Suppose that you are presented with three urns. Each urn contains five indistinguishable balls, except that one is green and four are red. You get to draw once from each urn. What is the probability that you get an odd number of green balls? Also: What type of random variable is involved in this problem? Solution P(odd no of green balls)=1-((1/5)^2*(4/5))=.97 discrete random variable.

1. Suppose that you are presented with three urns. Each urn contains five indistinguishable balls,
except that one is green and four are red. You get to draw once from each urn. What is the
probability that you get an odd number of green balls? Also: What type of random variable is
involved in this problem?
Solution
P(odd no of green balls)=1-((1/5)^2*(4/5))=.97 discrete random variable