B. The four key areas of identify and access management are identifi.pdf

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B. The four key areas of identify and access management are identification, authentication, authorization, and accountability. The fact that the security officer is reviewing the logs for accuracy is a form of accountability. Therefore, answers A, C, and D are incorrect. Solution B. The four key areas of identify and access management are identification, authentication, authorization, and accountability. The fact that the security officer is reviewing the logs for accuracy is a form of accountability. Therefore, answers A, C, and D are incorrect..

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The surprising revelation the quiz gave about races was that races are have not been around in the world since ever. They are a result of ideas developed in different cultures through-out modern history. Basically there are no scientific rules defining a race. For eg. if people differentiate in races based on skin colour and practice racism, it is absolutely wrong because skin colour is not sufficient to determine a person\'s race, culture or susceptibility to disease. it might be just an indication of the geographical origin of that person. If we observe the genetic composition of africans, asians and europeans, most of their DNA is the same but africans have several other novel genes. There is no set of genes that specify a race. Genetic diversity between people is much more detailed than how people definne races. An idea which cannot be proved with logic and science and which does not follow any specified rules should not be considered as real. Racism is a result of mentality of people considering one skin colour or one culture better than the other. It has always been and is still a huge cause of discrimination in the world leading to mental stress in a large number of people. Racism is no measure of a person\'s capabilities and awareness should be spread through the world to diminish this form of discrimination. You can add your own ideas and let me know how much this helped! :) Solution The surprising revelation the quiz gave about races was that races are have not been around in the world since ever. They are a result of ideas developed in different cultures through-out modern history. Basically there are no scientific rules defining a race. For eg. if people differentiate in races based on skin colour and practice racism, it is absolutely wrong because skin colour is not sufficient to determine a person\'s race, culture or susceptibility to disease. it might be just an indication of the geographical origin of that person. If we observe the genetic composition of africans, asians and europeans, most of their DNA is the same but africans have several other novel genes. There is no set of genes that specify a race. Genetic diversity between people is much more detailed than how people definne races. An idea which cannot be proved with logic and science and which does not follow any specified rules should not be considered as real. Racism is a result of mentality of people considering one skin colour or one culture better than the other. It has always been and is still a huge cause of discrimination in the world leading to mental stress in a large number of people. Racism is no measure of a person\'s capabilities and awareness should be spread through the world to diminish this form of discrimination. You can add your own ideas and let me know how much this helped! :).

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The answer is D. ChemoorganoheterotrophCow is a chemoorganohetero.pdf

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The A and B chains of human insulin are cloned in separate plasmids .pdf

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Question 1How many parameters does a default constructor haveAn.pdf

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Rio de Janeiro is a city located on Brazil\'s south-east coast. It is one of Brazil\'s largest settlements with a population of approximately 11.7 million people. The population of Rio de Janeiro has grown for a number of reasons. Natural Increase is one reason for its growth (this is when the birth rate is higher than the death rate). The population has also grown as the result of urbanisation. The has been caused by rural to urban migration. Millions of people have migrated from Brazil\'s rural areas to Rio de Janeiro. 65% of urban growth is a result of migration. This is caused by a variety of push and pull factors. The rapid growth of Rio de Janeiro\'s population has led to a severe shortage of housing. Millions of people have been forced to construct their own homes from scrap materials such as wood, corrugated iron and metals. These areas of temporary accommodation are known as favelas in Brazil. The conditions associated with favelas are very poor. Often families have to share one tap, there is no sewerage provision, disease is common and many people are unemployed. Favelas are located on the edge of most major Brazilian cities. They are located here for a number of reasons. Firstly, this is the only available land to build on within the city limits. Secondly, industry is located on the edge of the cities. Many people need jobs therefore they locate close to factories. Some of these settlements may be 40 or 50 km from the city centre (on the edge of the city), along main roads and up very steep hillsides. Causes of urban growth; Although the process of urbanisation happens in both MEDCs(more economically developed countries)and LEDCs,(less economically developed countries) the fastest-growing cities in the world are in LEDCs. The reasons for the growth of urban areas include: There are many problems associated with the rapid growth. These include unplanned housing (squatter settlements/shanty towns), dealing with urban waste, pollution and stress on the infrastructure and the city\'s services. Shanty towns/sqatter settlements; The fact that cities in LEDCs are growing rapidly means that conditions can be poor. There are often great inequalities within LEDC urban areas and they are even more pronounced in LEDCs. Some of the worst conditions are found in the shanty towns on the edge of the city, near the CBD(convention on biological diversity) or along main transport routes. They tend to be unplanned and are often illegal. Houses are self-built using basic materials and shanty towns have few services. Shanty town residents face many problems on a daily basis. Problems in shanty towns/squatter settlements this is how the squatter settlements effects the urban geography of brazil Solution Rio de Janeiro is a city located on Brazil\'s south-east coast. It is one of Brazil\'s largest settlements with a population of approximately 11.7 million people. The population of Rio de Janeiro has grown for a number of reasons. Natural Increase is one .

