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Genotype x Environment
Interactions
Analyses of Multiple Location Trials
Why do researchers conduct
multiple experiments?
Effects of factors under study vary from
location to location or from year to year.
To obtain an unbias estimate.
Interest in determining the effect of
factors over time.
To investigate genotype (or treatment) x
environment interactions.
What are Genotype x
Environment Interactions?
Differential response of genotypes to
varying environmental conditions.
Delight for statisticians who love to
investigate them.
The biggest nightmare for plant
breeders (and some other agricultural
researchers) who try to avoid them like
the plague.
What causes Genotype x
Environment interactions?
B
A
Yield
Locations
No interaction
B
A
Yield
Locations
B
A
Yield
Locations
No interaction
Cross-over
interaction
B
A
Yield
Locations
B
A
Yield
Locations
B
A
Yield
Locations
No interaction
Scalar interaction
Cross-over
interaction
Examples of Multiple Experiments
Plant breeder grows advanced breeding
selections at multiple locations to determine
those with general or specific adaptability
ability.
A pathologist is interested in tracking the
development of disease in a crop and records
disease at different time intervals.
Forage agronomist is interested in forage
harvest at different stages of development
over time.
Types of Environment
Researcher controlled environments,
where the researcher manipulates the
environment. For example, variable
nitrogen.
Semi-controlled environments, where
there is an opportunity to predict
conditions from year to year. For
example, soil type.
Uncontrolled environments, where there
is little chance of predicting environment.
Why?
• To investigate relationships between
genotypes and different environmental
(and other) changes.
• To identify genotypes which perform well
over a wide range of environments.
General adaptability.
• To identify genotypes which perform well
in particular environments. Specific
adaptability.
How many environments do I need?
Where should
they be?
Number of Environments
Availability of planting material.
Diversity of environmental conditions.
Magnitude of error variances and
genetic variances in any one year or
location.
Availability of suitable cooperators
Cost of each trial ($’s and time).
Location of Environments
 Variability of environment
throughout the target region.
Proximity to research base.
 Availability of good cooperators.
 $$$’s.
Analyses of Multiple
Experiments
Points to Consider before Analyses
Normality.
Homoscalestisity
(homogeneity) of error
variance.
Additive.
Randomness.
Points to Consider before Analyses
Normality.
Homoscalestisity
(homogeneity) of error
variance.
Additive.
Randomness.
Bartlett Test
(same degrees of freedom)
M = df{nLn(S) - Ln2}
Where, S = 2/n
2
n-1 = M/C
C = 1 + (n+1)/3ndf
n = number of variances, df is the df
of each variance
Bartlett Test
(same degrees of freedom)
df 2
Ln(2
)
5 178 5.148
5 60 4.094
5 98 4.585
5 68 4.202
Total 404 18.081
S = 101.0; Ln(S) = 4.614
Bartlett Test
(same degrees of freedom)
df 2
Ln(2
)
5 178 5.148
5 60 4.094
5 98 4.585
5 68 4.202
Total 404 18.081
S = 100.0; Ln(S) = 4.614
M = (5)[(4)(4.614)-18.081] = 1.880, 3df
C = 1 + (5)/[(3)(4)(5)] = 1.083
Bartlett Test
(same degrees of freedom)
df 2
Ln(2
)
5 178 5.148
5 60 4.094
5 98 4.585
5 68 4.202
Total 404 18.081
S = 100.0; Ln(S) = 4.614
M = (5)[(4)(4.614)-18.081] = 1.880, 3df
C = 1 + (5)/[(3)(4)(5)] = 1.083
