3Fe + 2O2 - Fe3O4 3 moles of Fe give 1 mol of Fe3 O4 1 mole gives, 1/3 ( 0.333)
mole of Fe3O4
Solution
3Fe + 2O2 - Fe3O4 3 moles of Fe give 1 mol of Fe3 O4 1 mole gives, 1/3 ( 0.333)
mole of Fe3O4.
The document discusses a solution for improving the efficiency of solar panels. It proposes coating solar panels with a new material that can absorb more wavelengths of light, increasing energy absorption by 40%. This coating material is inexpensive to produce and easy to apply, allowing for widespread implementation of more effective solar energy technology.
What is an OS • Interface between application programs and hardwa.pdfaparnacollection
What is an OS?
• Interface between application programs and hardware
• Ultimate control program
– Exploits hardware resources of one or more processors to provide a set of services to users
– Coordinates the use of hardware among various application programs for different users
– Manages secondary memory and I/O devices on behalf of its users
• Two different views of an OS
1. Extended machine view
– Virtual machine that is easier to understand and program
– Tool to make programmer’s job easy
2. Resource manager view
– Tool to facilitate efficient operation of computer system
– Provides services to users; processor, memory, I/O, system bus
– Must be fair; not partial to any process, specially for process in the same class
– Must discriminate between different class of jobs with different service requirements
– Do the above efficiently
Within the constraints of fairness and efficiency, an OS should attempt to maximize throughput,
minimize
response time, and accommodate as many users as possible
Basic elements
• A computer has a number of modules, with possibly more than one instance of each
• Processor/CPU
– Controls the operations of computer and performs data processing functions
– Exchanges data with memory using memory address register and memory buffer register
– Exchanges data with I/O devices using I/O address register and I/O buffer register
• Main memory/Primary memory
– Stores data and programs
– Typically volatile
– Abstracted as a set of locations, defined by sequentially numbered addresses
– Each location contains a bit pattern to be interpreted as either an instruction or data
• I/O modules/architecture
– Move data between a computer and external environment
– Communicate with a variety of devices including secondary memory (disks), communications
equipment, and
terminals
– Data flows between CPUs, RAM and I/O devices over buses
– System bus
Provides for communications among processors, main memory, and I/O modules
Connects most of the internal hardware devices
PCI bus, ISA bus, EISA bus, SCSI, USB
Solution
What is an OS?
• Interface between application programs and hardware
• Ultimate control program
– Exploits hardware resources of one or more processors to provide a set of services to users
– Coordinates the use of hardware among various application programs for different users
– Manages secondary memory and I/O devices on behalf of its users
• Two different views of an OS
1. Extended machine view
– Virtual machine that is easier to understand and program
– Tool to make programmer’s job easy
2. Resource manager view
– Tool to facilitate efficient operation of computer system
– Provides services to users; processor, memory, I/O, system bus
– Must be fair; not partial to any process, specially for process in the same class
– Must discriminate between different class of jobs with different service requirements
– Do the above efficiently
Within the constraints of fairness and efficiency, an OS should attempt to maximize throughput,.
Using a broad definition of file(note that it doesnt count h.pdfaparnacollection
Using a broad definition of \"file\"
(note that it doesn\'t count hidden files and assumes that file names don\'t contain newline
characters).
To include hidden files (except . and ..) and avoid problems with newline characters, the
canonical way is:
Or recursively:
Solution
Using a broad definition of \"file\"
(note that it doesn\'t count hidden files and assumes that file names don\'t contain newline
characters).
To include hidden files (except . and ..) and avoid problems with newline characters, the
canonical way is:
Or recursively:.
The multiplication sign simply means that the molecules have their i.pdfaparnacollection
The multiplication sign simply means that the molecules have their independent existance in the
compound. For example the formula you have given has three species in solution ZnCO3, 2
molecules of Zn(OH)2 and 1 molecule of water H20 for each molecule of your compound. These
species are bonded to each other but the bonds between the atoms of the participating molecules
are not broken. To get the molar mass of the compound simply add the molar masses of
indivisual molecules multiplied by number of molecules they are contributing. Thus for
ZnCO3*2Zn(OH)2*1H20 the molar mass would be:
Molar mass of ZnCO3 + 2*(Molar mass of Zn(OH)2) + Molar mass of H2O
= 125.4 + 2*99.4 + 18
= 342.2 g/mol
Solution
The multiplication sign simply means that the molecules have their independent existance in the
compound. For example the formula you have given has three species in solution ZnCO3, 2
molecules of Zn(OH)2 and 1 molecule of water H20 for each molecule of your compound. These
species are bonded to each other but the bonds between the atoms of the participating molecules
are not broken. To get the molar mass of the compound simply add the molar masses of
indivisual molecules multiplied by number of molecules they are contributing. Thus for
ZnCO3*2Zn(OH)2*1H20 the molar mass would be:
Molar mass of ZnCO3 + 2*(Molar mass of Zn(OH)2) + Molar mass of H2O
= 125.4 + 2*99.4 + 18
= 342.2 g/mol.
SolutionThe variance of individual assets is measure of total ris.pdfaparnacollection
The variance of individual assets measures total risk, but in a well-diversified portfolio only systematic risk matters as unsystematic risk is reduced. The variance of a diversified portfolio depends on its systematic risk, known as beta. Therefore, the statement in the question is false.
soldefnition of critical thinkingit is an intellectual process o.pdfaparnacollection
sol:
defnition of critical thinking:it is an intellectual process of applying ,analyizing,evaluating
information by means of observation which leads to believe in action
a. When you consider all the different perspectives on a topic and evaluate how true or
applicable they are in a given context.
Solution
sol:
defnition of critical thinking:it is an intellectual process of applying ,analyizing,evaluating
information by means of observation which leads to believe in action
a. When you consider all the different perspectives on a topic and evaluate how true or
applicable they are in a given context..
The document discusses a solution for improving the efficiency of solar panels. It proposes coating solar panels with a new material that can absorb more wavelengths of light, increasing energy absorption by 40%. This coating material is inexpensive to produce and easy to apply, allowing for widespread implementation of more effective solar energy technology.
What is an OS • Interface between application programs and hardwa.pdfaparnacollection
What is an OS?
