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AMORTIZACIONES
AMORTIZACIONES
ESTUDIANTE DE RELACIONES INDUSTRIALES
JOSE HERNANDEZ C.I 25.992.727.
INSITUTTO UNIVERSITARIO DE TECNOLOGIA ANTONIO JOSE DE SUCRE EXTENSION BARQUISIMETO.
3.5.1 Circuits
This single sentence document refers the reader to examine a specific figure, Figure 3.28, on a particular page, page 112, of a named publication, Electrical Trade Principles, to find relevant information.
4.1.1 Principles
Electromagnetic induction is the process by which a magnetic field creates an electric current. It was discovered by Michael Faraday in 1831 and describes how a changing magnetic field can generate an electric current in a conductor. This phenomenon forms the basis for electric power generation and many modern technologies including electric motors, generators, transformers, inductors and eddy current brakes.
3.1.1 Magnetising
This document defines the equations for magnetizing force, magnetic flux, and reluctance in magnetic circuits. The magnetizing force H is equal to the magnetomotive force Fm divided by the length l of the magnetic circuit. The magnetic reluctance Rm is equal to the magnetomotive force Fm divided by the magnetic flux Φ. Reluctance Rm is also equal to the length l of the circuit divided by the product of the absolute permeability μ, cross-sectional area a, relative permeability μr, and permeability of free space μ0.
6.5.2 Example
The document describes how to calculate the total current (Itotal) as the phasor sum of three currents (I1, I2, I3). It shows that I1 is 4A in phase with the voltage source. I2 is calculated to be 6.15A lagging the voltage by 75 degrees, by determining the impedance ZL of a circuit involving a resistor RL and inductor XL in series.
Recommended
AMORTIZACIONES
AMORTIZACIONES
ESTUDIANTE DE RELACIONES INDUSTRIALES
JOSE HERNANDEZ C.I 25.992.727.
INSITUTTO UNIVERSITARIO DE TECNOLOGIA ANTONIO JOSE DE SUCRE EXTENSION BARQUISIMETO.
3.5.1 Circuits
This single sentence document refers the reader to examine a specific figure, Figure 3.28, on a particular page, page 112, of a named publication, Electrical Trade Principles, to find relevant information.
4.1.1 Principles
Electromagnetic induction is the process by which a magnetic field creates an electric current. It was discovered by Michael Faraday in 1831 and describes how a changing magnetic field can generate an electric current in a conductor. This phenomenon forms the basis for electric power generation and many modern technologies including electric motors, generators, transformers, inductors and eddy current brakes.
3.1.1 Magnetising
This document defines the equations for magnetizing force, magnetic flux, and reluctance in magnetic circuits. The magnetizing force H is equal to the magnetomotive force Fm divided by the length l of the magnetic circuit. The magnetic reluctance Rm is equal to the magnetomotive force Fm divided by the magnetic flux Φ. Reluctance Rm is also equal to the length l of the circuit divided by the product of the absolute permeability μ, cross-sectional area a, relative permeability μr, and permeability of free space μ0.
6.5.2 Example
The document describes how to calculate the total current (Itotal) as the phasor sum of three currents (I1, I2, I3). It shows that I1 is 4A in phase with the voltage source. I2 is calculated to be 6.15A lagging the voltage by 75 degrees, by determining the impedance ZL of a circuit involving a resistor RL and inductor XL in series.
6.1.1 Parallel Ac Circuits
This document describes Kirchhoff's laws for electrical circuits. It shows that the total voltage around any closed loop is zero, and the total current entering a junction must equal the total current leaving that junction. Specifically, it presents equations for the voltage and current in a circuit with three resistors connected in series.
3circuitbreakers
Circuit breakers can be classified as magnetic, thermal, or thermal magnetic. Thermal circuit breakers work by heating a bimetallic strip with overcurrent, causing it to bend and open the contacts. This makes thermal circuit breakers best for overload protection but slow for short circuits. Magnetic circuit breakers use a strong magnetic field from a short circuit to force contacts open, making them faster than thermal breakers for short circuit protection. Thermal magnetic breakers combine both thermal and magnetic actions to provide protection from both overloads and short circuits.
4current
RCDs operate when an earth leakage fault is present, detecting current flow through earth. Fault currents cause circuit elements to melt, with the resulting melted sand forming an insulating barrier to cut the arc. Overloads can cause heating issues over long durations or with short circuits, while cables need sufficient size to carry currents without excessive heating due to resistance.
