This document discusses kinematics of simple harmonic motion and provides an example problem. It contains the following key points: 1. The acceleration of an object undergoing simple harmonic motion is always proportional and opposite in direction to the displacement from the equilibrium position. 2. The net force on the object when held stationary is always zero. 3. An example problem is provided to calculate the period of oscillation of a spring-mass system when the mass is increased from 0.5kg to 0.8kg. The period is calculated to be 5.49 seconds.

1. KINEMATICS OF SIMPLE
HARMONIC MOTION
Practice problems and key point summaries revised by Mike Wang

2. -THE ACCELERATION OF THE OBJECT
IS ALWAYS PROPORTIONAL AND
OPPOSITE IN DIRECTION TO THE
DISPLACEMENT FROM THE
EQUILIBRIUM POSITION
-THE NET FORCE WHEN THE MASS IS
HELD STATIONARY IS ALWAYS ZERO

3. A BLOCK OF MASS 500G IS ATTACHED TO A HORIZONTAL
SPRING THAT OSCILLATES AT A FREQUENCY OF 1/3
SECONDS. ASSUME THERE IS NO FRICTIONAL FORCES,
WHAT IS THE PERIOD OF THE OSCILLATION IF A 800G MASS IS
ATTACHED TO THE SPRING INSTEAD.

4. SOLUTION:
1: WE NEED TO CONVERT ALL THE UNITS SO THEY MATCH UP.
500G BECOMES 0.5KG
800G BECOMES 0.8KG
2: WE KNOW THAT K STAY CONSTANT BECAUSE THE SPRING STAYS
THE SAME. SO, WE NEED TO FIND K
WE USE THE FORMULA T=2PI*SQRT(M/K) TO SOLVE FOR K
M=0.5
T=3(BECAUSE THE PERIOD IS 1/F)
K=PI/3 OR 1.0471 IN THIS CASE
NOW WE HAVE K WE REPEAT THE PROCESS WITH THE SAME
EQUATION T=2PI*SQRT(M/K) TO SOLVE FOR T
M=0.8
K=PI/3
THE ANSWER IS 5.49 SECONDS

5. THANKS AND I HOPE MY QUESTION
HELPED YOU.
MIKE WANG