How does the shape of cellulose make possible its function Note the .pdf

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How does the shape of cellulose make possible its function? Note the arrangement of individual cellulose molecules and bonds as part of your answer and mention something about both covalent and noncovalent bonds. If you really want to see the H bonds, right click on the jsmol figure, choose \"style\" \"hydrogen bonds\" and then set their diameter to 30 Angstroms. You can also choose \"color\" and make them some other color to make them easier to see! Solution Cellulose is the most abundant organic compound on earth. It is a major component of tough cell walls that surround plant cells, and is what makes plant stems, leaves, and branches so strong. Its unique, rigid structure serves an important function in plants. Its molecules are joined together using hydrogen bonds and are arranged parallel to one another, forming a long, cable-like structure that merges with other cellulose molecules. This creates the strong support structure that allows plants to stand upright. Note: Image is missing in the question.

How does the shape of cellulose make possible its function? Note the arrangement of individual
cellulose molecules and bonds as part of your answer and mention something about both
covalent and noncovalent bonds. If you really want to see the H bonds, right click on the jsmol
figure, choose "style" "hydrogen bonds" and then set their diameter to 30 Angstroms. You can
also choose "color" and make them some other color to make them easier to see!
Solution
Cellulose is the most abundant organic compound on earth. It is a major component of tough cell
walls that surround plant cells, and is what makes plant stems, leaves, and branches so strong. Its
unique, rigid structure serves an important function in plants. Its molecules are joined together
using hydrogen bonds and are arranged parallel to one another, forming a long, cable-like
structure that merges with other cellulose molecules. This creates the strong support structure
that allows plants to stand upright.
Note: Image is missing in the question

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Part A: Briefly, explain the current hypotheses about how brown algae, red algae, chlorophytes and charophytes (couple of groups of green algae), and land plants are related. What are the characteristics of the land plants that distinguish it from the most closely related algal group, and (if applicable) how do each of these characteristics benefit plants in a terrestrial environment? Part B: What are the differences between plant cells, animal cells, and bacterial cells. And what are the characteristics of different plant cell types. Solution (1)Evolution of plants has facilitated the survival of life on earth and these land plants has their monophyletic lineage embedded with that of green algae and these green algae are believed to be the oldest eukaryotic lineages. Hypothesis states that land plants are related to brown algae, red algae, chlorophytes and charophytes. There are so many evidences to prove that these land plants share similar characteristics with that of brown algae, red algae, chlorophytes and charophytes. Plants and algae are eukaryotic and both posses the chlorophyll, which allows them to make their own food, both plants and algae have similar cell walls, stores energy in the form of starch, follows two stage life cycle. Sporopollenin, chlorophyll a, cellulose, chlorophyll b are common to both charophytes and land plants, but plants has lignin and is absent in case of charophytes. Some green algae exhibit alternation of generations like plants. All land plants exhibit alternation of generations. But no charophytes exhibit alternation of generations. Charophytes are very similar to plants as they both have homologous chloroplasts (chlorophyll b, beta carotene is present, thylakoid are arranged as grana, DNA as genetic material), with respect to biochemical similarity, both has cellulose cell wall, similar enzymes in peroxisomes, when it comes to mitosis and cytokinesis, follow similar mechanisms like disappearance of nuclear envelope and till cytokinesis the spindle will remain. Based on the above features the Charophytes are considered as the closest living algal relatives of land plants Most of the varieties of algal species live in extremely damp terrestrial environment, whereas most of the plants live on land and some plants can live in water also, but algae cannot survive on dry soil and they are very adapted to it. In case of alga, the surrounding water supports it and the whole alga is involved in helping it in the process of photosynthesis, absorption of water and minerals, holdfast will provides the anchoring. But in case of plants, each and every organ is specialized for different functions, like leaves for photosynthesis, cuticle to prevent water loss, stomata for gaseous exchange, stem to support, root to provide anchorage. But alternation of generation is absent in charophytes, but it is found in all plants providing them extra benefit to survive. 2) Animal Cell Plant cell Bacteria These are eukaryotes These ar.

