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PROJECTIONS OF PLANES

A plane is a two-dimensional geometrical entity
It has length and width but no thickness
For practical purposes, a flat face of an object may be treated as a
 plane



Information usually given:
1. Shape of the plane
2. Inclination of it’s surface with one of the reference planes
3. Inclination of one of it’s edges with the other reference plane will
   be given


                                                                     1
POSITIONS OF PLANES
1. Plane parallel to one RP and perpendicular to other
     Case (i): Plane in the HP and away from the VP
     Case (ii): Plane in the VP and away from the HP
     Case (iii): plane away from both the RPs and parallel to HP and perpendicular
to VP
     Case (iv): plane away from both the RPs and parallel to VP and perpendicular
to HP

2. Plane inclined to one RP and perpendicular to other
     Case (i): plane away from both the RPs and inclined to HP and perpendicular
to VP
     Case (ii): plane away from both the RPs and inclined to VP and perpendicular
to HP

3. Plane inclined to both the planes
CASE OF A RECTANGLE



SURFACE PARALLEL TO HP AND PERPINDICULAR TO VP

                                                   VP




          For T.V.
                                                        a’   d’
                                                        b’   c’


                     For
                         F   .V.
                                                        a    d



                                                        b    c



                                               HP
CASE OF A RECTANGLE



SURFACE INCLINED TO HP AND PERPINDICULAR TO VP



                                         VP          d’
                                                      c’

           For Tv


                                               a’
                                                b’

                    For
                        Fv                     a1     d1



                                               b1     c1


                                         HP
CASE OF A RECTANGLE.




SURFACE INCLINED TO HP AND INCLINED TO VP




      For T.V.                            VP
                                                              d1’         c1’

                                               a1’            b1’

                                                                    d1
                 Fo
                    r   F. V
                            .                                            c1
                                                 a1
                                                                                5
                                          HP          b   1
Rectangle 30mm and 50mm                  Read problem and answer following questions
sides is resting on HP on one            1. Surface inclined to which plane? -------    HP
small side which is 300 inclined         2. Assumption for initial position? ------// to HP
to VP,while the surface of the           3. So which view will show True shape? --- TV
plane makes 450 inclination with          4. Which side will be vertical? ---One small side.
HP. Draw it’s projections.               Hence begin with TV, draw rectangle below X-Y
                                                 drawing one small side vertical.

            Surface // to Hp           Surface inclined to Hp
                                                         d’c’               c’1     d’1
                               c’d’
    a’b’
                                           a’ b’ 450             b’1          a’1         Y
X                                                                       300
     a                                     a1               d1




                                                                       a1
                                   d                                                   Side
                                                                                     Inclined
                                                                                       to Vp


                                                                 b1
      b                            c       b1               c1




                                                                                    d1
                                                                                              6

                                                                        c1
A regular pentagon of 30 mm sides is resting             Read problem and answer following questions
  on HP on one of it’s sides while it’s opposite                                                 HP
                                                           1. Surface inclined to which plane? -------
  vertex (corner) is 30 mm above HP.                       2. Assumption for initial position?//HP
                                                                                               ------
  Draw projections when side in HP is 300                                                           TV
                                                           3. So which view will show True shape? ---
  inclined to VP.                                             Hence begin with TV,draw pentagon below
                                                              X-Y line, taking one side vertical.
 SURFACE INCLINATION INDIRECTLY GIVEN
    SIDE INCLINATION DIRECTLY GIVEN:

                    ONLY CHANGE is
   the manner in which surface inclination is described:
 One side on Hp & it’s opposite corner 30 mm above Hp.                             d’            d’1
Hence redraw 1st Fv as a 2nd Fv making above arrangement.
          Keep a’b’ on xy & d’ 30 mm above xy.                              c’e’                       c’1
                                                             30                    e’1


                             X   b’ a’         c’e’         d’         a’
                                                                       b’                 a’1          b’1 Y
                                                                                                300
                                                                            e1              a1
                                                       e
                                                                                     e1
                                    a                             a1                                   b1

                                                            d                      d1
                                                                                            d1         c1
                                   b                              b1

                                                   c                        c1                               7
CIRCULAR LAMINA INCLINED AT AN ANGLE 45O TO FRONTAL PLANE
       AND PERPENDICULAR TO TOP PLANE (USE IIIRD. ANGLE)
• Since the circular lamina is (Tutorial 5, qs. 3)
                                                                          TV: Top View
 to be inclined at 45 to the
                       o

 frontal plane (FV), draw it                                              FV: Front View
 initially parallel to the frontal                     d, f
                                                               e
                                                                           T                    d, f
                                                                                                            e

 plane.                                T          c, g                                  c, g
                                              b,h                                   b, h
                                                   45O                                         45O
• Next, rotate the TV by 45o                a                        e         a
                                               b, h c, g      d, f
  and draw an identical new
  TV
• For projection, divide the                                                               c’
                                                      c’
  circle in FV into sections                     b’           d’                    b’                 d’
  and project the points in the
                                           a’                        e’        a’                               e’
  TV
• With a as center and ab, ac,                  h’
                                                      g’
                                                               f’                   h’                 f’

  ad as radii, draw arcs to the       F                                   F                g’

  new positions.
• Project corresponding              From the new TV project points into
  points into the new TV and          the new FV to get points on the
                                      circumference of the lamina                                                    8
  FV
Drawing the side view

                w




                                                            w
T
F                     O        w
                                          T                      45o

                                          F                     O         w




                                   RSV
                                                                              RSV

    With O as center draw curves (1/4
                                           Draw a line from O at 45o to the
       circle) to project the corners
                                         horizontal axis to project the corners
                                                                                  9
Examples of projections of a triangular plane
                    III rd angle

