49 Sensation refers to the process of detection of a stimulus while.pdf
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49: Sensation refers to the process of detection of a stimulus while perception is the integration, organization and interpretation of sensations. The sense organs sense the stimulus and send it to sensory regions of brain in form of nerve impulse. Now, the nerve impulse is organized and translated by brain through the process of perception. Hence, perception enables the individual to decode the nerve impulse and to understand the meaning of sensations. For example, hearing a sound is sensation while distinguish the sound as music is perception. Solution 49: Sensation refers to the process of detection of a stimulus while perception is the integration, organization and interpretation of sensations. The sense organs sense the stimulus and send it to sensory regions of brain in form of nerve impulse. Now, the nerve impulse is organized and translated by brain through the process of perception. Hence, perception enables the individual to decode the nerve impulse and to understand the meaning of sensations. For example, hearing a sound is sensation while distinguish the sound as music is perception..
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The document summarizes key points about sensation from a seminar presented by Ms. Yashaswini P.S. It defines sensation as experiences that occur through the sense organs. It describes the five main types of sensations according to the sense organs (visual, auditory, olfactory, taste, and tactual). It provides details on the sensory organs and processes involved for each type of sensation, such as how light stimulates visual sensation in the eyes and sound waves stimulate auditory sensation in the ears. The document also outlines the main elements of the sensation process, including quality, intensity, extensity, duration, and clarity.
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(1) c. Two-tailed test
(2)d. Ho: Men and women are the same in their political understanding.
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Solution
(1) c. Two-tailed test
(2)d. Ho: Men and women are the same in their political understanding.
(3)b. Ho:.
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CO2 dissolves in water to form carbonic acid (H2CO3):
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2 S2O32- + H+ => HSO3- + S
Solution
The water must be boiled to remove traces of dissolved carbon dioxide (CO2).
CO2 dissolves in water to form carbonic acid (H2CO3):
CO2 + H2O => H2CO3
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H2CO3 => H+ + HCO3-
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The H+ ions can decompose thiosulfate ions and reduce the concentration of sodium thiosulfate
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2 S2O32- + H+ => HSO3- + S.
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A .82
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For 2008 the quick ratio = (140 + 780)/1120
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undergo fusion with other reproductive cells, thus they get diploid chromosomes after fusion. So
body’s maximum cells like somatic cells undergo mitosis rather than meiosis.
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Part4. The Anaphase II is responsible for the separation of sister chromatids to form
chromosomes. Sister chromatids are chromosomes of either maternal or paternal.
Part5. During Prophase I homologous chromosomes physically pair up. This phase includes
paring up of chromosomes and homologous recombination.
Solution
Part1. Option 3rd; Somatic cells such as liver cells cannot undergo meiosis cell division. Mitotic
cells are required to be diploid in number of chromosomes. Sperm cells and germ cells are
undergo fusion with other reproductive cells, thus they get diploid chromosomes after fusion. So
body’s maximum cells like somatic cells undergo mitosis rather than meiosis.
Part2. The S phase includes the duplication of each chromosome. All DNA has duplicated in this
section by multiple sites of duplication.
Part3. Maternal and parental chromosomes are separated in Anaphase I of meiosis cell division.
These are non-identical sister chromatids.
Part4. The Anaphase II is responsible for the separation of sister chromatids to form
chromosomes. Sister chromatids are chromosomes of either maternal or paternal.
Part5. During Prophase I homologous chromosomes physically pair up. This phase includes
paring up of chromosomes and homologous recombination..
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Performance Ratios
Market Value Added (MVA):
MVA=(Company’s market value) minus(Invested capital)
Market to book=Market value of shares/Book value of shares
Data on market value are not available.