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Kent and Emily have a baby boy Dustin by in vitro fertilization. Dustin does not resemble either one of his parents, so they suspect that the clinic made a mistake during the procedure and implanted the wrong embryo. At Dustin\'s first well-baby checkup they insist that they get his blood type. Baby Dustin is type B-negative. Kent is A-positive and Emily is AB-positive. Given this information answer the following questions. (a) What are Dustin\'s possible genotypes? __________ (b) What are Kent\'s possible genotypes? __________ (c) What are Emily\'s possible genotypes? __________ (d) Is it possible that Dustin is Kent and Emily\'s son? __________ (e) Explain your answer in (d) __________ Carrie is AB-positive and her father is AB-negative. Carrie marries Ryan, who is AB-negative. (f) What is Carrie\'s genotype? __________ (g)What is Ryan\'s genotype? __________ (h) What are the phenotypic ratios of blood types (for both the ABO gene and Rh gene) that would be expected among their children? __________ (Show your work in a Punnett square below!) Solution Answer: a). Dustin’s possible genotypes: IA IB : Rh+ Rh+ or IA IB : Rh+ Rh- b). Kent’s possible genotypes: IA IA : Rh+ Rh+ or IA IA : Rh+ Rh- or IA i : Rh+ Rh+ or IA i : Rh+ Rh- c). Emily’s possible genotypes: IB IB : Rh- Rh- or IB i : Rh- Rh- d). Yes Dustin belongs to Kenta and Emily’s son. e). The gamete, IA: Rh+ of Kent’s and the gamete, IB: Rh- of Emily’s fuse to produce IA IB : Rh+ Rh- (AB-positive). Rh+ is dominant over Rh- IA & IB are codominant. f). Carrie’s genotype (AB-positive): IAIB: Rh+Rh- g). Ryan’s genotype (AB-negative): IAIB: Rh-Rh- IAIB: Rh+Rh- x IAIB: Rh-Rh- IARh- IBRh- IARh+ IAIA Rh+Rh- (A+) IAIBRh+Rh- \\ (AB+) IA Rh- IAIA Rh-Rh- (A-) IAIB Rh-Rh- (AB-) IARh- IBRh- IARh+ IAIA Rh+Rh- (A+) IAIBRh+Rh- \\ (AB+) IA Rh- IAIA Rh-Rh- (A-) IAIB Rh-Rh- (AB-).

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Kent and Emily have a baby boy Dustin by in vitro fertilization. Dust.pdf

