4. At what temperature will a solution of 8.27 g CaCl2 in 45.0 g H2O begin to freeze? Assume complete dissociation of CaCl2. (The freezing point depression constant for water is Solution molality = (8.27/111)*(1000/45) = 1.655 vant hoff factor = 3 so deltaT= K*M*i = 1.86 * 1.655 *3 = 9.24 so Tsolvent - Tsolution = deltaT........ => Tsolution = Tsolvent - deltaT.... =>Tsolution = 1-9.24 = 8.24\'C.