870 The plates of a capacitor are not quite parallel, the distance between them at the bottom being (D a) and at the top (Dta), where a Solution let length of each plate be L and width be W. then area A=L*W at a distance x from the bottom end of the plate, distance between the plates as a function of x is given as d=D-a+(2*a/L)*x consider a small segment of length dx at a distance of x from the bottom end area of the segment=W*dx distance between the two plates=d=(D-a+(2*a/L)*x) then capacitance=dC=epsilon*area/distance between plates =epsilon*W*dx/(D-a+(2*a/L)*x) let D-a+(2*a/L)*x=y ==>(2*a/L)*dx=dy ==>dx=L*dy/(2*a) substituting, dC=epsilon*W*L*dy/(2*a*y) integrating both sides, C=(epsilon*W*L/(2*a))*ln(y) as y varies from D-a to D+a C=(epsilon*W*L/(2*a))*ln((D+a)/(D-a)) as A=W*L and ln((D+a)/(D-a)) =ln((1+(a/D))/(1-(a/D))) =2*(a/D)*(1+(a^2/(3*D^2))) then C=(epslion*A/(2*a))*(2*a/D)*(1+(a^2/(3*D^2))) =(epsilon*A/D)*(1+(a^2/(3*D^2))) .