Optimal cross section area of conductor

Matlap prog
a=50:100
k1=10^-4;
k2=2*(10^5);
d=0.08;
cr=k1*(10^6)./a;
cf=k2*d*(10^-6).*a;
ctot=cr+cf;
opt=sqrt(k1/(k2*d))
figure(1)
plot(a,cr)
figure(2)
plot(a,cf)
figure(3)
plot(a,ctot)

output.
Plot(a,cr)
Plot(a,cf)

Plot(a,ct)

Experiment (3)
Incremental fuel cost
Matlap prog.
p=10:100;
f=10^6.*(40+(4.*p)+(0.012.*p.^2));
i=0.12*10^-6;
h=f./p;
c=i.*h;
figure(1)
plot(p,f)
figure(2)
plot(p,h)
figure(3)
plot(p,c)

output
plot (p,F)

Plot (p,h)
Plot (p,c)

1

  • 1.
    Optimal cross sectionarea of conductor Matlap prog a=50:100 k1=10^-4; k2=2*(10^5); d=0.08; cr=k1*(10^6)./a; cf=k2*d*(10^-6).*a; ctot=cr+cf; opt=sqrt(k1/(k2*d)) figure(1) plot(a,cr) figure(2) plot(a,cf) figure(3) plot(a,ctot) output. Plot(a,cr)
  • 2.
  • 3.
    Incremental fuel cost Matlapprog. p=10:100; f=10^6.*(40+(4.*p)+(0.012.*p.^2)); i=0.12*10^-6; h=f./p; c=i.*h; figure(1) plot(p,f) figure(2) plot(p,h) figure(3) plot(p,c) output plot (p,F) Plot (p,h)
  • 4.