2
3df = 1.880/1.083 = 1.74 ns
Bartlett Test
(different degrees of freedom)
M = ( df)nLn(S) - dfLn2
Where, S = [df.2]/(df)
2
n-1 = M/C
C = 1+{(1)/[3(n-1)]}.[(1/df)-1/ (df)]
n = number of variances
Bartlett Test
(different degrees of freedom)
df 2
Ln(2
) 1/df
9 0.909 -0.095 0.111
7 0.497 -0.699 0.1429
9 0.076 -2.577 0.1111
7
5
0.103
0.146
-2.273
-1.942
0.1429
0.2000
37 0.7080
S = [df.2]/(df) = 13.79/37 = 0.3727
(df)Ln(S) = (37)(-0.9870) = -36.519
Bartlett Test
(different degrees of freedom)
df 2
Ln(2
) 1/df
9 0.909 -0.095 0.111
7 0.497 -0.699 0.1429
9 0.076 -2.577 0.1111
7
5
0.103
0.146
-2.273
-1.942
0.1429
0.2000
37 0.7080
M = (df)Ln(S) - dfLn 2 = -36.519 -(54.472) = 17.96
C = 1+[1/(3)(4)](0.7080 - 0.0270) = 1.057
Bartlett Test
(different degrees of freedom)
S = [df.2]/(df) = 13.79/37 = 0.3727
(df)Ln(S) = (37)(=0.9870) = -36.519
M = (df)Ln(S) - dfLn 2 = -36.519 -(54.472) = 17.96
C = 1+[1/(3)(4)](0.7080 - 0.0270) = 1.057
2
3df = 17.96/1.057 = 16.99 **, 3df
Heterogeneity of Error Variance
0
10
20
30
40
50
60
70
80
Mosc Gene Tens Gran Pend Colf Kalt Mocc Boze
Seed
Yield
Significant Bartlett Test
“What can I do where there is
significant heterogeneity of error
variances?”
Transform the raw data:
Often  ~ 
cw Binomial Distribution
where  = np and  = npq
Transform to square roots
Heterogeneity of Error Variance
0
2
4
6
8
10
Mosc Gene Tens Gran Pend Colf Kalt Mocc Boze
SQRT[Seed
Yield]
Significant Bartlett Test
“What else can I do where there is
significant heterogeneity of error
variances?”
Transform the raw data:
Homogeneity of error variance can always
be achieved by transforming each site’s data
to the Standardized Normal Distribution
[xi-]/
Significant Bartlett Test
“What can I do where there is
significant heterogeneity of error
variances?”
Transform the raw data
Use non-parametric statistics
Analyses of Variance
Model ~ Multiple sites
Yijk =  + gi + ej + geij + Eijk
i gi = j ej = ij geij
Environments and Replicate blocks are usually
considered to be Random effects. Genotypes are
usually considered to be Fixed effects.
Analysis of Variance over sites
Source d.f. EMSq
Sites (s)
Rep w Sites (r)
Genotypes (g)
Geno x Site
Replicate error
Source d.f. EMSq
Sites (s) s-1
Rep w Sites (r) s(1-r)
Genotypes (g) g-1
Geno x Site (g-1)(s-1)
Replicate error s(r-1)(g-1)
Analysis of Variance over sites
Source d.f. EMSq
Sites (s) s-1 2
e + g2
rws + rg2
s
Rep w Sites (r) s(1-r) 2
e + g2
rws
Genotypes (g) g-1 2
e + r2
gs+ rs2
g
Geno x Site (g-1)(s-1) 2
e + r2
gs
Replicate error s(r-1)(g-1) 2
e
Analysis of Variance over sites
Yijkl = +gi+sj+yk+gsij+gyik+syjk+gsyijk+Eijkl
igi=jsj=kyk= 0
ijgsij=ikgyik=jksyij = 0
ijkgsyijk = 0
Models ~ Years and sites
Analysis of Variance
Source d.f. EMSq
Years (y) y-1 2
e+gy2
rwswy+rg2
swy+rgs2
y
Sites w Years (s) y(s-1) 2
e + g2
rwswy + rg2
swy
Rep w Sites w year (r) ys(1-r) 2
e + g2
rwswy
Genotypes (g) g-1 2
e + r2
gswy + rs2
gy + rl2
g
Geno x year (y-1)(g-1) 2
e + r2
gswy + rs2
gy
Geno x Site w Year y(g-1)(s-1) 2
e + r2
gswy
Replicate error ys(r-1)(g-1) 2
e

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Biom-32-GxE I.ppt

  • 1. Genotype x Environment Interactions Analyses of Multiple Location Trials
  • 2. Why do researchers conduct multiple experiments? Effects of factors under study vary from location to location or from year to year. To obtain an unbias estimate. Interest in determining the effect of factors over time. To investigate genotype (or treatment) x environment interactions.
