(_oi_ r e.$,g,ar,.r, ,1, r, , ,.._ , Molecular forrnula = Lm.frCgH16O? .t t.<* t r',in .7 1 ", a# L, 3 .- t16'+1 ;" "" !; r, ,t ' ,. ,. ,_,. i", T. rt,40Kt9- t-lo^ -tV QCISX 7. ' ';;'i?*''"urryffitu t4s]:-&7 "{ t g. t'iL * lnt +ir,in. 'L '''", 7rAr, * g t,C ":./ tLrt""ii.. :.1{' , if;n*pu?if_lrig#v {') , ?,, . , --s,..._..:, --,y ,,-". ,,..3,,-',."'' 12.4179 l* --* 7 '' 13. "C = K - 273= 198 - nn. o.o- 273 = -75"C -l I ? r4.9L 13 oI12 lu
  • 2.
    wr^tt?OnP Y-liunbt'V) ?t'E $n'of Yt1a@ r*ffW' r'l-r.sQQ'Q r o-' o'b u= o),X, "tU;+ hwnno/b'''1 y*nv*A ,= Q: LQ'L)1':o 9x3rq1 '{ n,ot Q'?'- ttrh V 41Yw'} ol) o'L Lr ^d1't'{ {rr-rY*A (n (t,0b ft,q,rLr--*ru-;Y,w 16 tW YVW 1 W o1+
  • 3.
    Answer Key Testname: CH099AEX FINAL WINTER 2013 REVIEW 6oog 15. Volume: -Iutt - - =74.7 cm3 densrtv 8.03 g/cm3 16. Theoretical yield: . . . = Bs sz86zz4 (ca,c) f#ffi] [T*#] 40 0 g N2 [fr#f#+".'u] =140 gNaCN (corr) Percent yield: x 100 = 17.8571428o/o(calc): 17.9"11(con) tr## 17. Determination of limiting reactant: 1o.o g H2s - I I mole HrS I [2 moles HrOl Hrs j fAre;f{ mole H2O(calc) Lz*"r", ^ = C.58685446 = 6.597 mole H2O (corr) l1 r,rcie Or I [2 moles HrOl aoogo2.l3a00g6tj"l3*"l.'aj = 0.83333333 mole H2O (calc) = 0.833 mole H2O (corr) H2S is the lirniting reactant. 18.02 e HrO 0.587 mole HZO x 1;ffi - 10.57774 g SH2O (catc) = 10.6 g H2O (corr) 1.C 2,D 3.C 4.8 5.D 5.8 7.D 8.A 9.8 10. B 11. C 12. A 13. A 14. B 15. D 16. A 17. A 18. E 19. C 20. A 21,.8 74 of 72
  • 4.
    Answer Key Testname: CH099AEX FINAL WINTER 201: REVIEW 22. B 23. A 24. C 25. C 26. B 27. C 28. A 29. A 30. c 31. B 32. C 33. D 34. D 35. B 1. A scientific lar,^,'is different from a theory in that ihe law onlv describes a natural phenomenon; it does not attempt to explain the phenornenon. A theory is an attempt at explanation. 2. The examples snould follow this rule: Matter has rrass and volume; nonmatter has no mass or volume. Examples of matter are: air, 'water, metal, rock, solutions. Exa:nples of nonmatter are: energy, vacuum, force, magnetic or electric or gravitational fields. 3. A substance is a particular kind of matter that has a tmiform and definite composition. A diamond is a substance. 4. No. Changes ir, tire physical properties of a substance do not affect the chemical properties of the substance. 5. A solution is a type of mixture, namely a mixture ihat has a uniform composition. A mixture can have a nonuniform composition, brit .r solution cannot. AII solutions are mixtures, but not all mixtures are solutions. Salt water (brine) is a solution; sand in lvater is a mixture. 6. The examples sl'rould follow this rule: A homogeneous mixture is uniform in compositiory whereas a heterogeneous mixture is not. An example of a homogeneous rr,irture is air; an example of a heterogeneous mixture is soup. 7. An element cannot be broken dolr.'n into simpler .omponents in chemical reactions. Compounds are substances that can be broken dcrrrn into simpler substances in chemical reactions. 8. Physical changes Co not aiter the composition of ; substance, but chemical changes do. A/hen water is boiled the resulting gas is still made up of water molecules;ust like those in the liquid. However, when water molecules are broken down intc elemental hydrogen and oxygt.n in a chemical reaction, the water rnolecules no longer exist. The latter is a chemical change; the former a physical :hange. 9. The law of conservation of mass states that in anr ;ohysical or chemical reaction" mass is neither created nor destroyed. According to this iar'r., the total mass the product- in the reaction referred to here rvould be 10 grams, namely the same mass as that of the reactants. 10. The answer of an addition or subtraction can have no more digits to the right of the decimal point than are contained in tire measurement with the least number of digits to the right of the decimal point. The answer of a multiplication or division can have no more significant figures thai-r the measurement having the least number of significant figures. For these two opera.tions, the position of the decimal ncint has nothing to do with the number of significant figures. 15 of 12