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Project 2 : Lighting and Acoustics Integration with 
Design Studio 5 
Tutor : Mr. Sanjey Raman 
Nadia Othman 0303423 
1
2 
1.0 Lighting 
1.1 Daylighting _____________________________________________________________________ 3 
I) Market 
II) Reading Area 
III) Spa 
1.2 Artificial lighting _________________________________________________________________4 
I) Market 
II) Reading Area 
III) Spa 
2.0 Acoustic 
2.1 Reverberation time ______________________________________________________________10 
I) Market 
II) Reading Area 
III) Spa 
2.2 External noise sound pressure level _________________________________________________13 
2.3 Sound transmission class _________________________________________________________14 
I) Market 
II) Reading Area
3 
1.1 Daylighting 
DF = 
Ei 
Eo 
X 100% 
I) Market 
DF = 800/32000 X 100% 
= 2.5% 
This space has a fair daylight factor, the usage of artificial light would be sufficient to the space. 
II) Reading 
DF = 700/32000 X 100% 
= 2.19% 
This space has a fair daylight factor, the usage of artificial light would be sufficient to the space. 
III) Spa 
DF = 600/32000 X 100% 
= 1.88% 
This space has a fair daylight factor, the usage of artificial light would be sufficient to the space.
4 
1.2 Artificial Lighting 
I) Market 
Referring to MS 1525, the lighting level required for a market is 500lux. 
Location Ground floor 
Room Name Market 
Room Dimension L=3.0 m , W=3.0m 
Total Floor Area (m²) 9.0 
Standard Illuminance required (lux) 500 
Assumption of Reflectance value 
Mounting Height (hm) 4.5 – 1.0 = 3.5m 
Room Index (K) (3 x 3) / (3 + 3) x (4.5-1.0) 
= 0.43 
Utilization Factor (UF) 0.43 
Maintenance Factor (MF) 0.31 
N = 
E  
A 
  
F UF MF 
= (500 x 9) / (3500x 0.43 x 0.31) 
= 9.6 ≈ 10 
Type of Lighting Quantity Luminous Flux (lm) 
LUMILUX XT T8 
Wattage : 58W 
Color temperature : 3000K 
10 
3500
5 
II) Reading Area 
Referring to MS 1525, the lighting level required for a reading area is 300. 
Location First Floor 
Room Name Reading Area 
Room Dimension L=6.5m , W=7.5m 
Total Floor Area (m²) 48.75 
Standard Illuminance required (lux) 300 
Assumption of Reflectance value 
Mounting Height (hm) 3.5 – 0.8 = 2.7m 
Room Index (K) (6.5 x 7.5) / (6.5 + 7.5) x 2.7 
= 1.29 
Utilization Factor (UF) 0.46 
Maintenance Factor (MF) 0.35 
N = 
E  
A 
  
F UF MF 
= (300 x 48.75) / (3500x 0.46 x 0.35) 
= 25.9 ≈ 26 
Type of Lighting Quantity Luminous Flux (lm) 
Luminous flux : 11000 lm 
Color temp: 3000 K 
Lifespan: 300 h 
26 
3500
6 
III) Spa 
Referring to MS 1525, the lighting level required for a spa/bedroom is 150 
Location Second Floor 
Room Name Spa 
Room Dimension L=5.6m , W=3m 
Total Floor Area (m²) 16.8 
Standard Illuminance required (lux) 150 
Assumption of Reflectance value 
Mounting Height (hm) 3.5- 1.0 = 2.5 m 
Room Index (K) (5.6 x 3)/ (5.6 + 3) x (3.5-1.0) 
= 0.8 
Utilization Factor (UF) 0.40 
Maintenance Factor (MF) 0.35 
N = 
E  
A 
  
F UF MF 
= (150 x 16.8) / (1100 x 0.4 x 0.35) 
= 16.3 ≈ 18 
Type of Lighting Quantity Luminous Flux (lm) 
OSRAM DULUX 
INTELLIGENT DIM CFL 
Luminous flux: 1100 lm 