X                          X           A            X                        X
     TV                        TV                       TV                       TV
                                                                                          C
       B     A                                                A   C              B
                               B           C            B
           3 cm
                                                                                      A
                       Z                        Z                        Z                    Z
             A                                                                        A
                                3 cm                          A
                                                                                 B
                               B           C
                                       A                                                  C
      B           C                                     B         C
Y    FV                Y       FV                       FV                       FV

    Vertical plane 3           Horizontal               Inclined plane       Oblique plane (not
    cm from frontal            plane 3 cm               perpendicular        perpendicular to any
    plane                      from top plane           to top plane         principal plane)
                                                                                              10

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Projections of Planes and Solids

  • 1. PROJECTIONS OF PLANES A plane is a two-dimensional geometrical entity It has length and width but no thickness For practical purposes, a flat face of an object may be treated as a plane Information usually given: 1. Shape of the plane 2. Inclination of it’s surface with one of the reference planes 3. Inclination of one of it’s edges with the other reference plane will be given 1
  • 2. POSITIONS OF PLANES 1. Plane parallel to one RP and perpendicular to other Case (i): Plane in the HP and away from the VP Case (ii): Plane in the VP and away from the HP Case (iii): plane away from both the RPs and parallel to HP and perpendicular to VP Case (iv): plane away from both the RPs and parallel to VP and perpendicular to HP 2. Plane inclined to one RP and perpendicular to other Case (i): plane away from both the RPs and inclined to HP and perpendicular to VP Case (ii): plane away from both the RPs and inclined to VP and perpendicular to HP 3. Plane inclined to both the planes
  • 3. CASE OF A RECTANGLE SURFACE PARALLEL TO HP AND PERPINDICULAR TO VP VP For T.V. a’ d’ b’ c’ For F .V. a d b c HP
  • 4. CASE OF A RECTANGLE SURFACE INCLINED TO HP AND PERPINDICULAR TO VP VP d’ c’ For Tv a’ b’ For Fv a1 d1 b1 c1 HP
  • 5. CASE OF A RECTANGLE. SURFACE INCLINED TO HP AND INCLINED TO VP For T.V. VP d1’ c1’ a1’ b1’ d1 Fo r F. V . c1 a1 5 HP b 1
  • 6. Rectangle 30mm and 50mm Read problem and answer following questions sides is resting on HP on one 1. Surface inclined to which plane? ------- HP small side which is 300 inclined 2. Assumption for initial position? ------// to HP to VP,while the surface of the 3. So which view will show True shape? --- TV plane makes 450 inclination with 4. Which side will be vertical? ---One small side. HP. Draw it’s projections. Hence begin with TV, draw rectangle below X-Y drawing one small side vertical. Surface // to Hp Surface inclined to Hp d’c’ c’1 d’1 c’d’ a’b’ a’ b’ 450 b’1 a’1 Y X 300 a a1 d1 a1 d Side Inclined to Vp b1 b c b1 c1 d1 6 c1
  • 7. A regular pentagon of 30 mm sides is resting Read problem and answer following questions on HP on one of it’s sides while it’s opposite HP 1. Surface inclined to which plane? ------- vertex (corner) is 30 mm above HP. 2. Assumption for initial position?//HP ------ Draw projections when side in HP is 300 TV 3. So which view will show True shape? --- inclined to VP. Hence begin with TV,draw pentagon below X-Y line, taking one side vertical. SURFACE INCLINATION INDIRECTLY GIVEN SIDE INCLINATION DIRECTLY GIVEN: ONLY CHANGE is the manner in which surface inclination is described: One side on Hp & it’s opposite corner 30 mm above Hp. d’ d’1 Hence redraw 1st Fv as a 2nd Fv making above arrangement. Keep a’b’ on xy & d’ 30 mm above xy. c’e’ c’1 30 e’1 X b’ a’ c’e’ d’ a’ b’ a’1 b’1 Y 300 e1 a1 e e1 a a1 b1 d d1 d1 c1 b b1 c c1 7
  • 8. CIRCULAR LAMINA INCLINED AT AN ANGLE 45O TO FRONTAL PLANE AND PERPENDICULAR TO TOP PLANE (USE IIIRD. ANGLE) • Since the circular lamina is (Tutorial 5, qs. 3) TV: Top View to be inclined at 45 to the o frontal plane (FV), draw it FV: Front View initially parallel to the frontal d, f e T d, f e plane. T c, g c, g b,h b, h 45O 45O • Next, rotate the TV by 45o a e a b, h c, g d, f and draw an identical new TV • For projection, divide the c’ c’ circle in FV into sections b’ d’ b’ d’ and project the points in the a’ e’ a’ e’ TV • With a as center and ab, ac, h’ g’ f’ h’ f’ ad as radii, draw arcs to the F F g’ new positions. • Project corresponding From the new TV project points into points into the new TV and the new FV to get points on the circumference of the lamina 8 FV
  • 9. Drawing the side view w w T F O w T 45o F O w RSV RSV With O as center draw curves (1/4 Draw a line from O at 45o to the circle) to project the corners horizontal axis to project the corners 9
  • 10. Examples of projections of a triangular plane III rd angle X X A X X TV TV TV TV C B A A C B B C B 3 cm A Z Z Z Z A A 3 cm A B B C A C B C B C Y FV Y FV FV FV Vertical plane 3 Horizontal Inclined plane Oblique plane (not cm from frontal plane 3 cm perpendicular perpendicular to any plane from top plane to top plane principal plane) 10