A 8 100 C 8 099 and width (n + 3) cm. If the depth is 5 cm, calculate the volume of the box in cm3. B 8 101 D 8 098 34 Simplify: 6x + 3y - (4x - 2y) A 45n2 + 135n + 135 C 45n2 + 135n B 45n2 + 135n D 45n2 + 135n + 15 A 2x + 5y C 10x + y B 2x + 5y D 10x - y 39 The perimeter of a rectangle is 60 cm. If

1. Percentage :
NAMA :
SMK TAMAN MEGAH RIA
TING :
Time: 1 hour 15 8 What is the square of 11?
Paper 1 minutes
A 22 C 44
This paper consists of 40 questions. Answer all B 33 D 121
questions. Every question is followed by four
alternative answers A, B, C and D. For each 9 The value of 62.722 lies between
question, choose one answer only. Blacken your
answer on the objective answer sheet provided. If A 60 and 70
you wish to change your answer, erase the B 600 and 700
blackened mark that you have made. Then
C 3 600 and 4 900
blacken the new answer.
D 360 000 and 490 000
1 Which of the following numbers does not lie 10 Given that 9.5 = 3.08 and 95 = 9.75, then
between 112 and 172? 950 =
A 292 C 204 A 975 C 97.5
B 219 D 170 B 308 D 30.8
2 Given that 2.492 = 6.2, what is the value of 11 Given that 4.662 = 21.7, then 2 170 =
24.92?
A 0.466 C 466
A 62 C 6 200 B 46.6 D 4 660
B 620 D 62 000
12 Given that the area of a piece of square tile
3 Given that 2.352 = 5.52, then 10 × 23.52? is 196 cm2, find its perimeter.
A 552 000 C 5 520 A 14 cm C 56 cm
B 55 200 D 552 B 42 cm D 70 cm
4 152 ( 16)2 = 13 Which of the following is true?
A 12 C 152 + 162 A 6× 6= 6+6
B 312 D 152 162 B 3×3=2× 3
C 64 = 8
5 Which of the following numbers is not a
perfect square? 4 2
D =
9 3
A 49 C 256
B 196 D 401 14 Which of the following is true?
6 42 × 82 = A 3× 3=3
B 3×3=2× 3
A 1 094 C 1 024 C 81 = 9
B 1 074 D 994
1 5
D 6 =
4 2
7 Given that 3.592 = 12.89, what is the value
of 3592?
15 The value of 7.7 × 1 000 lies between
A 128 900 C 1 289
B 12 890 D 128.9 A 20 and 30 C 200 and 300
B 80 and 90 D 800 and 900
UJIAN TOPIKAL MATHEMATICS | 1
CHAPTER 2 & 3 FORM 2 | TAHUN 2012

2. SMK TAMAN MEGAH RIA
16 A cube has sides of 10 cm. The volume, in 23 p
cm3, of the cube is Simplify 2p ÷ q3 .
A 30 C 1 000 A 2p2q3 C 2pq
B 100 D 10 000 B 2q3 D 2pq3
17 The value of 1 0.23 is 24 (7mn3) × (6m3n)
m3n =
A 1.2 C 0.992
B 1.002 D 0.96 A 42m2n4 C 42mn
B 42m7n5 D 42mn3
18 3
Given that 2.23 = 10.6, then 0.0106 = 25 Which of the following is true?
A 0.22 C 0.0022 A The algebraic expression 6x + 8 has 1
B 0.022 D 0.00022 term.
B The algebraic expression 6m2 + 1 has 1
19 Which of the following is not true? term.
C The algebraic expression 4s3 + 9t + 9
A 3 0.125 = 0.5 has 4 terms.
D The algebraic expression 3x + 5y + 9
B 3 3 has 3 terms.
( 512) = 11
C 3 216 + 3 125 = 1 26 Simplify 6p + 9q + 10p 5q.
3 3 1 A 4p + 14q C 16p + 4q
D 38 = 12
B 16p + 14q D 4p + 4q
20 3 27 3x3
1 3 Given that x = 6 and y = 3, then 8y ( 5 +
+ 125 =
27 7x) =
16 14 A 1 264 C 1 269
A C
3 3 B 1 265 D 1 272
14 16
B D
3 3 28 x3
Given that x = 6 and y = 7, then y (4 + 4x) =
21 3m
9mn ÷ =
n A 869 C 864
B 868 D 860
A 3m C 3m2n2
29 Simplify 4p + q + p 5q.
B 3n2 D 3n
A 3p 4q C 5p + 6q
22 3a3
B 5p 4q D 3p + 6q
4 (2a) =
3 3 3 30 3p3 q3
A C Given that p = 4 and q = 3, then
2a 2a 5q
=
3 4 3 3
B D
2a 2a +a
A 9 C 11
B 10 D 16
UJIAN TOPIKAL MATHEMATICS | 2
CHAPTER 2 & 3 FORM 2 | TAHUN 2012

