(1 point) The combined math and verbal scores for females taking the S.pdf
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(1 point) The combined math and verbal scores for females taking the SAT-I test are normally distributed with a mean of 998 and a standard deviation of 202 (based on date from the College Board). If a college includes a minimum score of 825 among its requirements, what percentage of females do not satisfy that requirement? %.
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(1 point) The age distribution for senators in the 104th U-S- Congress.pdf
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handling multiple combinations of donor type and pledge amount as input. The donor name and
pledge amount should be retrieved and displayed for each pledge that matches the donor type
and is greater than the pledge amount indicated. Use a collection to provide the input data. Test
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(----IN C) Incorrect output on some test cases- I'm using a linked lis.pdf
(****IN C) Incorrect output on some test cases.
I'm using a linked list to take in information about a person and using structs to find the oldest
and youngest person in the list; however, I am having trouble with some test cases. For the most
part, The code seems to work the way I want it to, but certain test cases do have wrong outputs.
For example:
Input File Has Four Entries(2 Youngest are in the Same Month)
Here is the text file:
Smith,Bob,July,31,2002,CS/BS,Junior
Joe,Average,February,3,2002,CS/BS,Freshman
Doe,Jane,July,27,2003,CS/BS,Sophomore
Doe,John,July,12,2003,CS/BS,Sophomore:
Output:
Oldest - John Doe & Youngest Jane Doe.
John is clearly not the oldest in the list so please help, below is my code.
//add birthday struct here
struct birthday
{
int day, year;
char month[50];
}; typedef struct birthday bday;
//add node_t struct here (this struct will represent a node in the linked list)
struct node
{
char firstName[50], lastName[50], major[50], classStanding[50];
bday bd;
struct node* next;
};
typedef struct node node_t;
struct stats
{
// node pointer pointing at the oldest and youngest person in the list
node_t* oldest;
node_t* youngest;
// holding the number of birthdays in each month (0 = Jan. & 11 = Dec.)
int numBD[12];
}; typedef struct stats list_stats_t;
void add(node_t **node, node_t **head)
{
(*node)->next = *head;
*head = *node;
}
node_t* readNodeInfo(FILE* input)
{
node_t *node;
node = (node_t*)malloc(sizeof(node_t)); // allocates memory
char newLine[1]; // reads new line character
// uses scanset to read information between commas
fscanf(input, "%[^,], %[^,], %[^,], %d, %d, %[^,], %[^\n] %[\n]",
node->lastName, node->firstName, node->bd.month,
&node->bd.day, &node->bd.year, node->major,
node->classStanding, newLine);
return node;
}
node_t* createList(FILE* in, node_t** head)
{
node_t *temp;
while(!feof(in)) // loops until end of file in
{
temp = readNodeInfo(in); // calls function and assigns it to temp
add(&temp, head); // adds to linked list
}
return *head;
}
void printList(FILE* out, node_t* head) // prints data
{
// if there is no data in the linked list, print error code to terminal
if (head == NULL)
{
fprintf(stderr, "LIST IS EMPTY\n");
return;
}
node_t *temp = head;
printBorder(out);
fprintf(out, "\nList Info:\n");
while (temp != NULL)
{
fprintf(out, "Name:\t%s %s\n", temp->firstName, temp->lastName);
fprintf(out, "Date of Birth:\t%s %d, %d\n", temp->bd.month,
temp->bd.day,
temp->bd.year);
fprintf(out, "Major:\t%s\n", temp->major);
fprintf(out, "Year:\t%s\n\n", temp->classStanding);
temp = temp->next; // next element
}
printBorder(out);
}
void printBorder(FILE* out)
{
int i = 0;
for(i = 0; i < 80; i++)
fprintf(out,"*");
fprintf(out, "\n");
}
void deleteList(node_t** head) // deletes all nodes within the linked list
{
// deref head to get the real head
node_t* current = *head;
node_t* temp = NULL;
while (current != NULL)
{
temp = current->next;
free(current);
current = temp;
}
// deref head reference to affect the re.
