How many of these symmetry elements does this complex have? E C 2 ? v ? h i The answer is 3. Please explain which ones and why. Thank you in advance!! Cl Bri Co Cl Solution E is present because it\'s present in all molecules. It\'s the identity operation. Sigma(v) is present as a plane passing through F Br and Co in a single plane. So the position of two Cls are interchangable and they are identical. C2 is present when this axis passes through F Br and Co. When we rotate we get the same complex .