10 million.Sensory conflict theory argues , The brightest light at.pdf

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10 million. Sensory conflict theory argues , The brightest light at which we can see is about 10 million times as intense as the dimmest light at which we can see. Solution 10 million. Sensory conflict theory argues , The brightest light at which we can see is about 10 million times as intense as the dimmest light at which we can see..

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1.Rule based detection 2.Statical anomaly detection 1.Rule based detection : a set of rules are used to decide the behaviour of an intruder in this detection we have anomaly detection and penitration identification .in anomaly detection rules are developed to detect deviation from previous usage patterns. in penitration identification an expert system approach that searches for suspecious behaviour 2.Statistical anomaly datection : the collection of data relating to the behaviour of legitimate users over a period of time. then statistical tests are applied to observed behaviour to determine with a high level of confidence whethear that behaviour is not legitimate user behaviour in this detection we have threshold detection and profile based detection .in threshold detection it approaches to defining thresholds,independent of user,for the frequency of occurence of various events and in profile based a profile of the activity of each user is developed and used to detect changes in the behaviour of individual accounts. Solution 1.Rule based detection 2.Statical anomaly detection 1.Rule based detection : a set of rules are used to decide the behaviour of an intruder in this detection we have anomaly detection and penitration identification .in anomaly detection rules are developed to detect deviation from previous usage patterns. in penitration identification an expert system approach that searches for suspecious behaviour 2.Statistical anomaly datection : the collection of data relating to the behaviour of legitimate users over a period of time. then statistical tests are applied to observed behaviour to determine with a high level of confidence whethear that behaviour is not legitimate user behaviour in this detection we have threshold detection and profile based detection .in threshold detection it approaches to defining thresholds,independent of user,for the frequency of occurence of various events and in profile based a profile of the activity of each user is developed and used to detect changes in the behaviour of individual accounts..

14 = disease ff24 = carriers Ff25 chances that they will pro.pdf

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Mosses, lichens are great indicators of radioactive pollution. They .pdf

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Mosses, lichens are great indicators of radioactive pollution. They absorb radioactive elements specifically caesium as it is similar to patassium which forms important nutrient of mosses. Edible mushrooms too get contaminated with such harmful elements. Hence mosses and lichens serve as indicators for radioactive pollution areas. Inorder to check such pollution, one can collect moss samples and check their element content of radioactive pollution. Elements like lead, caesium, barium, titanium, berrylium are the important elements contributing o radioactive pollution. Mosses show mutations involving somatic type giving out flowers of different colors. Also, the mosses get damaged by reducing the plant vigor. Solution Mosses, lichens are great indicators of radioactive pollution. They absorb radioactive elements specifically caesium as it is similar to patassium which forms important nutrient of mosses. Edible mushrooms too get contaminated with such harmful elements. Hence mosses and lichens serve as indicators for radioactive pollution areas. Inorder to check such pollution, one can collect moss samples and check their element content of radioactive pollution. Elements like lead, caesium, barium, titanium, berrylium are the important elements contributing o radioactive pollution. Mosses show mutations involving somatic type giving out flowers of different colors. Also, the mosses get damaged by reducing the plant vigor..

We first find the slopes of the two lines 2M an.pdf

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We first find the slopes of the two lines: 2/M and -1/4 For two lines to be perpendicylar, the product of their slopes must be equal to -1. Hence the equation (2/M)*(-1/4) = -1. Solve for M to find M = 1/2. Solution We first find the slopes of the two lines: 2/M and -1/4 For two lines to be perpendicylar, the product of their slopes must be equal to -1. Hence the equation (2/M)*(-1/4) = -1. Solve for M to find M = 1/2..

SO2 is a gas that mixes with water to form sulfur.pdf

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SO2 is a gas that mixes with water to form sulfuric acid. The droplets can form clouds like water does (Venus is covered with them making it bright). Sulfuric acid has a high albedo (it reflects light), since it reflects the light, the energy it blocked from coming down. Therefore the electromagnetic radiation (aka light) cannot is not converted into thermal energy (it converts from light to thermal when it smacks into things). Therefore since the light cannot make it to the surface, the thermal energy will decrease (molecules will slow down) and the temperature will theoretically drop. :) I said theoretically because I\'m not quite sure how strong of a greenhouse gas CO2 is (I\'m not sure if it would trap any heat that did manage to get in) as compared to water vapor, but it doesn\'t sound like they care about that. :) Anyway sorry if I wrote that in a confusing way, basically the light will reflect off the clouds of sulfuric acid and so the light can\'t heat up the earth. Also, its better in the stratosphere because the sooner the light is blocked, the less it will heat up molecules it smacks into on the way down. Solution SO2 is a gas that mixes with water to form sulfuric acid. The droplets can form clouds like water does (Venus is covered with them making it bright). Sulfuric acid has a high albedo (it reflects light), since it reflects the light, the energy it blocked from coming down. Therefore the electromagnetic radiation (aka light) cannot is not converted into thermal energy (it converts from light to thermal when it smacks into things). Therefore since the light cannot make it to the surface, the thermal energy will decrease (molecules will slow down) and the temperature will theoretically drop. :) I said theoretically because I\'m not quite sure how strong of a greenhouse gas CO2 is (I\'m not sure if it would trap any heat that did manage to get in) as compared to water vapor, but it doesn\'t sound like they care about that. :) Anyway sorry if I wrote that in a confusing way, basically the light will reflect off the clouds of sulfuric acid and so the light can\'t heat up the earth. Also, its better in the stratosphere because the sooner the light is blocked, the less it will heat up molecules it smacks into on the way down..

