Radio Station call letters consist of four uppercase letters which may repeat but must begin with either a W or a K. If call letters are assigned at random, what is the probability that the second or third letter is an A but not both? Please provide details and explain. Solution if 2nd letter is A we have 25 other options to fill 3rd place if 3rd letter is A we have 25 other options to fill 2nd place . so total ways posiible when A is 2nd or 3rd letter = 25 + 25 = 50 Total no of ways in which 2nd and 3rd places can be filled = 26 * 26 = 676 so required probability = 50 / 676 = 0.074.