8.2.6
This short document provides instructions for marking a bearing, advising the reader to use a center punch to mark the bearing at the specified location. In concise terms, it outlines using a center punch to make a mark on a bearing.
7.4.1colour1
This document contains a series of numbers and letters that could be interpreted as a code or cipher. The numbers and letters are organized into distinct sections labeled 1st digit, 2nd digit, etc. and end with a phrase that may provide a clue to solving or interpreting the code.
7.1.1introduction
This document discusses resistors and their power ratings for use in electrical circuits. It mentions that resistors can dominate a total circuit and notes that precision and power ratings are important factors to consider for resistors. The document also indicates that it should be studied along with readings from an electrical trade principles textbook on resistors.
5protection
This document outlines fundamental principles for electrical installations including:
1. Protection against dangers from shock current, excessive temperatures, and explosive atmospheres.
2. Requirements for control and isolation devices to prevent hazards and allow maintenance.
3. Protection against electric shock must be provided from both direct contact with live parts and indirect contact with parts that become live due to faults. Methods of protection include basic protection under normal conditions, fault protection for single faults, and enhanced protection providing both.
6.2.1 Analyzing Parallel
This document discusses circuits and current. It states that the total current in a circuit equals the sum of the individual branch currents. It also says that the total resistance in a circuit equals the sum of the individual resistances connected in parallel. Finally, it introduces Kirchhoff's circuit laws which relate the total current and voltage in a circuit to its individual components.
10.3.3
This document discusses the relationship between rotational speed (n), frequency (f), and number of poles (p) in electric machines. It states that rotational speed (n) is equal to 120 times the frequency (f) divided by the number of poles (p). It then gives examples that a two-pole machine on a 50 Hz supply would rotate at 3000 revolutions per minute, while a four-pole machine at 50 Hz would rotate at 1500 revolutions per minute.
6protectiondirectcontact
This document discusses methods for providing basic protection against direct contact with live parts of an electrical installation. It outlines four main methods:
1) Insulation of live parts with material capable of withstanding mechanical, chemical, electrical and thermal influences. Paint or enamel alone is not sufficient.
2) Barriers or enclosures to prevent access to live parts, providing a minimum degree of protection. Openings are allowed if risks are addressed. Barriers must be securely fixed and withstand stresses.
3) Obstacles to prevent unintentional contact with live parts during normal operation, but can be intentionally circumvented. Only for use where access is restricted.
4) Placing live parts out of reach
Lighting
This document discusses various types of lighting technologies and their properties. It covers incandescent, fluorescent, high intensity discharge (HID), and emergency lighting. It provides information on spectral properties, luminous flux, luminous intensity, illuminance, efficacy, lamp types, ballasts, starters, advantages and disadvantages of each technology type. It also discusses lighting calculations, photometry, glare, distribution, and emergency evacuation lighting requirements and standards.
Microsoft TechDays 2012 France - BPOS301 La réversibilité des données dans le...
Vous réfléchissez à votre migration vers le Cloud mais vous vous posez la question de la réversibilité des données? Au cours de cette session nous lèverons vos inquiétudes et aborderons les bonnes pratiques pour s'assurer un possible retour en arrière le plus fluide possible. Nous répondrons également à la problématique d'un environnement hybride on premise/ online et comment se préparer à cette évolution et à son administration.
Google Plus et la visibilité: Pourquoi vous devez être sur Google Plus !
Saviez-vous que Google devient peu à peu Google Plus?
Si Google Plus a longtemps été qualifié de "réseau social désert", il réunit aujourd'hui plus de 300 millions d'utilisateurs actifs le propulsant ainsi au rang de second réseau social le plus peuplé.
Plus qu'un réseau social, Google Plus modifie peu à peu le paysage du web et devient indispensable à la visibilité des entreprises sur Internet.
- Comment Google a imposé son réseau social
- Quelles fonctionnalités propose Google Plus
- Comment utiliser Google Plus pour améliorer son référencement
- Comment développer une bonne stratégie de communication sur Google Plus
- Pourquoi G+ est devenu indispensable à la visibilité de votre entreprise
C'est pourquoi demain, la visibilité sur le web passera par une présence active sur Google+.
