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the issue of camera and cell phone privecy is importent many cell phone cameras by default and automatically reveal amount of information such as physical location of picture,time,and date etc...a number of companies facilities along with laws and implimentation have increased it is often difficult what privacy protection you have. according to the indectments the accused conducted sexual conversation with researcher person posting as 13 years old girls.some of them committed indecent act before the women\'s eyes.others sent them pronography. and all of themarranged to meet researchers apartments an acters was waiting for them there. after the man spoke with her briefly the program moderator showed up andconfronted them. thje men were arrested on camera by police Solution the issue of camera and cell phone privecy is importent many cell phone cameras by default and automatically reveal amount of information such as physical location of picture,time,and date etc...a number of companies facilities along with laws and implimentation have increased it is often difficult what privacy protection you have. according to the indectments the accused conducted sexual conversation with researcher person posting as 13 years old girls.some of them committed indecent act before the women\'s eyes.others sent them pronography. and all of themarranged to meet researchers apartments an acters was waiting for them there. after the man spoke with her briefly the program moderator showed up andconfronted them. thje men were arrested on camera by police.

the issue of camera and cell phone privecy is importent many cell phone cameras by default and
automatically reveal amount of information such as physical location of picture,time,and date
etc...a number of companies facilities along with laws and implimentation have increased it is
often difficult what privacy protection you have.
according to the indectments the accused conducted sexual conversation with researcher person
posting as 13 years old girls.some of them committed indecent act before the women's
eyes.others sent them pronography. and all of themarranged to meet researchers apartments an
acters was waiting for them there. after the man spoke with her briefly the program moderator
showed up andconfronted them. thje men were arrested on camera by police
Solution
the issue of camera and cell phone privecy is importent many cell phone cameras by default and
automatically reveal amount of information such as physical location of picture,time,and date
etc...a number of companies facilities along with laws and implimentation have increased it is
often difficult what privacy protection you have.
according to the indectments the accused conducted sexual conversation with researcher person
posting as 13 years old girls.some of them committed indecent act before the women's
eyes.others sent them pronography. and all of themarranged to meet researchers apartments an
acters was waiting for them there. after the man spoke with her briefly the program moderator
showed up andconfronted them. thje men were arrested on camera by police

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The tactics and the procedures that govern the interrogations of juveniles vary with each jurisdiction because they are based on the procedures of the individual department and the style of the questioning officer, but the one commonality is that they are the same ones used in adult interrogations. The most common interrogation tactic used by police is the Reid technique which was first developed in the 1940’s. Under these tactics, police rely on three concepts that are intended to lead the suspect to believe that confessing to the crime is in the suspect’s best interest. The first concept is isolation which consists of removing the individual from their family and friends in the hopes that it will make them feel all alone. The second is Maximization where the officers attempt to elicit a confession by telling the individual that they know they are guilty. In this phase the officer presents a theory of the crime and how the individual was involved, evidence if there is any, or in some instances the suggestion that there is evidence. The third is Minimization where the officer attempts to help the individual reconcile with the crime. In this phase the officer might show understanding of why the individual committed the crime (Mince-Dider, 2016). The potential problems presented with these tactics when questioning juveniles is similar to those found with them understanding their rights and the potential consequences associated with the waiver process. There has always been a debate over when juveniles are mature enough to fully comprehend the importance of what is going on. Research from one study has shown about one-third of a sample of institutional youths incorrectly believed that they had to talk with the police (Elrod, 2011). Combine that statistic, a juvenile’s perception that officers are always truthful, and that an adult or attorney do not have to be present if the right is waived and these tactics while not illegal or immoral could led a juvenile to falsely confess. The court has tried to mitigate the possible problems with these tactics. In the case of Fare v Michael C. the court attached Miranda and addressed another no longer used tactic, long interrogations with our breaks, applying the totality of the circumstance test. In the State v Benoit the court attached three factors to attempt to help: first clear and understandable explanation of rights, second they must be made aware of possible adult criminal prosecution and waiver if applicable, and third at the time of arrest the officer in charge must immediately secure the name of a friendly adult they can consult. reply in your own words 75 words or more In the 1967 ruling the Supreme Court ruled on the In re Gault case. That case was a landmark case involving juvenile rights. In that case the court ruled that a juvenile would be afforded the same rights as an adult. Also the court stated that “if counsel was not present for some permissible reason when an admissio.

