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You have to leave solids and liquids out of the equation.
This leaves only product B for the product, nothing for the reactants.
Initially there was no product B.
At equilibrium: you determine the molarity by multiplying 2.5% by (0.5M/10L)= .00125 =
which rounds to answer E) 1.3e-3
it was a trick question.
Solution
You have to leave solids and liquids out of the equation.
This leaves only product B for the product, nothing for the reactants.
Initially there was no product B.
At equilibrium: you determine the molarity by multiplying 2.5% by (0.5M/10L)= .00125 =
which rounds to answer E) 1.3e-3
it was a trick question.

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