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how do I solve the problem for b? A=(x*L/2)-x2
Solution
vertex for of the equation is in the ofrm of a(x-h)^2+k
where (h,k) is the vertix
a(x-h)^2+k=-x^2-23
a(x^2+h^2-2hx)+k=-x^2-23
equating equation on both sides
a=-1 (equating coefficients of x^2
h^2+k=-23 (equationg constants)
2h=0, h=0 (equating x coefficients)
so vertix is (0,-23)

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how do I solve the problem for b- A-(x-L-2)-x2Solution vertex for of t.docx

  • 1. how do I solve the problem for b? A=(x*L/2)-x2 Solution vertex for of the equation is in the ofrm of a(x-h)^2+k where (h,k) is the vertix a(x-h)^2+k=-x^2-23 a(x^2+h^2-2hx)+k=-x^2-23 equating equation on both sides a=-1 (equating coefficients of x^2 h^2+k=-23 (equationg constants) 2h=0, h=0 (equating x coefficients) so vertix is (0,-23)