assume tha x has a normal distribution with mean =137 and standard deviation -5.3 what is the probability that x is between 134.4 and 140.17 Solution µ = 137 s = 5.3 Use a standard normal table to find the following probabilities: P(134.4 < x < 140.17) = P((134.4 - 137)/5.3) < (x-µ)/s < (140.17 - 137)/5.3) = P(-0.49 < z < 0.6) = 1 - .3121 - .2743 = .4136.