Hence the above performance ratios cannot be calculated
Profitability Ratios
Return on capital(ROC)=(Net Income –Dividend)/(Debt+Equity)
Dividend information is not available
Return on capital(ROC)=(Net Income)/Average (Debt+Equity)
Return on asset(ROA)=Net Income/(Average total asset)
Return on Equity(ROE)=Net Income/(Average Equity)
A
B
(A+B)/2
Dec 31 2015
Dec 31 2014
2015Average
C
Net income
5139
D
Debt
9246
8432
8839
E
Equity
11747
13142
12444.5
F
Debt+Equity
20993
21574
21283.5
G
Total asset
25707
25509
25608
H=C/F
Return on capital(ROC)
0.241454648
I=C/G
Return on asset(ROA)
0.200679475
J=C/E
Return on Equity(ROE)
0.412953514
Return on capital(ROC)
24.15%
Return on asset(ROA)
20.07%
Return on Equity(ROE)
41.30%
Efficiency Ratios
Profit margin=Net Profit/Sales
Operating Profit margin=Operating Profit/Sales
Asset turnover=Sales/Average Total Assets
Inventory turnover(cogs)=Cost of goods sold/Average total inventory
Days in inventory=365/inventory turnover(cogs)
Inventory turnover is also calculated from sales:
Inventory turnover (Sales)=Sales/average total inventory
Days sales in inventory=365/inventory turnover (sales)
A
B
(A+B)/2
Dec 31 2015
Dec 31 2014
2015Average
C
Net income
5139
D
Operating Income
6946
E
Sales
30274
F
Total assets
25707
25509
25608
G
Cost of goods sold
15383
H
Total inventory
3518
3706
3612
I=C/E
Profit margin
0.16974962
J=D/E
Operating Profit margin
0.229437801
K=E/F
Asset turnover
1.182208685
L=G/H
Inventory turnover(cogs)
4.258859358
M=365/L
Days in inventory
85.70369889
N=E/H
Inventory turnover (Sales)
8.381506091
P=365/N
Days sales in inventory
43.54825923
Profit margin
16.97%
Operating Profit margin
22.94%
Asset turnover
1.18220868
Inventory turnover(cogs)
4.25885936
Days in inventory
85.7036989
Days
Inventory turnover (Sales)
8.38150609
Days sales in inventory
43.5482592
Days
A
B
(A+B)/2
Dec 31 2015
Dec 31 2014
2015Average
C
Net income
5139
D
Debt
9246
8432
8839
E
Equity
11747
13142
12444.5
F
Debt+Equity
20993
21574
21283.5
G
Total asset
25707
25509
25608
H=C/F
Return on capital(ROC)
0.241454648
I=C/G
Return on asset(ROA)
0.200679475
J=C/E
Return on Equity(ROE)
0.412953514
Solution
Performance Ratios
Market Value Added (MVA):
MVA=(Company’s market value) minus(Invested capital)
Market to book=Market value of shares/Book value of shares
Data on market value are not available.
Hence the above performance ratios cannot be calculated
Profitability Ratios
Return on capital(ROC)=(Net Income –Dividend)/(Debt+Equity)
Dividend information is not available
Return on capital(ROC)=(Net Income)/Average (Debt+Equity)
Return on asset(ROA)=Net Income/(Average total asset)
Return on Equity(ROE)=Net Income/(Average Equity)
A
B
(A+B)/2
Dec 31 2015
Dec 31 2014
2015Average
C
Net income
5139
D
Debt
9246
8432
8839
E
Equity
11747
13142
124.
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OSI MODEL:
It has 7 layers
INTERNET MODEL:
It has5 Layers
DOD MODEL:
It has 4 Layers
Solution
OSI MODEL:
It has 7 layers
INTERNET MODEL:
It has5 Layers
DOD MODEL:
It has 4 Layers.
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The water must be boiled to remove traces of dissolved carbon dioxide (CO2).
CO2 dissolves in water to form carbonic acid (H2CO3):
CO2 + H2O => H2CO3
H2CO3 is a weak acid and partially ionizes to give H+ ions:
H2CO3 => H+ + HCO3-
HCO3- => H+ + CO32-
The H+ ions can decompose thiosulfate ions and reduce the concentration of sodium thiosulfate
according to the reaction:
2 S2O32- + H+ => HSO3- + S.
adsorb onto silica gel Solu.pdf
The document discusses adsorbing a solution onto silica gel. Silica gel is used to adsorb or absorb a solution. Adsorption of the solution onto the silica gel is mentioned.
Solution Plants show different types of symptoms when there is an.pdf
Solution
:
Plants show different types of symptoms when there is any nutritional vacancy in
plants.Nitrogen is one of the most common nutrient deficiency in plants.Nitrogen deficiency
leads to decrease in growth.Plants are mainly short.Some leaves not able to produce chlorophyll
which leads to green color to them.So it give rise to yellow color in leaves..
SF4SolutionSF4.pdf
This very short document contains the acronym "SF4" repeated three times without any other context or explanation. It does not provide enough information to generate a multi-sentence summary.