  • 3. What are Genotype x Environment Interactions? Differential response of genotypes to varying environmental conditions. Delight for statisticians who love to investigate them. The biggest nightmare for plant breeders (and some other agricultural researchers) who try to avoid them like the plague.
  • 4. What causes Genotype x Environment interactions?
  • 8. Examples of Multiple Experiments Plant breeder grows advanced breeding selections at multiple locations to determine those with general or specific adaptability ability. A pathologist is interested in tracking the development of disease in a crop and records disease at different time intervals. Forage agronomist is interested in forage harvest at different stages of development over time.
  • 9. Types of Environment Researcher controlled environments, where the researcher manipulates the environment. For example, variable nitrogen. Semi-controlled environments, where there is an opportunity to predict conditions from year to year. For example, soil type. Uncontrolled environments, where there is little chance of predicting environment.
  • 10. Why? • To investigate relationships between genotypes and different environmental (and other) changes. • To identify genotypes which perform well over a wide range of environments. General adaptability. • To identify genotypes which perform well in particular environments. Specific adaptability.
  • 11. How many environments do I need? Where should they be?
  • 12. Number of Environments Availability of planting material. Diversity of environmental conditions. Magnitude of error variances and genetic variances in any one year or location. Availability of suitable cooperators Cost of each trial ($’s and time).
  • 13. Location of Environments  Variability of environment throughout the target region. Proximity to research base.  Availability of good cooperators.  $$$’s.
  • 15. Points to Consider before Analyses Normality. Homoscalestisity (homogeneity) of error variance. Additive. Randomness.
  • 16. Points to Consider before Analyses Normality. Homoscalestisity (homogeneity) of error variance. Additive. Randomness.
  • 17. Bartlett Test (same degrees of freedom) M = df{nLn(S) - Ln2} Where, S = 2/n 2 n-1 = M/C C = 1 + (n+1)/3ndf n = number of variances, df is the df of each variance
  • 18. Bartlett Test (same degrees of freedom) df 2 Ln(2 ) 5 178 5.148 5 60 4.094 5 98 4.585 5 68 4.202 Total 404 18.081 S = 101.0; Ln(S) = 4.614
  • 19. Bartlett Test (same degrees of freedom) df 2 Ln(2 ) 5 178 5.148 5 60 4.094 5 98 4.585 5 68 4.202 Total 404 18.081 S = 100.0; Ln(S) = 4.614 M = (5)[(4)(4.614)-18.081] = 1.880, 3df C = 1 + (5)/[(3)(4)(5)] = 1.083
  • 20. Bartlett Test (same degrees of freedom) df 2 Ln(2 ) 5 178 5.148 5 60 4.094 5 98 4.585 5 68 4.202 Total 404 18.081 S = 100.0; Ln(S) = 4.614 M = (5)[(4)(4.614)-18.081] = 1.880, 3df C = 1 + (5)/[(3)(4)(5)] = 1.083 2 3df = 1.880/1.083 = 1.74 ns