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Othello.java package othello; import core.Game; import userInterface.OthelloUi; public class Othello { // main is \"static\" because it\'s going to be called by the java interpreter // before any objects are created, thus, it does not need to be in an // instance of the Othello class to be called, it can simply be called // whenever. public static void main(String[] args) { Game game = new Game(); OthelloUi othelloUi = new OthelloUi(game); } } OthelloUi.java package userInterface; import core.Game; import userInterface.GameUi; import userInterface.BoardUi; import java.awt.BorderLayout; import java.awt.Dimension; import javax.swing.JFrame; public class OthelloUi extends JFrame { private Game game; private GameUi gameUi; private BoardUi boardUi; public OthelloUi(Game game) { this.game = game; // Create components and put them in JFrame upon class // instantiation. initComponents(); } private void initComponents() { this.setPreferredSize(new Dimension(600, 600)); this.setMinimumSize(new Dimension(600, 600)); // This is done to close the actual application once the // UI is closed via X. this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); gameUi = new GameUi(); boardUi = new BoardUi(); // By default, JFrame uses BorderLayout as its LayoutManager, // which is responsible for managing how UI components are placed // within framses/panels. this.add(gameUi, BorderLayout.NORTH); this.add(boardUi, BorderLayout.CENTER); this.setVisible(true); } } GameUi.java package userInterface; import java.awt.Dimension; import javax.swing.JLabel; import javax.swing.JPanel; public class GameUi extends JPanel { public GameUi() { // Creates components and puts them in the JPanel on // instantiation. initComponents(); } private JLabel nameOne; private JLabel nameTwo; private JLabel scoreOne; private JLabel scoreTwo; private void initComponents() { // Set dimensions for JPanel. this.setPreferredSize(new Dimension(200, 100)); this.setMinimumSize(new Dimension(200, 100)); // Label components. nameOne = new JLabel(\"Player One\"); nameTwo = new JLabel(\"Player Two\"); scoreOne = new JLabel(\"0\"); scoreTwo = new JLabel(\"0\"); nameOne.setMinimumSize(new Dimension(100, 50)); nameTwo.setMinimumSize(new Dimension(100, 50)); scoreOne.setMinimumSize(new Dimension(100, 50)); scoreTwo.setMinimumSize(new Dimension(100, 50)); // JPanel uses FlowLayout layout manager, which adds components // left to right in a row, until it runs out of space and creates // a new row. this.add(nameOne); this.add(scoreOne); this.add(nameTwo); this.add(scoreTwo); } } BoardUi.java package userInterface; import core.Constants; import java.awt.Color; import java.awt.Dimension; import java.awt.GridLayout; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.ImageIcon; import javax.swing.JButton; import javax.swing.JPanel; public class BoardUi extends JPanel { private JButton[][] board; private BoardListener listener; public BoardUi() { initComponents(); } private voi.