Color temp: 2500 K 
Lifespan: 20000 h 
18 
1100
7 
Acoustics 
Market 
Component Material Function Area(m²) Absorption 
Coefficient 
(2000Hz) 
Sound 
Absorption 
(SA) 
CEILING Glass Ceiling 255 0.05 12.75 
WALL Brick 
Glass 
Glass 
Wall 
Window 
Door 
127.2 
76.8 
38.7 
0.04 
0.07 
0.03 
5.088 
5.376 
1.161 
FLOOR Concrete Floor 255 0.06 15.3 
FURNITURE Wood 
Chairs 
Tables 
16 
16 
0.28 
0.06 
4.48 
2.76 
Total 
Absorption 
46.92 
RT = 
V  16. 0 
A 
RT = 0.16 x 2805 / 46.92 
RT = 9.6s
8 
Reading Room 
Component Material Function Area(m²) Absorption 
Coefficient 
(2000Hz) 
Sound 
Absorption 
(SA) 
CEILING Concrete Ceiling 48.75 0.06 2.93 
WALL Concrete 
Glass 
Wall 
Window 
76.9 
16.2 
0.06 
0.07 
4.6 
1.1 
FLOOR Carpet Floor 48.75 0.60 29.25 
FURNITURE 
PEOPLE 
Fabric Chair 
Chairs 
Tables 
10 
2 
10 
0.96 
0.06 
0.46 
9.6 
0.12 
4.6 
Total 
Absorption 
52.2 
RT = 
V  16. 0 
A 
RT = 0.16x 170.63 / 52.2 
RT = 0.52s
9 
Spa 
Component Material Function Area(m²) Absorption 
Coefficient 
(2000Hz) 
Sound 
Absorption 
(SA) 
CEILING Concrete Ceiling 16.8 0.06 1.008 
WALL Concrete 
Glass 
wood 
Wall 
Window 
Door 
7.5 
3 
3 
0.06 
0.07 
0.03 
0.45 
0.21 
0.09 
FLOOR Carpet Floor 16.8 0.60 10.08 
FURNITURE 
PEOPLE 
Fabric 
Wood 
Chairs 
Tables 
2 
1 
2 
0.96 
0.06 
0.46 
1.92 
0.06 
0.92 
Total 
Absorption 
14.74 
RT = 
V  16. 0 
A 
RT = 0.16 x 58.8 / 14.74 
RT = 0.64s
10 
External noise 
Sound pressure level 
Traffic noise: 83dB 
Activity noise: 60dB 
Traffic 
83 = 10 log (I₁/I₀) 
log¯ⁱ 8.3 = I₁/I₀ 
log¯ⁱ 8.3 = I₁/(1.0 x 10¯ⁱ²) 
I₁ = 1.995 x 10¯⁴ 
Activity 
65 = 10 log (I₁/I₀) 
log¯ⁱ 6.5 = I₁/I₀ 
log¯ⁱ 6.5 = I₁/(1.0 x 10¯ⁱ²) 
I₁ = 3.16 x 10¯⁶ 
Combine intensity 
(1.995 x 10¯⁴) + (3.16 x 10¯⁶) 
= 2.03 x 10¯⁴ 
Combined SPL 
10 log (I₁/I₀) 
= 10 log (2.03 x 10¯⁴/1 x 10¯ⁱ²) 
= 10 log 2.03 x 10⁸ 
=83dB
11 
Sound Transmission Class 
Reading Room 
TL for brick wall TL for glass window 
42 = 10log 
1 
T 
37 = 10log 
1 
T 
log¯ⁱ4.2 = 
1 
T 
log¯ⁱ3.7 = 
1 
T 
T = 1/ (1.585 x 10⁴) T = 1/ (5.01 x 10³) 
= 6.309 x 10¯⁵ T = 1.995 x 10¯⁴ 
Average Transmission Coefficient of Materials 
Toverall = (7.164 x 10¯4) + (1.407 x 10¯3)/25.9 
= 8.19x 10¯⁵ 
Total SRI of Wall 
SRI = 10log 1/8.19 x 10¯⁵ 
= 10log (12210) 
= 40.87 
83 – 40.87 
= 42.13dB
12 
Market 
TL for brick wall TL for glass window 
42 = 10log 
1 
T 
37 = 10log 
1 
T 
log¯ⁱ4.2 = 
1 
T 
log¯ⁱ3.7 = 
1 
T 
T = 1/ (1.585 x 10⁴) T = 1/ (5.01 x 10³) 
= 6.309 x 10¯⁵ T = 1.995 x 10¯⁴ 
Average Transmission Coefficient of Materials 
Toverall = (2.47 x 10¯2) /187 
= 1.32 x 10¯4 
Total SRI of Wall 
SRI = 10log 1/1.32 x 10¯4 
= 10log (7575) 
= 38.79 
83 – 38.79 
= 44.21dB
13 
References 
1. LED light colour, CRI and experiments. (n.d.). LED light colour, CRI and experiments. 
Retrieved December 4, 2014, from 
http://swhs.home.xs4all.nl/fiets/tests/verlichting/experimenten/index_en.html#cri 
2. Sanjeh R. (2014). Lumen Method, Lecture Notes. Taylor’s University. 
3. Sivaraman K. (2014). Acoustic Calculations, Lecture Notes. Taylor’s University. 
4. Binggeli, C. (2003). Building System for Interior Designers. New Jersey: John Wiley & 
Sons.