7.4.6 slip
This document describes how to calculate the rotor frequency of a two-pole, 50 Hz induction motor given the rotor speed of 2850 rpm. It shows that the slip speed is 3000 rpm, the slip percentage is 5%, and using the formula fs x %slip / 100, the rotor frequency is calculated to be 2.5 Hz.
4.2.1 Better Load
The document describes the circuits and loads for an electrical installation. It lists 19 circuits with various lighting, power outlet, motor, and appliance loads. It calculates the demand current in amps for each phase based on adding the full load or percentage of full load for each circuit based on rating and number of devices. The highest calculated demand is 153.25 amps on phase L2. With a 10% allowance for future additions, the total recommended maximum current is 168.575 amps.
4.1.13 Light Demand 3
This short document does not provide any substantive information to summarize in 3 sentences or less. It only notes that an explanation is not contained in a workbook, but provides no other context or details.
4.1.12 Light Demand 2 Table Part2
The document outlines the demand calculations for 19 different circuit load groups across 3 phases. It lists the load description, current allowance calculation method, and resulting demand current for each phase. The total demand current per phase is calculated at the bottom, with values of 143.8 amps for phase 1, 153.25 amps for phase 2, and 145.05 amps for phase 3.
4.1.11 Light Demand 2 Table
The document contains a table that calculates the current demand per phase for various circuit load groups in an electrical system. It lists 19 load groups categorized by letters A through D, describing each load. It shows the current allowance calculation method and resulting demand in amps for each phase. The total demand current calculated per phase is 143.8 amps for L1, 153.25 amps for L2, and 145.05 amps for L3.
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6.1.1 Parallel Ac Circuits
This document describes Kirchhoff's laws for electrical circuits. It shows that the total voltage around any closed loop is zero, and the total current entering a junction must equal the total current leaving that junction. Specifically, it presents equations for the voltage and current in a circuit with three resistors connected in series.
3circuitbreakers
Circuit breakers can be classified as magnetic, thermal, or thermal magnetic. Thermal circuit breakers work by heating a bimetallic strip with overcurrent, causing it to bend and open the contacts. This makes thermal circuit breakers best for overload protection but slow for short circuits. Magnetic circuit breakers use a strong magnetic field from a short circuit to force contacts open, making them faster than thermal breakers for short circuit protection. Thermal magnetic breakers combine both thermal and magnetic actions to provide protection from both overloads and short circuits.
4current
RCDs operate when an earth leakage fault is present, detecting current flow through earth. Fault currents cause circuit elements to melt, with the resulting melted sand forming an insulating barrier to cut the arc. Overloads can cause heating issues over long durations or with short circuits, while cables need sufficient size to carry currents without excessive heating due to resistance.
8.2.6
This short document provides instructions for marking a bearing, advising the reader to use a center punch to mark the bearing at the specified location. In concise terms, it outlines using a center punch to make a mark on a bearing.
7.4.1colour1
This document contains a series of numbers and letters that could be interpreted as a code or cipher. The numbers and letters are organized into distinct sections labeled 1st digit, 2nd digit, etc. and end with a phrase that may provide a clue to solving or interpreting the code.
7.1.1introduction
This document discusses resistors and their power ratings for use in electrical circuits. It mentions that resistors can dominate a total circuit and notes that precision and power ratings are important factors to consider for resistors. The document also indicates that it should be studied along with readings from an electrical trade principles textbook on resistors.
5protection
This document outlines fundamental principles for electrical installations including:
1. Protection against dangers from shock current, excessive temperatures, and explosive atmospheres.
2. Requirements for control and isolation devices to prevent hazards and allow maintenance.
3. Protection against electric shock must be provided from both direct contact with live parts and indirect contact with parts that become live due to faults. Methods of protection include basic protection under normal conditions, fault protection for single faults, and enhanced protection providing both.
6.2.1 Analyzing Parallel
This document discusses circuits and current. It states that the total current in a circuit equals the sum of the individual branch currents. It also says that the total resistance in a circuit equals the sum of the individual resistances connected in parallel. Finally, it introduces Kirchhoff's circuit laws which relate the total current and voltage in a circuit to its individual components.
10.3.3
This document discusses the relationship between rotational speed (n), frequency (f), and number of poles (p) in electric machines. It states that rotational speed (n) is equal to 120 times the frequency (f) divided by the number of poles (p). It then gives examples that a two-pole machine on a 50 Hz supply would rotate at 3000 revolutions per minute, while a four-pole machine at 50 Hz would rotate at 1500 revolutions per minute.