Quick ratio = (Cash + accounts receivable)Accounts payableFor 200.pdf
Quick ratio = (Cash + accounts receivable)/Accounts payable
For 2008 the quick ratio = (140 + 780)/1120
= 920/1120
= .82
A .82
Solution
Quick ratio = (Cash + accounts receivable)/Accounts payable
For 2008 the quick ratio = (140 + 780)/1120
= 920/1120
= .82
A .82.
Ques-1) What is the most likely cause of a throat infection in a 6-y.pdf
Ques-1) What is the most likely cause of a throat infection in a 6-year old child? Does she
require treatment?
Throat infections caused by streptococcal bacteria may cause \"post-streptococcal
glomerulonephritis\" if left untreated. Yes, the child needs treatment to treat these symptoms
(antibiotics such as penicillin, corticosteroids and diuretics are to be given).
The infection is strep throat and it is caused by streptococcal bacteria (group B). These bacteria
infect the upper respiratory tract and causes fever, sore throat, abdominal pain, fatigue, vomiting,
body aches. Throat infections caused by streptococcal bacteria may cause \"post-streptococcal
glomerulonephritis\" if left untreated. Apart from antibiotics, the major future intervention to
treat strep throat is to implement vaccination to boost innate immune levels in the infant because
antibiotics such as macrolides have potential inhibitor effects on the growth of the useful gutfolra
in infants & toddlers. Probiotics, gicing more Vitamin D & C and natural remedies are major
future interventions to avoid strep throat in children. Immunity stimulation is specific future
intervention to combat strep throat in infants as vaccination promotes immune factors to reduce
the bacteria that cause inflammation of the blood vessels near throat.
The infection is strep throat and streptococcal bacteria (group B) cause it. These bacteria infect
the upper respiratory tract and causes fever, sore throat, abdominal pain, fatigue, vomiting, body
aches. In a Gram stain of sputum specimen of beta hemolytic streptococci, \"squamous epithelial
cell type\" of body cell provides an indication that the sputum specimen represents material from
an active infection. Other cells are present in the sputum during the active infection are
polymorphonuclear leukocytes (PMNs)
Ques-2) What is the significance of facial swelling? List the possible causes of facial swelling?
1). Throat infections caused by streptococcal bacteria may cause \"post-streptococcal
glomerulonephritis\" if left untreated. Yes, the child needs treatment to treat these symptoms
(antibiotics such as penicillin, corticosteroids and diuretics are to be given).
2). The bacteria causes inflammation of the blood vessels supplying glomeruli, which impairs the
glomerular filtration. Decreased urine filtration causes edema (swelling of body organs).
Ques-3) What are the possible causes of dark urine?
Dark urine is mainly due to \"presence of RBC\" in the blood. Urine was positive for 3+ protein
and for3+ blood by dipstick. The examination of urinary sediment revealed numerous RBCs,
many of which were dismorphic. Red blood cell casts were also present.
Solution
Ques-1) What is the most likely cause of a throat infection in a 6-year old child? Does she
require treatment?
Throat infections caused by streptococcal bacteria may cause \"post-streptococcal
glomerulonephritis\" if left untreated. Yes, the child needs treatment to treat these symptoms
(antibioti.
Part1. Option 3rd; Somatic cells such as liver cells cannot undergo .pdf
Part1. Option 3rd; Somatic cells such as liver cells cannot undergo meiosis cell division. Mitotic
cells are required to be diploid in number of chromosomes. Sperm cells and germ cells are
undergo fusion with other reproductive cells, thus they get diploid chromosomes after fusion. So
body’s maximum cells like somatic cells undergo mitosis rather than meiosis.
Part2. The S phase includes the duplication of each chromosome. All DNA has duplicated in this
section by multiple sites of duplication.
Part3. Maternal and parental chromosomes are separated in Anaphase I of meiosis cell division.
These are non-identical sister chromatids.
Part4. The Anaphase II is responsible for the separation of sister chromatids to form
chromosomes. Sister chromatids are chromosomes of either maternal or paternal.
Part5. During Prophase I homologous chromosomes physically pair up. This phase includes
paring up of chromosomes and homologous recombination.
Solution
Part1. Option 3rd; Somatic cells such as liver cells cannot undergo meiosis cell division. Mitotic
cells are required to be diploid in number of chromosomes. Sperm cells and germ cells are
undergo fusion with other reproductive cells, thus they get diploid chromosomes after fusion. So
body’s maximum cells like somatic cells undergo mitosis rather than meiosis.
Part2. The S phase includes the duplication of each chromosome. All DNA has duplicated in this
section by multiple sites of duplication.