Othello.javapackage othello;import core.Game; import userInter.pdf

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1. Types of Computer Information Systems There are four basic types of computer-based information Systems: Transaction Processing Systems (TPS) Record day-to-day transactions such as customer orders, bills, inventory. Helps supervisors by generating databases needed for other information Systems. Examples: recording customer orders, bills, inventory levels, and production output. Management Information Systems (MIS) Summarizes the detailed data of the transaction processing system. Produces standard reports for middle-level managers. Examples: Production schedule and budget summaries. Decision Support Systems (DSS) Draws on the detailed data of the transaction processing system. Provides a flexible tool for middle-level managers for analysis. Examples: Analyzing the effects of events such as strikes, rising interest rates, etc. Executive Support Systems (ESS) Presents information in a very highly summarized form. Combines the internal data from TPS and MIS with external data. Helps top-level managers oversee operations and develop strategic plans. Examples: Introducing new products, starting a company wide cost control program, etc. 2. Benifits: 1. Enabling better and faster decision making By delivering relevant information at the time of need through structure, search, subscription, syndication, and support, a knowledge management environment can provide the basis for making good decisions. Collaboration brings the power of large numbers, diverse opinions, and varied experience to bear when decisions need to be made. The reuse of knowledge in repositories allows decisions be based on actual experience, large sample sizes, and practical lessons learned. 2. Making it easy to find relevant information and resources When faced with a need to respond to a customer, solve a problem, analyze trends, assess markets, benchmark against peers, understand competition, create new offerings, plan strategy, and to think critically, you typically look for information and resources to support these activities. If it is easy and fast to find what you need when you need it, you can perform all of these tasks efficiently. 3. Reusing ideas, documents, and expertise Once you have developed an effective process, you want to ensure that others use the process each time a similar requirement arises. If someone has written a document or created a presentation which addresses a recurring need, it should be used in all future similar situations. When members of your organization have figured out how to solve a common problem, know how to deliver a recurring service, or have invented a new product, you want that same solution, service, and product to be replicated as much as possible. Just as the recycling of materials is good for the environment, reuse is good for organizations because it minimizes rework, prevents problems, saves time, and accelerates progress. 4. Avoiding redundant effort No one likes to spend time doing something over again. But they do so all the .

1.Types of Computer Information SystemsThere are four basic type.pdf

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Microbiome of human body: Researchers currently studying human normal microbiota such as Escherichia coli (vitamin K producing), lactobacilli are essential and important to the human health & these microsymbionts lives in the gut of human with symbiotic relationship. This microbiota is going to generate vitamins, cofactors (NADH, FADH2) and human body does not synthesize some vitamins but these microbiota is going to synthesize essential vitamins. These microbiotas are going to digest cellulose content in fruits and vegetables and whole grains finally improve essential nutrients to the human body. Health digestion activity of insoluble fibres can ensure that you have a good health. Local nutrient source: Whole grain bread possesses higher content of insoluble fiber followed by enzymatic digestion of gut microbiota into n-butyrate. Insoluble fiber digestion into n-butyrate mediated by coloncocci and streptococci intestinal bacterial species by enzymatic activity. Effect of immune system: M cells: These are called as microfold cell and they are located within the gut epithelium of payer’s patches. M cell functions mainly samples usual gut flora and enable movement of the gut microbiota to basolateral side to immune cells in the gastrointestinal tract followed by response produced by B and T lymphocytes on as usual basis. These cells are acting like border control and enable pumping T cells and immunoglobulin-A (IgA) across gastro intestinal mucosa. These cells enable colonizing gut microbiota on the epithelium for appropriate digestion of food bolus. The normal microbiota is pathogenic and may induce severe effects when they migrated to another tissue from their native place of living. Nose and mouse microbiota are such as Staphylococcus epidermis and are nearly 100% occurrence in both nose and mouth. These microbes are pathogenic if they move other organs. Diversified microbiota was observed and this microbiota includes both Gram positive and Gram- negative species. Corynebacterium and Steptococcus pyogenes are at least form 25% of nasal microbiota whereas Spirochaetes and is highly abundant in mouth & its presence was not mentioned in OSU. Elders often possess weakened immune system and these circumstances leading to opportunistic viral infection and gastroinstestinal infections (fungal, protozoan) where microbiota enables human digestion. These viral particles act as bacteriophages to invade bacterial cells to generate more virions to propagate further infection leaving the microbiota inactive and dead. Sometimes excess use of anti-microbial chemotherapeutic agents acts as agents to invade gut microbiota due to inhibition of their growth via various cell-synthesizing mechanisms for example, inhibiting cell wall synthesis of bacteria. Some antibiotics inhibit DNA gyrase non- specifically including host cells and useful microbiota result in death of useful vitamin producing microbiota. The causes of altered microbiota in the elderly: 1. Aging,.

