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let 10x+5 =z 10dx = dz I = int 110 dzz = 110 ln z 110 ln.pdf

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let 10x+5 =z 10dx = dz I = int 1/10 dz/z = 1/10 ln z 1/10 ln (10x+5) + C Solution let 10x+5 =z 10dx = dz I = int 1/10 dz/z = 1/10 ln z 1/10 ln (10x+5) + C.

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let 10x+5 =z 10dx = dz I = int 1/10 dz/z = 1/10 ln z 1/10 ln (10x+5) + C Solution let 10x+5 =z 10dx = dz I = int 1/10 dz/z = 1/10 ln z 1/10 ln (10x+5) + C

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  • 1. let 10x+5 =z 10dx = dz I = int 1/10 dz/z = 1/10 ln z 1/10 ln (10x+5) + C Solution let 10x+5 =z 10dx = dz I = int 1/10 dz/z = 1/10 ln z 1/10 ln (10x+5) + C