1. Heterozygosity by migration calculated using the below formulaH.pdf

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1. Heterozygosity by migration calculated using the below formula H= 1 - F where F= finite population N= Population size F= 1/ (2N) By substituting F = 1/ (2N) in H= 1- F H= 1 - 1/ 2N H= 1 - 1/2 x 1000 = 0.9995 2. Heterozygosity by mutational drift can be calculated using H= 4Nu / 1+ 4Nu u= mutation rate H= 4 x 1000 x 1 x 10-9 / 1 + 4 x 1000 x 10-9 = 3.9 x 10-6 Heterozygosity is decreased by mutation and migration. The differences in the values is large because large mutation rates causes totally shift of the population and evolves into new species. But migration will not act as fast as mutation . Solution 1. Heterozygosity by migration calculated using the below formula H= 1 - F where F= finite population N= Population size F= 1/ (2N) By substituting F = 1/ (2N) in H= 1- F H= 1 - 1/ 2N H= 1 - 1/2 x 1000 = 0.9995 2. Heterozygosity by mutational drift can be calculated using H= 4Nu / 1+ 4Nu u= mutation rate H= 4 x 1000 x 1 x 10-9 / 1 + 4 x 1000 x 10-9 = 3.9 x 10-6 Heterozygosity is decreased by mutation and migration. The differences in the values is large because large mutation rates causes totally shift of the population and evolves into new species. But migration will not act as fast as mutation ..

1).Monohybrid cross between true breeding parents. Assume that the.pdf

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1). Monohybrid cross between true breeding parents. Assume that the gene “A” is dominant and “a” is recessive. The genotype of parents are, AA (true breeding for dominant), aa (true breeding for recessive). Genotypes of the true-breeding parents in the _____parental___ generation are ___AA__ and ___aa_. Genotype(s) of the offspring from the true-breeding parents is(are)_Aa____and the symbol for this generation of offspring is __F1__. Punnet square: AA (male) and aa (female) A A a Aa Aa a Aa Aa A A a Aa Aa a Aa Aa Solution 1). Monohybrid cross between true breeding parents. Assume that the gene “A” is dominant and “a” is recessive. The genotype of parents are, AA (true breeding for dominant), aa (true breeding for recessive). Genotypes of the true-breeding parents in the _____parental___ generation are ___AA__ and ___aa_. Genotype(s) of the offspring from the true-breeding parents is(are)_Aa____and the symbol for this generation of offspring is __F1__. Punnet square: AA (male) and aa (female) A A a Aa Aa a Aa Aa A A a Aa Aa a Aa Aa.

1. Moving down a group, the electronegativity decreases due to the l.pdf

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1. Moving down a group, the electronegativity decreases due to the longer distance between the nucleus and the valence electron shell, thereby decreasing the attraction, making the atom have less of an attraction for electrons or protons. 2.Trend-wise, as one moves from left to right across a period in the periodic table, the electronegativity increases due to the stronger attraction that the atoms obtain as the nuclear charge increases. Solution 1. Moving down a group, the electronegativity decreases due to the longer distance between the nucleus and the valence electron shell, thereby decreasing the attraction, making the atom have less of an attraction for electrons or protons. 2.Trend-wise, as one moves from left to right across a period in the periodic table, the electronegativity increases due to the stronger attraction that the atoms obtain as the nuclear charge increases..

1 Ans Bacteria are unicellular organisms that reproduce by cell division, while viruses are acellular and are incapable of reproducing on their own and they need a living host. 2 Ans Persistant viral infections are slow viral infections progressive over a long period of time and are usually fatal. Examples: AIDS dementia comples (HIV) Progressive encephalitis (Rubella virus) Latent viral infection can remain in host cells throughout life without causing disease. They may be reactivated by immunosuppression, however, and cause disease. Examples: Cold sores Shingles Solution 1 Ans Bacteria are unicellular organisms that reproduce by cell division, while viruses are acellular and are incapable of reproducing on their own and they need a living host. 2 Ans Persistant viral infections are slow viral infections progressive over a long period of time and are usually fatal. Examples: AIDS dementia comples (HIV) Progressive encephalitis (Rubella virus) Latent viral infection can remain in host cells throughout life without causing disease. They may be reactivated by immunosuppression, however, and cause disease. Examples: Cold sores Shingles.