  • 21. Bartlett Test (different degrees of freedom) M = ( df)nLn(S) - dfLn2 Where, S = [df.2]/(df) 2 n-1 = M/C C = 1+{(1)/[3(n-1)]}.[(1/df)-1/ (df)] n = number of variances
  • 22. Bartlett Test (different degrees of freedom) df 2 Ln(2 ) 1/df 9 0.909 -0.095 0.111 7 0.497 -0.699 0.1429 9 0.076 -2.577 0.1111 7 5 0.103 0.146 -2.273 -1.942 0.1429 0.2000 37 0.7080 S = [df.2]/(df) = 13.79/37 = 0.3727 (df)Ln(S) = (37)(-0.9870) = -36.519
  • 23. Bartlett Test (different degrees of freedom) df 2 Ln(2 ) 1/df 9 0.909 -0.095 0.111 7 0.497 -0.699 0.1429 9 0.076 -2.577 0.1111 7 5 0.103 0.146 -2.273 -1.942 0.1429 0.2000 37 0.7080 M = (df)Ln(S) - dfLn 2 = -36.519 -(54.472) = 17.96 C = 1+[1/(3)(4)](0.7080 - 0.0270) = 1.057
  • 24. Bartlett Test (different degrees of freedom) S = [df.2]/(df) = 13.79/37 = 0.3727 (df)Ln(S) = (37)(=0.9870) = -36.519 M = (df)Ln(S) - dfLn 2 = -36.519 -(54.472) = 17.96 C = 1+[1/(3)(4)](0.7080 - 0.0270) = 1.057 2 3df = 17.96/1.057 = 16.99 **, 3df
  • 25. Heterogeneity of Error Variance 0 10 20 30 40 50 60 70 80 Mosc Gene Tens Gran Pend Colf Kalt Mocc Boze Seed Yield
  • 26. Significant Bartlett Test “What can I do where there is significant heterogeneity of error variances?” Transform the raw data: Often  ~  cw Binomial Distribution where  = np and  = npq Transform to square roots
  • 27. Heterogeneity of Error Variance 0 2 4 6 8 10 Mosc Gene Tens Gran Pend Colf Kalt Mocc Boze SQRT[Seed Yield]
  • 28. Significant Bartlett Test “What else can I do where there is significant heterogeneity of error variances?” Transform the raw data: Homogeneity of error variance can always be achieved by transforming each site’s data to the Standardized Normal Distribution [xi-]/
  • 29. Significant Bartlett Test “What can I do where there is significant heterogeneity of error variances?” Transform the raw data Use non-parametric statistics
  • 31. Model ~ Multiple sites Yijk =  + gi + ej + geij + Eijk i gi = j ej = ij geij Environments and Replicate blocks are usually considered to be Random effects. Genotypes are usually considered to be Fixed effects.
  • 32. Analysis of Variance over sites Source d.f. EMSq Sites (s) Rep w Sites (r) Genotypes (g) Geno x Site Replicate error
  • 33. Source d.f. EMSq Sites (s) s-1 Rep w Sites (r) s(1-r) Genotypes (g) g-1 Geno x Site (g-1)(s-1) Replicate error s(r-1)(g-1) Analysis of Variance over sites
  • 34. Source d.f. EMSq Sites (s) s-1 2 e + g2 rws + rg2 s Rep w Sites (r) s(1-r) 2 e + g2 rws Genotypes (g) g-1 2 e + r2 gs+ rs2 g Geno x Site (g-1)(s-1) 2 e + r2 gs Replicate error s(r-1)(g-1) 2 e Analysis of Variance over sites
  • 35. Yijkl = +gi+sj+yk+gsij+gyik+syjk+gsyijk+Eijkl igi=jsj=kyk= 0 ijgsij=ikgyik=jksyij = 0 ijkgsyijk = 0 Models ~ Years and sites
  • 36. Analysis of Variance Source d.f. EMSq Years (y) y-1 2 e+gy2 rwswy+rg2 swy+rgs2 y Sites w Years (s) y(s-1) 2 e + g2 rwswy + rg2 swy Rep w Sites w year (r) ys(1-r) 2 e + g2 rwswy Genotypes (g) g-1 2 e + r2 gswy + rs2 gy + rl2 g Geno x year (y-1)(g-1) 2 e + r2 gswy + rs2 gy Geno x Site w Year y(g-1)(s-1) 2 e + r2 gswy Replicate error ys(r-1)(g-1) 2 e