Part3. Maternal and parental chromosomes are separated in Anaphase I of meiosis cell division.
These are non-identical sister chromatids.
Part4. The Anaphase II is responsible for the separation of sister chromatids to form
chromosomes. Sister chromatids are chromosomes of either maternal or paternal.
Part5. During Prophase I homologous chromosomes physically pair up. This phase includes
paring up of chromosomes and homologous recombination..
Performance RatiosMarket Value Added (MVA)MVA=(Company’s market.pdf
Performance Ratios
Market Value Added (MVA):
MVA=(Company’s market value) minus(Invested capital)
Market to book=Market value of shares/Book value of shares
Data on market value are not available.
Hence the above performance ratios cannot be calculated
Profitability Ratios
Return on capital(ROC)=(Net Income –Dividend)/(Debt+Equity)
Dividend information is not available
Return on capital(ROC)=(Net Income)/Average (Debt+Equity)
Return on asset(ROA)=Net Income/(Average total asset)
Return on Equity(ROE)=Net Income/(Average Equity)
A
B
(A+B)/2
Dec 31 2015
Dec 31 2014
2015Average
C
Net income
5139
D
Debt
9246
8432
8839
E
Equity
11747
13142
12444.5
F
Debt+Equity
20993
21574
21283.5
G
Total asset
25707
25509
25608
H=C/F
Return on capital(ROC)
0.241454648
I=C/G
Return on asset(ROA)
0.200679475
J=C/E
Return on Equity(ROE)
0.412953514
Return on capital(ROC)
24.15%
Return on asset(ROA)
20.07%
Return on Equity(ROE)
41.30%
Efficiency Ratios
Profit margin=Net Profit/Sales
Operating Profit margin=Operating Profit/Sales
Asset turnover=Sales/Average Total Assets
Inventory turnover(cogs)=Cost of goods sold/Average total inventory
Days in inventory=365/inventory turnover(cogs)
Inventory turnover is also calculated from sales:
Inventory turnover (Sales)=Sales/average total inventory
Days sales in inventory=365/inventory turnover (sales)
A
B
(A+B)/2
Dec 31 2015
Dec 31 2014
2015Average
C
Net income
5139
D
Operating Income
6946
E
Sales
30274
F
Total assets
25707
25509
25608
G
Cost of goods sold
15383
H
Total inventory
3518
3706
3612
I=C/E
Profit margin
0.16974962
J=D/E
Operating Profit margin
0.229437801
K=E/F
Asset turnover
1.182208685
L=G/H
Inventory turnover(cogs)
4.258859358
M=365/L
Days in inventory
85.70369889
N=E/H
Inventory turnover (Sales)
8.381506091
P=365/N
Days sales in inventory
43.54825923
Profit margin
16.97%
Operating Profit margin
22.94%
Asset turnover
1.18220868
Inventory turnover(cogs)
4.25885936
Days in inventory
85.7036989
Days
Inventory turnover (Sales)
8.38150609
Days sales in inventory
43.5482592
Days
A
B
(A+B)/2
Dec 31 2015
Dec 31 2014
2015Average
C
Net income
5139
D
Debt
9246
8432
8839
E
Equity
11747
13142
12444.5
F
Debt+Equity
20993
21574
21283.5
G
Total asset
25707
25509
25608
H=C/F
Return on capital(ROC)
0.241454648
I=C/G
Return on asset(ROA)
0.200679475
J=C/E
Return on Equity(ROE)
0.412953514
Solution
Performance Ratios
Market Value Added (MVA):
MVA=(Company’s market value) minus(Invested capital)
Market to book=Market value of shares/Book value of shares
Data on market value are not available.
Hence the above performance ratios cannot be calculated
Profitability Ratios
Return on capital(ROC)=(Net Income –Dividend)/(Debt+Equity)
Dividend information is not available
Return on capital(ROC)=(Net Income)/Average (Debt+Equity)
Return on asset(ROA)=Net Income/(Average total asset)
Return on Equity(ROE)=Net Income/(Average Equity)
A
B
(A+B)/2
Dec 31 2015
Dec 31 2014
2015Average
C
Net income
5139
D
Debt
9246
8432
8839
E
Equity
11747
13142
124.
package employeeType.employee;public class Employee { private .pdf
The document defines an Employee class and subclasses for Hourly, Salary, and Commission employees. It includes methods to calculate pay, apply raises, and reset tracking periods. The main method creates sample employees, alters values, calculates pay and bonuses, applies raises, and outputs the results.