1#include stdio.h#include stdlib.h#include assert.h .pdf

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1 #include #include #include /* Link list node */ struct node { int data; struct node* next; }; /* Given a reference (pointer to pointer) to the head of a list and an int, push a new node on the front of the list. */ void push(struct node** head_ref, int new_data) { /* allocate node */ struct node* new_node = (struct node*) malloc(sizeof(struct node)); /* put in the data */ new_node->data = new_data; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref) = new_node; } /* Takes head pointer of the linked list and index as arguments and return data at index*/ int GetNth(struct node* head, int index) { struct node* current = head; int count = 0; /* the index of the node we\'re currently looking at */ while (current != NULL) { if (count == index) return(current->data); count++; current = current->next; } /* if we get to this line, the caller was asking for a non-existent element so we assert fail */ assert(0); } /* Drier program to test above function*/ int main() { /* Start with the empty list */ struct node* head = NULL; /* Use push() to construct below list 1->12->1->4->1 */ push(&head, 1); push(&head, 4); push(&head, 1); push(&head, 12); push(&head, 1); /* Check the count function */ printf(\"Element at index 3 is %d\", GetNth(head, 3)); getchar(); } 2 #include #include #include /* Link list node */ struct node { int data; struct node* next; }; /* Given a reference (pointer to pointer) to the head of a list and an int, push a new node on the front of the list. */ void push(struct node** head_ref, int new_data) { /* allocate node */ struct node* new_node = (struct node*) malloc(sizeof(struct node)); /* put in the data */ new_node->data = new_data; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref) = new_node; } /* Takes head pointer of the linked list and index as arguments and return data at index*/ int GetNth(struct node* head, int index) { struct node* current = head; int count = 0; /* the index of the node we\'re currently looking at */ while (current != NULL) { if (count == index) return(current->data); count++; current = current->next; } /* if we get to this line, the caller was asking for a non-existent element so we assert fail */ assert(0); } /* Drier program to test above function*/ int main() { /* Start with the empty list */ struct node* head = NULL; /* Use push() to construct below list 1->12->1->4->1 */ push(&head, 1); push(&head, 4); push(&head, 1); push(&head, 12); push(&head, 1); /* Check the count function */ printf(\"Element at index 3 is %d\", GetNth(head, 3)); getchar(); } Solution 1 #include #include #include /* Link list node */ struct node { int data; struct node* next; }; /* Given a reference (pointer to pointer) to the head of a list and an int, push a new node on the front of the list. */ void push(struct node** head_ref, int new_data) { /* allocate node */ struct node*.

Ques-6 answerThe clinical significance of beta-hemolytic (on blo.pdf

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Ques-6: answer: The clinical significance of beta-hemolytic (on blood agar medium) streptococci isolated from throat specimen is consequent incidence of rheumatoid fever and acute glomerulonephritis. Streptococcus pneumoniae (normally present in our body, can be found in the upper respiratory tract) is an organism that cause upper respiratory tract infections and otitis media. When children with running nose touch each other, the organism passed through the secretions. This causes infection in the healthy child, decreased immunity against the bacteria and increased activation of the flora causes otitis media (a painful ear infection) in children. These respiratory bacteria produce inflammatory virulent toxins to invade respiratory cells and nutrients finally become pathogenic to host immune system result in severe respiratory illness. Throat infections caused by beta-hemolytic streptococcal bacteria may cause \"post-streptococcal glomerulonephritis\" if left untreated. Therefore, patient needs treatment to treat these symptoms (antibiotics such as penicillin, corticosteroids and diuretics are to be given). The bacteria causes inflammation of the blood vessels supplying glomeruli, which impairs the glomerular filtration. Decreased urine filtration causes edema (swelling of body organs). Ques-7: The infection is strep throat and streptococcal bacteria (group B) cause it. These bacteria infect the upper respiratory tract and causes fever, sore throat, abdominal pain, fatigue, vomiting, body aches. In a Gram stain of sputum specimen of beta hemolytic streptococci, \"squamous epithelial cell type\" of body cell provides an indication that the sputum specimen represents material from an active infection. Other cells are present in the sputum during the active infection are polymorphonuclear leukocytes (PMNs) Solution Ques-6: answer: The clinical significance of beta-hemolytic (on blood agar medium) streptococci isolated from throat specimen is consequent incidence of rheumatoid fever and acute glomerulonephritis. Streptococcus pneumoniae (normally present in our body, can be found in the upper respiratory tract) is an organism that cause upper respiratory tract infections and otitis media. When children with running nose touch each other, the organism passed through the secretions. This causes infection in the healthy child, decreased immunity against the bacteria and increased activation of the flora causes otitis media (a painful ear infection) in children. These respiratory bacteria produce inflammatory virulent toxins to invade respiratory cells and nutrients finally become pathogenic to host immune system result in severe respiratory illness. Throat infections caused by beta-hemolytic streptococcal bacteria may cause \"post-streptococcal glomerulonephritis\" if left untreated. Therefore, patient needs treatment to treat these symptoms (antibiotics such as penicillin, corticosteroids and diuretics are to be given). The bacteria causes inflammat.

