Evaluate the following limits. If needed, enter INF for infinity and MINF for -infinity. Solution write it as ((1 - 5/x +1/x2 ) -1)/1/x both numerator and denominator are going to 0 so by differentiating it we\'ll get 1/2(1 - 5/x +1/x2 ) / (-1/x^2) -x^2 / 2(1 - 5/x +1/x2 ) so numerator isgonig fast this will give -inf answer = -inf.