Dave threw a ball into the air while standing on a 10 foot tall table. The height, h(t), of the ball t seconds after it is tossed is can be modeled by the function h(t) = 16t 2 + 32t + 10 How long was the ball in the air? Solution h(t) = 16t^2 + 32t + 10 we need to find time t at which h(t) = 0 h(t) = 16t^2 + 32t + 10 = 0 16t^2 -32t - 10 = 0 8t^2 -16t - 5 = 0 solving for t we get, t= 2.27 s and t = -0.27 s since t can\'t be negative t = 2.27 s Answer: 2.27 s.