Bandwidth of a Series Resonance Circuit The area under the curve shows all acceptable signals with frequency greater than fL and less than fh that can pass through the resonance circuit. This is used in radio receivers to tune for different channels. If the following equation I(f) represents the curve for a frequency bandwidth similar to the one above, find the area under the curve from fL = .8 H to fH. = 1.2 H. Round all values to the 100ths. I(f)=1/2 squareroot 2 pi .e^-(f- 1)^2/(2)^2, xmin= -2, xmax = 3, ymin= -2, ymax = 3 Solution from the above graph, the band width is BW=fH-fL=1.2-0.8=0.4Hz if we substitue 0.8Hz in the current equation I(0.8)=(1/0.2sqrt(2pi))*exp(-(f-1)^2/2(0.2)^2))=1.21A Imin=1.21 A Imax=1.711 A.

1. Bandwidth of a Series Resonance Circuit The area under the curve shows all acceptable signals
with frequency greater than fL and less than fh that can pass through the resonance circuit. This
is used in radio receivers to tune for different channels. If the following equation I(f) represents
the curve for a frequency bandwidth similar to the one above, find the area under the curve from
fL = .8 H to fH. = 1.2 H. Round all values to the 100ths. I(f)=1/2 squareroot 2 pi .e^-(f-
1)^2/(2)^2, xmin= -2, xmax = 3, ymin= -2, ymax = 3
Solution
from the above graph, the band width is
BW=fH-fL=1.2-0.8=0.4Hz
if we substitue 0.8Hz in the current equation
I(0.8)=(1/0.2sqrt(2pi))*exp(-(f-1)^2/2(0.2)^2))=1.21A
Imin=1.21 A
Imax=1.711 A