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You will want to look at electronegativity differences between elements in a molecule. Ionic bonds will only occur when the difference of electronegativity for the bonding elemets is high, such as Sodium (very low electronegativity) and Chlorine (very high electronegativity). Depending on which chemistry you are taking, you could even go as simple is ionic bonding occurs only when bonding elements on different sides of the periodic table. Phosphorous and Antimony are fairly close to Chlorine, and thus will form a covalent bond. To find out whether it is polar or non-polar, you must look closer into the difference of electronegativity in the entire molecule, but for this example, just take a quick glance at a Lewis Dot Diagram. If the molecule is symmetric (like most organic chemicals), the molecule is non- polar (like most organic chemicals). If the molecule is not symmetric, it will be polar, like water. Solution You will want to look at electronegativity differences between elements in a molecule. Ionic bonds will only occur when the difference of electronegativity for the bonding elemets is high, such as Sodium (very low electronegativity) and Chlorine (very high electronegativity). Depending on which chemistry you are taking, you could even go as simple is ionic bonding occurs only when bonding elements on different sides of the periodic table. Phosphorous and Antimony are fairly close to Chlorine, and thus will form a covalent bond. To find out whether it is polar or non-polar, you must look closer into the difference of electronegativity in the entire molecule, but for this example, just take a quick glance at a Lewis Dot Diagram. If the molecule is symmetric (like most organic chemicals), the molecule is non- polar (like most organic chemicals). If the molecule is not symmetric, it will be polar, like water..

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Well 1-Heptanol is a straight chained 7 carbon molecule with an OHgroup attached to one end, to state the obvious. Because 1-Heptanol is longer than Ethanol, the Oxygen does not havemuch of an effect on the electron distribution at the far end ofthe molecule. Conversely, Ethanol has two carbons attached toan OH group. The electrons around those two carbons aregreatly affected by the OH group. So if you made a map of polarity of each of these molecules, theentire Ethanol molecule would likely be affected by the OHgroup. In 1-Heptanol, the polarity would be concentrated nearthe OH group, but the other end of the molecule would likely beunaffected by the presence of the OH group. Therefore theEthanol molecule is more polar, because the entire molecule\'selectron density is affected. Does this make sense? If you have any questions about myexplanation or you want clarification please ask. Solution Well 1-Heptanol is a straight chained 7 carbon molecule with an OHgroup attached to one end, to state the obvious. Because 1-Heptanol is longer than Ethanol, the Oxygen does not havemuch of an effect on the electron distribution at the far end ofthe molecule. Conversely, Ethanol has two carbons attached toan OH group. The electrons around those two carbons aregreatly affected by the OH group. So if you made a map of polarity of each of these molecules, theentire Ethanol molecule would likely be affected by the OHgroup. In 1-Heptanol, the polarity would be concentrated nearthe OH group, but the other end of the molecule would likely beunaffected by the presence of the OH group. Therefore theEthanol molecule is more polar, because the entire molecule\'selectron density is affected. Does this make sense? If you have any questions about myexplanation or you want clarification please ask..

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Water\'s bent structure leads to its polar nature, which is the cause for most of its unique properties. It the molecule were straight, it would not be polar and this would be quite disruptive. Water would no longer be strongly attracted to itself or other polar molecules. So water would no longer have surface tension. Insects which walk on water would fall through. Water would have a far lower boiling point, so it would evaporate much more easily. Also, boiling water would no longer be hot enough to cook food. The hydrogen bonding character of water would change, resulting in that ice would no longer be less dense than liquid water, and therefore ice would sink to the bottom of bodies of water. Most disastrous would be the effect on living things. Water would no longer be a solvent and so anything which is dissolved in water in animal\'s bodies would come out of solution. Ions and electrolytes would come out of the water and clump up in the body. Without water to dissolve things, the blood could no longer carry certain essential chemicals to the cells, nor could it carry certain toxic wastes away from cells. Cellular metabolism would soon cease to function and life as we know it would for the most part cease. ===================== If water were a linear molecule, would it still be polar? 1 Yes No .Would the water molecules still be able to form hydrogen bonds with one another? 2 Yes No . ANsWER Answer Details 1. no 2. yes. note: if the water molecule is linear, the net dipole moment is zero. thus, it is not polar. However, the O-H bond is still polar due to the different electronegativity of O and H atoms. Thus, the H---O-H hydrogen bonds still exist. Solution Water\'s bent structure leads to its polar nature, which is the cause for most of its unique properties. It the molecule were straight, it would not be polar and this would be quite disruptive. Water would no longer be strongly attracted to itself or other polar molecules. So water would no longer have surface tension. Insects which walk on water would fall through. Water would have a far lower boiling point, so it would evaporate much more easily. Also, boiling water would no longer be hot enough to cook food. The hydrogen bonding character of water would change, resulting in that ice would no longer be less dense than liquid water, and therefore ice would sink to the bottom of bodies of water. Most disastrous would be the effect on living things. Water would no longer be a solvent and so anything which is dissolved in water in animal\'s bodies would come out of solution. Ions and electrolytes would come out of the water and clump up in the body. Without water to dissolve things, the blood could no longer carry certain essential chemicals to the cells, nor could it carry certain toxic wastes away from cells. Cellular metabolism would soon cease to function and life as we know it would for the most part cease. ===================== If water were a linear molecule, would it still be pol.

