Consider two point sources separated by a distance of 10 meters. The longitudinal waves emitted from the two sources have the wavelength of = lm. The velocity of the wave is 2m/sec. What is the frequency f and the period T? Solution Frequency=Velocity/wavelength =(2m/sec)/1m =2 Hz Time period= 1/Frequency =1/2 =0.5 sec a) Amplitude at C =0.1+0.1=0.2 m (Since waves are in phase) b) Waveform will be at same amplitude that is 0.2 m c) If the distance between the points A and B is changed. The waves interfere distructively. Therefore, amplitude is zero. That is 0.1-0.1=0 d) If source A is delayed by 0.5 sec The path difference is= 2(0.5)=1 m Therefore, waves interfere constructevely. The wave amplitude at point C is., 0.1+0.1=0.2 m.