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Nadia bsc2 p2

  • 1. Project 2 : Lighting and Acoustics Integration with Design Studio 5 Tutor : Mr. Sanjey Raman Nadia Othman 0303423 1
  • 2. 2 1.0 Lighting 1.1 Daylighting _____________________________________________________________________ 3 I) Market II) Reading Area III) Spa 1.2 Artificial lighting _________________________________________________________________4 I) Market II) Reading Area III) Spa 2.0 Acoustic 2.1 Reverberation time ______________________________________________________________10 I) Market II) Reading Area III) Spa 2.2 External noise sound pressure level _________________________________________________13 2.3 Sound transmission class _________________________________________________________14 I) Market II) Reading Area
  • 3. 3 1.1 Daylighting DF = Ei Eo X 100% I) Market DF = 800/32000 X 100% = 2.5% This space has a fair daylight factor, the usage of artificial light would be sufficient to the space. II) Reading DF = 700/32000 X 100% = 2.19% This space has a fair daylight factor, the usage of artificial light would be sufficient to the space. III) Spa DF = 600/32000 X 100% = 1.88% This space has a fair daylight factor, the usage of artificial light would be sufficient to the space.
  • 4. 4 1.2 Artificial Lighting I) Market Referring to MS 1525, the lighting level required for a market is 500lux. Location Ground floor Room Name Market Room Dimension L=3.0 m , W=3.0m Total Floor Area (m²) 9.0 Standard Illuminance required (lux) 500 Assumption of Reflectance value Mounting Height (hm) 4.5 – 1.0 = 3.5m Room Index (K) (3 x 3) / (3 + 3) x (4.5-1.0) = 0.43 Utilization Factor (UF) 0.43 Maintenance Factor (MF) 0.31 N = E  A   F UF MF = (500 x 9) / (3500x 0.43 x 0.31) = 9.6 ≈ 10 Type of Lighting Quantity Luminous Flux (lm) LUMILUX XT T8 Wattage : 58W Color temperature : 3000K 10 3500
  • 5. 5 II) Reading Area Referring to MS 1525, the lighting level required for a reading area is 300. Location First Floor Room Name Reading Area Room Dimension L=6.5m , W=7.5m Total Floor Area (m²) 48.75 Standard Illuminance required (lux) 300 Assumption of Reflectance value Mounting Height (hm) 3.5 – 0.8 = 2.7m Room Index (K) (6.5 x 7.5) / (6.5 + 7.5) x 2.7 = 1.29 Utilization Factor (UF) 0.46 Maintenance Factor (MF) 0.35 N = E  A   F UF MF = (300 x 48.75) / (3500x 0.46 x 0.35) = 25.9 ≈ 26 Type of Lighting Quantity Luminous Flux (lm) Luminous flux : 11000 lm Color temp: 3000 K Lifespan: 300 h 26 3500
  • 6. 6 III) Spa Referring to MS 1525, the lighting level required for a spa/bedroom is 150 Location Second Floor Room Name Spa Room Dimension L=5.6m , W=3m Total Floor Area (m²) 16.8 Standard Illuminance required (lux) 150 Assumption of Reflectance value Mounting Height (hm) 3.5- 1.0 = 2.5 m Room Index (K) (5.6 x 3)/ (5.6 + 3) x (3.5-1.0) = 0.8 Utilization Factor (UF) 0.40 Maintenance Factor (MF) 0.35 N = E  A   F UF MF = (150 x 16.8) / (1100 x 0.4 x 0.35) = 16.3 ≈ 18 Type of Lighting Quantity Luminous Flux (lm) OSRAM DULUX INTELLIGENT DIM CFL Luminous flux: 1100 lm Color temp: 2500 K Lifespan: 20000 h 18 1100
