A box contains 5 tickets numbered 1.2.3.4 and 5. Four tickets are drawn at random with replacement from the box. Let X = the total of the numbers on the four tickets Y = number of times a 3 appears Z = number of times the ticket shows a number less than or equal to 2 then which of the following is true none of X. Y and Z are binomial Only X and Z are binomial Only Y and Z are binomial Only X and Y are binomial X, Y and Z are all binomial Solution a)none of X,Y,Z are binomial.