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Na2SeO3 ---> 2 Na+ + SeO32- 0.08 0.16 0.08 SeO32- + H2O <---> HSeO3- + OH- 0.08 0 0 -x x x 0.08-x x x Kb2 = Kw/Ka2 = 1E-14/(4.8E-9) Kb2 = 0.21E-5 0.21E-5 = x2/(0.08-x) x = 4.1E-4 HSeO3- + H2O <---> H2SeO3 + OH- 4.1E-4 0 0 -y y y 4.1E-4 - y y y Kb1 = Kw/Ka1 Kb1 = 1E-14/(2.4E-3) = 0.42E-11 The second hydrolysis constant is much smaller than the first, so we can the assume that the first step dominates. [H+]*[OH-]=1E-14 [H+]*4.1E-4=1E-14 [H+] = 0.24E-10 pH = 10.6 Ok? Solution Na2SeO3 ---> 2 Na+ + SeO32- 0.08 0.16 0.08 SeO32- + H2O <---> HSeO3- + OH- 0.08 0 0 -x x x 0.08-x x x Kb2 = Kw/Ka2 = 1E-14/(4.8E-9) Kb2 = 0.21E-5 0.21E-5 = x2/(0.08-x) x = 4.1E-4 HSeO3- + H2O <---> H2SeO3 + OH- 4.1E-4 0 0 -y y y 4.1E-4 - y y y Kb1 = Kw/Ka1 Kb1 = 1E-14/(2.4E-3) = 0.42E-11 The second hydrolysis constant is much smaller than the first, so we can the assume that the first step dominates. [H+]*[OH-]=1E-14 [H+]*4.1E-4=1E-14 [H+] = 0.24E-10 pH = 10.6 Ok?.

Na2SeO3 --- 2 Na+ + SeO32- 0.08 0.16 0.08 .pdf

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It is an important to understand the early stages of reproduction. When, the egg and sperm unite to form a zygote, each of the parents supply the zygote with half of the chromosomes necessary for a full set. The zygote, which is a single cell, then begins to reproduce itself by the cellular division process called mitosis, this stage is called morula and the new cells are called elastomers. When enough cells have been produced (the number varies from species to species), cell differentiation begins to take place. The first differentiation appears to be when the blastocyst is formed, which is an almost hollow sphere with a cluster of cells inside; and the differentiation appears to be between the cells inside, which become the fetus, and the cells outside, which become the fetal membranes and placenta. However, the process is not entirely understood at the present time and there is some variation between species; so it is difficult to pinpoint the onset of differentiation, which some scientists believe occurs during blastomere division. The purpose of this ability of a single blastomere to produce an entire embryo is probably to defence the process of embryo development against the destruction of any of the blastomeres. In theory, it should be possible to produce an entire embryo from each blastomere (and blastomeres are generally totipotent from the four to eight cell stage), but in practice it is usually only possible to produce two embryos. That is why this procedure is generally referred to as embryo splitting rather than cloning; although both terms refer to the same thing (cloning is the production of genetically identical embryos, which is a direct result of embryo splitting). Interestingly enough, although the embryos produced from separated blastomeres usually have fewer cells than a normal embryo, the resulting offspring fall within the normal range of size for the species. Another interesting embryonic manipulation is the creation of chimaeras. These are formed by uniting two different gametes, so that the embryo has two distinct cell lineages. Chimaeras do not combine the genetic information of both lineages in each cell. Instead, they are a patchwork of cells containing one lineage or the other. For this reason, the offspring of chimaeras are from one distinct genotype or the other, but not from both. Thus chimaeras are not useful for creating new animal populations beyond the first generation. However, they are extremely useful in other contexts. For instance, while embryo division as described above is limited in the number of viable embryos that can be produced, chimaeras can be used to increase the number. After the blastomeres are separated, they can be combined with blastomeres of a different genetic lineage. It has been found that with the additional tissue, the survival rate of the new embryos is more favorable. For some reason only a small percentage of the resulting embryos are chimaeric; this is thought to be because on.

