Find the length and width of a rectangle whose perimeter is equal to 160 cm and its length is equal to triple its width. Solution Let the width of the perimeter be \"w\" and the length be \"L\" Given that the perimeter is 160 cm But the perimeter is given by : P = 2L + 2W = 160 We will divide by 2. ==> L + w = 80 ............(1) We are given that the length if triple the width. Then the length if 3 times the width. ==> L = 3*W Now we will substitute into (1). ==> L + w = 80 ==> 3w + w = 80 ==> 4w = 80 ==> w = 80/4 = 20 ==> L = 3*20 = 60 Then the length of the rectangle = 60 cm, and the width = 20 cm.

1. Find the length and width of a rectangle whose perimeter is equal to 160 cm and its length is
equal to triple its width.
Solution
Let the width of the perimeter be "w" and the length be "L"
Given that the perimeter is 160 cm
But the perimeter is given by :
P = 2L + 2W = 160
We will divide by 2.
==> L + w = 80 ............(1)
We are given that the length if triple the width.
Then the length if 3 times the width.
==> L = 3*W
Now we will substitute into (1).
==> L + w = 80
==> 3w + w = 80
==> 4w = 80
==> w = 80/4 = 20
==> L = 3*20 = 60
Then the length of the rectangle = 60 cm, and the width = 20 cm