JIM SMITH JCHS
Checks for understanding
3108.3.3
THE EQUATION OF A CIRCLE ON
A GRAPH CAN BE DEFINED AS
( x - h )² + ( y – k )² = r²
( h , k ) = center r = radius
IF YOU HAVE THE CENTER AND RADIUS
OF A CIRCLE, PLUG IN
TO FIND THE EQUATION.
Center = ( 3 , 6 ) radius = 4
h , k r
( x - h )² + ( y – k )² = r²
( x - 3 )² + ( y – 6 )² = 4²
( x - 3 )² + ( y – 6 )² = 16
IF YOU HAVE THE CENTER AND RADIUS
OF A CIRCLE, PLUG IN
TO FIND THE EQUATION.
Center = ( -5 , 0 ) radius = 8
h , k r
( x - h )² + ( y – k )² = r²
( x - -5 )² + ( y – 0 )² = 8²
( x + 5 )² + y ² = 64
FIND THE EQUATION
OF THE CIRCLE
Center At ( 3 , 9 ) Radius = 5
( x - 3 )² + ( y - 9 )² = 25
(X + 5) ² + ( y - 3 )² = 4
x ² + y ² = 289
Center At ( -5 , 3 ) Radius = 2
Center At ( 0 , 0 ) Radius = 17
IF YOU HAVE THE EQUATION OF A
CIRCLE, UNPLUG TO FIND THE
CENTER AND RADIUS.
( x - h )² + ( y – k )² = r²
( h , k ) = center r = radius
( x - 7 )² + ( y – 1 )² = 36
Center = 7 , 1
Radius = 36 = 6
IF YOU HAVE THE EQUATION OF A
CIRCLE, UNPLUG TO FIND THE
CENTER AND RADIUS.
( x - h )² + ( y – k )² = r²
( h , k ) = center r = radius
( x + 2 )² + ( y + 9 )² = 17
( x – (- 2 ) )² + ( y - ( -9 ) )² = 17
Center = -2 , -9
Radius = 17
FIND THE CENTER AND RADIUS
OF EACH CIRCLE
( x – 11 )² + ( y – 8 )² = 25
( x – 3 )² + ( y + 1 )² = 81
( x + 6 )² + y ² = 21
Center = ( 11,8 ) Radius = 5
Center = ( 3,-1 ) Radius = 9
Center = ( -6,0 ) Radius = 21
YOU NEED TO KNOW THE CENTER AND RADIUS
TO FIND THE EQUATION OF A CIRCLE.
If A Circle Has A Center At ( 2 , 4)
And Passes Through (4 , 8 ),
What Is The Equation Of The Circle?
Center At ( 2 , 4) Passes Through (4 , 8 )
( x - 2 )² + ( y - 4 )² = r²
The Radius Is The Distance From The
Center To A Point On The Circle.
r = (x-x)² + (y-y)²
r = ( 4 – 2 )² + ( 8 – 4 )²
r = 2² + 4² = 20
( x - 2 )² + ( y - 4 )² = 20 ²
( x - 2 )² + ( y - 4 )² = 20
FIND THE EQUATION
OF THE CIRCLE
Center At ( 3 , 6 ) Passes Through ( 1 , 5 )
Center At ( 0 , 5 ) Passes Through ( 6 , 2 )
Center At ( -3 , 1 ) Passes Through (-4 , -4 )
( x - 3 )² + ( y - 6 )² = 5
x ² + ( y - 5 )² = 45
( x + 3 )² + ( y – 1 )² = 26

10-8 Equations of circles.ppt

  • 1.
    JIM SMITH JCHS Checksfor understanding 3108.3.3
  • 2.
    THE EQUATION OFA CIRCLE ON A GRAPH CAN BE DEFINED AS ( x - h )² + ( y – k )² = r² ( h , k ) = center r = radius
  • 3.
    IF YOU HAVETHE CENTER AND RADIUS OF A CIRCLE, PLUG IN TO FIND THE EQUATION. Center = ( 3 , 6 ) radius = 4 h , k r ( x - h )² + ( y – k )² = r² ( x - 3 )² + ( y – 6 )² = 4² ( x - 3 )² + ( y – 6 )² = 16
  • 4.
    IF YOU HAVETHE CENTER AND RADIUS OF A CIRCLE, PLUG IN TO FIND THE EQUATION. Center = ( -5 , 0 ) radius = 8 h , k r ( x - h )² + ( y – k )² = r² ( x - -5 )² + ( y – 0 )² = 8² ( x + 5 )² + y ² = 64
  • 5.
    FIND THE EQUATION OFTHE CIRCLE Center At ( 3 , 9 ) Radius = 5 ( x - 3 )² + ( y - 9 )² = 25 (X + 5) ² + ( y - 3 )² = 4 x ² + y ² = 289 Center At ( -5 , 3 ) Radius = 2 Center At ( 0 , 0 ) Radius = 17
  • 6.
    IF YOU HAVETHE EQUATION OF A CIRCLE, UNPLUG TO FIND THE CENTER AND RADIUS. ( x - h )² + ( y – k )² = r² ( h , k ) = center r = radius ( x - 7 )² + ( y – 1 )² = 36 Center = 7 , 1 Radius = 36 = 6
  • 7.
    IF YOU HAVETHE EQUATION OF A CIRCLE, UNPLUG TO FIND THE CENTER AND RADIUS. ( x - h )² + ( y – k )² = r² ( h , k ) = center r = radius ( x + 2 )² + ( y + 9 )² = 17 ( x – (- 2 ) )² + ( y - ( -9 ) )² = 17 Center = -2 , -9 Radius = 17
  • 8.
    FIND THE CENTERAND RADIUS OF EACH CIRCLE ( x – 11 )² + ( y – 8 )² = 25 ( x – 3 )² + ( y + 1 )² = 81 ( x + 6 )² + y ² = 21 Center = ( 11,8 ) Radius = 5 Center = ( 3,-1 ) Radius = 9 Center = ( -6,0 ) Radius = 21
  • 9.
    YOU NEED TOKNOW THE CENTER AND RADIUS TO FIND THE EQUATION OF A CIRCLE. If A Circle Has A Center At ( 2 , 4) And Passes Through (4 , 8 ), What Is The Equation Of The Circle?
  • 10.
    Center At (2 , 4) Passes Through (4 , 8 ) ( x - 2 )² + ( y - 4 )² = r² The Radius Is The Distance From The Center To A Point On The Circle. r = (x-x)² + (y-y)² r = ( 4 – 2 )² + ( 8 – 4 )² r = 2² + 4² = 20 ( x - 2 )² + ( y - 4 )² = 20 ² ( x - 2 )² + ( y - 4 )² = 20
  • 11.
    FIND THE EQUATION OFTHE CIRCLE Center At ( 3 , 6 ) Passes Through ( 1 , 5 ) Center At ( 0 , 5 ) Passes Through ( 6 , 2 ) Center At ( -3 , 1 ) Passes Through (-4 , -4 ) ( x - 3 )² + ( y - 6 )² = 5 x ² + ( y - 5 )² = 45 ( x + 3 )² + ( y – 1 )² = 26