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handling multiple combinations of donor type and pledge amount as input. The donor name and
pledge amount should be retrieved and displayed for each pledge that matches the donor type
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(****IN C) Incorrect output on some test cases.
I'm using a linked list to take in information about a person and using structs to find the oldest
and youngest person in the list; however, I am having trouble with some test cases. For the most
part, The code seems to work the way I want it to, but certain test cases do have wrong outputs.
For example:
Input File Has Four Entries(2 Youngest are in the Same Month)
Here is the text file:
Smith,Bob,July,31,2002,CS/BS,Junior
Joe,Average,February,3,2002,CS/BS,Freshman
Doe,Jane,July,27,2003,CS/BS,Sophomore
Doe,John,July,12,2003,CS/BS,Sophomore:
Output:
Oldest - John Doe & Youngest Jane Doe.
John is clearly not the oldest in the list so please help, below is my code.
//add birthday struct here
struct birthday
{
int day, year;
char month[50];
}; typedef struct birthday bday;
//add node_t struct here (this struct will represent a node in the linked list)
struct node
{
char firstName[50], lastName[50], major[50], classStanding[50];
bday bd;
struct node* next;
};
typedef struct node node_t;
struct stats
{
// node pointer pointing at the oldest and youngest person in the list
node_t* oldest;
node_t* youngest;
// holding the number of birthdays in each month (0 = Jan. & 11 = Dec.)
int numBD[12];
}; typedef struct stats list_stats_t;
void add(node_t **node, node_t **head)
{
(*node)->next = *head;
*head = *node;
}
node_t* readNodeInfo(FILE* input)
{
node_t *node;
node = (node_t*)malloc(sizeof(node_t)); // allocates memory
char newLine[1]; // reads new line character
// uses scanset to read information between commas
fscanf(input, "%[^,], %[^,], %[^,], %d, %d, %[^,], %[^\n] %[\n]",
node->lastName, node->firstName, node->bd.month,
&node->bd.day, &node->bd.year, node->major,
node->classStanding, newLine);
return node;
}
node_t* createList(FILE* in, node_t** head)
{
node_t *temp;
while(!feof(in)) // loops until end of file in
{
temp = readNodeInfo(in); // calls function and assigns it to temp
add(&temp, head); // adds to linked list
}
return *head;
}
void printList(FILE* out, node_t* head) // prints data
{
// if there is no data in the linked list, print error code to terminal
if (head == NULL)
{
fprintf(stderr, "LIST IS EMPTY\n");
return;
}
node_t *temp = head;
printBorder(out);
fprintf(out, "\nList Info:\n");
while (temp != NULL)
{
fprintf(out, "Name:\t%s %s\n", temp->firstName, temp->lastName);
fprintf(out, "Date of Birth:\t%s %d, %d\n", temp->bd.month,
temp->bd.day,
temp->bd.year);
fprintf(out, "Major:\t%s\n", temp->major);
fprintf(out, "Year:\t%s\n\n", temp->classStanding);
temp = temp->next; // next element
}
printBorder(out);
}
void printBorder(FILE* out)
{
int i = 0;
for(i = 0; i < 80; i++)
fprintf(out,"*");
fprintf(out, "\n");
}
void deleteList(node_t** head) // deletes all nodes within the linked list
{
// deref head to get the real head
node_t* current = *head;
node_t* temp = NULL;
while (current != NULL)
{
temp = current->next;
free(current);
current = temp;
}
// deref head reference to affect the re.