• Interface between application programs and hardware
• Ultimate control program
– Exploits hardware resources of one or more processors to provide a set of services to users
– Coordinates the use of hardware among various application programs for different users
– Manages secondary memory and I/O devices on behalf of its users
• Two different views of an OS
1. Extended machine view
– Virtual machine that is easier to understand and program
– Tool to make programmer’s job easy
2. Resource manager view
– Tool to facilitate efficient operation of computer system
– Provides services to users; processor, memory, I/O, system bus
– Must be fair; not partial to any process, specially for process in the same class
– Must discriminate between different class of jobs with different service requirements
– Do the above efficiently
Within the constraints of fairness and efficiency, an OS should attempt to maximize throughput,
minimize
response time, and accommodate as many users as possible
Basic elements
• A computer has a number of modules, with possibly more than one instance of each
• Processor/CPU
– Controls the operations of computer and performs data processing functions
– Exchanges data with memory using memory address register and memory buffer register
– Exchanges data with I/O devices using I/O address register and I/O buffer register
• Main memory/Primary memory
– Stores data and programs
– Typically volatile
– Abstracted as a set of locations, defined by sequentially numbered addresses
– Each location contains a bit pattern to be interpreted as either an instruction or data
• I/O modules/architecture
– Move data between a computer and external environment
– Communicate with a variety of devices including secondary memory (disks), communications
equipment, and
terminals
– Data flows between CPUs, RAM and I/O devices over buses
– System bus
Provides for communications among processors, main memory, and I/O modules
Connects most of the internal hardware devices
PCI bus, ISA bus, EISA bus, SCSI, USB
Solution
What is an OS?
• Interface between application programs and hardware
• Ultimate control program
– Exploits hardware resources of one or more processors to provide a set of services to users
– Coordinates the use of hardware among various application programs for different users
– Manages secondary memory and I/O devices on behalf of its users
• Two different views of an OS
1. Extended machine view
– Virtual machine that is easier to understand and program
– Tool to make programmer’s job easy
2. Resource manager view
– Tool to facilitate efficient operation of computer system
– Provides services to users; processor, memory, I/O, system bus
– Must be fair; not partial to any process, specially for process in the same class
– Must discriminate between different class of jobs with different service requirements
– Do the above efficiently
Within the constraints of fairness and efficiency, an OS should attempt to maximize throughput,.
Using a broad definition of file(note that it doesnt count h.pdfaparnacollection
Using a broad definition of \"file\"
(note that it doesn\'t count hidden files and assumes that file names don\'t contain newline
characters).
To include hidden files (except . and ..) and avoid problems with newline characters, the
canonical way is:
Or recursively:
Solution
Using a broad definition of \"file\"
(note that it doesn\'t count hidden files and assumes that file names don\'t contain newline
characters).
To include hidden files (except . and ..) and avoid problems with newline characters, the
canonical way is:
Or recursively:.
The multiplication sign simply means that the molecules have their i.pdfaparnacollection
The multiplication sign simply means that the molecules have their independent existance in the
compound. For example the formula you have given has three species in solution ZnCO3, 2
molecules of Zn(OH)2 and 1 molecule of water H20 for each molecule of your compound. These
species are bonded to each other but the bonds between the atoms of the participating molecules
are not broken. To get the molar mass of the compound simply add the molar masses of
indivisual molecules multiplied by number of molecules they are contributing. Thus for
ZnCO3*2Zn(OH)2*1H20 the molar mass would be:
Molar mass of ZnCO3 + 2*(Molar mass of Zn(OH)2) + Molar mass of H2O
= 125.4 + 2*99.4 + 18
= 342.2 g/mol
Solution
The multiplication sign simply means that the molecules have their independent existance in the
compound. For example the formula you have given has three species in solution ZnCO3, 2
molecules of Zn(OH)2 and 1 molecule of water H20 for each molecule of your compound. These
species are bonded to each other but the bonds between the atoms of the participating molecules
are not broken. To get the molar mass of the compound simply add the molar masses of
indivisual molecules multiplied by number of molecules they are contributing. Thus for
ZnCO3*2Zn(OH)2*1H20 the molar mass would be:
Molar mass of ZnCO3 + 2*(Molar mass of Zn(OH)2) + Molar mass of H2O
= 125.4 + 2*99.4 + 18
= 342.2 g/mol.
SolutionThe variance of individual assets is measure of total ris.pdfaparnacollection
The variance of individual assets measures total risk, but in a well-diversified portfolio only systematic risk matters as unsystematic risk is reduced. The variance of a diversified portfolio depends on its systematic risk, known as beta. Therefore, the statement in the question is false.
soldefnition of critical thinkingit is an intellectual process o.pdfaparnacollection
sol:
defnition of critical thinking:it is an intellectual process of applying ,analyizing,evaluating
information by means of observation which leads to believe in action
a. When you consider all the different perspectives on a topic and evaluate how true or
applicable they are in a given context.
Solution
sol:
defnition of critical thinking:it is an intellectual process of applying ,analyizing,evaluating
information by means of observation which leads to believe in action
a. When you consider all the different perspectives on a topic and evaluate how true or
applicable they are in a given context..
Program-a. library is importedimport java.awt.; import j.pdfaparnacollection
Program:-
a.
// library is imported
import java.awt.*;
import java.applet.*;
import java.awt.event.*;
import javax.swing.*;
public class JPasswordA extends Applet implements ActionListener //Class Applet is //extended
using inheritance
{boolean clicked=false,code=false; // Boolean function is defined
Label passwordlabel = new Label(\"Password:\"); // object creation
TextField passwordfield = new TextField(15); // text field is assigned to the password
Button enterbutton = new Button(\"Enter\");
public void init() // initialization method is defined
{
add(passwordlabel);
add(passwordfield);
add(enterbutton);
enterbutton.addActionListener(this); // button and password field is set
passwordlabel.setVisible(true);
passwordfield.setVisible(true);
}
public void actionPerformed(ActionEvent e) // method
{ String pass;
clicked=true;
pass=passwordfield.getText();
if(pass.compareTo(\"Rosebud\")==0) // conditional statement is defined
code=true;
else
code=false;
repaint();
}
public void paint(Graphics g) //paint method is defined
{
if(clicked)
{if(code)
g.drawString(\"Access Granted\",120,150); // according to question.
else
g.drawString(\"Access Denied\",120,150);
}
}
}
b.
// library is imported
import java.awt.*;
import java.applet.*;
import java.awt.event.*;
import javax.swing.*;
public class JPasswordB extends Applet implements ActionListener//Class Applet is //extended
using inheritance
{boolean clicked=false,code=false; // Boolean function is defined
Label passwordlabel = new Label(\"Password:\"); // object creation
TextField passwordfield = new TextField(15); // text field is assigned to the password
Button enterbutton = new Button(\"Enter\");
public void init()// initialization method is defined
{
add(passwordlabel);
add(passwordfield);
add(enterbutton);
enterbutton.addActionListener(this);
passwordlabel.setVisible(true); // button and password field is set
passwordfield.setVisible(true);
}
public void actionPerformed(ActionEvent e) // method
{ String pass;
clicked=true;
pass=passwordfield.getText();
if(pass.compareToIgnoreCase(\"Rosebud\")==0) // conditional statement is defined
code=true;
else
code=false;
repaint();
}
public void paint(Graphics g) //paint method is defined
{
if(clicked)
{if(code)
g.drawString(\"Access Granted\",120,150); // according to question.
else
g.drawString(\"Access Denied\",120,150);
}
}
}
c.
