Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in water. Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in water. Solution Ca(OH)2 is partially soluble in water and we can find solubility based on solubility product Ca(OH)2 (s) <-----> Ca2+ (aq) + 2OH- (aq) at equilibrium [Ca2+] = S , [OH-] = 2S Ksp = [Ca2+] [OH-]^2 ( where Ksp is solubility product of Ca(OH)2 in water) 5.5 x 10^ -6 = (S) (2S)^2 S = 0.0111 M Thus [Ca2+] = 0.0111 , [OH-] = 2 x 0.0111 = 0.0222 M Total concetrations of ions = [Ca2+] + 2 [OH-] = ( 0.0111) + 2 ( 0.0222) = 0.0555 M .

1. Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in
water.
Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in
water.
Solution
Ca(OH)2 is partially soluble in water and we can find solubility based on solubility product
Ca(OH)2 (s) <-----> Ca2+ (aq) + 2OH- (aq)
at equilibrium [Ca2+] = S , [OH-] = 2S
Ksp = [Ca2+] [OH-]^2 ( where Ksp is solubility product of Ca(OH)2 in water)
5.5 x 10^ -6 = (S) (2S)^2
S = 0.0111 M
Thus [Ca2+] = 0.0111 , [OH-] = 2 x 0.0111 = 0.0222 M
Total concetrations of ions = [Ca2+] + 2 [OH-] = ( 0.0111) + 2 ( 0.0222) = 0.0555 M