How can an insoluble salt with a basic anion be made to dissolve.pdf

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Give the Characteristic Polynomial for A in fully factored form. Give a basis for the eigenspace for each eigenvalue of A. Work justifying your answers must be shown for credit to be 4 3 1 given. A = [4 3 1 0 3 4 0 1 3] Justify your answers. Fully factored Characteristic Polynomial: ___ 1st Eigenvalue: ____Basis for Eigenspace: ___ 2nd Eigenvalue: __ Basis for Eigenspace: ___ 3rd Eigenvalue: ___ Basis for Eigenspace: ____ Solution The characteristic equation of A is det(A- I3) = 0 or, 3 -102 +29 -20 = 0 or, (-5)(-4)(-1) = 0. The 1st eigenvalue of A is 1 = 5. The second eigenvalue of A is 2 = 4. The 3rd eigenvalue of A is 3 = 1 The eigenvector of A corresponding to 1 = 5 is the solution of the equation (A- 5I3)X = 0. The RREF of A- 5I3 is 1 0 -7 0 1 -2 0 0 0 If X = (x,y,z)T the above equation is equivalent to x-7z = 0 and y-2z = 0. Then X = (7z,2z,z)T = z(7,2,1)T. Hence the basis for the eigenspace of A corresponding to the eigenvalue 1 = 5 is {(7,2,1)T}. Similarly, the eigenvector of A corresponding to 2 = 4 is the solution of the equation (A- 4I3)X = 0. The RREF of A- 4I3 is 0 1 0 0 0 1 0 0 0 The equation (A- 4I3)X = 0 is equivalent to y = 0, z = 0. Hence X = (x,0,0)T = x(1,0,0)T. Hence the basis for the eigenspace of A corresponding to the eigenvalue 2 = 4 is {(1,0,0)T}. Also, the eigenvector of A corresponding to 3 = 1 is the solution of the equation (A- I3)X = 0. The RREF of A- I3 is 1 0 -5/3 0 1 2 0 0 0 The equation (A-I3)X=0 is equivalent to x-5z/3=0 and y+2z= 0.Let z= 3t. Then X=(5t, -6t,3t)T = t(5,-6,3)T. Hence the basis for the eigenspace of A corresponding to the eigenvalue 3 = 1 is {(5,- 6,3)T}. 1 0 -7 0 1 -2 0 0 0.

How can an insoluble salt with a basic anion be made to dissolve?
Solution
Generally these salt remain in the equilibrium with their ions in the solvent but equilibrium
remains shifted towards the salt side. Hence they don't show the solubility in a particular
solvent.
If we want to dissolve the salt then we have to shift the eulibrium twards right hence if there is a
basic anion is present in the salt then it can be dissolved using acid in the solvent. so that the eq.
will get shifted towards right and the salt will get solubilize.

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For the questions below, use the W3Schools customer orders database. You need to submit thoroughly tested SQL statements. For your convenience and reference, relevant data model is attached as a PDF document with the assignment in the Blackboard. Name of this document is \"Relationship diagram for W3schools order pdf.\" 1) Write a query to show Customers\' Country wise sales totals. Your query should show Customers\' Country name and the total sale value for that Country 2) Write a query to show Product wise sales totals. Your query should Product name and the total sale value for that Product. 3) Write a query to show the number of orders for each shipper. Your query should show shipper name and the count of orders with the shipper. 4) Write a query to show number of products in each product category. Your query should show Category name and number of products in that category 5) Write a query that shows Customers\' country wise customer count, and order count. Your query should show country name, total number of customers from that country, and total number of orders from the customers of that country 6) Write a query that shows the number of products supplied by each Supplier. Your query should show Country name, supplier name and the count of products supplied by that supplier. Note: Sale Price Orderdetails.Quantity Products.price (see an example in the class slides deck) W3SCHOOLS SQL is located at http://www.w3schools.com/sql/default.asp (Preferred browser is Chrome). On this page you will find a button called \"Try it yourself\". Click on that button. You will be redirected to a page where you see a list of tables on the right side of the page. It is highly recommended to click \'Restore Database\' button on this page during every session. The page contains a box where you can type in an SQL statement involving the listed tables. You type in your SQL statement in that box and click on \"Run SQL\'\' button. The results will be displayed if your SQL statement is syntactically correct. Solution 1. SELECT Customers.Country, SUM(OrderDetails.Quantity * Products.Price) AS Total_Sale FROM Customers LEFT JOIN Orders ON Customers.CustomerID=Orders.CustomerID LEFT JOIN OrderDetails ON Orders.OrderId=OrderDetails.OrderId LEFT JOIN Products ON OrderDetails.ProductId=Products.ProductId Group BY Customers.Country; 2. SELECT Products.ProductName, SUM(OrderDetails.Quantity * Products.Price) AS Total_Sale FROM Customers LEFT JOIN Orders ON Customers.CustomerID=Orders.CustomerID LEFT JOIN OrderDetails ON Orders.OrderId=OrderDetails.OrderId LEFT JOIN Products ON OrderDetails.ProductId=Products.ProductId Group BY Products.ProductName; You can edit these query to get other results set..