// library is imported
import java.awt.*;
import java.applet.*;
import java.awt.event.*;
import javax.swing.*;
public class JPasswordC extends Applet implements ActionListener //Class Applet is //extended
using inheritance
{boolean clicked=false,code=false;
Label passwordlabel = new Label(\"Password:\"); // Boolean function is defined
TextField passwordfield = new TextField(15);
Button enterbutton = new Button(\"Enter\"); // object creation
public void init()// text field is assigned to the password
{
add(passwordlabel);
add(passwordfield);
add(enterbutton);
enterbutton.addActionListener(this); // button and password field is set
p.
Given below is the completed code along with comments. Output of the.pdfaparnacollection
Given below is the completed code along with comments. Output of the program is shown at the
end. You will need to create an input file containing multiple lines of input as specified in the
question. I have given a sample input file with just 1 line of input.
Please do rate the answer if it helped. Thank you very much.
#include
/*
extractBits extracts the specified number of bits starting specified start location from left.
bit numbering starts with 0 from left. len specifies the number of bits to extract.
So extract leftmost 4 bits of a number n, the call should be extractBits(n, 0, 4). Here start = 0
means the 0th bit from left.
Similarly to extract bit 16 through 20 (i.e 5 bits), we use extractBits(n, 16, 5)
The way this function works is - First calculate the remaining number of bits on the rightside .
Since int takes 32 bits, we subtract (start+len) from 32 to get remaining bits on right.
it first clears all the bits upto starting bit by left shift <<
by start bits. Now we shift back the same number of times to right +
*/
int extractBits(unsigned n, int start, int len)
{
int rightRemaining = 32 - (start + len);
//shift left and then right by start no. of bits clears leftside bits
n = (n << start) >> start;
//now shifting by remaining number of bits on right will extract only needed bits
n = n >> rightRemaining;
return n;
}
int main (int argc, char *argv[]) {
// Get the filename to open, then open the file. If we can\'t
// open the file, complain and quit.
char *filename;
// *** Your Code *** if argv[1] exists, set filename to it,
// otherwise set filename to \"Lab3_data.txt\";
if(argv[1] != NULL)
filename = argv[1];
else
filename = \"Lab3_data.txt\";
// Open the file; if opening fails, say so and return 1.
// otherwise say what file we\'re reading from.
FILE *in_file;
in_file = fopen(filename, \"r\"); // NULL if the open failed
// *** Your Code *** if in_file is NULL, complain and quit
// otherwise say that we\'ve opened the filename
if (in_file == NULL){
printf(\"Couldn\'t open file %s\ \", filename);
return 1;
}
printf(\"Opened file %s for reading...\ \", filename);
// Repeatedly read and process each line of the file. The
// line should have a hex integer and two integer lengths.
int val, len1, len2, len3;
int nbr_vals_on_line
= fscanf(in_file, \"%x %d %d\", &val, &len1, &len2);
// Read until we hit end-of-file or a line without the 3 values.
while (nbr_vals_on_line == 3) {
// We\'re going to break up the value into bitstrings of
// length len1, len2, and len3 (going left-to-right).
// The user gives us len1 and len2, and we calculate
// len3 = the remainder of the 32 bits of value.
// All three lengths should be > 0, else we complain
// and go onto the next line.
//
len3 = 32 - (len1 + len2);
// *** Your Code***
// if any of the lengths aren\'t > 0,
// print out the value and the lengths and complain
// about the lengths not all being positive
if(len1 <= 0 || len2 <= 0 || len3 <= 0)
{
printf(\"Invalid lengths : len1=%d, len2=%d, len.
(a) The American Institute of Certified Accountants. (AICPA)(b) Th.pdfaparnacollection
(a) The American Institute of Certified Accountants. (AICPA)
(b) This Statement establishes accounting and financial reporting standards for public colleges
and universities within the financial reporting guidelines of GASB Statement No. 34, Basic
Financial Statements-and Management’s Discussion and Analysis-for State and Local
Governments. The standards are designed to provide financial information that responds to the
needs of three groups of primary users of general purpose external financial reports: the
citizenry, legislative and oversight bodies, and investors and creditors. Generally, this
amendment to Statement 34 permits public colleges and universities, in separately issued
financial statements, to use the guidance for special-purpose governments engaged only in
business-type activities, engaged only in governmental activities, or engaged in both
governmental and business-type activities in their separately issued reports. Under this guidance,
in its separately issued reports, a public institution is required to include management’s
discussion and analysis (MD&A); basic financial statements, as appropriate for the category of
special-purpose government reporting selected; notes to the financial statements; and required
supplementary information other than MD&A.
Unless otherwise specified, pronouncements of the GASB apply to financial reports of all state
and local governmental entities, including general purpose governments, public benefit
corporations and authorities, and public employee retirement systems, utilities, hospitals and
other healthcare providers, and colleges and universities. Paragraph 2 discusses the applicability
of this Statement.
(c) A statement of financial position, including accompanying notes to financial statements,
provides relevant information about liquidity, financial flexibility, and the interrelationship of an
organization\'s assets and liabilities. That information generally is provided by aggregating assets
and liabilities that possess similar characteristics into reasonably homogeneous groups. For
example, entities generally report individual items of assets in homogeneous groups, such as
cash and cash equivalents; accounts and notes receivable from patients, students, members, and
other recipients of services; inventories of materials and supplies; deposits and prepayments for
rent, insurance, and other services; marketable securities and other investment assets held for
long-term purposes; and land, buildings, equipment, and other long-lived assets used to provide
goods and services. Cash or other assets received with a donor-imposed restriction that limits
their use to long-term purposes should not be classified with cash or other assets that are
unrestricted and available for current use.
(d) A statement of activities shall report revenues as increases in unrestricted net assets unless
the use of the assets received is limited by donor-imposed restrictions. For example, fees from
rendering servic.
