Number of flaws in a glass sheet has a Poisson distribution with a parameter of 0.5 , which indicates the expected number of flaws per sheet is 0.5. What is the probability that a random sample of ten sheets does not contain any defective sheets ( at most one flaw)? Solution lamda=0.5/10=0.05 P(X=0)=e^-0.05*0.05^0/0!=e^-0.05=0.9512.

1. Number of flaws in a glass sheet has a Poisson distribution with a parameter of 0.5 , which
indicates the expected number of flaws per sheet is 0.5. What is the probability that a random
sample of ten sheets does not contain any defective sheets ( at most one flaw)?
Solution
lamda=0.5/10=0.05
P(X=0)=e^-0.05*0.05^0/0!=e^-0.05=0.9512