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Yes,all macromolecule are passed from nuclear pore envelope to cytoplasmic compartments(including ER).Transport of macromolecules between the nuclear and cytoplasmic compartments occurs through nuclear pore complexes that span the double membrane of this envelope. Solution Yes,all macromolecule are passed from nuclear pore envelope to cytoplasmic compartments(including ER).Transport of macromolecules between the nuclear and cytoplasmic compartments occurs through nuclear pore complexes that span the double membrane of this envelope..

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The transport of sodium ions and glucose into the cell is through symnport. For every two sodium ions transported into cell, one glucose is also transported in the same direction. The concentration gradient of sodium is used to transport glucose into the cell, against its own concentration gradient (that is, irrespective of the concentration of glucose). This is why, though the glucose concentration inside the cell is higher compared to the cell exterior, glucose is transported inside. In the given experiment, the concentration of sodium ions inside the cell is initially low or very less. There is a large concentration gradient of Na+ ions, due to which they are transported into the cell easily. Glucose is also transported along with, without any hindrance. When equilibrium is attained between the cell exterior and the cell interior with respect to sodium ions, there is no net movement of ions into the cell. Therefore, symport of glucose is stopped. When the concentration of extracellular Na+ ions increases, the concentration gradient also increases as a result of which there is high net movement of Na+ ions into the cells. The cells reaches equilibrium quickly, and this is why the plateau is reached. B. Leaky channels allow leaking of Na+ and K+ ions to leak down their concentration gradient. Therefore, apart from Na+ K+ pump, the channels also transport the ions, without transporting glucose. Therefore, less glucose enters the cells, the cells reach equilibrium quickly. Solution The transport of sodium ions and glucose into the cell is through symnport. For every two sodium ions transported into cell, one glucose is also transported in the same direction. The concentration gradient of sodium is used to transport glucose into the cell, against its own concentration gradient (that is, irrespective of the concentration of glucose). This is why, though the glucose concentration inside the cell is higher compared to the cell exterior, glucose is transported inside. In the given experiment, the concentration of sodium ions inside the cell is initially low or very less. There is a large concentration gradient of Na+ ions, due to which they are transported into the cell easily. Glucose is also transported along with, without any hindrance. When equilibrium is attained between the cell exterior and the cell interior with respect to sodium ions, there is no net movement of ions into the cell. Therefore, symport of glucose is stopped. When the concentration of extracellular Na+ ions increases, the concentration gradient also increases as a result of which there is high net movement of Na+ ions into the cells. The cells reaches equilibrium quickly, and this is why the plateau is reached. B. Leaky channels allow leaking of Na+ and K+ ions to leak down their concentration gradient. Therefore, apart from Na+ K+ pump, the channels also transport the ions, without transporting glucose. Therefore, less glucose enters the cells, the cells reach equilibrium qu.

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Summary of JavaScript https://en.wikipedia.org/wiki/JavaScript http://www.tutorialspoint.com/javascript/ http://www.w3schools.com/js/ParadigmMulti-paradigm: scripting, object-oriented (prototype- based), imperative, functional, event-drivenDesigned byBrendan EichDeveloperNetscape Communications Corporation, Mozilla Foundation, Ecma InternationalFirst appearedMay 23, 1995; 21 years agoStable releaseECMAScript 2016 / June 17, 2016; 2 months agoTyping disciplinedynamic, duckMajor implementationsV8, JavaScriptCore, SpiderMonkey, ChakraInfluenced byLua, Scheme, Perl, Self, Java, C, Python, AWK, HyperTalkInfluencedActionScript, AtScript, CoffeeScript, Dart, JScript .NET, LiveScript, Objective-J, Opa, Perl 6, QML, TypeScriptFilename extension.jsInternet media typeapplication/javascript text/javascript (obsolete)Uniform Type Identifier (UTI)com.netscape.javascript-sourceType of formatScripting languageURL https://en.wikipedia.org/wiki/JavaScript http://www.tutorialspoint.com/javascript/ http://www.w3schools.com/js/ Solution Summary of JavaScript https://en.wikipedia.org/wiki/JavaScript http://www.tutorialspoint.com/javascript/ http://www.w3schools.com/js/ParadigmMulti-paradigm: scripting, object-oriented (prototype- based), imperative, functional, event-drivenDesigned byBrendan EichDeveloperNetscape Communications Corporation, Mozilla Foundation, Ecma InternationalFirst appearedMay 23, 1995; 21 years agoStable releaseECMAScript 2016 / June 17, 2016; 2 months agoTyping disciplinedynamic, duckMajor implementationsV8, JavaScriptCore, SpiderMonkey, ChakraInfluenced byLua, Scheme, Perl, Self, Java, C, Python, AWK, HyperTalkInfluencedActionScript, AtScript, CoffeeScript, Dart, JScript .NET, LiveScript, Objective-J, Opa, Perl 6, QML, TypeScriptFilename extension.jsInternet media typeapplication/javascript text/javascript (obsolete)Uniform Type Identifier (UTI)com.netscape.javascript-sourceType of formatScripting languageURL https://en.wikipedia.org/wiki/JavaScript http://www.tutorialspoint.com/javascript/ http://www.w3schools.com/js/.