3. SMK TAMAN MEGAH RIA
31 Which of the following is true? 36 Fazlena bought m mangoes at a price of 25
sen each and n oranges at a price of 35 sen
A The algebraic expression 6s + 3t + 5 each. If she sold the mangoes at a price of 70
has 3 terms. sen each and oranges at a price of 45 sen
B The algebraic expression 5s + 7 has 1 each, calculate the total profit, in sen,
term. received by Fazlena after all the mangoes
C The algebraic expression 9p3 + 3q3 + 7 and oranges were sold.
has 2 terms.
D The algebraic expression 6x3 + 3y + 8 A 70m + 45n C 35m + 45n
has 4 terms. B 45m + 10n D 25m + 70n
32 p2 37 The registration fee charged by a tuition
Given that p = 10 and q = 5, then q ( 8 centre is RM6. Each Mathematics subject is
3p) = charged RM35 and each Science subject is
charged RM20. If Joseph took x
A 755 C 760 Mathematics subjects and y Science
subjects, what is the total payment, in RM,
B 758 D 761 was paid by Joseph?
33 10m2 A 6 + 35x + 20y C 35x + 20y
Given that m = 10 and n = 2, then ( 1
5n B 6(35x + 20y) D 61 + x + y
8m) =
38 A rectangular box has length (9n 9) cm
A 8 103 C 8 099 and width (8n + 2) cm. Calculate the
B 8 100 D 8 095 perimeter, in cm, of the box.
34 Simplify p 7q 9p 4q. A 34n 14 C 17n 7
B 34n 7 D 17n 14
A 10p 11q C 10p 3q
B 8p 3q D 8p 11q 39 9(10 6d) + 7d 10 =
35 Diagram 1 shows a triangle. A 47d 9 C 61d 9
B 61d 100 D 47d 100
40 4a 8b 9c (8a 10b 7c) =
A 12a 18b 2c C 12a + 2b 2c
B 4a + 2b 2c D 4a 18b 16c
Diagram 1
Answer:
The perimeter, in cm, of the triangle is
A 11p 2q C 11p 12q 1 9 17 25 33
B 13p 4q D 5p 2q 2 10 18 26 34
3 11 19 27 35
4 12 20 28 36
5 13 21 29 37
6 14 22 30 38
7 15 23 31 39
8 16 24 32 40
UJIAN TOPIKAL MATHEMATICS | 3
CHAPTER 2 & 3 FORM 2 | TAHUN 2012

4. SMK TAMAN MEGAH RIA
Paper 2
1 1 3 5 1 32
Calculate the value of 18 2 4 2 and Calculate the value of 3 × 1 .
16 49
express the answer as a mixed number.
[3 marks]
[3 marks] Answer:
Answer:
2 Given that 3.62 = 13, find the value of 0.362.
6 Find the value of
[3 marks] (a) 0.25
Answer: 1
(b)
81
[3 marks]
Answer:
3 Find the value of
(a) 72
2
(b) 1 2
5
7 Given that 38 = 6.2 and 3.8 = 1.9, find
[3 marks] the value of 380.
Answer:
[3 marks]
Answer:
4 1
Find the value of ( 8)2 15 2
and give the
8 Calculate the value of
answer in decimal. (a) ( 8)3 ( 5)3
(b) (3.22 4.24)3
[3 marks]
Answer:
[4 marks]
Answer:
UJIAN TOPIKAL MATHEMATICS | 4
CHAPTER 2 & 3 FORM 2 | TAHUN 2012

5. SMK TAMAN MEGAH RIA
Answer Paper 1 1 564
= 25
1A 2B 3C 4D 5D = 62.56
6C 7A 8D 9C 10 D
11 B 12 C 13 C 14 A 15 B 5 1 32
16 C 17 C 18 A 19 C 20 C 316 × 149
21 B 22 B 23 B 24 D 25 D
26 D 27 C 28 C 29 B 30 C 49 81
= 16 × 49
31 A 32 C 33 B 34 D 35 A
36 B 37 A 38 A 39 B 40 C 7 2 9 2
= 4 × 7
7 9
Answer Paper 2: =4×7
1
1 1 3 =2
2 2 4
18 4
1 1 3 3 6 (a) 0.25
= 18 × 18 4 × 4
= 0.52
9 9 3 3
= × × = 0.5
8 8 4 4
(b) 1
81 9
= 64 16 81
81 36 1 2
= 64 64 = 9
45 1
= =9
64
2 0.362 7 380
= (3.6 ÷ 10)2 = 3.8 × 100
= 3.62 ÷ 102 = 3.8 × 100
= 13 ÷ 100 = 1.9 × 10
= 0.13 = 19
3 (a) 72 8 (a) ( 8)3 ( 5)3
=7×7 = ( 512) ( 125)
= 49 = 387
(b) 2
15 2 (b) (3.22 4.24)3
7 7 = (10.24 4.24)3
= 5 × 5 = 63
24 = 216
= 125
4 1
( 8)2 15 2
1 1
= (( 8) × ( 8)) 15 × 15
6 6
= 64 5 × 5
36
= 64 25
1 600 36
= 25 25
UJIAN TOPIKAL MATHEMATICS | 5
CHAPTER 2 & 3 FORM 2 | TAHUN 2012