It is an important to understand the early stages of reproduction. W.pdf

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Let the normal gene be represented by P, and the two mutations be represented by p# and p*. Given that the plant is p#p*, and that the two mutations seggregate independently. Therefore, the gametes p# and p* will be obtained in equal frequencies (1:1). Upon self-cross, the genotypes obtained will be: p# p* p# p#p# (1) p#p* (1) p* p#p* (1) p*p* (1) In the table given above, it can be seen that p#p* appears twice (1 + 1 = 2), whereas p#p# and p*p* appear only once (1). Since, both the mutations are recessive, three phenotypes would be obtained in the ratio: mutant 1 : normal : mutant 2 :: 1:2:1 Three genotypes will be obtained in the ratio: p#p# : p#p* : p*p* :: 1:2:1 p# p* p# p#p# (1) p#p* (1) p* p#p* (1) p*p* (1) Solution Let the normal gene be represented by P, and the two mutations be represented by p# and p*. Given that the plant is p#p*, and that the two mutations seggregate independently. Therefore, the gametes p# and p* will be obtained in equal frequencies (1:1). Upon self-cross, the genotypes obtained will be: p# p* p# p#p# (1) p#p* (1) p* p#p* (1) p*p* (1) In the table given above, it can be seen that p#p* appears twice (1 + 1 = 2), whereas p#p# and p*p* appear only once (1). Since, both the mutations are recessive, three phenotypes would be obtained in the ratio: mutant 1 : normal : mutant 2 :: 1:2:1 Three genotypes will be obtained in the ratio: p#p# : p#p* : p*p* :: 1:2:1 p# p* p# p#p# (1) p#p* (1) p* p#p* (1) p*p* (1).

Let the normal gene be represented by P, and the two mutations be re.pdf

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Imagine you are an Information Systems Security Officer for a medium-sized financial services firm that has operations in four (4) states (Virginia, Florida, Arizona, and California). Due to the highly sensitive data created, stored, and transported by your organization, the CIO is concerned with implementing proper security controls for the LAN-to-WAN domain. Specifically, the CIO is concerned with the following areas: Protecting data privacy across the WAN Filtering undesirable network traffic from the Internet Filtering the traffic to the Internet that does not adhere to the organizational acceptable use policy (AUP) for the Web Having a zone that allows access for anonymous users but aggressively controls information exchange with internal resources Having an area designed to trap attackers in order to monitor attacker activities Allowing a means to monitor network traffic in real time as a means to identify and block unusual activity Hiding internal IP addresses Allowing operating system and application patch management The CIO has tasked you with proposing a series of hardware and software controls designed to provide security for the LAN-to-WAN domain. The CIO anticipates receiving both a written report and diagram(s) to support your recommendations. Write a three to five (3-5) page paper in which you: Use MS Visio or an open source equivalent to graphically depict a solution for the provided scenario that will: filter undesirable network traffic from the Internet filter Web traffic to the Internet that does not adhere to the organizational AUP for the Web allow for a zone for anonymous users but aggressively controls information exchange with internal resources allow for an area designed to trap attackers in order to monitor attacker activities offer a means to monitor network traffic in real time as a means to identify and block unusual activity hide internal IP addresses Identify the fundamentals of public key infrastructure (PKI). Describe the manner in which your solution will protect the privacy of data transmitted across the WAN. Protecting data privacy across the WAN Filtering undesirable network traffic from the Internet Filtering the traffic to the Internet that does not adhere to the organizational acceptable use policy (AUP) for the Web Having a zone that allows access for anonymous users but aggressively controls information exchange with internal resources Having an area designed to trap attackers in order to monitor attacker activities Allowing a means to monitor network traffic in real time as a means to identify and block unusual activity Hiding internal IP addresses Allowing operating system and application patch management Solution Imagine you are an Information Systems Security Officer for a medium-sized financial services firm that has operations in four (4) states (Virginia, Florida, Arizona, and California). Due to the highly sensitive data created, stored, and transported by your organization, the CIO is concern.

Imagine you are an Information Systems Security Officer for a medium.pdf

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Each water molecule has 4 hydrogen bonds holding it in the solid phase. These are the bonds that are broken when the water sublimes (converts from solid to gas). Therefore, the H-bond energy is 11.9kcal/4 = 2.98 kcal/bond Solution Each water molecule has 4 hydrogen bonds holding it in the solid phase. These are the bonds that are broken when the water sublimes (converts from solid to gas). Therefore, the H-bond energy is 11.9kcal/4 = 2.98 kcal/bond.

