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80 years of Dow Jones 
Industrial 
BY: FAITH ADEFARAKAN
regular Exponential
Power
1. Describe the association between β€œDJIA price” and β€œYears Since 1930” 1. Describe the association between β€œDJIA price” and 
β€œYears Since 1930”. 1. Describe the association between β€œDJIA price” and β€œYears Since 1930”. 
There association is a positive exponential relationship between the years since and the 
dow price. 
2. What is the equation for your linear model? (Use descriptive variables) 
Dow Price = 125.3(years)-2.4425x10^05 
3. Interpret the slope of the line in context. 
As the years increase the price goes up by 125 per year. The slope is steep 
4. Does the y-intercept of your model have a meaningful interpretation or is it just 
a hypothetical base value? Explain. 
The y intercept DOES NOT have a meaningful interpretation because the R^2 is 
63% which means that the y intercept has little to no association to the years 
since.
5. Look at the residuals plot for your linear model. Do you have any concerns 
about predictions made by your model? Explain. 
Yes. I’m concerned that the data being used isn’t descriptive enough . 
6. What is the equation of your new model? (Use descriptive variables) 
Y hat=.06234(year)-116 
7. Interpret the slope of the line in context. 
As the year increases the price goes up .06234. 
8. The y-intercept of your model have a meaningful 
interpretation? Explain. 
The y-intercept has a meaningful interpretation because there is a strong 
correlation and association ,because of R^2. 
9. The residuals plot for your transformed model still doesn’t look perfect, but has 
it improved? How do you feel about the appropriateness of your new model? 
The residual plot has improved from the original graph because there is a 
clearer correlation. 
10. What is the correlation for your transformed data? What does this indicate 
about the association? 
The correlation is roughly linear but also positive. This indicates that the 
exponential graph has the best "line of best fit". 
11. What is R2 for your transformed data? Interpret this value in context. 
R squared is 0.94 which is also 94%. This means that the natural log of the dow 
price and the years since have a strong correlation and association. 
12. Use your model to make a prediction about the Dow price in July of 2012.
Y hat= .06234(2012)-116=9.42808 
E^9.42808=12432.63315 
13. You will most likely retire sometime between 2040 and 2050. What does your 
model predict for the Dow price in 2045? Comment on the appropriateness of 
this prediction. 
Y hat= .06234(2045)-116= 11.4853 
E^11.4853=97275.2628514. What is the equation of the exponential model that Microsoft Excel fit to the 
original data? 
Y hat=.06234(year)-116 
15. Use the exponential model to make a prediction about the Dow price in 2012. 
Compare it to the prediction made by your model. Are they close? 
Y hat= .06234(2012)-116=9.42808 
E^9.42808=12432.6331 
16. Calculate the y-intercept of your model and the y-intercept of the exponential 
model. Are they close? Are these predictions lower or higher than the actual 
Dow price on 2012? 
Y- intercept for model a is -2.44e 
Y-intercept for model b is -116. 
The prediction for model B is lower than the predictions for model A.
80 years of dow jones industrial (3)

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80 years of dow jones industrial (3)

  • 1. 80 years of Dow Jones Industrial BY: FAITH ADEFARAKAN
  • 2.
  • 3.
  • 6. 1. Describe the association between β€œDJIA price” and β€œYears Since 1930” 1. Describe the association between β€œDJIA price” and β€œYears Since 1930”. 1. Describe the association between β€œDJIA price” and β€œYears Since 1930”. There association is a positive exponential relationship between the years since and the dow price. 2. What is the equation for your linear model? (Use descriptive variables) Dow Price = 125.3(years)-2.4425x10^05 3. Interpret the slope of the line in context. As the years increase the price goes up by 125 per year. The slope is steep 4. Does the y-intercept of your model have a meaningful interpretation or is it just a hypothetical base value? Explain. The y intercept DOES NOT have a meaningful interpretation because the R^2 is 63% which means that the y intercept has little to no association to the years since.
  • 7. 5. Look at the residuals plot for your linear model. Do you have any concerns about predictions made by your model? Explain. Yes. I’m concerned that the data being used isn’t descriptive enough . 6. What is the equation of your new model? (Use descriptive variables) Y hat=.06234(year)-116 7. Interpret the slope of the line in context. As the year increases the price goes up .06234. 8. The y-intercept of your model have a meaningful interpretation? Explain. The y-intercept has a meaningful interpretation because there is a strong correlation and association ,because of R^2. 9. The residuals plot for your transformed model still doesn’t look perfect, but has it improved? How do you feel about the appropriateness of your new model? The residual plot has improved from the original graph because there is a clearer correlation. 10. What is the correlation for your transformed data? What does this indicate about the association? The correlation is roughly linear but also positive. This indicates that the exponential graph has the best "line of best fit". 11. What is R2 for your transformed data? Interpret this value in context. R squared is 0.94 which is also 94%. This means that the natural log of the dow price and the years since have a strong correlation and association. 12. Use your model to make a prediction about the Dow price in July of 2012.
  • 8. Y hat= .06234(2012)-116=9.42808 E^9.42808=12432.63315 13. You will most likely retire sometime between 2040 and 2050. What does your model predict for the Dow price in 2045? Comment on the appropriateness of this prediction. Y hat= .06234(2045)-116= 11.4853 E^11.4853=97275.2628514. What is the equation of the exponential model that Microsoft Excel fit to the original data? Y hat=.06234(year)-116 15. Use the exponential model to make a prediction about the Dow price in 2012. Compare it to the prediction made by your model. Are they close? Y hat= .06234(2012)-116=9.42808 E^9.42808=12432.6331 16. Calculate the y-intercept of your model and the y-intercept of the exponential model. Are they close? Are these predictions lower or higher than the actual Dow price on 2012? Y- intercept for model a is -2.44e Y-intercept for model b is -116. The prediction for model B is lower than the predictions for model A.