Na2SeO3 ---> 2 Na+ + SeO32- 0.08 0.16 0.08 SeO32- + H2O <---> HSeO3- + OH- 0.08 0 0 -x x x 0.08-x x x Kb2 = Kw/Ka2 = 1E-14/(4.8E-9) Kb2 = 0.21E-5 0.21E-5 = x2/(0.08-x) x = 4.1E-4 HSeO3- + H2O <---> H2SeO3 + OH- 4.1E-4 0 0 -y y y 4.1E-4 - y y y Kb1 = Kw/Ka1 Kb1 = 1E-14/(2.4E-3) = 0.42E-11 The second hydrolysis constant is much smaller than the first, so we can the assume that the first step dominates. [H+]*[OH-]=1E-14 [H+]*4.1E-4=1E-14 [H+] = 0.24E-10 pH = 10.6 Ok? Solution Na2SeO3 ---> 2 Na+ + SeO32- 0.08 0.16 0.08 SeO32- + H2O <---> HSeO3- + OH- 0.08 0 0 -x x x 0.08-x x x Kb2 = Kw/Ka2 = 1E-14/(4.8E-9) Kb2 = 0.21E-5 0.21E-5 = x2/(0.08-x) x = 4.1E-4 HSeO3- + H2O <---> H2SeO3 + OH- 4.1E-4 0 0 -y y y 4.1E-4 - y y y Kb1 = Kw/Ka1 Kb1 = 1E-14/(2.4E-3) = 0.42E-11 The second hydrolysis constant is much smaller than the first, so we can the assume that the first step dominates. [H+]*[OH-]=1E-14 [H+]*4.1E-4=1E-14 [H+] = 0.24E-10 pH = 10.6 Ok?.