Valence electrons electrons at outer-most energy level.Effective.pdf

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Valence electrons : electrons at outer-most energy level. Effective nuclear charge: net positive charge experienced by an electron in a multi-electron atom. Atomic radius: distance from the nucleus to the boundary of the surrounding cloud of electrons. Ionic radius: measure of the size of an atom\'s ion. Ionization Energy: nergy needed to remove electrons from an atom. Electron Affinity: the energy change when an electron is added to the neutral atom to form a negative ion. Electronegativity: tendency of an atom or a functional group to attract electrons. Oxidation number (or Oxidation state): hypothetical charge that an atom would have if all bonds to atoms of different elements were 100% ionic. Oxidation: Lossing electrons Reductio: Gaining electrons Oxidizing agent: Element being Reduced Reducing agent: Element being Oxidized Covalent Bond: chemical bonding by shaing of electrons (Non-metal with Non-metal). Ionic Bond: chemical bonding of non-metal and metal Compounds: combinations of two or more elements Octet rule: maximum of 8 electrons (in the valence shell) can be added during a reaction. Electrolytes: substance that can conduct electricity. Hydration: chemical reaction when adding water. Solubility: property of a solid, liquid, or gaseous chemical substance mix with one other to form a homogeneous solution. Concentration: abundance of a constituent divided by the total volume of a mixture. Dilute: lowering the concentration of a chemical. Concentrated solution: solution in which much of the water has been removed. Brønsted acid: proton donor. Brønsted base: proton acceptor. Monoprotic acids: donate one proton per molecule during the process of dissociation. Diprotic acids: donate two protons per molecule during the process of dissociation. Triprotic acids: donate three protons per molecule during the process of dissociation. pH: measure of acidity and basic of a solution. Strong acid: ionizes completely in an aqueous solution by losing one proton. Weak acids: acid that dissociates incompletely. Strong base: accept hydrogen ions or more generally or donate electron pairs. Weak base: does not ionize fully in an aqueous solution Supersaturated solution: solute > solvent Saturated solution: solute = solvent unsaturated solution: solute < solvent Solution Valence electrons : electrons at outer-most energy level. Effective nuclear charge: net positive charge experienced by an electron in a multi-electron atom. Atomic radius: distance from the nucleus to the boundary of the surrounding cloud of electrons. Ionic radius: measure of the size of an atom\'s ion. Ionization Energy: nergy needed to remove electrons from an atom. Electron Affinity: the energy change when an electron is added to the neutral atom to form a negative ion. Electronegativity: tendency of an atom or a functional group to attract electrons. Oxidation number (or Oxidation state): hypothetical charge that an atom would have if all bonds to atoms of different elements were 10.

What is storage mediaAns-C. the physical material on which a co.pdf

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What is storage media? Ans- C. the physical material on which a computer keeps data, instructions, and information Storage media are devices that store application and user information. Storage media is device on which data can be electronically places kept and retrieved .The primary storage media for a computer is usually the internal hard drive. Solution What is storage media? Ans- C. the physical material on which a computer keeps data, instructions, and information Storage media are devices that store application and user information. Storage media is device on which data can be electronically places kept and retrieved .The primary storage media for a computer is usually the internal hard drive..

Transactional model of communication states that if people are conne.pdf

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Transactional model of communication states that if people are connected through communication, they engage in transaction. It propogates that communication is simultaneous. 5 parts or labels: The first part is the sender and receiver - they are the people involved in the communication. The 2nd part is the message i.e the information being send/received. The 3rd part is the channel of communication. The 4th part is the response and the decoding of messages by the sender/receiver. The 5th part is the feedback. It is different from the linear model of communication, in the sense that unlike the one way model in the linear communication, the transactional model is a simultaneous model. Linear model does not involve any feedback, unlike the transactional model. Ethics means rules of behavior based on ideas about what is right and wrong. Interpersonal communication is exchange of information between 2 or more people. The ethical choices involved here is that one should be humble and polite in conversations. One should not hurt the other person\'s religious or cultural beliefs. I grew up in an Asian culture in the Indian subcontinent. My family and my society was orthodox in thinking. This made me (as well as other people growing up and exposed to this culture) not much of a risk taker. This was due to the fact that we were made to believe that god will always help us, whatever happens, happens for good (destiny). If i had grown in a different culture, i probably would be more of a risk taker. Adam has perception problems. He does not interpret sensory information correctly. His cognitive (senses of the mind) powers are not that strong. He can improve his communication by focusing on proxemics i.e non verbal communication. He should have a strong body movement (kinesics) for better non verbal communication. It includes facial expressions, gestures etc. He should also focus on paralanguage - the tone and pitch of his voice. Solution Transactional model of communication states that if people are connected through communication, they engage in transaction. It propogates that communication is simultaneous. 5 parts or labels: The first part is the sender and receiver - they are the people involved in the communication. The 2nd part is the message i.e the information being send/received. The 3rd part is the channel of communication. The 4th part is the response and the decoding of messages by the sender/receiver. The 5th part is the feedback. It is different from the linear model of communication, in the sense that unlike the one way model in the linear communication, the transactional model is a simultaneous model. Linear model does not involve any feedback, unlike the transactional model. Ethics means rules of behavior based on ideas about what is right and wrong. Interpersonal communication is exchange of information between 2 or more people. The ethical choices involved here is that one should be humble and polite in conversations. One should not hur.