6protectiondirectcontact
This document discusses methods for providing basic protection against direct contact with live parts of an electrical installation. It outlines four main methods:
1) Insulation of live parts with material capable of withstanding mechanical, chemical, electrical and thermal influences. Paint or enamel alone is not sufficient.
2) Barriers or enclosures to prevent access to live parts, providing a minimum degree of protection. Openings are allowed if risks are addressed. Barriers must be securely fixed and withstand stresses.
3) Obstacles to prevent unintentional contact with live parts during normal operation, but can be intentionally circumvented. Only for use where access is restricted.
4) Placing live parts out of reach
Lighting
This document discusses various types of lighting technologies and their properties. It covers incandescent, fluorescent, high intensity discharge (HID), and emergency lighting. It provides information on spectral properties, luminous flux, luminous intensity, illuminance, efficacy, lamp types, ballasts, starters, advantages and disadvantages of each technology type. It also discusses lighting calculations, photometry, glare, distribution, and emergency evacuation lighting requirements and standards.
Microsoft TechDays 2012 France - BPOS301 La réversibilité des données dans le...
Vous réfléchissez à votre migration vers le Cloud mais vous vous posez la question de la réversibilité des données? Au cours de cette session nous lèverons vos inquiétudes et aborderons les bonnes pratiques pour s'assurer un possible retour en arrière le plus fluide possible. Nous répondrons également à la problématique d'un environnement hybride on premise/ online et comment se préparer à cette évolution et à son administration.
Google Plus et la visibilité: Pourquoi vous devez être sur Google Plus !
Saviez-vous que Google devient peu à peu Google Plus?
Si Google Plus a longtemps été qualifié de "réseau social désert", il réunit aujourd'hui plus de 300 millions d'utilisateurs actifs le propulsant ainsi au rang de second réseau social le plus peuplé.
Plus qu'un réseau social, Google Plus modifie peu à peu le paysage du web et devient indispensable à la visibilité des entreprises sur Internet.
- Comment Google a imposé son réseau social
- Quelles fonctionnalités propose Google Plus
- Comment utiliser Google Plus pour améliorer son référencement
- Comment développer une bonne stratégie de communication sur Google Plus
- Pourquoi G+ est devenu indispensable à la visibilité de votre entreprise
C'est pourquoi demain, la visibilité sur le web passera par une présence active sur Google+.
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Microsoft TechDays 2012 France - BPOS301 La réversibilité des données dans le...
Microsoft TechDays 2012 France - BPOS301 La réversibilité des données dans le...
Google Plus et la visibilité: Pourquoi vous devez être sur Google Plus !
Google Plus et la visibilité: Pourquoi vous devez être sur Google Plus !
More from Talia Carbis
7.4.6 slip
This document describes how to calculate the rotor frequency of a two-pole, 50 Hz induction motor given the rotor speed of 2850 rpm. It shows that the slip speed is 3000 rpm, the slip percentage is 5%, and using the formula fs x %slip / 100, the rotor frequency is calculated to be 2.5 Hz.
4.2.1 Better Load
The document describes the circuits and loads for an electrical installation. It lists 19 circuits with various lighting, power outlet, motor, and appliance loads. It calculates the demand current in amps for each phase based on adding the full load or percentage of full load for each circuit based on rating and number of devices. The highest calculated demand is 153.25 amps on phase L2. With a 10% allowance for future additions, the total recommended maximum current is 168.575 amps.
4.1.13 Light Demand 3
This short document does not provide any substantive information to summarize in 3 sentences or less. It only notes that an explanation is not contained in a workbook, but provides no other context or details.
4.1.12 Light Demand 2 Table Part2
The document outlines the demand calculations for 19 different circuit load groups across 3 phases. It lists the load description, current allowance calculation method, and resulting demand current for each phase. The total demand current per phase is calculated at the bottom, with values of 143.8 amps for phase 1, 153.25 amps for phase 2, and 145.05 amps for phase 3.
4.1.11 Light Demand 2 Table
The document contains a table that calculates the current demand per phase for various circuit load groups in an electrical system. It lists 19 load groups categorized by letters A through D, describing each load. It shows the current allowance calculation method and resulting demand in amps for each phase. The total demand current calculated per phase is 143.8 amps for L1, 153.25 amps for L2, and 145.05 amps for L3.