HELP IN JAVACreate a main method and use these input files to tes.pdf

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HELP IN JAVACreate a main method and use these input files to tes.pdf

Consider the program: var s: int:= 1, i: int co i:= 1 to 2 rightarrow do true rightarrow (await s > 0 rightarrow s: = s - 1) (s:= s + 1) Above, S_i is a statement list that is assumed not to modify shared variable s. Develop complete proof outlines for the two processes. Demonstrate that the proofs of the processes are interference-free. Then use the proof outlines and the method of Exclusion of Configurations (2.25) to show that S_1 and S_2 cannot execute at the same time and that the program is deadlock-free. What scheduling policy is required to ensure that a process delayed at its first await statement will eventually be able to proceed? Explain. Solution int i=1 do(i=1 to 2) { wait(s>0){ s=s-1 Si } s=s+1 } to prove that it should be deadlock free it should support mutual exclusion,progress,bounded waiting. mutual exclusion:- p1: int i=1 do(i=1 to 2) //entry section { wait(s>0){ //critical section s=s-1 Si } s=s+1 } //exit section so while p1 is exexcuting p2 while s enters into critical section as we don\'t update any values so mutual exclusion is possible and can be formed. progress:- when p1 is in non-critical section p2can execute in critical section.program gurantees progress. bounded-waiting :- suitable for ony countable no of procedures and processes. as it satisfies all properties ....so it\'s deadlock free..

Describe the steps in Sanger DNA sequencing. Provide a high level des.pdf

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Consider the following pedigree for Hunter Syndrome, a sex-linked, recessive condition leading to loss of hearing and cardiac problems among other symptoms. What is the probability that individuals IV 3 and IV 4 will have a child with Hunter syndrome? O Solution Answer is 25% Due to the chances of become a carrier in III rd generation female is 50 % so if the female in IIIrd generation is a carrier then the IV 3 and IV 4 having a Huntington syndrome is 25%..

Describe the advantages and disadvantages of the four standard acces.pdf

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Computing bond price and recording issuance P1 Flagstaff Systems issues bonds dated January 1, 2016, that pay June 30 and December 31. The bonds have a $90,000 par value and an annual contract rate interest semiannually on of 12%, and they mature in five years. Required For each of the following three separate situations,(a) determine the bonds\' issue price on January 1 2013 and (b) prepare the journal entry to record their issuance 1. 2. The market rate at the date of issuance is 10%. The market rate at the date of issuance is 14% BRIEF EXPLANATION REQUIRED FOR THE TWO JOURNAL ENTRIES Solution Assumption \"Bond is repayable at par i.e $ 90,000 1. When Market Interest Rate is 10% (a) Issue Price of the Bond:- Par Value of the Bond = $90,000 Maturity= 5 Years Interest Rate is 12% payable semi annualy, so interest amount = 12% of $90,000 *6/12 =$ 5,400 Bond\'s Issue Price = Present Vlaue = PVAF (5%,10) * $5,400 + PVIF (5%,10) * $ 90,000 = 7.7217 * $ 5400 + 0.6139* $ 90,000 = $ 41,697 + $ 55,251 =$ 96,948 (b) Journal Entry:- On January 1 2016 at the time of issuance Bank/ Cash......................................Debit $96,948 12% Bonds......................................Credit $96,948 Also the Interest Expense for 1st Year would be 10% of $96,948 = $ 9,695 2. When Market Interest Rate is 14% (a) Issue Price of the Bond:- Par Value of the Bond = $90,000 Maturity= 5 Years Interest Rate is 12% payable semi annualy, so interest amount = 12% of $90,000 *6/12 =$ 5,400 Bond\'s Issue Price = Present Value =PVAF (7%,10) * $5,400 + PVIF (7%,10) * $ 90,000 = 7.0236 * $ 5400 + 0.5083 * $ 90,000 = $ 37,927 + $ 45,747 =$ 83,674 (b) Journal Entry:- On January 1 2016 at the time of issuance Bank/ Cash......................................Debit $ 83,674 12% Bonds......................................Credit $ 83,674 Also the Interest Expense for 1st Year would be 14% of $83,674 = $ 11,714.

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