1. Project 2 : Lighting and Acoustics Integration with
Design Studio 5
Tutor : Mr. Sanjey Raman
Nadia Othman 0303423
1
2. 2
1.0 Lighting
1.1 Daylighting _____________________________________________________________________ 3
I) Market
II) Reading Area
III) Spa
1.2 Artificial lighting _________________________________________________________________4
I) Market
II) Reading Area
III) Spa
2.0 Acoustic
2.1 Reverberation time ______________________________________________________________10
I) Market
II) Reading Area
III) Spa
2.2 External noise sound pressure level _________________________________________________13
2.3 Sound transmission class _________________________________________________________14
I) Market
II) Reading Area
3. 3
1.1 Daylighting
DF =
Ei
Eo
X 100%
I) Market
DF = 800/32000 X 100%
= 2.5%
This space has a fair daylight factor, the usage of artificial light would be sufficient to the space.
II) Reading
DF = 700/32000 X 100%
= 2.19%
This space has a fair daylight factor, the usage of artificial light would be sufficient to the space.
III) Spa
DF = 600/32000 X 100%
= 1.88%
This space has a fair daylight factor, the usage of artificial light would be sufficient to the space.
4. 4
1.2 Artificial Lighting
I) Market
Referring to MS 1525, the lighting level required for a market is 500lux.
Location Ground floor
Room Name Market
Room Dimension L=3.0 m , W=3.0m
Total Floor Area (m²) 9.0
Standard Illuminance required (lux) 500
Assumption of Reflectance value
Mounting Height (hm) 4.5 – 1.0 = 3.5m
Room Index (K) (3 x 3) / (3 + 3) x (4.5-1.0)
= 0.43
Utilization Factor (UF) 0.43
Maintenance Factor (MF) 0.31
N =
E
A
F UF MF
= (500 x 9) / (3500x 0.43 x 0.31)
= 9.6 ≈ 10
Type of Lighting Quantity Luminous Flux (lm)
LUMILUX XT T8
Wattage : 58W
Color temperature : 3000K
10
3500
5. 5
II) Reading Area
Referring to MS 1525, the lighting level required for a reading area is 300.
Location First Floor
Room Name Reading Area
Room Dimension L=6.5m , W=7.5m
Total Floor Area (m²) 48.75
Standard Illuminance required (lux) 300
Assumption of Reflectance value
Mounting Height (hm) 3.5 – 0.8 = 2.7m
Room Index (K) (6.5 x 7.5) / (6.5 + 7.5) x 2.7
= 1.29
Utilization Factor (UF) 0.46
Maintenance Factor (MF) 0.35
N =
E
A
F UF MF
= (300 x 48.75) / (3500x 0.46 x 0.35)
= 25.9 ≈ 26
Type of Lighting Quantity Luminous Flux (lm)
Luminous flux : 11000 lm
Color temp: 3000 K
Lifespan: 300 h
26
3500
6. 6
III) Spa
Referring to MS 1525, the lighting level required for a spa/bedroom is 150
Location Second Floor
Room Name Spa
Room Dimension L=5.6m , W=3m
Total Floor Area (m²) 16.8
Standard Illuminance required (lux) 150
Assumption of Reflectance value
Mounting Height (hm) 3.5- 1.0 = 2.5 m
Room Index (K) (5.6 x 3)/ (5.6 + 3) x (3.5-1.0)
= 0.8
Utilization Factor (UF) 0.40
Maintenance Factor (MF) 0.35
N =
E
A
F UF MF
= (150 x 16.8) / (1100 x 0.4 x 0.35)
= 16.3 ≈ 18
Type of Lighting Quantity Luminous Flux (lm)
OSRAM DULUX
INTELLIGENT DIM CFL
Luminous flux: 1100 lm
Color temp: 2500 K
Lifespan: 20000 h
18
1100
9. 9
Spa
Component Material Function Area(m²) Absorption
Coefficient
(2000Hz)
Sound
Absorption
(SA)
CEILING Concrete Ceiling 16.8 0.06 1.008
WALL Concrete
Glass
wood
Wall
Window
Door
7.5
3
3
0.06
0.07
0.03
0.45
0.21
0.09
FLOOR Carpet Floor 16.8 0.60 10.08
FURNITURE
PEOPLE
Fabric
Wood
Chairs
Tables
2
1
2
0.96
0.06
0.46
1.92
0.06
0.92
Total
Absorption
14.74
RT =
V 16. 0
A
RT = 0.16 x 58.8 / 14.74
RT = 0.64s
10. 10
External noise
Sound pressure level
Traffic noise: 83dB
Activity noise: 60dB
Traffic
83 = 10 log (I₁/I₀)
log¯ⁱ 8.3 = I₁/I₀
log¯ⁱ 8.3 = I₁/(1.0 x 10¯ⁱ²)
I₁ = 1.995 x 10¯⁴
Activity
65 = 10 log (I₁/I₀)
log¯ⁱ 6.5 = I₁/I₀
log¯ⁱ 6.5 = I₁/(1.0 x 10¯ⁱ²)
I₁ = 3.16 x 10¯⁶
Combine intensity
(1.995 x 10¯⁴) + (3.16 x 10¯⁶)
= 2.03 x 10¯⁴
Combined SPL
10 log (I₁/I₀)
= 10 log (2.03 x 10¯⁴/1 x 10¯ⁱ²)
= 10 log 2.03 x 10⁸
=83dB
11. 11
Sound Transmission Class
Reading Room
TL for brick wall TL for glass window
42 = 10log
1
T
37 = 10log
1
T
log¯ⁱ4.2 =
1
T
log¯ⁱ3.7 =
1
T
T = 1/ (1.585 x 10⁴) T = 1/ (5.01 x 10³)
= 6.309 x 10¯⁵ T = 1.995 x 10¯⁴
Average Transmission Coefficient of Materials
Toverall = (7.164 x 10¯4) + (1.407 x 10¯3)/25.9
= 8.19x 10¯⁵
Total SRI of Wall
SRI = 10log 1/8.19 x 10¯⁵
= 10log (12210)
= 40.87
83 – 40.87
= 42.13dB
12. 12
Market
TL for brick wall TL for glass window
42 = 10log
1
T
37 = 10log
1
T
log¯ⁱ4.2 =
1
T
log¯ⁱ3.7 =
1
T
T = 1/ (1.585 x 10⁴) T = 1/ (5.01 x 10³)
= 6.309 x 10¯⁵ T = 1.995 x 10¯⁴
Average Transmission Coefficient of Materials
Toverall = (2.47 x 10¯2) /187
= 1.32 x 10¯4
Total SRI of Wall
SRI = 10log 1/1.32 x 10¯4
= 10log (7575)
= 38.79
83 – 38.79
= 44.21dB
13. 13
References
1. LED light colour, CRI and experiments. (n.d.). LED light colour, CRI and experiments.
Retrieved December 4, 2014, from
http://swhs.home.xs4all.nl/fiets/tests/verlichting/experimenten/index_en.html#cri
2. Sanjeh R. (2014). Lumen Method, Lecture Notes. Taylor’s University.
3. Sivaraman K. (2014). Acoustic Calculations, Lecture Notes. Taylor’s University.
4. Binggeli, C. (2003). Building System for Interior Designers. New Jersey: John Wiley &
Sons.