A box in a certain supply room contains seven 40-W lightbulbs, six 60-W bulbs, and four 75-W bulbs. Suppose that three bulbs are randomly selected. (Round your answers to four decimal places.) (a) What is the probability that exactly two of the selected bulbs are rated 75-W? (b) What is the probability that all three of the selected bulbs have the same rating? (c) What is the probability that one bulb of each type is selected? (d) Suppose now that bulbs are to be selected one by one until a 75-W bulb is found. What is the probability that it is necessary to examine at least six bulbs? Solution a) p=prob of success =4/17 x=2 n=3 P(x=2)= 3*(4/17)^2*13/17=.1270 b) Probability that all bulbs has the same rating= P(3 40-W) +P(3 60-W) +P(3 75- W)=(7/17)^3+(6/17)^3 +(4/17)^3=.1268 c)7/17*6/17*4/17 = .0342 d) 13/17*12/16*11/15*10/14*9/13*4/12=.0693.