What is the measure of the strength of the relationship between inde.pdf

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Some of the SO32- is oxidized by atmospheric oxygen in air into SO42.pdf

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Some of the SO32- is oxidized by atmospheric oxygen in air into SO42-: 2 SO32-(aq) + O2 (g) --> 2 SO42-(aq) Thus a positive test forSO42-is expected in solutions ofSO32-even when noSO42-has been placed. Solution Some of the SO32- is oxidized by atmospheric oxygen in air into SO42-: 2 SO32-(aq) + O2 (g) --> 2 SO42-(aq) Thus a positive test forSO42-is expected in solutions ofSO32-even when noSO42-has been placed..

Should begin with a letter and may contain additional letters and di.pdf

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Should begin with a letter and may contain additional letters and digits. Identifiers are the same as variables. Use descriptive n Use single letters only for the counter in loops. Variable names start with lower-case Multi-word identifiers are internally capitalized Do not use hyphens or underscores to separate multi-word identifiers. Need to print extra characters? What about the unicode set? This is the format: \\uHHHH Remember any other escape characters such as \ , \\t and \\\\? The following lists some of these conventions based on the type of identifier: Class name The first letter of each word is capitalized, examples: Mammal, SeaMammal Function name The first letter of each, except the first, word is capitalized, examples: getAge, setHeight Variable name The first letter of each, except the first, word is capitalized, examples: age, brainSize Constant names Every letter is capitalized and underscores are used between words, examples: MAX_HEIGHT, MAX_AGE RESERVED WORDS As you may have noticed, many of Java\'s keywords are borrowed from C/C++. Also, as in C/C++, keywords are always written in lowercase. Data declaration keywords (boolean, float, int) Loop keywords (continue, while, for) Conditional keywords (if, else, switch) Exception keywords (try, throw, catch) Structure keywords (class, extends) Modifier and access keywords (private, public) Miscellaneous keywords (true, null) The following keywords and their use, you SHOULD know. boolean default for private switch break double if protected this case else import public throws catch extends int return try char final new static void class float package super while VARIABLE SCOPE Where is it appropriate to declare a variable? Does it make a difference? PRIMITIVE DATA TYPES int (16-bit) float (32-bit) double (64-bit boolean (true/false) char (16-bit unicode) What about String? What about Integer, and Double? OBJECTS Why object oriented programming? Objects need to be built, so we need constructors. Instance variables and the role they play when defining objects. What about methods of an object? ARRAYS int[] array = new int[5]; // one-dimensional array it may also be declared as: int[] array = {1, 2, 3, 4, 5}; // it is initialized and declared at the same time. Arrays can be of any primitive data type or object. Arrays have an instance variable \"length\" that we can access to find out how big the array is. Remember that an Array can throw an IndexOutOfBoundsException. Make use of it to make your code safe. VECTORS Must import java.util.*; Unlike arrays, vectors can only hold objects, no primitive data types are allowed. Vectors can grow big and unbounded. You may want to specify the capacity of the vector but you dont need to. The default capacity is 10 and it doubles in size every time the capacity is reached. Just like arrays have the \"length\" instance variable, Vectors have a .size() method that returns the current size of the vector. void .addElement(Object obj) void .setElementA.

#include iostream #include string #include iomanip #incl.pdf

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#include #include #include #include #include #include using std::cin; using std::cout; using std::string; using std::endl; using std::vector; static const string colors[] = { \"red\", \"green\", \"blue\", \"cyan\", \"magenta\", \"yellow\" }; static const int PEGNUM = 4; static int getRandomValue() { static bool first = true; if (first) { first = false; srand((int)time(0)); } return(rand()); } static string easyToLower(string word) { transform(word.begin(), word.end(), word.begin(), ::tolower); return word; } inline string trim(string& str) // courtesy of stack overflow { str.erase(0, str.find_first_not_of(\' \')); //prefixing spaces str.erase(str.find_last_not_of(\' \') + 1); //surfixing spaces return str; } static vector setNewCode() { vector theCode; for (int i = 0; i < PEGNUM; i++) { theCode.push_back(colors[getRandomValue() % 6]); } return theCode; } static vector getPlayerGuess() { vector words; string in = \"\", word=\"\"; bool okay = false; bool quitting = false; while (!okay) { cout << \"Enter your guess (red, green, blue, cyan, magenta, yellow. Enter 4 colors): \ \"< 0) //get input { in = trim(in); index = in.find_first_of(\" \"); if (index == -1) { word = in; in = \"\"; } else word = in.substr(0, index); words.push_back(word); in = in.substr(index+1); if (words.size() == PEGNUM) { break; } } okay = true; for (int i = 0; i < words.size(); i++) // check and standardize inputs { words[i] = easyToLower(words[i]); if (words[i] == \"red\" || words[i] == \"r\") { words[i] = colors[0]; //cout << words[i] << endl; } else if (words[i] == \"green\" || words[i] == \"g\") { words[i] = colors[1]; //cout << words[i] << endl; } else if (words[i] == \"blue\" || words[i] == \"b\") { words[i] = colors[2]; //cout << words[i] << endl; } else if (words[i] == \"cyan\" || words[i] == \"c\") { words[i] = colors[3]; //cout << words[i] << endl; } else if (words[i] == \"magenta\" || words[i] == \"m\") { words[i] = colors[4]; //cout << words[i] << endl; } else if (words[i] == \"yellow\" || words[i] == \"y\") { words[i] = colors[5]; //cout << words[i] << endl; } else if (words[i] == \"quit\") { quitting = true; words.clear(); words.push_back(\"quit\"); return words; } else { cout << words[i] << \" is an invalid submittion\" << endl; words.clear(); okay = false; } } if (!okay) cout << \"Invalid entry. Please try again\ \" << endl; if (words.size() != PEGNUM) // check if 4 entries { cout << \"Must enter 4 colors. Try again\ \" << endl; words.clear(); okay = false; } } return words; } static int setBlackPegs(vector theCode, vector guessCode) { int bps = 0; for (int i = 0; i < PEGNUM; i++) { if (theCode[i] == guessCode[i]) bps++; } return bps; } static int setWhitePegs(vector theCode, vector guessCode, int bps) { int RGBCMYnumsTheCode[6]; int RGBCMYnumsGuessCode[6]; int wps=0; for (int i = 0; i < 6; i++) { RGBCMYnumsTheCode[i] = 0; RGBCMYnumsGuessCode[i] = 0; } for (int i = 0; i < PEGNUM; i++) { if (theCode[i] == colors[0]) { RGBCMYnumsTheCode[0]++; } else if (theCo.