Yes. The compound is actively active. It is mainl.pdfaparnacollection
Yes. The compound is actively active. It is mainly caused by the carbon to the right
of the 2 oxygens. I think i forgot about the stereoisomers when I last answered them. The number
of stereoisomers is dependent on the number of chiral centers. Since there are 3 chiral centers, it
is 2^3, which is 8 possible stereoisomers. So I mentioned before that the chiral centers are the
carbons directly to the right and left of the oxygens. All the bonds in the ring structure are in the
plane. The other 2 bonds can be alternated to be pointing inside the page or out of the page. That
is why if you have 3 carbon centers, it is just a matter of probability of 2^3 (2 possible choices
over 3 possible carbons) which give you 8. And as I previously explained: To be optically
active, you need to have chiral center, which is any carbon with 4 different subgroups. There is 3
such centers. The carbons to the left of both oxygens (this makes up 2 carbons) are chirally
active since they have 4 different groups. However, since they are mirror images of each other,
they cancel each other out. It is the third and final carbon to the right of both oxygens, that
makes this compound chirally active. Since it has also 4 different groups attached to the carbon
and is not canceled out by anything. One simple way to test if something is optically active is to
see if it is a mirror image of itself. If it is not a mirror image and it has at least 1 chiral center,
then it is optically active
Solution
Yes. The compound is actively active. It is mainly caused by the carbon to the right
of the 2 oxygens. I think i forgot about the stereoisomers when I last answered them. The number
of stereoisomers is dependent on the number of chiral centers. Since there are 3 chiral centers, it
is 2^3, which is 8 possible stereoisomers. So I mentioned before that the chiral centers are the
carbons directly to the right and left of the oxygens. All the bonds in the ring structure are in the
plane. The other 2 bonds can be alternated to be pointing inside the page or out of the page. That
is why if you have 3 carbon centers, it is just a matter of probability of 2^3 (2 possible choices
over 3 possible carbons) which give you 8. And as I previously explained: To be optically
active, you need to have chiral center, which is any carbon with 4 different subgroups. There is 3
such centers. The carbons to the left of both oxygens (this makes up 2 carbons) are chirally
active since they have 4 different groups. However, since they are mirror images of each other,
they cancel each other out. It is the third and final carbon to the right of both oxygens, that
makes this compound chirally active. Since it has also 4 different groups attached to the carbon
and is not canceled out by anything. One simple way to test if something is optically active is to
see if it is a mirror image of itself. If it is not a mirror image and it has at least 1 chiral center,
then it is optically active.
This document contains chemical symbols for hydrogen ions and cyanide ions in solution. It indicates that hydrogen ions and cyanide ions are present together in an aqueous solution. The document provides a brief representation of the composition of an ionic solution through chemical symbols but does not include additional context or details.
Adding elements public void add(String element) { For fi.pdfaparnacollection
// Adding elements
public void add(String element) {
// For first element Head is null. So, create a new node and mark it as head.
// and increase numElements
if(head == null){
head = new StringNode(element, null);
numElements++;
} else {
// if not, find its place first.
// then create a node and mark position link to new node
// mark new node as link to positional node
StringNode node = head;
while(node.getLink() != null){
if(node.getData().compareTo(element) < 0){
break;
}
}
StringNode newNode = new StringNode(element, null);
newNode.setLink(node.getLink());
node.setLink(newNode);
numElements++;
}
}
// Removing elements
public boolean remove(String target)
{
StringNode targetNode = head;
boolean found = false;
while (targetNode!= null && !found)
{
if(targetNode.getData().equalsIgnoreCase(target))
found = true;
else
targetNode = targetNode.getLink();
}
if(found)
{
// copy the head to targetNode
// and then advance head to the next node.
targetNode.setData(targetNode.getLink().getData());
targetNode.setLink(targetNode.getLink());
numElements --;
}
return found;
}
Solution
// Adding elements
public void add(String element) {
// For first element Head is null. So, create a new node and mark it as head.
// and increase numElements
if(head == null){
head = new StringNode(element, null);
numElements++;
} else {
// if not, find its place first.
// then create a node and mark position link to new node
// mark new node as link to positional node
StringNode node = head;
while(node.getLink() != null){
if(node.getData().compareTo(element) < 0){
break;
}
}
StringNode newNode = new StringNode(element, null);
newNode.setLink(node.getLink());
node.setLink(newNode);
numElements++;
}
}
// Removing elements
public boolean remove(String target)
{
StringNode targetNode = head;
boolean found = false;
while (targetNode!= null && !found)
{
if(targetNode.getData().equalsIgnoreCase(target))
found = true;
else
targetNode = targetNode.getLink();
}
if(found)
{
// copy the head to targetNode
// and then advance head to the next node.
targetNode.setData(targetNode.getLink().getData());
targetNode.setLink(targetNode.getLink());
numElements --;
}
return found;
}.
1) Investment Grade Domestic Bonds As bond bears a fixed rate of i.pdfaparnacollection
1) Investment Grade Domestic Bonds As bond bears a fixed rate of interest hence Mutual
Fund or ETFS can\'t Represent Bonds as an asset class. 2) High Yield Bonds 3) Domestic
stock Both are consist of shares and debentures so Mutual Fund or ETFS can\'t Represent them
as an asset class. 4) International Stock 6) Energy Similarly ETF and Mutual fund never
meet the defination of these 3 asset class so can\'t represent them 7) Commodities 8) Real
Estate 5)E merging Market Stock An emerging market fund is a mutual fund or ETF
that invests the bulk of its assets in stocks of developing countries. E merging countries are
those which are not developed yet in the stage of development i.e. china, india etc. so
invetment in these fund brings highest reurn for prospective investor. So
ETF and Mutual fund Represents E merging market stock.
Solution
1) Investment Grade Domestic Bonds As bond bears a fixed rate of interest hence Mutual
Fund or ETFS can\'t Represent Bonds as an asset class. 2) High Yield Bonds 3) Domestic
stock Both are consist of shares and debentures so Mutual Fund or ETFS can\'t Represent them
as an asset class. 4) International Stock 6) Energy Similarly ETF and Mutual fund never
meet the defination of these 3 asset class so can\'t represent them 7) Commodities 8) Real
Estate 5)E merging Market Stock An emerging market fund is a mutual fund or ETF
that invests the bulk of its assets in stocks of developing countries. E merging countries are
those which are not developed yet in the stage of development i.e. china, india etc. so
invetment in these fund brings highest reurn for prospective investor. So
ETF and Mutual fund Represents E merging market stock..
When atoms share one or more pairs of electrons t.pdfaparnacollection
When atoms share one or more pairs of electrons the bonds are called covalent
bonds.
Solution
When atoms share one or more pairs of electrons the bonds are called covalent
bonds..
This is quite simple to do. Barium sulfate is ins.pdfaparnacollection
This is quite simple to do. Barium sulfate is insoluble in water and sodium chloride
is soluble in water. So this is what you do. Dump them both in water. As I said the NaCl will
dissolve. Then do vacuum or suction filtration. That will filter out the barium sulfate from the
solution. Now the two are separate. To get the NaCl out of the water just boil it off.