P = 212option ASolutionP = 212option A.pdf
This short document discusses a mathematical problem where P equals 2/12. The solution provided is option A. No other context or explanation is given about the nature of the problem or what option A represents as the solution.
OSI MODELIt has 7 layersINTERNET MODELIt has5 LayersDOD MO.pdf
OSI MODEL:
It has 7 layers
INTERNET MODEL:
It has5 Layers
DOD MODEL:
It has 4 Layers
Solution
OSI MODEL:
It has 7 layers
INTERNET MODEL:
It has5 Layers
DOD MODEL:
It has 4 Layers.
Option 2 namely TPP contains a thiazolium ring is correct. This is b.pdf
Option 2 namely TPP contains a thiazolium ring is correct. This is because TPP contains
pyrimidine ring which is linked to thiazole ring
Solution
Option 2 namely TPP contains a thiazolium ring is correct. This is because TPP contains
pyrimidine ring which is linked to thiazole ring.
NH4NO3 = N2O + 2 H2OMoles of NH4NO3 = 12 x moles of H2O= 12 x .pdf
NH4NO3 = N2O + 2 H2O
Moles of NH4NO3 = 1/2 x moles of H2O
= 1/2 x 0.625
= 0.3125 mol
Solution
NH4NO3 = N2O + 2 H2O
Moles of NH4NO3 = 1/2 x moles of H2O
= 1/2 x 0.625
= 0.3125 mol.
No. of shares outstanding = Total assets x weight of equity price .pdf
No. of shares outstanding = Total assets x weight of equity / price per share
= $12,020,000 x50% / $8
= 751250
Net Income = Total assets x Return on assets
= $12,020,000 x 15.10%
= 1,815,020
Earnings per share = Net Income/ No. of shares outstanding
= 1,815,020 / 751250
= 2.416
Solution
No. of shares outstanding = Total assets x weight of equity / price per share
= $12,020,000 x50% / $8
= 751250
Net Income = Total assets x Return on assets
= $12,020,000 x 15.10%
= 1,815,020
Earnings per share = Net Income/ No. of shares outstanding
= 1,815,020 / 751250
= 2.416.
molarity = moles volume = 2.0 x 10-3 mol (18.51000) L = 0.11 M.pdf
molarity = moles / volume = 2.0 x 10-3 mol / (18.5/1000) L = 0.11 M
Solution
molarity = moles / volume = 2.0 x 10-3 mol / (18.5/1000) L = 0.11 M.
import java.util.Scanner;public class Main { public static in.pdf
import java.util.Scanner;
public class Main {
public static int gridArray1[][] = null;
public static int gridArray2[][] = null;
public static boolean playerTurn = true;
public static int count = 0;
public static void setGridDimensions(int x_max, int y_max) {
Main.gridArray1 = new int[x_max][y_max];
Main.gridArray2 = new int[x_max][y_max];
for (int i = 0; i < x_max; i++) {
for (int j = 0; j < y_max; j++) {
gridArray1[i][j] = -1;
gridArray2[i][j] = -1;
}
}
}
static void placeShip(int starting_x, int starting_y, int length, int direction) {
count++;
int ships[] = new int[10];
int battleshipArrayPositions1[] = new int[4];
int cruiserArrayPositions1[] = new int[3];
int submarineArrayPositions1[] = new int[3];
int destroyerArrayPositions1[] = new int[2];
int carrierArrayPositions2[] = new int[5];
int battleshipArrayPositions2[] = new int[4];
int cruiserArrayPositions2[] = new int[3];
int submarineArrayPositions2[] = new int[3];
int destroyerArrayPositions2[] = new int[2];
if (playerTurn) {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray1[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray1[starting_x][i] = 0;
}
}
} else {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray2[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray2[starting_x][i] = 0;
}
}
}
}
boolean isConflictingShipPlacement(int starting_x, int starting_y, int length, int direction) {
return false;
}
static int shoot(int x, int y) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (Main.gridArray2[i][j] == 0) {
return 0;
}
}
}
} else {
}
return 0;
}
boolean hasBeenAttempted(int x, int y) {
return false;
}
static void displayGrid(boolean showShips) {
int count = 0;
System.out.print(\" 0 1 2 3 4 5 6 7 8 9\");
if (showShips) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray1[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
} else {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray2[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray2[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray2[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
}
} else {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"- \");
} el.
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