Prostomes are mollusca, annelids and arthropods while deuterostomes .pdf

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KCl is salt and having ionic forces between ions.So, its boiling poi.pdf

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KCl is salt and having ionic forces between ions.So, its boiling point is more and ranked first compare to remaining two. CH2O is liquid in solution and its having intermolcular hydrogen bonding.So, its boiling point is more compare to CO2 and ranked second. CO2 is gas at room temperature due to vandarval forces between molecules.So, its boiling point is less compare to remaining two and ranked three. Hence, the decreasing order of boiling points of given molecules is, KCl > CH2O > CO2 Solution KCl is salt and having ionic forces between ions.So, its boiling point is more and ranked first compare to remaining two. CH2O is liquid in solution and its having intermolcular hydrogen bonding.So, its boiling point is more compare to CO2 and ranked second. CO2 is gas at room temperature due to vandarval forces between molecules.So, its boiling point is less compare to remaining two and ranked three. Hence, the decreasing order of boiling points of given molecules is, KCl > CH2O > CO2.

Income Statement of Baker and Co.Services Provided$98000Intere.pdf

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Income Statement of Baker and Co. Services Provided $98000 Interest($13000*6%*4/12) $260 Total Income $98260 Salary Expenses $34000 Uncollectible Account Expense $980 Net Income $63280 Dividend $2000 Transferred to retained earnings $61280 Balance Sheet of Baker & Co Liabilities Assets Owners equity $190000 Accounts Receivables $13020 Retained Earnings $61280 Investment(with Interest Accrued) $13260 Cash $225000 Total $251280 Total $251280 Cash A/c Owners Equity $190000 Investment $13000 Accounts Receivables $84000 Salary $34000 Dividend $2000 Balance $225000 $274000 $274000 Cash Flow Statement Cash from Operating Activities Cash generated from operations $63280 Less Dividend $2000 Less Interest income $260 Less Increase in Accounts Receivables 13020 $48000 Cash From Investing Activities ($13000) Investments ($13000) Cash From Financing Activities Proceeds from Shares Issued $190000 $190000 Cash and Cash equivalents at the beginning of the year 0 Cash and Cash equivalents at the Ending of the year $225000 Statement of Changes of Share holders Equity Share Holders Equity $190000 Add Retained Earnings $61280 Share Holders Equity as on 31-12-2010 $251280 Income Statement of Baker and Co. Services Provided $98000 Interest($13000*6%*4/12) $260 Total Income $98260 Salary Expenses $34000 Uncollectible Account Expense $980 Net Income $63280 Dividend $2000 Transferred to retained earnings $61280 Solution Income Statement of Baker and Co. Services Provided $98000 Interest($13000*6%*4/12) $260 Total Income $98260 Salary Expenses $34000 Uncollectible Account Expense $980 Net Income $63280 Dividend $2000 Transferred to retained earnings $61280 Balance Sheet of Baker & Co Liabilities Assets Owners equity $190000 Accounts Receivables $13020 Retained Earnings $61280 Investment(with Interest Accrued) $13260 Cash $225000 Total $251280 Total $251280 Cash A/c Owners Equity $190000 Investment $13000 Accounts Receivables $84000 Salary $34000 Dividend $2000 Balance $225000 $274000 $274000 Cash Flow Statement Cash from Operating Activities Cash generated from operations $63280 Less Dividend $2000 Less Interest income $260 Less Increase in Accounts Receivables 13020 $48000 Cash From Investing Activities ($13000) Investments ($13000) Cash From Financing Activities Proceeds from Shares Issued $190000 $190000 Cash and Cash equivalents at the beginning of the year 0 Cash and Cash equivalents at the Ending of the year $225000 Statement of Changes of Share holders Equity Share Holders Equity $190000 Add Retained Earnings $61280 Share Holders Equity as on 31-12-2010 $251280 Income Statement of Baker and Co. Services Provided $98000 Interest($13000*6%*4/12) $260 Total Income $98260 Salary Expenses $34000 Uncollectible Account Expense $980 Net Income $63280 Dividend $2000 Transferred to retained earnings $61280.