Each water molecule has 4 hydrogen bonds holding .pdf

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Knowing the electronegativities of each atom involved in the bonds will be helpful in doing this problem. The greater the ionic character of a bond, the more ionic it is. When doing a problem like this, you have to keep in mind of the trends for electronegativity (EN): (1) EN increases from left to right in a period. (2) EN increases from bottom to top in a group. Na-F K-O Li-Li S-O K-Br Therefore, looking at the bonds above, you can list the bonds in the following order: Li-Li < S-O < K-Br < K-O < Na-F. Logically think this problem out using the trends first before checking with the electronegativites (change in EN will tell you how polar the bond is; the larger the change in electronegativity, the more polar/ionic the bond). This problem requires that you know the relative locations of the elements on the periodic table. If this helps you, then please rate lifesaver. Thanks. Solution Knowing the electronegativities of each atom involved in the bonds will be helpful in doing this problem. The greater the ionic character of a bond, the more ionic it is. When doing a problem like this, you have to keep in mind of the trends for electronegativity (EN): (1) EN increases from left to right in a period. (2) EN increases from bottom to top in a group. Na-F K-O Li-Li S-O K-Br Therefore, looking at the bonds above, you can list the bonds in the following order: Li-Li < S-O < K-Br < K-O < Na-F. Logically think this problem out using the trends first before checking with the electronegativites (change in EN will tell you how polar the bond is; the larger the change in electronegativity, the more polar/ionic the bond). This problem requires that you know the relative locations of the elements on the periodic table. If this helps you, then please rate lifesaver. Thanks..

Knowing the electronegativities of each atom involved in the bonds w.pdf

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Hi I have added a loop for adding values to list. Highlighted the code changes below. public static ArrayList doArrayListAdd(int numItems) { System.out.print(\"doArrayListAdd: \"); ArrayList list = new ArrayList<>(); long startTime = getTimestamp(); // TODO Write code that adds 0 through (numitems - 1) // to list inside a loop for(int i=0; i Solution Hi I have added a loop for adding values to list. Highlighted the code changes below. public static ArrayList doArrayListAdd(int numItems) { System.out.print(\"doArrayListAdd: \"); ArrayList list = new ArrayList<>(); long startTime = getTimestamp(); // TODO Write code that adds 0 through (numitems - 1) // to list inside a loop for(int i=0; i.

HiI have added a loop for adding values to list. Highlighted the c.pdf

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How a network connection is created ? A network connection is initiated by a client program when it creates a socket for the communication with the server. To create the socket in Java, the client calls the Socket constructor and passes the server address and the the specific server port number to it. At this stage the server must be started on the machine having the specified address and listening for connections on its specific port number. The server uses a specific port dedicated only to listening for connection requests from clients. It can not use this specific port for data communication with the clients because the server must be able to accept the client connection at any instant. So, its specific port is dedicated only to listening for new connection requests. The server side socket associated with specific port is called server socket. When a connection request arrives on this socket from the client side, the client and the server establish a connection. This connection is established as follows: The java.net package in the Java development environment provides the class Socket that implements the client side and the class serverSocket class that implements the server side sockets. The client and the server must agree on a protocol. They must agree on the language of the information transferred back and forth through the socket. There are two communication protocols : The stream communication protocol is known as TCP (transfer control protocol). TCP is a connection-oriented protocol. It works as described in this document. In order to communicate over the TCP protocol, a connection must first be established between two sockets. While one of the sockets listens for a connection request (server), the other asks for a connection (client). Once the two sockets are connected, they can be used to transmit and/or to receive data. When we say \"two sockets are connected\" we mean the fact that the server accepted a connection. As it was explained above the server creates a new local socket for the new connection. The process of the new local socket creation, however, is transparent for the client. The datagram communication protocol, known as UDP (user datagram protocol), is a connectionless protocol. No connection is established before sending the data. The data are sent in a packet called datagram. The datagram is sent like a request for establishing a connection. However, the datagram contains not only the addresses, it contains the user data also. Once it arrives to the destination the user data are read by the remote application and no connection is established. This protocol requires that each time a datagram is sent, the local socket and the remote socket addresses must also be sent in the datagram. These addresses are sent in each datagram. The java.net package in the Java development environment provides the class DatagramSocket for programming datagram communications. UDP is an unreliable protocol. There is no guarantee that the .

