2. An object with electric
charge of + 500 coulombs.
Is approached to another
object with electric charge of
– 200 coloumbs in 3 m
distance. What is the
attractive force between
both objecs in newton?
3. We have q1 = -200 c
q2 = +500 c
r = 3 m
k = 9 x 109 Nm2c-2
QUESTION : F = ....?
4. ANSWER : F = k. q1 x q2
r
2
= 9 x 109 Nm2C-2 x 200 C x 500C
( 3 m )2
= 9 x 10 9 Nm2C-2 x 105C2
9 m 2
= 1014N
Thus,attractive force between both objects is
1014 N
5. - An object with electric charge of +400 C is
approached to another object with -200 C
electric charge at 5 m in distance. how
accurred force and what is the amount ?
-An object with electric charge -200 C receives a
force of 1014 N from an object with +500 C in
electric charged. What is the distance between
both electric charged objects ?