In the list above. OH is a strong base in its ionic form ofOH- a.pdf

sudhinjv

In the list above. OH is a strong base in its ionic form ofOH- and NH2- is also a strong base. between Cl and I. I is a weakerbase and the better leaving group. I hope that helped. Just remember the weaker the base thebetter the leaving group. Solution In the list above. OH is a strong base in its ionic form ofOH- and NH2- is also a strong base. between Cl and I. I is a weakerbase and the better leaving group. I hope that helped. Just remember the weaker the base thebetter the leaving group..

import java.util.Arrays;import components.simplereader.SimpleReade.pdf

sudhinjv

import java.util.Arrays; import components.simplereader.SimpleReader; import components.simplereader.SimpleReader1L; import components.simplewriter.SimpleWriter; import components.simplewriter.SimpleWriter1L; public class ABCDGuesser2 { /** * Constructor. */ private ABCDGuesser2() { } /** * Program entry point. */ public static void main(String[] args) { SimpleReader in = new SimpleReader1L(); SimpleWriter out = new SimpleWriter1L(); //ALT CODE FOR = ALT+230 //0,12,11,16 final double[] exponents = { -5, -4, -3, -2, -1, (double) -1 / 2, (double) -1 / 3, (double) -1 / 4, 0, (double) 1 / 4, (double) 1 / 3, (double) 1 / 2, 1, 2, 3, 4, 5 }; System.out.println(Arrays.toString(exponents)); double constant, w, x, y, z; out.print(\"Enter your favorite constant to estimate: \"); constant = in.nextDouble(); out.print(\"Enter your first favorite number(Not 1): \"); w = in.nextDouble(); out.print(\"Enter your second favorite number(Not 1): \"); x = in.nextDouble(); out.print(\"Enter your thrird favorite number(Not 1): \"); y = in.nextDouble(); out.print(\"Enter your fourth favorite number(Not 1): \"); z = in.nextDouble(); int a1 = 0, b1 = 0, c1 = 0, d1 = 0; double estimate = 0; double lowError = error(constant, estimate); for (int a = 0; a < exponents.length; a++) { for (int b = 0; b < exponents.length; b++) { for (int c = 0; c < exponents.length; c++) { for (int d = 0; d < exponents.length; d++) { double newEstimate = Math.pow(w, exponents[a]) * Math.pow(x, exponents[b]) * Math.pow(y, exponents[c]) * Math.pow(z, exponents[d]); double newError = error(constant, newEstimate); if (newError < lowError) { estimate = newEstimate; lowError = newError; a1 = a; b1 = b; c1 = c; d1 = d; } } } } } out.println(\": \" + constant); out.println(\"Estimate: \" + estimate); out.println(\"ABDC Values: \" + exponents[a1] + \" \" + exponents[b1] + \" \" + exponents[c1] + \" \" + exponents[d1]); out.println(\"Error = \" + error(constant, estimate) + \" %\"); } /** * Calcuates the % error between the two numbers * */ private static double error(double a, double b) { return Math.abs(a - b) / a * 100; } } Solution import java.util.Arrays; import components.simplereader.SimpleReader; import components.simplereader.SimpleReader1L; import components.simplewriter.SimpleWriter; import components.simplewriter.SimpleWriter1L; public class ABCDGuesser2 { /** * Constructor. */ private ABCDGuesser2() { } /** * Program entry point. */ public static void main(String[] args) { SimpleReader in = new SimpleReader1L(); SimpleWriter out = new SimpleWriter1L(); //ALT CODE FOR = ALT+230 //0,12,11,16 final double[] exponents = { -5, -4, -3, -2, -1, (double) -1 / 2, (double) -1 / 3, (double) -1 / 4, 0, (double) 1 / 4, (double) 1 / 3, (double) 1 / 2, 1, 2, 3, 4, 5 }; System.out.println(Arrays.toString(exponents)); double constant, w, x, y, z; out.print(\"Enter your favorite constant to estimate: \"); constant = in.nextDouble(); out.print(\"Enter your first favorite number(Not 1): \"); w = in.nextDoub.