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## Part B: Conway's Game of Life
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<img src="images/game-of-life-1.png"
alt="Game of Life example"
style="display: block; margin: 0 auto; width:650px;"/>
Many living cell patterns have been discovered that result in
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as a tuple where the first element is a tuple of two integers $(w,h)$
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following function, which takes as input the width and height:
makeWorld :: (Int,Int) -> ((Int,Int), [[Bool]])
makeWorld dims@(w,h) = (dims, replicate h (replicate w False))
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liveNeighbors :: ((Int,Int), [[Bool]]) -- world
-> (Int,Int) -- cell
-> Int -- number of living neighbors
nextWorld :: ((Int,Int), [[Bool]]) -- world
-> ((Int,Int), [[Bool]]) -- next world (one generation later)
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#include -algorithm- #include -cstdlib- #include -iostream- #include -.pdf
#include <algorithm>
#include <cstdlib>
#include <iostream>
#include <iterator>
/************************************************************/
// Local includes
/************************************************************/
// Using declarations
// YOU DO NOT NECESSARILY NEED TO USE ALL OF THESE!
using std::copy;
using std::copy_backward;
using std::distance;
using std::fill;
using std::ostream;
using std::ptrdiff_t;
/************************************************************/
template<typename T>
class Array
{
public:
//*****************************************************
// DO NOT MODIFY THIS SECTION!
// Some standard Container type aliases
using value_type = T;
// Iterators are just pointers to objects of type T
using iterator = value_type*;
using const_iterator = const value_type*;
using reference = value_type&;
using const_reference = const value_type&;
using size_type = size_t;
using difference_type = ptrdiff_t;
//*****************************************************
// Default ctor.
// Initialize an empty Array.
// This method is complete, and does NOT need modification.
// Remember to use a _member initialization list_ for each ctor,
// like I have below for the default ctor.
Array ()
: m_size (0),
m_capacity (0),
m_array (nullptr)
{
}
// Size ctor.
// Initialize an Array of size "pSize", with each element
// set to "value".
explicit Array (size_t pSize, const T& value = T ())
: m_size (pSize),
m_capacity (pSize),
m_array (new T[m_capacity])
{
fill (begin (), end (), value);
}
// TODO!
// Range ctor.
// Initialize an Array from the range [first, last).
// "first" and "last" must be Array iterators or pointers
// into a primitive array.
Array (const_iterator first, const_iterator last)
:m_size(distance(first,last)),m_capacity(m_size),m_array(new T[m_capacity])
{
copy(first,last,m_array);
}
// TODO!
// Copy ctor.
// Initialize this object from "a".
Array (const Array& a)
:m_size(a.m_size),m_capacity(a.m_capacity),m_array(new T[m_capacity])
{
copy(a.begin(),a.end(),m_array);
}
// TODO!
// Destructor.
// Release allocated memory.
~Array ()
{
delete[] m_array;
}
// TODO!
// Assignment operator.
// Assign "a" to this object.
// Be careful to check for self-assignment.
Array&
operator= (const Array& a)
{
if (this != &a)
{
delete[] m_array;
m_size = a.m_size;
m_capacity = a.m_capacity;
m_array = new T[m_capacity];
copy(a.begin(),a.end(),m_array);
}
return *this;
}
// Return the size.
size_t
size () const
{
return m_size;
}
// TODO!
// Return true if this Array is empty, false o/w.
bool
empty () const
{
return m_size == 0;
}
// TODO!
// Return the capacity.
size_t
capacity () const
{
return m_capacity;
}
// TODO!
// Return the element at position "index".
T& operator[] (size_t index)
{
return m_array[index];
}
// TODO!
const T& operator[] (size_t index) const
{
return m_array[index];
}
// TODO!
// Insert an element at the back.
// If the capacity is insufficient, DOUBLE it.
// If the capacity is 0, increase it to 1.
void
push_back (const T&.
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statements are "in accordance with gencrally accepted accounting principles applicable to
governmental entities in the United States" or some other phrase? Is the opinion qualified in
some manner, disclaimed, or adverse? Does the auditor indicate that the opinion covers the basic
financial statements or that plus combining statements? (2) Basic Financial Statements. Does the
CAFR contain the two governmentwide financial statements and seven fund statements and
required reconciliation? (3) Notes to the Financial Statements. How many notes follow the
required basic financial statements? Is there a phrase at the bottom of the basic financial
statements indicating that the notes are an integral part of the financial statements? (4) Individual
Fund and Combining Statements. Following the notes to the financial statements, does the CAFR
provide combining and individual fund statements? Do these combining statements aggregate all
the funds of a given fund type or all the nonmajor funds? (5) Management's Discussion and
Analysis (MD\&A). Does the CAFR contain an MD\&A? If so, where is it located and what type
of information does it contain?.
