Two friends board an airliner just before departure time. There are only ten seats left, two of which are aisle seats. How many ways can the two people arrange themselves in available seats so that at least one of them sits on the aisle? Solution total seats avaiable: 10 2= aisle , 8 = normal 1) both the friends get the aisle seats= 2P2= 2 ways 2) one gets an aisle seat while other gets the normal seat = 2P1x 8P1= 2x8 = 16 ways Total way s= 2 + 16 = 18 ways.