1) What would the concentration of OH - be if the concentration of H 3 O + was 1 × 10 -5 M?
[H 3 O + ] × [OH - ] = K w = 1 × 10 -14
2) Over the past 50 years, the global amount of carbon dioxide in the atmosphere increased by 158 billion tons, but over 215 billion were released by burning of fossil fuels. Where did the rest go? A. It was recycled. B.It was converted into carbohydrates. C.it escaped into space. D.It was converted into acid rain. E.It was absorbed by the oceans.
Solution
1)
Ionic product of water Kw expeession is
Kw = [H3O+][OH-]
therefore,
[H3O+] [OH-] = 1.0×10 -14
substitute the given H3O+ concentration
1.0×10 -5 M × [OH-] = 1.0×10 -14 M 2
[OH-] = 1.0×10 -14 M 2 /1.0×10 -5 M
[OH-] = 1.0 ×10 -9 M
Therefore,
concentration of OH- = 1.0×10 -9 M
2) E) It was absorbed by the oceans
.
1. 1) What would the concentration of OH -
be if the concentration of H 3 O +
was 1 × 10 -5
M?
[H 3 O +
] × [OH -
] = K w = 1 × 10 -14
2) Over the past 50 years, the global amount of carbon dioxide in the atmosphere increased by
158 billion tons, but over 215 billion were released by burning of fossil fuels. Where did the rest
go? A. It was recycled. B.It was converted into carbohydrates. C.it escaped into space. D.It was
converted into acid rain. E.It was absorbed by the oceans.
Solution
1)
Ionic product of water Kw expeession is
Kw = [H3O+][OH-]
therefore,
[H3O+] [OH-] = 1.0×10 -14
substitute the given H3O+ concentration
1.0×10 -5
M × [OH-] = 1.0×10 -14
M 2
[OH-] = 1.0×10 -14
M 2
/1.0×10 -5
M
[OH-] = 1.0 ×10 -9
M
Therefore,
concentration of OH- = 1.0×10 -9
M
2) E) It was absorbed by the oceans
![1) What would the concentration of OH -
be if the concentration of H 3 O +
was 1 × 10 -5
M?
[H 3 O +
] × [OH -
] = K w = 1 × 10 -14
2) Over the past 50 years, the global amount of carbon dioxide in the atmosphere increased by
158 billion tons, but over 215 billion were released by burning of fossil fuels. Where did the rest
go? A. It was recycled. B.It was converted into carbohydrates. C.it escaped into space. D.It was
converted into acid rain. E.It was absorbed by the oceans.
Solution
1)
Ionic product of water Kw expeession is
Kw = [H3O+][OH-]
therefore,
[H3O+] [OH-] = 1.0×10 -14
substitute the given H3O+ concentration
1.0×10 -5
M × [OH-] = 1.0×10 -14
M 2
[OH-] = 1.0×10 -14
M 2
/1.0×10 -5
M
[OH-] = 1.0 ×10 -9
M
Therefore,
concentration of OH- = 1.0×10 -9
M
2) E) It was absorbed by the oceans](https://image.slidesharecdn.com/1whatwouldtheconcentrationofoh-beiftheconcentrationofh3o-230131003414-874e13aa/85/1-What-would-the-concentration-of-OH-be-if-the-concentration-of-H3O-docx-1-320.jpg)
