1. If there is no discount lending, the Fed can change the _____ to change the amount of
borrowing from the Federal Reserve.
discount rate
reserve requirement
both of the above
neither of the above
2. When the Fed raises the discount rate, the _____ of reserves shifts _____.
supply, down
demand, up
demand, down
supply, up
3. Which of the following countries had some success with targeting monetary aggregates?
Germany
United States
New Zealand
none of the aboveA.
discount rateB.
reserve requirementC.
both of the aboveD.
neither of the above
Solution
Answer:
1.Correct Answer = (A) Discount Rate
Justification: Change in discount rate bring the change in the amount of borrowing, higher
discount rate discourage the bank borrowing while lower discount rate shall encourage the bank
borrowing.
2. Correct Answer = (A) Supply, Down
Justification: Lower discount rate will encourage bank borrowing, increasing the supply of
reserves inversely the Higher discount rate discourages the bank borrowing and decrease the
supply of reserve.
3. Correct Answer = (A) Germany
Justification: Germany and Switzerland are the countries who had some success with targeting
monetary aggregates..
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1. If X is a hypergeometric random variable with parameters n, K, an.pdf
1. 1. If X is a hypergeometric random variable with parameters n, K, and N, and p = K/N, the mean
and variance of X are:
a. np and np(1 – p)
b. p and np(1 – p)
c. np and p(1 – p)
d. np and np(1 – p)[(N – n)/(N – 1)]
2. If X is a discrete uniform random variable defined on the consecutive integers 10, 11, …, 20,
the mean of X is:
a. 30
b. 15
c. 12
d. none
3. If S is the sample space of a random experiment and E is any event, the axioms of probability
are
a. P(S) = 1
b. 0 <= P(E) <= 1
c. For any two events E1, E2 with E1 intersect E2 = null, P(E1 union E2) = P(E1) + P(E2)
d. none of the above
e. all of the above
4. Two events A and B are independent with P(A) = P(B) = 0.5. Then P(A intersect B) is:
a. 0.50
b. 0.75
c. 1.0
d. 0.25
5. If X is a binomial random variable with n = 20 and p = 0.25, the mean of X is
a. 10
2. b. 5
c. 4
d. None
Solution
1. d 2. b (20-10)/2 = 15 3. d 4. d (.5)(.5) =.25 5. b n*p=20*.25=5
![1. If X is a hypergeometric random variable with parameters n, K, and N, and p = K/N, the mean
and variance of X are:
a. np and np(1 – p)
b. p and np(1 – p)
c. np and p(1 – p)
d. np and np(1 – p)[(N – n)/(N – 1)]
2. If X is a discrete uniform random variable defined on the consecutive integers 10, 11, …, 20,
the mean of X is:
a. 30
b. 15
c. 12
d. none
3. If S is the sample space of a random experiment and E is any event, the axioms of probability
are
a. P(S) = 1
b. 0 <= P(E) <= 1
c. For any two events E1, E2 with E1 intersect E2 = null, P(E1 union E2) = P(E1) + P(E2)
d. none of the above
e. all of the above
4. Two events A and B are independent with P(A) = P(B) = 0.5. Then P(A intersect B) is:
a. 0.50
b. 0.75
c. 1.0
d. 0.25
5. If X is a binomial random variable with n = 20 and p = 0.25, the mean of X is
a. 10](https://image.slidesharecdn.com/1-230327161445-5ec887d5/85/1-if-x-is-a-hypergeometric-random-variable-with-parameters-n-k-anpdf-1-320.jpg)