Solution
This is quite simple to do. Barium sulfate is insoluble in water and sodium chloride
is soluble in water. So this is what you do. Dump them both in water. As I said the NaCl will
dissolve. Then do vacuum or suction filtration. That will filter out the barium sulfate from the
solution. Now the two are separate. To get the NaCl out of the water just boil it off..
Nitric acid is a strong acid... we can assume com.pdfaparnacollection
Nitric acid is a strong acid... we can assume complete dissociation, So [H+] is 0.04
M
Solution
Nitric acid is a strong acid... we can assume complete dissociation, So [H+] is 0.04
M.
molar ratio : 6 carbon 12 hydirgen 6 oxygen molar ratio : C : H : O = 1 : 2 : 1
Solution
molar ratio : 6 carbon 12 hydirgen 6 oxygen molar ratio : C : H : O = 1 : 2 : 1.
as Na+ ions replace H+ from H2S,as 2moles of Na+ .pdfaparnacollection
as Na+ ions replace H+ from H2S,as 2moles of Na+ are produced exactly double
H+ions will be produced.Option D
Solution
as Na+ ions replace H+ from H2S,as 2moles of Na+ are produced exactly double
H+ions will be produced.Option D.
This 3 sentence document does not provide enough context or information to generate an accurate 3 sentence summary. The document contains two sentences with the label "Dependent:" but no further details are given. Therefore, a meaningful high-level summary cannot be produced from the limited information provided.
Bear with me, Im trying to type the Lewis structure O=Se-O.pdfaparnacollection
Bear with me, I\'m trying to type the Lewis structure:
::O=Se-O:::
and there are four electrons surrounding the selenium.
So: Oxygen with four unpaired electrons and a double bond to Selenium. Selenium with four
unpaired electrons bonded by a single bond to Oxygen with six unpaired electrons.
Hope I helped!
Solution
Bear with me, I\'m trying to type the Lewis structure:
::O=Se-O:::
and there are four electrons surrounding the selenium.
So: Oxygen with four unpaired electrons and a double bond to Selenium. Selenium with four
unpaired electrons bonded by a single bond to Oxygen with six unpaired electrons.
Hope I helped!.
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...PECB
Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
-------------------------------------------------------------------------------
Find out more about ISO training and certification services
Training: ISO/IEC 27001 Information Security Management System - EN | PECB
ISO/IEC 42001 Artificial Intelligence Management System - EN | PECB
General Data Protection Regulation (GDPR) - Training Courses - EN | PECB
Webinars: https://pecb.com/webinars
Article: https://pecb.com/article
-------------------------------------------------------------------------------
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LinkedIn: https://www.linkedin.com/company/pecb/
Facebook: https://www.facebook.com/PECBInternational/
Slideshare: http://www.slideshare.net/PECBCERTIFICATION
Program-a. library is importedimport java.awt.; import j.pdfaparnacollection
Program:-
a.
// library is imported
import java.awt.*;
import java.applet.*;
import java.awt.event.*;
import javax.swing.*;
public class JPasswordA extends Applet implements ActionListener //Class Applet is //extended
using inheritance
{boolean clicked=false,code=false; // Boolean function is defined
Label passwordlabel = new Label(\"Password:\"); // object creation
TextField passwordfield = new TextField(15); // text field is assigned to the password
Button enterbutton = new Button(\"Enter\");
public void init() // initialization method is defined
{
add(passwordlabel);
add(passwordfield);
add(enterbutton);
enterbutton.addActionListener(this); // button and password field is set
passwordlabel.setVisible(true);
passwordfield.setVisible(true);
}
public void actionPerformed(ActionEvent e) // method
{ String pass;
clicked=true;
pass=passwordfield.getText();
if(pass.compareTo(\"Rosebud\")==0) // conditional statement is defined
code=true;
else
code=false;
repaint();
}
public void paint(Graphics g) //paint method is defined
{
if(clicked)
{if(code)
g.drawString(\"Access Granted\",120,150); // according to question.
else
g.drawString(\"Access Denied\",120,150);
}
}
}
b.
// library is imported
import java.awt.*;
import java.applet.*;
import java.awt.event.*;
import javax.swing.*;
public class JPasswordB extends Applet implements ActionListener//Class Applet is //extended
using inheritance
{boolean clicked=false,code=false; // Boolean function is defined
Label passwordlabel = new Label(\"Password:\"); // object creation
TextField passwordfield = new TextField(15); // text field is assigned to the password
Button enterbutton = new Button(\"Enter\");
public void init()// initialization method is defined
{
add(passwordlabel);
add(passwordfield);
add(enterbutton);
enterbutton.addActionListener(this);
passwordlabel.setVisible(true); // button and password field is set
passwordfield.setVisible(true);
}
public void actionPerformed(ActionEvent e) // method
{ String pass;
clicked=true;
pass=passwordfield.getText();
if(pass.compareToIgnoreCase(\"Rosebud\")==0) // conditional statement is defined
code=true;
else
code=false;
repaint();
}
public void paint(Graphics g) //paint method is defined
{
if(clicked)
{if(code)
g.drawString(\"Access Granted\",120,150); // according to question.
else
g.drawString(\"Access Denied\",120,150);
}
}
}
c.
// library is imported
import java.awt.*;
import java.applet.*;
import java.awt.event.*;
import javax.swing.*;
public class JPasswordC extends Applet implements ActionListener //Class Applet is //extended
using inheritance
{boolean clicked=false,code=false;
Label passwordlabel = new Label(\"Password:\"); // Boolean function is defined
TextField passwordfield = new TextField(15);
Button enterbutton = new Button(\"Enter\"); // object creation
public void init()// text field is assigned to the password
{
add(passwordlabel);
add(passwordfield);
add(enterbutton);
enterbutton.addActionListener(this); // button and password field is set
p.
Given below is the completed code along with comments. Output of the.pdfaparnacollection
Given below is the completed code along with comments. Output of the program is shown at the
end. You will need to create an input file containing multiple lines of input as specified in the
question. I have given a sample input file with just 1 line of input.
Please do rate the answer if it helped. Thank you very much.
#include
/*
extractBits extracts the specified number of bits starting specified start location from left.
bit numbering starts with 0 from left. len specifies the number of bits to extract.
So extract leftmost 4 bits of a number n, the call should be extractBits(n, 0, 4). Here start = 0
means the 0th bit from left.
Similarly to extract bit 16 through 20 (i.e 5 bits), we use extractBits(n, 16, 5)
The way this function works is - First calculate the remaining number of bits on the rightside .