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Reason:
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#4 concepts of programming language question:
(a) Explain the advantages of a system programming language versus an application
programming language.
(b) Explain what are the differences in the structure of a compiler and an interpreter.
(c) Which is more efficient at runtime, an object-oriented programming program or a non
object-oriented program? Explain..
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(2) Twelve major earthquakes on Richter mapnitades had shown here. Find (a) the mean, (b) the
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## Part B- Conway's Game of Life ### Introduction John Conway's Ga.pdf
## Part B: Conway's Game of Life
### Introduction
John Conway's Game of Life is a well known "game" with a very simple set of
rules that can simulate incredibly sophisticated behavior (as sophisticated, in
fact, as any computer program). Its setting -- which we'll refer to as the
game's "world" -- is a two-dimensional grid of cells, each one either living or
dead, and considered to be in contact with its eight neighbors (i.e.,
orthogonally or diagonally adjacent cells).
Given the state of each cell in the world at time $t_n$, we can compute the
state of each cell at time $t_{n+1}$ (i.e., one generation later) using the
following rules:
- **Birth rule**: a dead cell with exactly three living neighbors comes alive.
- **Survival rule**: a living cell with two to three neighbors remains alive.
- **Death rule**: a living cell with zero or one neighbors dies in isolation; a
living cell with four or more neighbors dies of overcrowding
The image below depicts a world before and after the rules are applied to a
group of cells.
<img src="images/game-of-life-1.png"
alt="Game of Life example"
style="display: block; margin: 0 auto; width:650px;"/>
Many living cell patterns have been discovered that result in
stable/non-changing shapes and repeatedly oscillating shapes, among other types
(see the [example patterns in the Game of Life Wikipedia
article](https://en.wikipedia.org/wiki/Conway%27s_Game_of_Life#Examples_of_patterns)
for some). An interesting fact about the Game of Life is that there is no
algorithm which can reliably predict whether or not a given pattern will appear
in the world given some starting state (this is related to the halting problem,
covered in CS 330).
Since each world state (after the initial state) is a pure function of the
preceding one, and the game world can be easily modeled using lists,
implementing the Game of Life makes for another fun list processing
exercise!
### Implementation in Haskell
We will represent the game world using the type: `((Int,Int), [[Bool]])`. I.e.,
as a tuple where the first element is a tuple of two integers $(w,h)$
representing the width and height of the world, and the second element is a list
of lists of Booleans representing the 2D grid, where each sublist of length
$w$ represents the cells in a row of the world, with $h$ sublists total.
A barren (i.e., containing only dead cells) world can be created with the
following function, which takes as input the width and height:
makeWorld :: (Int,Int) -> ((Int,Int), [[Bool]])
makeWorld dims@(w,h) = (dims, replicate h (replicate w False))
In "src/MP2b.hs" you will find declarations for functions you must complete to
implement the Game of Life. The first two functions compute the number of live
neighbors of a cell and the next world state:
liveNeighbors :: ((Int,Int), [[Bool]]) -- world
-> (Int,Int) -- cell
-> Int -- number of living neighbors
nextWorld :: ((Int,Int), [[Bool]]) -- world
-> ((Int,Int), [[Bool]]) -- next world (one generation later)
To animat.