Kent and Emily have a baby boy Dustin by in vitro fertilization. Dust.pdf

Isabel Lopez started Biz Consulting, a new business, and completed the following transactions during its first year of operations a. I. Lopez invests $69,000 cash and office equipment valued at $37,000 in the company in exchange for its common stock b. The company purchased a $309,000 building to use as an office. Biz paid $41,000 in cash and signed a note payable promising to pay the $268,000 balance over the next ten years. c. The company purchased office equipment for $5,400 cash. d. The company purchased $3,500 of office supplies and $1,700 of office equipment on credit. e. The company paid a local newspaper $960 cash for printing an announcement of the office\'s opening. f. The company completed a financial plan for a client and billed that client $4,200 for the service g. The company designed a financial plan for another client and immediately collected an $8.100 cash fe h. The company paid $1,600 cash in dividends to the owner . The company received $3.200 cash as partial payment from the client described in transaction f payment of $850 cash on the equipment purchased in transaction d k. The company paid $2.400 cash for the office secretary\'s wages for this period. Required: 2. Enter the amount of each transaction on individual items of the accounting equation. (Enter reductions to account balances with a minus sign.) Assets Office Office Accounts Solution Answer Assets Liabilities Equity Cash Accounts receivables Office Supplies Office Equip ments Buildings Accounts Payable Notes Payable Common Stock Dividends Revenues Expenses a 69000 37000 106000 b -41000 309000 268000 28000 0 0 37000 309000 0 268000 106000 0 0 0 c -5400 5400 22600 0 0 42400 309000 0 268000 106000 0 0 0 d 3500 1700 5200 22600 0 3500 44100 309000 5200 268000 106000 0 0 0 e -960 960 21640 0 3500 44100 309000 5200 268000 106000 0 0 960 f 4200 4200 21640 4200 3500 44100 309000 5200 268000 106000 0 4200 960 g 8100 8100 29740 4200 3500 44100 309000 5200 268000 106000 0 12300 960 h -1600 1600 28140 4200 3500 44100 309000 5200 268000 106000 1600 12300 960 i 3200 -3200 31340 1000 3500 44100 309000 5200 268000 106000 1600 12300 960 j -850 -850 30490 1000 3500 44100 309000 4350 268000 106000 1600 12300 960 k -2400 2400 Bal 28090 1000 3500 44100 309000 4350 268000 106000 1600 12300 3360 Assets Liabilities Equity Cash Accounts receivables Office Supplies Office Equip ments Buildings Accounts Payable Notes Payable Common Stock Dividends Revenues Expenses a 69000 37000 106000 b -41000 309000 268000 28000 0 0 37000 309000 0 268000 106000 0 0 0 c -5400 5400 22600 0 0 42400 309000 0 268000 106000 0 0 0 d 3500 1700 5200 22600 0 3500 44100 309000 5200 268000 106000 0 0 0 e -960 960 21640 0 3500 44100 309000 5200 268000 106000 0 0 960 f 4200 4200 21640 4200 3500 44100 309000 5200 268000 106000 0 4200 960 g 8100 8100 29740 4200 3500 44100 309000 5200 268000 106000 0 12300 960 h -1600 1600 28140 4200 3500 44100 309000 5200 268000 106000 1600 12300 960 i 3200 -3200 31340 1000 3500 44100 .

Isabel Lopez started Biz Consulting, a new business, and completed th.pdf

Isabel Lopez started Biz Consulting, a new business, and completed th.pdf

Isabel Lopez started Biz Consulting, a new business, and completed th.pdf

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Indicate all personsinvestigators participating in the Program and .pdf

Indicate all personsinvestigators participating in the Program and .pdf

Indicate all personsinvestigators participating in the Program and .pdf

In the context of materials science & engineering, what is the difference between Curie temperature and Debye temperature? Solution Curie temperature (TC), or Curie point, is the temperature at which certain materials lose theirpermanent magnetic properties, to be replaced by induced magnetism. The Curie temperature is named after Pierre Curie, who showed that magnetism was lost at a critical temperature. Debye temperature is thetemperature of a crystal\'s highest normal mode of vibration, i.e., the highest temperature that can be achieved due to a single normal vibration.

In the context of materials science & engineering, what is the diffe.pdf

In the context of materials science & engineering, what is the diffe.pdf

In the context of materials science & engineering, what is the diffe.pdf

22. Mrs. Jones gave birth prematurely to her first child. At birth, the baby weighed 2 lb 8 oz. Within a few hours, the baby had developed severe dyspnea and was becoming cyanotic. Therapy with a positive pressure ventilator was prescribed. Answer the following questions related to the situation just described. Place your responses in the answer blanks. 1. The infant\'s condition is referred to as infant Res 2. It occurs because of a relative lack of 3. The function of the deficient substance is to 4. Explain what the positive pressure apparatus accomplishes. Solution 1. The condition is referred to as infant respiratory distress syndrome (IRDS) also called neonatal respiratory distress syndrome. 2. It occurs due to relative lack of pulmonary surfactant. It is a developmental insufficiency and can also be caused due to structural immaturity in lungs. 3. The function of deficient substance (Surfactant) is to prevent collapse of terminal air spaces during the normal cycle of inhalation and exhalation. 4. Positive pressure keeps the alveoli open at the end of expiration and used to treat IRDS. It decreases the requirement of endotracheal ventilation in infants ..

