What is the range of y= absolute value f(x) if f(x) = -x^2? And can you explain how you got the answer? Thanks Solution f(x)=-x^2 before commenting about the range of this firstly check its domain now we can see that there is not a single point where the function is not defined hence the domain is all real now as x2 is always positive whether x is +ve or -ve hence -x2 is always negaive which is our function hence f(x)=-x2 is alwayys negative hence its range is (-infinnity, 0].