4.1.10 Light Demand 2
This 3 sentence document provides instructions to refer to a specific table on a specific page of a particular standard for additional explanatory information not contained in the current workbook. The instructions direct the reader to Table C2 on page 359 of AS/NZA 3000:2007 for an explanation that is not included in the current document.
4.1.9 Light Demand 1
The document describes the functions of 19 electrical circuits in a building. It lists the types of equipment connected to each circuit such as fluorescent lighting, outlets, motors, and appliances. It also indicates which of the 3 electrical phases (L1, L2, L3) each circuit is connected to.
4.1.7 Example Domestic 3
The document calculates the electrical load of communal services in an apartment building. It shows that 24 lighting points will draw 240 watts and 6 10A sockets will draw up to 12A, for a total demand of 18A per phase. The total demand current per phase for communal services is 18A.
4.1.6 Example Domestic 2
The document calculates the electrical load and demand for 6 living units per phase. It lists the types of loads in each unit, the quantity and allowance per unit, and uses this to calculate the total demand current for phases L1, L2 and L3, which is 154.4 amps for each phase. The key loads included are lighting, power outlets, cooking ranges, air conditioners and hot water systems.
4.1.5 Example Domestic 1
This document discusses the number of living units per phase of a project. It calculates that for 18 total living units divided into 3 phases, there would be 6 living units per phase.
4.1.4 Step 2
This document summarizes the electrical load calculations for 11 circuits in a home. It lists the load type and description for each circuit, the current allowance per unit, and calculates the demand in amps for circuits 1-10. The largest demands are 17.7 amps for an air conditioner and 15 amps for an off-peak hot water system. The total calculated demand current for each phase is 40.7, 39.5, and 46.5 amps respectively.
4.1.3 Example Solution Three
The document calculates the electrical load and demand current for 11 circuits in a home. It groups the loads into categories like lighting, outlets, appliances, and assigns each a description, allowance, and demand calculation. The total demand current per phase is summarized at the bottom, with the highest draw of 46.5 amps on phase L3.
4.1.2 Example Three
The document outlines the functions and ratings of 12 electrical circuits. Circuit 1 provides power for 13 indoor lighting points. Circuit 10 powers an air conditioner rated at 23.6 amps per phase and can draw power from circuits L1, L2, and L3. Circuits 11a and 11b each power a controlled load hot water unit rated at 3.6 kW.
4.1.1 Example Single
This document calculates the total demand current for an electrical installation consisting of:
- 21 lighting points and 12 double sockets, contributing 5A and 15A respectively
- 15 single sockets contributing 10A
- A 6kW oven contributing 0.5A
- A 2.4kW water heater contributing 0.33A
The total demand current calculated is 45.83A.
5.4.4 LR Circuits
The document discusses the time constant and final current value for an RL circuit. It states that:
1) The time constant for the circuit is 0.17 seconds based on the given inductance and resistance values.
2) It will take approximately 0.85 seconds (5 time constants) for the current to reach its final value.
3) Using Ohm's law, the approximate final current after 0.85 seconds is 2 amps.
14.5.4 Example 1 Part 1
This document calculates the apparent power, power factor, and phase angle for a circuit. It finds that the apparent power is 2.308 kVA by multiplying the current of 9.615 by the voltage of 240. This apparent power is larger than the actual power of 1.5 kW, indicating a poor power factor of 0.65 or a 49.46 degree phase angle between the current and voltage.
14.1.2 TRA Power
Reactive power (Q) and true power (P) combine to form apparent power (S). Apparent power is the combination of true power, which is the usable energy in a circuit, and reactive power, which is stored energy that results from the combination of voltage and current out of phase.
14.5.8 Example 1 Part 5
This document calculates the true power, apparent power, and total current for a circuit. It determines that the true power is 1.5 kW, the apparent power is 1.5009 kVA, and the power factor is 0.99994. It then calculates that with an apparent power of 1.5009 kVA at 240 Volts, the total current would be 6.25 amps.
More from Talia Carbis (20)
12scientificnotation B
- 1. Significant Figures 6 250 000 000 000 000 000
- 2. Scientific Notation 6 250 000 000 000 000 000 Must be represented by a number between 1-10. This = 6.25 x 1018
- 3. 6 250 000 000 000 000 000 ? .
- 4. 6 .250 000 000 000 000 000
- 5. 6 .250 000 000 000 000 000 x 10?
- 6. 6 .250 000 000 000 000 000 x 10 18
- 7. 6.25 x 1018