22. Mrs. Jones gave birth prematurely to her first child. At birth, t.pdf

22. Mrs. Jones gave birth prematurely to her first child. At birth, t.pdf

22. Mrs. Jones gave birth prematurely to her first child. At birth, t.pdf

First year students: Mean 125, SD?, size 350 Third year students: Mean 112, SD?, size 150 Significance level = 0.02 Solution Let group 1 = first year group 2 = third year Formulating the hypotheses Ho: p1^ - p2^ >= 0 Ha: p1^ - p2^ < 0 Here, we see that pdo = 0 , the hypothesized population proportion difference. Getting p1^ and p2^, p1^ = x1/n1 = 0.357142857 p2 = x2/n2 = 0.746666667 Also, the standard error of the difference is sd = sqrt[ p1 (1 - p1) / n1 + p2 (1 - p2) / n2] = 0.043783715 Thus, z = [p1 - p2 - pdo]/sd = -8.896545395 As significance level = 0.02 , then the critical z is zcrit = -2.053748911 Also, the p value is P = 2.8806E-19 Thus comparing z and zcrit (or p and significance level), then we REJECT THE NULL HYPOTHESIS. Thus, there is significant evidence that the proportion of third year students who buy used textbooks is greater than the proportion of first year student who buy used textbooks. [CONCLUSION].

First year students Mean 125, SD, size 350Third year students M.pdf

First year students Mean 125, SD, size 350Third year students M.pdf

First year students Mean 125, SD, size 350Third year students M.pdf

Explain clearly how pseudonyms become credentials in VANETs? Explain clearly how pseudonyms become credentials in VANETs? Solution Each vehicle is equipped with a set of short-term certificates, termed pseudonyms, each with a corresponding short-term private key to sign outgoing messages. Example: Vehicle A digitally signs outgoing messages (time- and geo-stamped) with the private key, kiv , corresponding to the pseudonym Piv({Piv}(PCA) represents the pseudonym signed by the pseudonym issuer) and is attached to messages to facilitate verification on the receiver side. Receiving vehicles B and C verify the pseudonym {Piv}(P CA) and validate the signature (assuming they trust the pseudonym issuer discussed below). This process ensures the authenticity and integrity of the message and enables further validation based on its content. At the same time, transmissions by vehicle A do not reveal its identity (as the short-term certificates are anonymised), and messages signed under different pseudonyms (with different private keys) are, in principle, unlinkable. Vehicles switch from one pseudonym to another (not previously used) to achieve unlinkability of authorities with distinct roles: the Root Certification Author- ity (RCA), the Long Term Certification Authority (LTCA), the Pseudonym Certification Authority (PCA), and the Resolution Authority (RA). Different proposals may refer to these entities with various names, e.g., CAMP refers to the LTCA as the Enrollment Certification Authority (ECA). The RCAs are the highest-level authorities certifying LTCAs, PCAs, and RAs. An LTCA is responsible for registering vehicles and issuing Long Term Certificates (LTCs). A PCA issues sets of pseudonyms for the registered vehicles. An RA can initiate a process to resolve a pseudonym, i.e., identify the long-term identity of the vehicle that used (in a nonrepudiable manner) its short-term keys and credentials..

Explain clearly how pseudonyms become credentials in VANETsExpl.pdf

Explain clearly how pseudonyms become credentials in VANETsExpl.pdf

Explain clearly how pseudonyms become credentials in VANETsExpl.pdf

Explain the use and importance of the scientific name, genus and species. Explain the use and importance of the scientific name, genus and species. Solution Scientific Names(May be called Binomial Nomenclature) is the system of nomenclature in which two terms (mostly Latin forms,sometimes others are also used)are used to denote a species of living organism(The 1 st one is for Genus and the 2nd one is for species). e.g-Escherichia coli, Lactobacillus acidophilus IMPORTANCE- 1.Universal- Everyone in the world use the specific name to identify the specific organism. 2.organisms are easily categorized. 3.The chance of nomenclature is reduced. IMPORTANCE OF GENUS- The genus name forms the first part of the binomial nomenclature for each species. In the hierarchy of biological classification genus comes above species and below family. IMPORTANCE OF SPECIES- Basic unit of biological hierarchy It forms the second part of the biological binomial nomenclature. there are many species under a common genus..

Explain the use and importance of the scientific name, genus and .pdf

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