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1. 4 by 3 Multiplication
Vedic Mathematics
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4 x 3 Multiplication:4 x 3 Multiplication:
 Answer is divided into 7 parts (4+3)-1=6
 The pattern for each part is given below :
 Each dot (•) represent single digit in the number & line
jointly represents the no’s to be multiplication
• • •
• • • •• • • •
• • •
• • • •
• • •
• • • •• • • •• • • •
• • •• • •• • •

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Find 2013 x 101
2 0 1 3
11 0
x
(3x1)
3

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Find 2013 x 101
2 0 1 3
11 0
x
(1x1)
4
+(0x3)

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Find 2013 x 101
2 0 1 3
11 0
x
(0x1)
3
+(1x3) +(1x0)

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Find 2013 x 101
2 0 1 3
1 0 1
x
(2x1)
3
+(0x0) +(1x1)

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Find 2013 x 101
2 0 1 3
1 0 1
x
(2x0)
0
+(0x1)

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Find 2013 x 101
2 0 1 3
1 0 1
x
(2x1)
2

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Find 2013 x 101
2 0 1 3
11 0
x
(3x1)(1x1)+(0x3)(0x1)+(1x3)+(0x1)(2x1)+(1x1)+(0x0)(2x3)+(0x1)(2x1)
313362
Ans: 263313

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Find 3123 x 213
3 1 2 3
32 1
x
(3x3)(2x3)+(3x1)(1x3)+(2x1)+(3x2)(3x3)+(1x1)+(2x2)(3x1)+(1x2)(3x2)
99111456
Ans: 665199
1 1

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Find 3241 x 232
3 2 4 1
22 3
x
(1x2)(4x2)+(1x3)(2x2)+(4x3)+(1x2)(3x2)+(2x3)+(4x2)(3x3)+(2x2)(3x2)
2111820136
Ans: 751912
2 1 11

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Find 4253 x 335
4 2 5 3
53 3
x
(3x5)(5x5)+(3x3)(2x5)+(5x3)+(3x3)(4x5)+(2x3)+(5x3)(4x3)+(2x3)(4x3)
153434411812
Ans: 1424755
4 3 31 1

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Find 1991 x 108
2 0 1 1
21 1
x
(1x2)(1x2)+(1x1)(0x2)+(1x1)+(1x1)(2x2)+(0x1)+(1x1)(2x1)+(0x1)(2x1)
230522
Ans:215028
1991=2 01 1 &
 Convert Vinculum to Normal
108= 1 1 2
2 2 5 0 3 2

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Find 2771 x 2425
3 2 3 1
2 54 3
x
(1x5)(3x5)+(1x3)(2x5)+(3x3)+(1x4
)
(3x5)+(2x3)+(3x4)+(1x2)(3x3)+(2x4)+(3x2)(3x4)+(2x2)(3x2)
51853 1586
Ans: 6719675
-3 1
2771=3 2 3 1 & 2425=2 4 3 5
= 6 8 8 1 6 8 5
 Convert Vinculum to Normal

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Find 826 x 2626
1 2 3 4
3 44 3
x
(4x4)(3x4)+(4x3)(2x4)+(3x3)+(4x4
)
(1x4)+(2x3)+(3x4)+(4x3)(1x3)+(2x4)+(3x3
)
(1x4)+(2x3)(1x3)
162 43 33 42 01 03
Ans: 2169076
-3 -2
826=1 2 3 4 & 2626 = 3 4 3 4
= 2 2 3 1 1 3 6
 Convert Vinculum to Normal
132-1

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Find 1655 x 1432
2 3 4 5
1 24 3
x
(5x2)(4x2)+(5x3)(3x2)+(4x3)+(5x4
)
(2x2)+(3x3)+(4x4)+(5x1)(2x3)+(3x4)+(4x1)(2x4)+(3x1)(2x1)
1 02 33 82 61 052
Ans: 2369960
1655= 2 3 4 5 & 1432
= 2 4 3 0 0 4 0
 Convert Vinculum to Normal
-2 -1-3-2-1

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Find 3662 x 3379
4 3 24
3 124
x
(2x1)(4x1)+(2x2)(3x1)+(4x2)+(2x4
)
(4x1)+(3x2)+(4x4)+(2x3)(4x2)+(3x4)+(4x3)(4x4)+(3x3)(4x3)
201 983 271 2
Ans: 12373898
3662 = 4 3 4 2 & 3379 = 3 4 2 1
= 1 2 4 2 7 9 0 2
 Convert Vinculum to Normal
1-3