the procedures and requirements of international business correspond.pdf

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the procedures and requirements of international business correspondence Solution International correspondence is an integral part of a trading house which is done through written communication. Procedures: Letters: Parties of international trade, like importer and exporter, can communicate through letters, like placing an inquiry and subsequent replying of it. Such letters are usually delivered through speed post. Email: This is the way of connecting people through internet. Queries and information are two vital parts in this form, like the information about product quality and discount rates are communicated. Text message: This could be done through mobile phone of having international facility. It helps in quick communication. Requirements: Evidence: International correspondence through any one of the above procedures gives proper evidence of communication. Parties involved can’t deny of such, since this is enforceable by law. Reference: Such correspondences are kept for future reference; suppose the reference of discount, price, acceptance of order, etc..

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Indicicate the coordinaiton number of the metal and oxidation number of the metal as well as the number and type of each donor atom of the ligands for the folloing complexes: Na2[CdBr4] [Pt(en)3](ClO4)4 [Co(en)2(C2O4)] + Also, Likely coordination number of the metal in: Na2[Co(EDTA)Br] Thanks. Solution 1) Donar atom: Br; Oxidation number: +2; type: monodentate ligand, metal is Cd 2) Donar atom: en and ClO4; Oxidation number: +4; type: en is bidentate ligand, ClO4 is monodentate ligand; metal is Pt 3) Donar atom: en and C2O4; Oxidation number: +3; type: en is neutal bidentate ligand, C2O4 is bidentate ligand with -2 charge; metal : Co 4) Donar atom: EDTA and Br; Oxidation number: +3; type: EDTA is charged tetradentate ligand (having -4 chagre), Br is charged monodentate ligand (having -1 charge)..

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Please need help on C++ language. Infix to Postfix) Write a program that converts an infix expression into an equivalent postfix expression. The rules to convert an infix expression into an equivalent postfix expression are as follows: Initialize pfx to an empty expression and also initialize the stack. Get the next symbol, sym, from infx. If sym is an operand, append sym to pfx. If sym is (, push sym into the stack. If sym is ), pop and append all of the symbols from the stack until the most recent left parentheses. Pop and discard the left parentheses. If sym is an operator: Pop and append all of the operators from the stack to pfx that are above the most recent left parentheses and have precedence greater than or equal to sym. Push sym onto the stack. After processing infx, some operators might be left in the stack. Pop and append to pfx everything from the stack. In this program, you will consider the following (binary) arithmetic operators: +, -, *, and /. You may assume that the expressions you will process are error free. Design a class that stores the infix and postfix strings. The class must include the following operations: getInfix: Stores the infix expression. showInfix: Outputs the infix expression. showPostfix: Outputs the postfix expression. convertToPostfix: Converts the infix expression into a postfix expression. The resulting postfix expression is stored in pfx. precedence: Determines the precedence between two operators. If the first operator is of higher or equal precedence than the second operator, it returns the value true; otherwise, it returns the value false. A + B - C; (A + B ) * C; (A + B) * (C - D); A + ((B + C) * (E - F) - G) / (H - I); A + B * (C + D ) - E / F * G + H; Infix Expression: A+B-C; Postfix Expression: AB+C- Infix Expression: (A+B)*C; Postfix Expression: AB+C* Infix Expression: (A+B)*(C-D); Postfix Expression: AB+CD-* Infix Expression: A+((B+C)*(E-F)-G)/(H-I); Postfix Expression: ABC+EF-*G-HI-/+ Infix Expression: A+B*(C+D)-E/F*G+H; Postfix Expression: ABCD+*+EF/G*-H+ PLEASE PROVIDE FOLLOWING. A UML diagram for your class. The header file for your class. The implementation file for your class. The source code for your test program. Solution #include using namespace std; const int MAX = 50 ; class InfixToPostfix { private : char target[MAX], stack[MAX] ; char *s, *t ; int top ; public : InfixToPostfix( ) ; void getInfix ( char *str ) ; void showInfix () ; void push ( char c ) ; char pop( ) ; void convertToPostfix( ) ; int precedence ( char c ) ; void showPostfix( ) ; void Delete(); } ; InfixToPostfix :: InfixToPostfix( ) { top = -1 ; strcpy ( target, \"\" ) ; strcpy ( stack, \"\" ) ; t = target ; s = \"\" ; } void InfixToPostfix :: getInfix ( char *str ) { s = str ; } void InfixToPostfix :: showInfix ( ) { cout<<\"Infix Expression :\"<= precedence ( *s ) ) { *t = opr ; t++ ; opr = pop( ) ; } push ( opr ) ; push ( *s ) ; } else push ( *s ) ; s++ ; } if ( *s == \')\' ) { opr = pop( ) ; while ( ( opr ) != \.

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