Now we will modify the problem specification slightly. The program should now display the
depreciated values using three different rates: 15%,20%, and 25%. Figure 812 shows the
modified problem specification and C++ code, as well as a sample run of the program. The
modifications made to the original code are shaded in the figure. Notice that the modified code
contains two loops rather than one loop. Both loops are counter-controlled loops, and one is
nested within the other. The outer loop keeps track of the depreciation rates, and the nested loop
keeps track of the years. The flowchart for the modified program is shown in Figure 8-13.
Problem specification Create a program that displays the value of a new car at the end of each of
five years, using annual depreciation rates of 15%,20%, and 25%. int maino f double
originalvalue =0.0 double depreciation =0.0 double currentValue =0.0 cout "Original value: ";
cin originalValue; cout end fixed setprecision (0)
(continued).
Now we will modify the problem specification slightly. The program sh.pdf
1. Now we will modify the problem specification slightly. The program should now display the
depreciated values using three different rates: 15%,20%, and 25%. Figure 812 shows the
modified problem specification and C++ code, as well as a sample run of the program. The
modifications made to the original code are shaded in the figure. Notice that the modified code
contains two loops rather than one loop. Both loops are counter-controlled loops, and one is
nested within the other. The outer loop keeps track of the depreciation rates, and the nested loop
keeps track of the years. The flowchart for the modified program is shown in Figure 8-13.
Problem specification Create a program that displays the value of a new car at the end of each of
five years, using annual depreciation rates of 15%,20%, and 25%. int maino f double
originalvalue =0.0 double depreciation =0.0 double currentValue =0.0 cout "Original value: ";
cin originalValue; cout end fixed setprecision (0)
(continued)