Since int takes 32 bits, we subtract (start+len) from 32 to get remaining bits on right.
it first clears all the bits upto starting bit by left shift <<
by start bits. Now we shift back the same number of times to right +
*/
int extractBits(unsigned n, int start, int len)
{
int rightRemaining = 32 - (start + len);
//shift left and then right by start no. of bits clears leftside bits
n = (n << start) >> start;
//now shifting by remaining number of bits on right will extract only needed bits
n = n >> rightRemaining;
return n;
}
int main (int argc, char *argv[]) {
// Get the filename to open, then open the file. If we can\'t
// open the file, complain and quit.
char *filename;
// *** Your Code *** if argv[1] exists, set filename to it,
// otherwise set filename to \"Lab3_data.txt\";
if(argv[1] != NULL)
filename = argv[1];
else
filename = \"Lab3_data.txt\";
// Open the file; if opening fails, say so and return 1.
// otherwise say what file we\'re reading from.
FILE *in_file;
in_file = fopen(filename, \"r\"); // NULL if the open failed
// *** Your Code *** if in_file is NULL, complain and quit
// otherwise say that we\'ve opened the filename
if (in_file == NULL){
printf(\"Couldn\'t open file %s\ \", filename);
return 1;
}
printf(\"Opened file %s for reading...\ \", filename);
// Repeatedly read and process each line of the file. The
// line should have a hex integer and two integer lengths.
int val, len1, len2, len3;
int nbr_vals_on_line
= fscanf(in_file, \"%x %d %d\", &val, &len1, &len2);
// Read until we hit end-of-file or a line without the 3 values.
while (nbr_vals_on_line == 3) {
// We\'re going to break up the value into bitstrings of
// length len1, len2, and len3 (going left-to-right).
// The user gives us len1 and len2, and we calculate
// len3 = the remainder of the 32 bits of value.
// All three lengths should be > 0, else we complain
// and go onto the next line.
//
len3 = 32 - (len1 + len2);
// *** Your Code***
// if any of the lengths aren\'t > 0,
// print out the value and the lengths and complain
// about the lengths not all being positive
if(len1 <= 0 || len2 <= 0 || len3 <= 0)
{
printf(\"Invalid lengths : len1=%d, len2=%d, len.
(a) The American Institute of Certified Accountants. (AICPA)(b) Th.pdfaparnacollection
(a) The American Institute of Certified Accountants. (AICPA)
(b) This Statement establishes accounting and financial reporting standards for public colleges
and universities within the financial reporting guidelines of GASB Statement No. 34, Basic
Financial Statements-and Management’s Discussion and Analysis-for State and Local
Governments. The standards are designed to provide financial information that responds to the
needs of three groups of primary users of general purpose external financial reports: the
citizenry, legislative and oversight bodies, and investors and creditors. Generally, this
amendment to Statement 34 permits public colleges and universities, in separately issued
financial statements, to use the guidance for special-purpose governments engaged only in
business-type activities, engaged only in governmental activities, or engaged in both
governmental and business-type activities in their separately issued reports. Under this guidance,
in its separately issued reports, a public institution is required to include management’s
discussion and analysis (MD&A); basic financial statements, as appropriate for the category of
special-purpose government reporting selected; notes to the financial statements; and required
supplementary information other than MD&A.
Unless otherwise specified, pronouncements of the GASB apply to financial reports of all state
and local governmental entities, including general purpose governments, public benefit
corporations and authorities, and public employee retirement systems, utilities, hospitals and
other healthcare providers, and colleges and universities. Paragraph 2 discusses the applicability
of this Statement.
(c) A statement of financial position, including accompanying notes to financial statements,
provides relevant information about liquidity, financial flexibility, and the interrelationship of an
organization\'s assets and liabilities. That information generally is provided by aggregating assets
and liabilities that possess similar characteristics into reasonably homogeneous groups. For
example, entities generally report individual items of assets in homogeneous groups, such as
cash and cash equivalents; accounts and notes receivable from patients, students, members, and
other recipients of services; inventories of materials and supplies; deposits and prepayments for
rent, insurance, and other services; marketable securities and other investment assets held for
long-term purposes; and land, buildings, equipment, and other long-lived assets used to provide
goods and services. Cash or other assets received with a donor-imposed restriction that limits
their use to long-term purposes should not be classified with cash or other assets that are
unrestricted and available for current use.
(d) A statement of activities shall report revenues as increases in unrestricted net assets unless
the use of the assets received is limited by donor-imposed restrictions. For example, fees from
rendering servic.
Yes. The compound is actively active. It is mainl.pdfaparnacollection
Yes. The compound is actively active. It is mainly caused by the carbon to the right
of the 2 oxygens. I think i forgot about the stereoisomers when I last answered them. The number
of stereoisomers is dependent on the number of chiral centers. Since there are 3 chiral centers, it
is 2^3, which is 8 possible stereoisomers. So I mentioned before that the chiral centers are the
carbons directly to the right and left of the oxygens. All the bonds in the ring structure are in the
plane. The other 2 bonds can be alternated to be pointing inside the page or out of the page. That
is why if you have 3 carbon centers, it is just a matter of probability of 2^3 (2 possible choices
over 3 possible carbons) which give you 8. And as I previously explained: To be optically
active, you need to have chiral center, which is any carbon with 4 different subgroups. There is 3
such centers. The carbons to the left of both oxygens (this makes up 2 carbons) are chirally
active since they have 4 different groups. However, since they are mirror images of each other,
they cancel each other out. It is the third and final carbon to the right of both oxygens, that
makes this compound chirally active. Since it has also 4 different groups attached to the carbon
and is not canceled out by anything. One simple way to test if something is optically active is to
see if it is a mirror image of itself. If it is not a mirror image and it has at least 1 chiral center,
then it is optically active
Solution
Yes. The compound is actively active. It is mainly caused by the carbon to the right
of the 2 oxygens. I think i forgot about the stereoisomers when I last answered them. The number
of stereoisomers is dependent on the number of chiral centers. Since there are 3 chiral centers, it
is 2^3, which is 8 possible stereoisomers. So I mentioned before that the chiral centers are the
carbons directly to the right and left of the oxygens. All the bonds in the ring structure are in the
plane. The other 2 bonds can be alternated to be pointing inside the page or out of the page. That
is why if you have 3 carbon centers, it is just a matter of probability of 2^3 (2 possible choices
over 3 possible carbons) which give you 8. And as I previously explained: To be optically
active, you need to have chiral center, which is any carbon with 4 different subgroups. There is 3
such centers. The carbons to the left of both oxygens (this makes up 2 carbons) are chirally
active since they have 4 different groups. However, since they are mirror images of each other,
they cancel each other out. It is the third and final carbon to the right of both oxygens, that
makes this compound chirally active. Since it has also 4 different groups attached to the carbon
and is not canceled out by anything. One simple way to test if something is optically active is to
see if it is a mirror image of itself. If it is not a mirror image and it has at least 1 chiral center,
then it is optically active.