  • 7. 7 Acoustics Market Component Material Function Area(m²) Absorption Coefficient (2000Hz) Sound Absorption (SA) CEILING Glass Ceiling 255 0.05 12.75 WALL Brick Glass Glass Wall Window Door 127.2 76.8 38.7 0.04 0.07 0.03 5.088 5.376 1.161 FLOOR Concrete Floor 255 0.06 15.3 FURNITURE Wood Chairs Tables 16 16 0.28 0.06 4.48 2.76 Total Absorption 46.92 RT = V  16. 0 A RT = 0.16 x 2805 / 46.92 RT = 9.6s
  • 8. 8 Reading Room Component Material Function Area(m²) Absorption Coefficient (2000Hz) Sound Absorption (SA) CEILING Concrete Ceiling 48.75 0.06 2.93 WALL Concrete Glass Wall Window 76.9 16.2 0.06 0.07 4.6 1.1 FLOOR Carpet Floor 48.75 0.60 29.25 FURNITURE PEOPLE Fabric Chair Chairs Tables 10 2 10 0.96 0.06 0.46 9.6 0.12 4.6 Total Absorption 52.2 RT = V  16. 0 A RT = 0.16x 170.63 / 52.2 RT = 0.52s
  • 9. 9 Spa Component Material Function Area(m²) Absorption Coefficient (2000Hz) Sound Absorption (SA) CEILING Concrete Ceiling 16.8 0.06 1.008 WALL Concrete Glass wood Wall Window Door 7.5 3 3 0.06 0.07 0.03 0.45 0.21 0.09 FLOOR Carpet Floor 16.8 0.60 10.08 FURNITURE PEOPLE Fabric Wood Chairs Tables 2 1 2 0.96 0.06 0.46 1.92 0.06 0.92 Total Absorption 14.74 RT = V  16. 0 A RT = 0.16 x 58.8 / 14.74 RT = 0.64s
  • 10. 10 External noise Sound pressure level Traffic noise: 83dB Activity noise: 60dB Traffic 83 = 10 log (I₁/I₀) log¯ⁱ 8.3 = I₁/I₀ log¯ⁱ 8.3 = I₁/(1.0 x 10¯ⁱ²) I₁ = 1.995 x 10¯⁴ Activity 65 = 10 log (I₁/I₀) log¯ⁱ 6.5 = I₁/I₀ log¯ⁱ 6.5 = I₁/(1.0 x 10¯ⁱ²) I₁ = 3.16 x 10¯⁶ Combine intensity (1.995 x 10¯⁴) + (3.16 x 10¯⁶) = 2.03 x 10¯⁴ Combined SPL 10 log (I₁/I₀) = 10 log (2.03 x 10¯⁴/1 x 10¯ⁱ²) = 10 log 2.03 x 10⁸ =83dB
  • 11. 11 Sound Transmission Class Reading Room TL for brick wall TL for glass window 42 = 10log 1 T 37 = 10log 1 T log¯ⁱ4.2 = 1 T log¯ⁱ3.7 = 1 T T = 1/ (1.585 x 10⁴) T = 1/ (5.01 x 10³) = 6.309 x 10¯⁵ T = 1.995 x 10¯⁴ Average Transmission Coefficient of Materials Toverall = (7.164 x 10¯4) + (1.407 x 10¯3)/25.9 = 8.19x 10¯⁵ Total SRI of Wall SRI = 10log 1/8.19 x 10¯⁵ = 10log (12210) = 40.87 83 – 40.87 = 42.13dB
  • 12. 12 Market TL for brick wall TL for glass window 42 = 10log 1 T 37 = 10log 1 T log¯ⁱ4.2 = 1 T log¯ⁱ3.7 = 1 T T = 1/ (1.585 x 10⁴) T = 1/ (5.01 x 10³) = 6.309 x 10¯⁵ T = 1.995 x 10¯⁴ Average Transmission Coefficient of Materials Toverall = (2.47 x 10¯2) /187 = 1.32 x 10¯4 Total SRI of Wall SRI = 10log 1/1.32 x 10¯4 = 10log (7575) = 38.79 83 – 38.79 = 44.21dB
  • 13. 13 References 1. LED light colour, CRI and experiments. (n.d.). LED light colour, CRI and experiments. Retrieved December 4, 2014, from http://swhs.home.xs4all.nl/fiets/tests/verlichting/experimenten/index_en.html#cri 2. Sanjeh R. (2014). Lumen Method, Lecture Notes. Taylor’s University. 3. Sivaraman K. (2014). Acoustic Calculations, Lecture Notes. Taylor’s University. 4. Binggeli, C. (2003). Building System for Interior Designers. New Jersey: John Wiley & Sons.