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Yes. You can prove it experimentally, but if you want a logical reason, look at the electronegativities of Li and F. F is much more electronegative, and will have a lot of the electron density around it, whereas Li will have much less. (In fact LiF is considered an ionic compound with Li+ and F-.) Solution Yes. You can prove it experimentally, but if you want a logical reason, look at the electronegativities of Li and F. F is much more electronegative, and will have a lot of the electron density around it, whereas Li will have much less. (In fact LiF is considered an ionic compound with Li+ and F-.).

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Yes. You can prove it experimentally, but if you want a logical reason, look at the electronegativities of Li and F. F is much more electronegative, and will have a lot of the electron density around it, whereas Li will have much less. (In fact LiF is considered an ionic compound with Li+ and F-.) Solution Yes. You can prove it experimentally, but if you want a logical reason, look at the electronegativities of Li and F. F is much more electronegative, and will have a lot of the electron density around it, whereas Li will have much less. (In fact LiF is considered an ionic compound with Li+ and F-.)

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Yes. You can prove it experimentally, but if you.pdf

  • 1. Yes. You can prove it experimentally, but if you want a logical reason, look at the electronegativities of Li and F. F is much more electronegative, and will have a lot of the electron density around it, whereas Li will have much less. (In fact LiF is considered an ionic compound with Li+ and F-.) Solution Yes. You can prove it experimentally, but if you want a logical reason, look at the electronegativities of Li and F. F is much more electronegative, and will have a lot of the electron density around it, whereas Li will have much less. (In fact LiF is considered an ionic compound with Li+ and F-.)