This document contains chemical symbols for hydrogen ions and cyanide ions in solution. It indicates that hydrogen ions and cyanide ions are present together in an aqueous solution. The document provides a brief representation of the composition of an ionic solution through chemical symbols but does not include additional context or details.
Adding elements public void add(String element) { For fi.pdfaparnacollection
// Adding elements
public void add(String element) {
// For first element Head is null. So, create a new node and mark it as head.
// and increase numElements
if(head == null){
head = new StringNode(element, null);
numElements++;
} else {
// if not, find its place first.
// then create a node and mark position link to new node
// mark new node as link to positional node
StringNode node = head;
while(node.getLink() != null){
if(node.getData().compareTo(element) < 0){
break;
}
}
StringNode newNode = new StringNode(element, null);
newNode.setLink(node.getLink());
node.setLink(newNode);
numElements++;
}
}
// Removing elements
public boolean remove(String target)
{
StringNode targetNode = head;
boolean found = false;
while (targetNode!= null && !found)
{
if(targetNode.getData().equalsIgnoreCase(target))
found = true;
else
targetNode = targetNode.getLink();
}
if(found)
{
// copy the head to targetNode
// and then advance head to the next node.
targetNode.setData(targetNode.getLink().getData());
targetNode.setLink(targetNode.getLink());
numElements --;
}
return found;
}
Solution
// Adding elements
public void add(String element) {
// For first element Head is null. So, create a new node and mark it as head.
// and increase numElements
if(head == null){
head = new StringNode(element, null);
numElements++;
} else {
// if not, find its place first.
// then create a node and mark position link to new node
// mark new node as link to positional node
StringNode node = head;
while(node.getLink() != null){
if(node.getData().compareTo(element) < 0){
break;
}
}
StringNode newNode = new StringNode(element, null);
newNode.setLink(node.getLink());
node.setLink(newNode);
numElements++;
}
}
// Removing elements
public boolean remove(String target)
{
StringNode targetNode = head;
boolean found = false;
while (targetNode!= null && !found)
{
if(targetNode.getData().equalsIgnoreCase(target))
found = true;
else
targetNode = targetNode.getLink();
}
if(found)
{
// copy the head to targetNode
// and then advance head to the next node.
targetNode.setData(targetNode.getLink().getData());
targetNode.setLink(targetNode.getLink());
numElements --;
}
return found;
}.
1) Investment Grade Domestic Bonds As bond bears a fixed rate of i.pdfaparnacollection
1) Investment Grade Domestic Bonds As bond bears a fixed rate of interest hence Mutual
Fund or ETFS can\'t Represent Bonds as an asset class. 2) High Yield Bonds 3) Domestic
stock Both are consist of shares and debentures so Mutual Fund or ETFS can\'t Represent them
as an asset class. 4) International Stock 6) Energy Similarly ETF and Mutual fund never
meet the defination of these 3 asset class so can\'t represent them 7) Commodities 8) Real
Estate 5)E merging Market Stock An emerging market fund is a mutual fund or ETF
that invests the bulk of its assets in stocks of developing countries. E merging countries are
those which are not developed yet in the stage of development i.e. china, india etc. so
invetment in these fund brings highest reurn for prospective investor. So
ETF and Mutual fund Represents E merging market stock.
Solution
1) Investment Grade Domestic Bonds As bond bears a fixed rate of interest hence Mutual
Fund or ETFS can\'t Represent Bonds as an asset class. 2) High Yield Bonds 3) Domestic
stock Both are consist of shares and debentures so Mutual Fund or ETFS can\'t Represent them
as an asset class. 4) International Stock 6) Energy Similarly ETF and Mutual fund never
meet the defination of these 3 asset class so can\'t represent them 7) Commodities 8) Real
Estate 5)E merging Market Stock An emerging market fund is a mutual fund or ETF
that invests the bulk of its assets in stocks of developing countries. E merging countries are
those which are not developed yet in the stage of development i.e. china, india etc. so
invetment in these fund brings highest reurn for prospective investor. So
ETF and Mutual fund Represents E merging market stock..
When atoms share one or more pairs of electrons t.pdfaparnacollection
When atoms share one or more pairs of electrons the bonds are called covalent
bonds.
Solution
When atoms share one or more pairs of electrons the bonds are called covalent
bonds..
This is quite simple to do. Barium sulfate is ins.pdfaparnacollection
This is quite simple to do. Barium sulfate is insoluble in water and sodium chloride
is soluble in water. So this is what you do. Dump them both in water. As I said the NaCl will
dissolve. Then do vacuum or suction filtration. That will filter out the barium sulfate from the
solution. Now the two are separate. To get the NaCl out of the water just boil it off.
Solution
This is quite simple to do. Barium sulfate is insoluble in water and sodium chloride
is soluble in water. So this is what you do. Dump them both in water. As I said the NaCl will
dissolve. Then do vacuum or suction filtration. That will filter out the barium sulfate from the
solution. Now the two are separate. To get the NaCl out of the water just boil it off..
Nitric acid is a strong acid... we can assume com.pdfaparnacollection
Nitric acid is a strong acid... we can assume complete dissociation, So [H+] is 0.04
M
Solution
Nitric acid is a strong acid... we can assume complete dissociation, So [H+] is 0.04
M.
molar ratio : 6 carbon 12 hydirgen 6 oxygen molar ratio : C : H : O = 1 : 2 : 1
Solution
molar ratio : 6 carbon 12 hydirgen 6 oxygen molar ratio : C : H : O = 1 : 2 : 1.
as Na+ ions replace H+ from H2S,as 2moles of Na+ .pdfaparnacollection
as Na+ ions replace H+ from H2S,as 2moles of Na+ are produced exactly double
H+ions will be produced.Option D
Solution
as Na+ ions replace H+ from H2S,as 2moles of Na+ are produced exactly double
H+ions will be produced.Option D.
This 3 sentence document does not provide enough context or information to generate an accurate 3 sentence summary. The document contains two sentences with the label "Dependent:" but no further details are given. Therefore, a meaningful high-level summary cannot be produced from the limited information provided.
Bear with me, Im trying to type the Lewis structure O=Se-O.pdfaparnacollection
Bear with me, I\'m trying to type the Lewis structure:
::O=Se-O:::
and there are four electrons surrounding the selenium.
So: Oxygen with four unpaired electrons and a double bond to Selenium. Selenium with four
unpaired electrons bonded by a single bond to Oxygen with six unpaired electrons.
Hope I helped!
Solution
Bear with me, I\'m trying to type the Lewis structure:
::O=Se-O:::
and there are four electrons surrounding the selenium.
So: Oxygen with four unpaired electrons and a double bond to Selenium. Selenium with four
unpaired electrons bonded by a single bond to Oxygen with six unpaired electrons.