Hydrophobic substances are water repelling and not water attracting .pdf

sudhinjv

Hydrophobic substances are water repelling and not water attracting or interacting moecules. Thus, the given statement is \'False\'. Hydrophobic substances do not dissolve in water because water is polar substance. Thus, the given statement is \'False\'. Hydrophobic molecules form weak interactions between them and are not attracted strongly to each other. Thus, the given statement is \'False\'. Hydrophobic molecules include alkanes, oils, fats etc. These molecules are rich in C-C and C-H bonds. Thus, the given statement is \'True\'. Hydrophobic molecules are nonpolar and do not have charge. Polar molecules like water contain partial charges due to uneven bonding and electronegative oxygen atom in it. Thus, the given statement is \'False\'. Solution Hydrophobic substances are water repelling and not water attracting or interacting moecules. Thus, the given statement is \'False\'. Hydrophobic substances do not dissolve in water because water is polar substance. Thus, the given statement is \'False\'. Hydrophobic molecules form weak interactions between them and are not attracted strongly to each other. Thus, the given statement is \'False\'. Hydrophobic molecules include alkanes, oils, fats etc. These molecules are rich in C-C and C-H bonds. Thus, the given statement is \'True\'. Hydrophobic molecules are nonpolar and do not have charge. Polar molecules like water contain partial charges due to uneven bonding and electronegative oxygen atom in it. Thus, the given statement is \'False\'..

E is the answer note only E involves the oxidat.pdf

sudhinjv

E is the answer note: only E involves the oxidation state change of elements. N in NH4 is -3 oxidation state N in NO3 is +5 oxidation state N in N2O is +1 oxidation state. the oxidation state of N changes from -3 and +5 into +1. Solution E is the answer note: only E involves the oxidation state change of elements. N in NH4 is -3 oxidation state N in NO3 is +5 oxidation state N in N2O is +1 oxidation state. the oxidation state of N changes from -3 and +5 into +1..

I worte the code according to the requirement.And also I wrote the c.pdf

sudhinjv

I worte the code according to the requirement.And also I wrote the code to continue the program until user enters 4 to quit the program. If you want me to do any modifications other than these I will modify. ________________________________________ GeometricShape.java public class GeometricShape { private double side1, side2, side3; //These are the variables necessary to calculat the perimeter of a triangle private double radius; //Radius is needed to calculate the perimeter of a circle private double length, width; //Length and Width are needed to calculate the perimeter of a rectangle private boolean isTriangle = false; private boolean isRectangle = false; private boolean isCircle = false; //Constructor for a triangle public GeometricShape(double aSide1, double aSide2, double aSide3) { side1 = aSide1; side2 = aSide2; side3 = aSide3; isTriangle = true; } //Task #1a - Finish writing an Overloaded Constructor for a rectangle here: (don\'t forget to set isRectangle to true) public GeometricShape(double aLength, double aWidth) { this.length=aLength; this.width=aWidth; isRectangle=true; } //Task #1b - Write an Overloaded Constructor for a circle here: (don\'t forget to set isCircle to true) public GeometricShape(double radius) { this.radius=radius; isCircle=true; } public double getRadius() { return radius; } public double getSide1() { return side1; } public double getSide2() { return side2; } public double getSide3() { return side3; } public double getLength() { return length; } public double getWidth() { return width; } public void setRadius(double aRadius) { radius = aRadius; } public void setSide1(double aSide1) { side1 = aSide1; } public void setSide2(double aSide2) { side2 = aSide2; } public void setSide3(double aSide3) { side3 = aSide3; } public void setLength(double aLength) { length = aLength; } public void setWidth(double aWidth) { width = aWidth; } public double getPerimeter() { double perimeter =0; //Calculate the perimeter of the Geometric object depending on what the object is. //Remember the following formulas: //Perimeter of a Triangle = Side1 + Side2+ Side3 //Perimeter of a Rectangle = (2 * length) + (2 * width) //Perimeter of a Circle = 2 * Math.PI * radius if (isTriangle == true) { //Complete formula for triangle perimeter perimeter = side1 + side2 + side3; } else if (isRectangle == true) { //Task 2a: Complete formula for rectangle perimeter perimeter= (2 * length) + (2 * width); } else if (isCircle == true) { //Task 2b: Complete formula for circle perimeter perimeter=2 * Math.PI * radius; } //Continue with the rest of the else if logic here. //change return statement to match the perimeter of the shape return perimeter; } public String toString() { if (isTriangle == true) { //Return \"It\'s a Triangle: \" and concatenate all the attributes of a triangle return \"It\'s a Triangle, with side1 = \" + side1 + \" side2 = \" + side2 + \" side3 = \"+ side3; } else if (isRectangle == true) { //Task 3a: return \"It\'s a Rectangle: \" a.

Future value of annuity due = (1+r) Annuity amount{(1+r)n-1}rA.pdf

sudhinjv

Future value of annuity due = (1+r) * Annuity amount*{(1+r)n-1}/r Annuity amount = $2,200 Number of periods = n = 14 Interest rate = r = 12% = 0.12 Future value of annuity = 1.12 * $2,200*(1.1214-1)/0.12 = 1.12*$71,263.73 = $79,815.37 Solution Future value of annuity due = (1+r) * Annuity amount*{(1+r)n-1}/r Annuity amount = $2,200 Number of periods = n = 14 Interest rate = r = 12% = 0.12 Future value of annuity = 1.12 * $2,200*(1.1214-1)/0.12 = 1.12*$71,263.73 = $79,815.37.

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