How a network connection is created A network connection is initi.pdf

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DNA is the callde as molucule which gives genetic information. It gives or stores instruction to give large molucules called proteins. These instructions are there in side of every cells, distributed by 46 long structures called chromosomes. These are made up of thusands of DNA, called genes. Each gene stores the directions for making protein fragments, whole proteins, or multiple specific proteins. DNA is well-suited to perform this biological function because of its molecular structure, and because of the development of a series of high performance enzymes that are fine-tuned to interact with this molecular structure in specific ways. The match between DNA structure and the activities of these enzymes is so effective and well-refined that DNA has become, over evolutionary time, the universal information-storage molecule for all forms of life. Nature has yet to find a better solution than DNA for storing, expressing, and passing along instructions for making proteins. Ribonuclic acid functions as genetic messengers and builders of the cellular world. 3 types of RNA mainly r-RNA (ribosomal RNA) , t-RNA (transfer RNA) and m-RNA (messenger RNA) one of the main function of RNA is protein synthesis Differences between RNA and DNA Genetic code is stored in DNA as linear/ non-overlaping form in the nitrogenous base of adenine, guanine, cytosine and thymineDNARNALong polymer with deoxyriboses and phosphate backboneRNA is a polymer with a ribose and phosphate backboneHaving nitrogenous bases: adenine, guanine, cytosine and thymineHaving nitrogenous bases: adenine, guanine, cytosine, and uracilIt usually accours in side the nucleus and some cell organellesVery little present in side nucleus most of it accours in cytoplasmDauble standard exception of some virusesSingle standard exception of some virusesFunction is to transfer gentitic information to one generation to other generation.Main function is protein synthesisLong life spanshart life span Solution DNA is the callde as molucule which gives genetic information. It gives or stores instruction to give large molucules called proteins. These instructions are there in side of every cells, distributed by 46 long structures called chromosomes. These are made up of thusands of DNA, called genes. Each gene stores the directions for making protein fragments, whole proteins, or multiple specific proteins. DNA is well-suited to perform this biological function because of its molecular structure, and because of the development of a series of high performance enzymes that are fine-tuned to interact with this molecular structure in specific ways. The match between DNA structure and the activities of these enzymes is so effective and well-refined that DNA has become, over evolutionary time, the universal information-storage molecule for all forms of life. Nature has yet to find a better solution than DNA for storing, expressing, and passing along instructions for making proteins. Ribonuclic acid functions as gen.

DNA is the callde as molucule which gives genetic information. It gi.pdf

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false, Because Conservatsim is define as a plitical policy that promote the conservation of traditional ,cultural and social stability. establising institutions, and preferring gradual development to abrupt change. Solution false, Because Conservatsim is define as a plitical policy that promote the conservation of traditional ,cultural and social stability. establising institutions, and preferring gradual development to abrupt change..

false,Because Conservatsim is define as a plitical policy that pro.pdf

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d. Fungiform, foliate, and circumvallate papillae Fungiform papillae are mushroom shaped, present at the dorsal surface of the tongue Foliate papillae are ridges and grooves present at the posterior edge of the tongue circumvallate papillae are only few in number, and are located posterior to the oral part of the tongue. ** Filiform papillae are not associated with taste buds. Solution d. Fungiform, foliate, and circumvallate papillae Fungiform papillae are mushroom shaped, present at the dorsal surface of the tongue Foliate papillae are ridges and grooves present at the posterior edge of the tongue circumvallate papillae are only few in number, and are located posterior to the oral part of the tongue. ** Filiform papillae are not associated with taste buds..

d. Fungiform, foliate, and circumvallate papillaeFungiform papilla.pdf

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Carrier sense multiple access with collision detection (CSMA/CD) is a media access method used by twisted-pair Ethernet networks. CSMA/CA is used in wireless networks . Token passing is used in token ring and ARCNET. OFDMA is used in WiMAX. Solution Carrier sense multiple access with collision detection (CSMA/CD) is a media access method used by twisted-pair Ethernet networks. CSMA/CA is used in wireless networks . Token passing is used in token ring and ARCNET. OFDMA is used in WiMAX..

Carrier sense multiple access with collision detection (CSMACD) is .pdf

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