Hope I helped!.
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...PECB
Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
-------------------------------------------------------------------------------
Find out more about ISO training and certification services
Training: ISO/IEC 27001 Information Security Management System - EN | PECB
ISO/IEC 42001 Artificial Intelligence Management System - EN | PECB
General Data Protection Regulation (GDPR) - Training Courses - EN | PECB
Webinars: https://pecb.com/webinars
Article: https://pecb.com/article
-------------------------------------------------------------------------------
For more information about PECB:
Website: https://pecb.com/
LinkedIn: https://www.linkedin.com/company/pecb/
Facebook: https://www.facebook.com/PECBInternational/
Slideshare: http://www.slideshare.net/PECBCERTIFICATION
How to Manage Your Lost Opportunities in Odoo 17 CRMCeline George
Odoo 17 CRM allows us to track why we lose sales opportunities with "Lost Reasons." This helps analyze our sales process and identify areas for improvement. Here's how to configure lost reasons in Odoo 17 CRM
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...Diana Rendina
Librarians are leading the way in creating future-ready citizens – now we need to update our spaces to match. In this session, attendees will get inspiration for transforming their library spaces. You’ll learn how to survey students and patrons, create a focus group, and use design thinking to brainstorm ideas for your space. We’ll discuss budget friendly ways to change your space as well as how to find funding. No matter where you’re at, you’ll find ideas for reimagining your space in this session.
Walmart Business+ and Spark Good for Nonprofits.pdfTechSoup
"Learn about all the ways Walmart supports nonprofit organizations.
You will hear from Liz Willett, the Head of Nonprofits, and hear about what Walmart is doing to help nonprofits, including Walmart Business and Spark Good. Walmart Business+ is a new offer for nonprofits that offers discounts and also streamlines nonprofits order and expense tracking, saving time and money.
The webinar may also give some examples on how nonprofits can best leverage Walmart Business+.
The event will cover the following::
Walmart Business + (https://business.walmart.com/plus) is a new shopping experience for nonprofits, schools, and local business customers that connects an exclusive online shopping experience to stores. Benefits include free delivery and shipping, a 'Spend Analytics” feature, special discounts, deals and tax-exempt shopping.
Special TechSoup offer for a free 180 days membership, and up to $150 in discounts on eligible orders.
Spark Good (walmart.com/sparkgood) is a charitable platform that enables nonprofits to receive donations directly from customers and associates.
Answers about how you can do more with Walmart!"
Chapter wise All Notes of First year Basic Civil Engineering.pptxDenish Jangid
Chapter wise All Notes of First year Basic Civil Engineering
Syllabus
Chapter-1
Introduction to objective, scope and outcome the subject
Chapter 2
Introduction: Scope and Specialization of Civil Engineering, Role of civil Engineer in Society, Impact of infrastructural development on economy of country.
Chapter 3
Surveying: Object Principles & Types of Surveying; Site Plans, Plans & Maps; Scales & Unit of different Measurements.
Linear Measurements: Instruments used. Linear Measurement by Tape, Ranging out Survey Lines and overcoming Obstructions; Measurements on sloping ground; Tape corrections, conventional symbols. Angular Measurements: Instruments used; Introduction to Compass Surveying, Bearings and Longitude & Latitude of a Line, Introduction to total station.
Levelling: Instrument used Object of levelling, Methods of levelling in brief, and Contour maps.
Chapter 4
Buildings: Selection of site for Buildings, Layout of Building Plan, Types of buildings, Plinth area, carpet area, floor space index, Introduction to building byelaws, concept of sun light & ventilation. Components of Buildings & their functions, Basic concept of R.C.C., Introduction to types of foundation
Chapter 5
Transportation: Introduction to Transportation Engineering; Traffic and Road Safety: Types and Characteristics of Various Modes of Transportation; Various Road Traffic Signs, Causes of Accidents and Road Safety Measures.
Chapter 6
Environmental Engineering: Environmental Pollution, Environmental Acts and Regulations, Functional Concepts of Ecology, Basics of Species, Biodiversity, Ecosystem, Hydrological Cycle; Chemical Cycles: Carbon, Nitrogen & Phosphorus; Energy Flow in Ecosystems.
Water Pollution: Water Quality standards, Introduction to Treatment & Disposal of Waste Water. Reuse and Saving of Water, Rain Water Harvesting. Solid Waste Management: Classification of Solid Waste, Collection, Transportation and Disposal of Solid. Recycling of Solid Waste: Energy Recovery, Sanitary Landfill, On-Site Sanitation. Air & Noise Pollution: Primary and Secondary air pollutants, Harmful effects of Air Pollution, Control of Air Pollution. . Noise Pollution Harmful Effects of noise pollution, control of noise pollution, Global warming & Climate Change, Ozone depletion, Greenhouse effect
Text Books:
1. Palancharmy, Basic Civil Engineering, McGraw Hill publishers.
2. Satheesh Gopi, Basic Civil Engineering, Pearson Publishers.
3. Ketki Rangwala Dalal, Essentials of Civil Engineering, Charotar Publishing House.
4. BCP, Surveying volume 1
A workshop hosted by the South African Journal of Science aimed at postgraduate students and early career researchers with little or no experience in writing and publishing journal articles.
This presentation was provided by Steph Pollock of The American Psychological Association’s Journals Program, and Damita Snow, of The American Society of Civil Engineers (ASCE), for the initial session of NISO's 2024 Training Series "DEIA in the Scholarly Landscape." Session One: 'Setting Expectations: a DEIA Primer,' was held June 6, 2024.
How to Add Chatter in the odoo 17 ERP ModuleCeline George
In Odoo, the chatter is like a chat tool that helps you work together on records. You can leave notes and track things, making it easier to talk with your team and partners. Inside chatter, all communication history, activity, and changes will be displayed.
This presentation includes basic of PCOS their pathology and treatment and also Ayurveda correlation of PCOS and Ayurvedic line of treatment mentioned in classics.
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
How to Setup Warehouse & Location in Odoo 17 InventoryCeline George
In this slide, we'll explore how to set up warehouses and locations in Odoo 17 Inventory. This will help us manage our stock effectively, track inventory levels, and streamline warehouse operations.
How to Setup Warehouse & Location in Odoo 17 Inventory
3Fe + 2O2 - Fe3O4 3 moles of Fe give 1 mol of Fe.pdf
1. 3Fe + 2O2 - Fe3O4 3 moles of Fe give 1 mol of Fe3 O4 1 mole gives, 1/3 ( 0.333)
mole of Fe3O4
Solution
3Fe + 2O2 - Fe3O4 3 moles of Fe give 1 mol of Fe3 O4 1 mole gives, 1/3 ( 0.333)
mole of Fe3O4