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can use it to manage their bank accounts, transfer funds, pay bills, and access other banking
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(1) (5 points) A doubly linked list is a linear data structure where (1) each element (called node)
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woekers who have ilegally entered tho US should be fillowed to keep their fobs and apply for US
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poitical ideology are consistent wht the table shown below. Round all answers to four decimal
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#include <algorithm>
#include <cstdlib>
#include <iostream>
#include <iterator>
/************************************************************/
// Local includes
/************************************************************/
// Using declarations
// YOU DO NOT NECESSARILY NEED TO USE ALL OF THESE!
using std::copy;
using std::copy_backward;
using std::distance;
using std::fill;
using std::ostream;
using std::ptrdiff_t;
/************************************************************/
template<typename T>
class Array
{
public:
//*****************************************************
// DO NOT MODIFY THIS SECTION!
// Some standard Container type aliases
using value_type = T;
// Iterators are just pointers to objects of type T
using iterator = value_type*;
using const_iterator = const value_type*;
using reference = value_type&;
using const_reference = const value_type&;
using size_type = size_t;
using difference_type = ptrdiff_t;
//*****************************************************
// Default ctor.
// Initialize an empty Array.
// This method is complete, and does NOT need modification.
// Remember to use a _member initialization list_ for each ctor,
// like I have below for the default ctor.
Array ()
: m_size (0),
m_capacity (0),
m_array (nullptr)
{
}
// Size ctor.
// Initialize an Array of size "pSize", with each element
// set to "value".
explicit Array (size_t pSize, const T& value = T ())
: m_size (pSize),
m_capacity (pSize),
m_array (new T[m_capacity])
{
fill (begin (), end (), value);
}
// TODO!
// Range ctor.
// Initialize an Array from the range [first, last).
// "first" and "last" must be Array iterators or pointers
// into a primitive array.
Array (const_iterator first, const_iterator last)
:m_size(distance(first,last)),m_capacity(m_size),m_array(new T[m_capacity])
{
copy(first,last,m_array);
}
// TODO!
// Copy ctor.
// Initialize this object from "a".
Array (const Array& a)
:m_size(a.m_size),m_capacity(a.m_capacity),m_array(new T[m_capacity])
{
copy(a.begin(),a.end(),m_array);
}
// TODO!
// Destructor.
// Release allocated memory.
~Array ()
{
delete[] m_array;
}
// TODO!
// Assignment operator.
// Assign "a" to this object.
// Be careful to check for self-assignment.
Array&
operator= (const Array& a)
{
if (this != &a)
{
delete[] m_array;
m_size = a.m_size;
m_capacity = a.m_capacity;
m_array = new T[m_capacity];
copy(a.begin(),a.end(),m_array);
}
return *this;
}
// Return the size.
size_t
size () const
{
return m_size;
}
// TODO!
// Return true if this Array is empty, false o/w.
bool
empty () const
{
return m_size == 0;
}
// TODO!
// Return the capacity.
size_t
capacity () const
{
return m_capacity;
}
// TODO!
// Return the element at position "index".
T& operator[] (size_t index)
{
return m_array[index];
}
// TODO!
const T& operator[] (size_t index) const
{
return m_array[index];
}
// TODO!
// Insert an element at the back.
// If the capacity is insufficient, DOUBLE it.
// If the capacity is 0, increase it to 1.
void
push_back (const T&.
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accelerated due to factors such as agriculture and urbanization. Information regarding land use and
cover is essential for various planning and management tasks related to the Earth's surface,
providing crucial environmental data for scientific, resource management, policy purposes, and
diverse human activities.
Accurate understanding of land use and cover is imperative for the development planning
of any area. Consequently, a wide range of professionals, including earth system scientists, land
and water managers, and urban planners, are interested in obtaining data on land use and cover
changes, conversion trends, and other related patterns. The spatial dimensions of land use and
cover support policymakers and scientists in making well-informed decisions, as alterations in
these patterns indicate shifts in economic and social conditions. Monitoring such changes with the
help of Advanced technologies like Remote Sensing and Geographic Information Systems is
crucial for coordinated efforts across different administrative levels. Advanced technologies like
Remote Sensing and Geographic Information Systems
9
Changes in vegetation cover refer to variations in the distribution, composition, and overall
structure of plant communities across different temporal and spatial scales. These changes can
occur natural.
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Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
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