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R is a very flexible and powerful programming language, as well as a package that is written using that language (and others like C). The following program demonstrates many of its basic features. You can cut and paste it into R, or download the file that includes it from here. If you run it line by line, many of its features will become clear. Both editions of R for SAS and SPSS Users and R for Stata Users work through a version of this program line-by-line, showing the output and explaining what R is doing. # Filename: ProgrammingBasics.R # ---Simple Calculations--- 2 + 3 x <- 2 y <- 3 x + y x * y # ---Data Structures--- # Vectors workshop <- c(1, 2, 1, 2, 1, 2, 1, 2) print(workshop) workshop gender <- c(\"f\", \"f\", \"f\", NA, \"m\", \"m\", \"m\", \"m\") q1 <- c(1, 2, 2, 3, 4, 5, 5, 4) q2 <- c(1, 1, 2, 1, 5, 4, 3, 5) q3 <- c(5, 4, 4,NA, 2, 5, 4, 5) q4 <- c(1, 1, 3, 3, 4, 5, 4, 5) # Selecting Elements of Vectors q1[5] q1[ c(5, 6, 7, 8) ] q1[5:8] q1[gender == \"m\"] mean( q1[ gender == \"m\" ], na.rm = TRUE) # ---Factors--- # Numeric Factors # First, as a vector workshop <- c(1, 2, 1, 2, 1, 2, 1, 2) workshop table(workshop) mean(workshop) gender[workshop == 2] # Now as a factor workshop <- c(1, 2, 1, 2, 1, 2, 1, 2) workshop <- factor(workshop) workshop table(workshop) mean(workshop) #generates error now. gender[workshop == 2] gender[workshop == \"2\"] # Recreate workshop, making it a factor # including levels that don\'t yet exist. workshop <- c(1, 2, 1, 2, 1, 2, 1, 2) workshop <- factor( workshop, levels = c( 1, 2, 3, 4), labels = c(\"R\", \"SAS\", \"SPSS\", \"Stata\") ) # Recreate it with just the levels it # curently has. workshop <- c(1, 2, 1, 2, 1, 2, 1, 2) workshop <- factor( workshop, levels = c( 1, 2), labels = c(\"R\",\"SAS\") ) workshop table(workshop) gender[workshop == 2] gender[workshop == \"2\"] gender[workshop == \"SAS\"] # Character factors gender <- c(\"f\", \"f\", \"f\", NA, \"m\", \"m\", \"m\", \"m\") gender <- factor( gender, levels = c(\"m\", \"f\"), labels = c(\"Male\", \"Female\") ) gender table(gender) workshop[gender == \"m\"] workshop[gender == \"Male\"] # Recreate gender and make it a factor, # keeping simpler m and f as labels. gender <- c(\"f\", \"f\", \"f\", NA, \"m\", \"m\", \"m\", \"m\") gender <- factor(gender) gender # Data Frames mydata <- data.frame(workshop, gender, q1, q2, q3, q4) mydata names(mydata) row.names(mydata) # Selecting components by index number mydata[8, 6] #8th obs, 6th var mydata[ , 6] #All obs, 6th var mydata[ , 6][5:8] #6th var, obs 5:8 # Selecting components by name mydata$q1 mydata$q1[5:8] # Example renaming gender to sex while # creating a data frame (left as a comment) # # mydata <- data.frame(workshop, sex = gender, # q1, q2, q3, q4) # Matrices # Creating from vectors mymatrix <- cbind(q1, q2, q3, q4) mymatrix dim(mymatrix) # Creating from matrix function # left as a comment so we keep # version with names q1, q2... # # mymatrix <- matrix( # c(1, 1, 5, 1, # 2, 1, 4, 1, # 2, 2, 4, 3.

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