Coded in C++; Visual Studios 2013 Write a program that will prompt for the full name of a person until I press Solution #include #include #include using namespace std; int main(int argc,char** argv) { string name; cout << \"Enter full name: \"; getline(cin,name,\'\ \'); istringstream iss(name); string first, middle, last; iss >> first >> middle >> last; cout << \"First: \" << first << \'\ \'; cout << \"Middle: \" << middle << \'\ \'; cout << \"Last: \" << last << \'\ \'; return 0; }.

1. Create a bash script named ‘most_proc.sh’. This script should show the top 10 users according to
the number of processes they are running. It should show the process count and the user name.
The output of the script should look something like this, depending on which users are active.
$ ./most_proc.sh
157 root
12 apache
11 brun1992
4 bb
2 postfix
2 hart4492
2 68
1 USER
1 sshd
1 rpcuser
I don’t care about the order of users with the same number of processes.
Some hints: 1) you will probably want to use ‘ps’ with certain options to see all processes of all
users. 2) if you use “awk ‘{print $2}’ “ you will get the second column of text. 3) don’t forget
some of the text processing commands we covered in lecture this week.
Solution
most_proc.sh:
$> ps hax -o user |sort | uniq -c | sort -n -r | head -n 10
In above script,
ps - Lists processes
h in hax will remove header
-o prints only user column
sort will sort in alphabetically
uniq -c - counts each occurence for particular user and displays count of all occurences instead of
separately dipalying each occurence
sort -n -r - prints the output in descending order by listing users with maximum number of
processes first
head -n -10 will print only top 10 users